1. If AB = 4x+5 and CD = 5x-6, find CD.

Answer:

(-4,-2)

Step-by-step explanation:

B(3,4)

x=3 , y=4

(3-7,4-6)

(-4,-2)

Transformation involves changing the position of a shape.

The coordinates of B after the translation is (-4,-2)

The vertices are given as:

[tex]\mathbf{A =(1,1)}[/tex]

[tex]\mathbf{B =(3,4)}[/tex]

[tex]\mathbf{C =(-1,8)}[/tex]

The translation rule is given as:

[tex]\mathbf{(x-7,y-6)}[/tex]

So, the coordinates of B' is calculated using:

[tex]\mathbf{(x,y) \to (x-7,y-6)}[/tex]

This gives

[tex]\mathbf{(3,4) \to (3-7,4-6)}[/tex]

[tex]\mathbf{(3,4) \to (-4,-2)}[/tex]

Rewrite as:

[tex]\mathbf{B' = (-4,-2)}[/tex]

Hence, the coordinates of B after the translation is (-4,-2)

Read more about translations at:

https://brainly.com/question/12463306

Answer:

a= 90 i think

hope this helped

Answer:

4/25 (Srr if incorrect)

Step-by-step explanation:

Answer:

31 7/8

16+8=24

4+2=6

2/4+1/4=3/4+1/8=7/8

Answer:

hey, sorry i cant see the image so whats the problem here? i would gladly help!

Step-by-step explanation:

Answer: Independent

Step-by-step explanation: I think this is probability..I assume it's probability right?

Answer: The perimeter is 20 cm

Step-by-step explanation: The top and bottom are same length, so 6+6, and the sides are the same length, so 4+4 don’t forget it’s cm and it becomes 20 cm.

PERIMITER = ADDING ALL SIDES

AREA = MULTIPLYING

its triangle and 7.3 and 23.7 hope this helps

Answer:

a)H0: β1= 1 and Ha: β1 ≠1

b) The test statistic is____.t= b- β/ sb

c) The p-value is____.0.999144

(d) Therefore, we can conclude that:_____. there is not enough evidence to reject the null hypothesis.    

The data provides no evidence at the 0.1 significance level that these thermometers are not consistent.

Step-by-step explanation:

This is called testing hypotheses about β, the population regression co efficient.

The null and alternate hypotheses are

H0: β1= 1 and Ha: β1 ≠1

The significance level is ∝=0.1 and ∝/2 is 0.05

The critical region at t ∝/2 (29)=  t ≤ - 1.699 , t ≥ 1.699

The test statistic is

t= b- β/ sb

which has t distribution with υ= 31-2= 29 degrees of freedom.

Calculations

Ŷ = a +bX

b = SPxy /SS x= Σ(xi-x`)(yi-y`)/Σ(xi-x`)²

b = 39671.6/39680= 0.9998

a = y` - bx`

x`= 60

y`= 59.989

a = 59.989 -0.9998*60 = 0.001734

Syx²= Σ( yi -y`)²/ n-2= 39663.3857/ 29=1367.68965

Syx= 36.9822

Sb= Syx/ √∑  (x-x`)²

Sb= 36.9823/ √39680

Sb= 36.9823/ 199.984

Sb= 0.18493

x-x`                 y-y`                    (x-x`)²     (x-x`)(y-y`)

-60                 -59.969            3600              3598.1419

-56                  -55.999           3136          3135.9458

-52                 -52.079             2704          2708.1097

-48                -47.959              2304           2302.0335

-44                 -43.899              1936          1931.5574

-40                -39.989               1600          1599.5613

-36              -36.009                1296            1296.3252

-32               -31.899              1024              1020.769

-28               -28.049             784                785.3729

-24                -23.959             576               575.0168

-20               -19.989             400                  399.7806

-16                 -15.939            256                  255.0245

-12               -12.039             144                    144.4684

-8                  -7.989             64                       63.9123  

-4                 -4.119                16                      16.4761

0                 -0.08903           0                         0

4                  3.921              16                      15.6839

8                7.961                64                       63.6877

12                12.121             144                     145.4516

16                16.031             256                   256.4955

20               20.021           400                  400.4194

24               24.111              576                   578.6632

28                28.071           784                     785.9871

32                 31.751            1024                    1016.031

36               36.031           1296                    1297.1148

40                39.961          1600                    1598.4387

44                43.881           1936                     1930.7626

48               48.021           2304                     2305.0065

52              52.001             2704                     2704.0503

56             56.051              3136                       3138.8542

60            60.041                3600                     3602.4581

∑0          0                 39680 (SSx)     39671.6 (SPxy)

Putting the values

The test statistic is

t= b- β/ sb

t= 0.9998-1/ 0.18493

t=-0.0010815

Since the calculated t=-0.0010815  does not lie in the critical region  t ∝/2 (29)=  t ≤ - 1.699 , t ≥ 1.699 we conclude that these thermometers seem to be measure temperatures.

The p-value is  ≈ 0.999144

there is not enough evidence to reject the null hypothesis.    

Answer:

56

Step-by-step explanation:

Average = sum/count

sum = 30 + 45 + 50 + 75 + 80

sum = 280

Count = 5

Average = 280/5

Average = 56

Answer:

56

Step-by-step explanation:

30+45+50+75+80=280

280÷5 days =56 units per day

Answer:

use photo math

Step-by-step explanation:

go to gogle play if you have android, look for the a search bar it is usually on the top right. type in photo math in the key pad. install it

Answer:

this question doesn5t make sence

Step-by-step explanation:

Answer:

please explainn

Step-by-step explanation:

Answer:

20

Step-by-step explanation:

Answer:

Step-by-step explanation:

6600

The car is about $6529.12 eleven years after it was bought.

