1. For the reaction 3A — C, the initial concentration of A was 0.2 M, and the reaction rate was
1.0 M/s. When [A] was doubled, the reaction rate increased to 4.0 M/s. Determine the rate
law for the reaction.

Answer:

874.89 mmHg

Explanation:

Using the combined gas law equation as follows:

P1V1/T1 = P2V2/T2

Where;

P1 = initial pressure (mmHg)

P2 = final pressure (mmHg)

V1 = initial volume (L)

V2 = final volume (L)

T1 = initial temperature (K)

T2 = final temperature (K)

Based on the information provided in this question;

P1 = 950 mm Hg

P2 = ?

V1 = 25 L

V2 = 30 L

T1 = 155°C = 155 + 273 = 428K

T2 = 200°C = 200 + 273 = 473K

Using P1V1/T1 = P2V2/T2

950 × 25/428 = P2 × 30/473

23750/428 = 30P2/473

55.49 = 0.063P2

P2 = 55.49 ÷ 0.063

P2 = 874.89 mmHg

Answer:

4. D sounds like the best option.

5. D is the correct answer.

Explanation:

You're Welcome

Answer:

1. Stop throwing trash and bottles in lakes because it can have our animals live longer and not have issues

2. Reducing the number of bags you use from the store because they can end up being on the ground and cause plenty of damage around us

3. probably trying not to having fires because there is alot of problems that are happening like the wildfires in californa which is leading to our animals and trees dying

hope this helps

have a good day :)

Explanation:

Explanation:

Take shelter in a hard wall building

Close doors and windows cut off ventilation

Answer:

Total pressure of the mixture = 1 atm

Partial pressure of He = 0.863 atm

Partial pressure of Ar  = 0.0173 atm

Partial pressure of Ne = 0.1197 atm

We confirm that the sum of partial pressure of each gas valu

Explanation:

STP conditions are:

1 atm of pressure and

273K of T°

We can also say that those value reffers to 1 mol.

We determine the moles of each:

5 g . 1mol / 4g = 1.25 moles of He

1g . 1mol / 39.9 g = 0.0250 moles of Ar

3.5g . 1mol / 20.18 g = 0.173 moles of Ne

Total pressure of a mixture can be obtained from the Ideal Gases Law.

P . V = n . R . T

Total moles: 1.25 + 0.025 + 0.173 = 1.448 moles

But now, we need the volume. We know that 1 mol is contained at 22.4L at STP.

1.448 mol . 22.4L / 1 mol = 32.4 L

That's the volume for our mixture. We replace:

32.4 L . P  = 1.448 mol . 0.082 . 273K

P = (1.448 mol . 0.082 . 273K) / 32.4L = 1 atm

Now we can obtained the partial pressure of each gas from mole fraction

Mol of gas / Total pressure = Partial pressure of gas / Total pressure

Partial pressure of He = (1.25 / 1.448) . 1 atm = 0.863 atm

Partial pressure of Ar = (0.025 / 1.448) . 1 atm = 0.0173 atm

We know that sum of partial pressure is 1 - (Mole fraction He + Mole fr. Ar)

Partial pressure of Ne = 1 - (0.863 + 0.0173) = 0.1197 atm

We confirm that the sum of partial pressure of each gas values the total pressure of the mixture: 0.863 + 0.0173 + 0.1197 = 1

Answer:

Three isomers

Isomer I  CH3-CHOH - CH3

Isomer 2 CH2OH-CH2-CH3

Isomer 3  CH3-CH2-CH2OH

Explanation:

Complete question

How many isomers are there with the following descriptions?

a) Alcohol with formula C3H8O

Solution

There are total 3 carbon atoms in this alcohol. Hence, there will be three isomers of Alcohol with formula C3H8O .

The three isomers will comprise of alcohol group (OH) attached to the three carbon atoms one by one.