The formula below can be used to determine a car's value after a particular number of years if its value depreciates by half every five years:

[tex]\rm P=P_{\circ} \left ( \dfrac{1}{2} \right)^{x/5}[/tex]

Here, x is how long ago the car was bought.

With x = 11 and a starting value of $30,000, this calculation yields:

[tex]\rm P=$30,000 \times \left ( \dfrac{1}{2} \right)^{11/5}\\[/tex]

Simplify the equation, then we have

P = $30,000 x 0.2176

P = $6529.12

The car is about $6529.12 eleven years after it was bought.

More about the exponent link is given below.

https://brainly.com/question/5497425

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Answer:

Solution given:

AB parallel BH parallel CH

1.

In triangle ∆AFD ,∆BGD ,∆CHD

<AFD=<BGD=<CHD

[being corresponding angle]

<DAF=<DBG=<DCH

[being corresponding angle]

<D is common for all.

So

∆AFD ~∆BGD ~∆CHD

[By A .A .A. axiom]

Answer:

5x^2 +28x - 100

Step-by-step explanation:

f(x)=7x^2−2 and g(x)=2(x−7)^2

First simplify g(x)

g(x) = 2 ( x-7)(x-7) = 2( x^2 - 7x -7x +49) = 2(x^2 -14x +49) = 2x^2 -28x +98

Now f(x) - g(x)

f(x) - g(x) = 7x^2−2 - (2x^2 -28x +98)

Distribute the minus sign

            = 7x^2−2 - 2x^2 +28x -98

Combine like terms

            = 5x^2 +28x - 100

Answer:

22 is the range for the data set.

Answer:

Clint would have to run 127 yards next game to average the same number of yards as Jack.

Step-by-step explanation:

First, we find the boys' averages by adding all their yards and then dividing by the number of games.

For Jack, we get 490 yards in total, which we divide by 5, the number of games. We get a 98 yard average.

For Clint, we get 461 yards in total, which we divide by 5, the number of games. We get a 92.2 yard average.

We know Clint wants to average 98 yards at the end of the next game. That would make 6 games total. We can multiply 98 x 6 to get the total number of yards for a 98 yard average in 6 games. We get 588 yards in total. Clint already ran 461 yards in total, so we can subtract that from 588. We have 127 yards left. We now know that Clint needs to run 127 yards in the next game for a 98 yard average.

The number of yards that client needs to run in his next game to average the same number of yards as jack will be 127.

The mean is the average of a data set. Mean gives us an idea of that how small the amount of overall data have.

In other words, the mean is the foundation of the deviation of data from all data sets.

Mean = sum of data / Number of data

The average of Jack = (123 + 87 + 108 + 80 + 92)/5 = 98

The average of Clint = (88 + 101 + 96 + 92 + 84)/5 = 92.2

To make this average 98 let's say Clint's score in the next game is x.

Mean = (88 + 101 + 96 + 92 + 84 + x)/6 = 98

(92.2 x 5 + x) = 98 x 6

x = 127

Hence"Clint needed to add 127 to be mean as same as Jack".

For more about the mean,

https://brainly.com/question/17060266

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Answer:

X=7

Step-by-step explanation MARK AS BRAINLIEST!!

Answer:

a^2 + b^2 = c^2

a^2 + 32^2 = 58^2

a^2 + 1024 = 3364

a^2 = 2340

a = 48.37

Step-by-step explanation:

Answer:

x = 33.49

Step-by-step explanation:

I took the the test and got this answer, sorry for the not so detailed explanation

have a decent day

Answer:

-14y + 30

Step-by-step explanation:

Tell me if I am wrong but I think this is it.

Answer:

-14y+30

Step-by-step explanation:

Hope this helpss

Answer:

C. Saying​ "data vary" means that the values of the variable change from individual to individual. In​ addition, certain variables can change over time for certain individuals. Because data​ vary, two different statistical analysis of the same variable can lead to different results.

Step-by-step explanation:

Variation in data may be explained as the non-uniformity in the values assigned to each individual variable in the data table. As a result of the non-uniformity or differences which exists in the values assigned to individual variables or changes due over time. This will usually lead to differences in the statistical result obtained when data undergoes analysis.

Answer:

D

Step-by-step explanation:

There is no 2x in D answer

Answer:

Step-by-step explanation:

13.  All equilateral triangles are acute triangles. An equilateral triangle has three sides of equal length and three equal angles of 60.~ I think it is False.

14. If a triangle has two acute angles, then the third angle must also be acute.~ I think it is true.

15.  A triangle cannot be right-angled and obtuse angled at the same time. Since a right-angled triangle has one right angle, the other two angles are acute. Therefore, an obtuse-angled triangle can never have a right angle; and vice versa. ~I think it is false.

Please don't trust me... I hope I helped

~LampteyJ

Answer:

proper I believe if I'm wrong sorry

Answer:

c

Step-by-step explanation:

Answer:

Step-by-step explanation:

It’s b

Answer:

Pam is correct!

Step-by-step explanation:

Pam is correct it would be between nine minutes and 12!