Isomer I  CH3-CHOH - CH3

Isomer 2 CH2OH-CH2-CH3

Isomer 3  CH3-CH2-CH2OH

Answer:

3

Explanation:

potassium is a highly electropositive metal with one electron for bonding, it reacts with a highly electro negative non metal like chlorine to give an electrovalent or ionic bonding

Answer:

pH = 2.66

Explanation:

First we calculate the number of moles of each reactant, using the given volumes and concentrations:

We calculate how many acetic acid moles remain after the reaction:

We now calculate the molar concentration of acetic acid after the reaction:

27.5 mmol / (50.0 mL + 10.0 mL) = 0.458 M

Then we calculate [H⁺], using the following formula for weak acid solutions:

Finally we calculate the pH:

Answer:

Rutherford used scientific investigation to study atoms.

Scientist who used scientific investigations to study atoms is Rutherford.

Atoms are the basic fundamental or functional unit of any substance present in the nature.

Rutherford is also known as the father of nuclear physics and he did scientific investigation on the massive part of atom called nucleus he discovered that there are two types of radiation, coming from the uranium atom are alpha and beta particles.

Scientific investigation is a method in which scientist will study, perform and observe results for the experiment.

Hence Rutherford used scientific investigation.

To know more about Scientific investigation, visit the below link:
https://brainly.com/question/17216882

Answer:

the correct answer is 12 sides (:

Explanation:

Answer:

When they're sleeping

Explanation:

After they've been drugged

Answer:

a. 6 grams

b. 108 grams

c. 2 grams

d. 54 grams

Answer:

32.57g

Explanation:

mass = mole x molar mass

mass of LiBr = 0.375 x 86.85

mass = 32.57g

when you strongly heat the potassium chlorate it leaves oxygen if you'll not heat it strongly to decompose it the oxygen would not release and the compound will remain thermally unstable.

Heating of Potassium Chlorate results into decomposition of Potassium Chloride and Oxygen gas.

When KClO₃ is heated strongly, it breaks down, releasing oxygen gas and leaving behind a thermally stable (i.e., heat-insensitive) solid residue of an ionic potassium compound.

If enough heat is not provided to potassium chlorate then it will not decompose into its substituent products and also some of the potassium chloride product splattered out of the crucible during the heating process.

Learn more:

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The correct question is: 10 kg of R-134a at 300 kPa fills a rigid container whose volume is 14 L. Determine the temperature and total enthalpy in the container. The container is now heated until the pressure is 600 kPa. Determine the temperature and total enthalpy when the heating is completed.

Answer: The temperature is [tex]21.6^{o}C[/tex] and total enthalpy when the heating is completed is 300 kJ.

Explanation:

Given: Mass = 10 kg

Volume = 14 L

Final pressure = 600 K

First, convert volume from L to [tex]m^{3}/kg[/tex] as follows.

[tex]v_{1} = \frac{14 \times 10^{-3}}{10}\\= 0.0014 m^{3}/kg[/tex]

According to the R-134a tables at 300 kPa and [tex]0.0014 m^{3}/kg[/tex].

[tex]h_{1}[/tex] = 54.6 kJ/kg

[tex]T_{sat}[/tex] = 0.7 C

[tex]u_{1}[/tex] = 54.1 kJ/kg

Now, at the state 2 [tex]p_{2}[/tex] = 600 kPa and [tex]v_{2} = v_{1} = 0.0014 m^{3}/kg[/tex]

This means that the final temperature at state 2 is [tex]T_{2} = T_{sat} = 21.6^{o}C[/tex]

Hence, the change in enthalpy is calculated as follows.

[tex]\Delta H = m(h_{2} - h_{1})\\= 10(84.6 - 54.6)\\= 300 kJ[/tex]

The first law is applied to transfer the heat transfer as follows.

[tex]Q = m(u_{2} - u_{1})\\= 10(83.8 - 54.1) kJ\\= 297 kJ[/tex]

Thus, we can conclude that the temperature is [tex]21.6^{o}C[/tex] and total enthalpy when the heating is completed is 300 kJ.

Explanation:

Have a good luck with ur exam

Answer:

In all the patients with rheumatoid arthritis RF is not present. It can also be witnessed in patients with conditions like hepatitis, bacterial endocarditis, and tuberculosis. Some of the reasons that can also produce false-positive results for RF assay are lipemic, hemolyzed, or heavily contaminated serum, other rheumatic diseases like systemic lupus erythematous, reading test results post the specified time of two minutes, and due to some of the chronic infectious diseases like hepatitis, tuberculosis, and syphilis.

b. The symptoms of the oatient like inflammation and pain in joints and the results of the lab indicate that the synovial fluid is drying and formation of crystal is taking place. These are the conditions that suggests the existence of rheumatoid arthritis.

c. In the given case, the first choice diagnosis would be the blood test that would show the presence of anti-CCP antibodies and the drying of synovial fluid. The presence of anti-CCP antibodies results in wear and tear in the joints, thus showing the diseased conditions.

Answer:

cdjkekendnekekekeknenwkwkwkwnrnrnrjejjwjwksnsjnrheifjfuufjeenenej

Answer:

Explanation:

The density of a substance can be found by using the formula

[tex]d = \frac{m}{v} \\ [/tex]

We have

[tex]d = \frac{1.25 \times {10}^{2} }{51} \\ = 2.45098..[/tex]

We have the final answer as

Hope this helps you

Answer: A balanced chemical equation, including physical state symbols, for the decomposition of solid sodium azide ([tex]NaN_{3}[/tex]) into solid sodium and gaseous dinitrogen is [tex]2NaN_{3}(s) \rightarrow 2Na(s) + 3N_{2}(g)[/tex].

Explanation:

A chemical equation which contains same number of atoms on both reactant and product side is called a balanced chemical equation.

For example, [tex]NaN_{3}(s) \rightarrow Na(s) + N_{2}(g)[/tex]

Here, number of atoms present on reactant side are as follows.

Number of atoms present on product side are as follows.

To balance this equation, multiply [tex]NaN_{3}[/tex] by 2 on reactant side. Also, multiply Na by 2 and [tex]N_{2}[/tex] by 3 on product side.

The equation will be rewritten as follows.

[tex]2NaN_{3}(s) \rightarrow 2Na(s) + 3N_{2}(g)[/tex]

This equation contains same number of atoms on both reactant and product side. Hence, this equation is now balanced.

The symbols (s) and (g) depicts the physical state of substances present in the equation as solid and gas.

Thus, we can conclude that balanced chemical equation, including physical state symbols, for the decomposition of solid sodium azide ([tex]NaN_{3}[/tex]) into solid sodium and gaseous dinitrogen is [tex]2NaN_{3}(s) \rightarrow 2Na(s) + 3N_{2}(g)[/tex].

Answer:

Explanation

i k the ansewer

The question is incomplete, the complete question is;

Assume that your empty crucible weighs 15.98 g, and the crucible plus the sodium bicarbonate sample weighs 18.56 g. After the first heating, your crucible and contents weighs 17.51 g. After the second heating, your crucible and contents weighs 17.50 g.

What is the theoretical yield of sodium carbonate?

What is the experimental yield of sodium carbonate?

What is the percent yield for sodium carbonate?

Which errors could cause your percent yield to be falsely high, or even over 100%?

Answer:

See Explanation

Explanation:

We have to note that water is driven away after the second heating hence we are concerned with the weight of the pure dry product.

Hence;

From the reaction;

2 NaHCO3 → Na2CO3(s) + H2O(l) + CO2(g)

Number of moles of  sodium bicarbonate = 18.56 - 15.98 = 2.58 g/87 g/mol

= 0.0297 moles

2 moles of sodium bicarbonate yields 1 mole of sodium carbonate

0.0297 moles of 0.015 moles  sodium bicarbonate yields 0.0297 * 1/2 = 0.015 moles

Theoretical yield of sodium carbonate = 0.015 moles * 106 g/mol = 1.59 g

Experimental yield of sodium bicarbonate = 17.50 g - 15.98 g = 1.52 g

% yield = experimental yield/Theoretical yield * 100

% yield = 1.52/1.59 * 100

% yield = 96%

The percent yield may exceed 100% if the water and CO2 are not removed from the system by heating the solid product to a constant mass.

Answer:

There is one valence electron in a neutral lithium atom.

Explanation:

The number of valence electrons in a neutral lithium atom is equal to one.

Valence electrons can be described as the electrons filling the outermost shell of an atom while the electrons in the inner shell of an atom are known as core electrons. Lewis structures are used to determine the number of valence electrons and know the types of chemical bonds.

Valence electrons of an atom can be filled in the same or different orbitals and these electrons are responsible for the interaction between atoms and cause the formation of chemical bonds.

Only electrons occupied in the outermost shell can participate in the formation of a bond or a molecule and are responsible for the reactivity of the element.

The number of electrons in the neutral atom of lithium is 3. There is only one electron present on the outermost shell 2s-orbital.

Learn more about valence electrons, here:

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To Find :

The number of molecules of carbon tetrachloride in 0.32 mol of

carbon tetrachloride.

Solution :

We know, 1 mole of any element/compound contains [tex]6.022 \times 10^{23}[/tex] number of atoms/molecules.

So, Number of molecules in 0.32 mol are :

[tex]n = 0.32 \times 6.022 \times 10^{23}\\\\n = 1.93 \times 10^{23}[/tex]

Therefore, number of molecules of carbon tetrachloride in 0.32 mol of

carbon tetrachloride are [tex]1.93 \times 10^{23}[/tex].

Answer:

chlorous acid

Explanation:

The acidic equilibrium of weak acids, HX, occurs as follows:

HX ⇄ H+ + X-

Where Ka is written as:

Ka = [H+] [X-] / [HX]

The strongest acid is the acid that produce more H+. The acid with the higher Ka is the acid that produce more [H+] and is, thus, the strongest acid.

The higher Ka is the Ka of chlorus acid = 1.2x10-2

Right answer is:

Answer:

chlorous acid :)

Explanation:

Answer:

approximately 15.1 grams.

Explanation:

The key to chemistry is to change everything to moles. Then when you have the answer in moles change the answer back to grams, liters, or whatever you want.

change 25 grams of potassium chlorate to moles.

calculate the gram molecular mass of potassium chlorate.

Chlorate is Cl with 3 oxygens. ate = saturated. Chlorine has seven valance electrons when it is saturated six of these electrons are used by oxygen ( 2 electrons per oxygen) leaving only 1 electron.

1 K x 39 grams/mole

+1 Cl x 35.4 grams/ mole

+3 O x 16 grams/ mole

= 122.4 grams / mole Potassium Chlorate

25

122.4

= moles.

2.05 moles of Potassium Chlorate.

There is a 1:1 mole ratio. 1 mole of Potassium Chlorate will produce 1 mole of Potassium Chloride.

2.05 moles of Potassium Chlorate will produce 2.05 moles of Potassium Chloride.

Find the gram molecular mass of Potassium Chloride.

1 K x 39 = 39

+1 Cl x 35.4 = 35.4

= 74.4 grams / mole.

2.05 moles x 74.4 grams/ mole = 15.2 grams

Answer:

idont know nalimotan ko hhhh...

Answer:

The molarity will be "0.43 M" and molality will be "0.43 m".

Explanation:

Given that:

mass of NaCl,

= 25 g

Volume of solution,

= 1 L

Density of solution,

= 1 gm/cm³

Now,

The weight of solvent will be:

= [tex]Volume\times density[/tex]

= [tex]1\times 1[/tex]

= [tex]1 \ kg[/tex]

The mole of NaCl will be:

= [tex]\frac{mass}{Molar \ mass}[/tex]

= [tex]\frac{25}{58.44}[/tex]

= [tex]0.43[/tex]

hence,

The molarity will be:

= [tex]\frac{number \ of \ mole}{Volume \ of \ solution}[/tex]

= [tex]\frac{0.43}{1}[/tex]

= [tex]0.43 \ M[/tex]

The molality will be:

= [tex]\frac{mole \ of \ solute}{Weight \ of \ solvent}[/tex]

= [tex]\frac{0.43}{1}[/tex]

= [tex]0.43 \ m[/tex]