1. The volume of the cylinder is 78 cubic cm, find the volume of the cone.

Answers

Answer 1

Answer:

The volume of a cylinder = 78 \mathrm{cm}^{3}78cm3

Let us substitute the volume of cylinder in the formula.

The formula for volume of a cone is V=\frac{\pi r^{2} h}{3}V=3πr2h                    (1)

The formula for volume of a cylinder is V=\pi r^{2} hV=πr2h              (2)

Substituting V=78V=78 in equation (2), we get,

\begin{gathered}\begin{array}{c}{V=\pi r^{2} h} \\{78=\pi r^{2} h}\end{array}\end{gathered}V=πr2h78=πr2h

Given that the cone has the same radius and height of that of the cylinder, let us substitute 78=\pi r^{2} h78=πr2h in equation (1)

\begin{gathered}\begin{array}{l}{V=\frac{\pi r^{2} h}{3}} \\{V=\frac{78}{3}} \\{V=26}\end{array}\end{gathered}V=3πr2hV=378V=26

Thus, the volume of a cone with the same radius and height of a cylinder is 26 \mathrm{cm}^{3}26cm3 .

Answer 2

Answer:

26 cm^3 I hope this helps!

Step-by-step explanation:


Related Questions

Fine the area of a triangle with :base=7ft and height =5ft

Answers

Answer:

Step-by-step explanation:

7 x 5 = 35

35/2 = 17.5

[tex]17.5ft^{2}[/tex]

The area of the given triangle is 17.5 ft²

What is area?

Area is defined as the total space taken up by a flat (2-D) surface or shape of an object.

Given a triangle with base=7ft and height =5ft

We know that area of a triangle = 1/2 × base × height

Therefore, the area of a triangle = 1/2 (7)(5) = 17.5 ft²

Hence, the area of the given triangle is 17.5 ft²

For more references on area, click;

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Can some help with this Math question .?

No linksss

Answers

Answer:

I think ir is 2 -2

Step-by-step explanation:

hope it helps

hey! i’ll give brainliest please help

Answers

Answer:

The second option, external conflict w/other citizens who don't want the Cinema.

Step-by-step explanation:

Angel saved $100 a week for a year. She spent 40%
of her savings on a new bed. How much did she
spend on the bed?

Answers

Answer:

40 because 40 percent of 100 is 40. You can just multiply the number by the percentage $100x40%

[tex]2h-3\ \textgreater \ 15[/tex]

Answers

[tex]\huge\text{Hey there!}[/tex]

[tex]\large\textsf{2h - 3 }\mathsf{>}\large\textsf{ 15}[/tex]

[tex]\large\text{ADD 3 to BOTH SIDES}[/tex]

[tex]\large\textsf{2h - 3 + 3 }>\large\textsf{ 15 + 3}[/tex]

[tex]\large\text{CANCEL out: \textsf{-3 + 3} because that gives you 0}[/tex]

[tex]\large\text{KEEP: \textsf{15 + 3} because it helps you solve for your h-value}[/tex]

[tex]\large\textsf{15 + 3 = \boxed{\large\textsf{\bf 18}}}[/tex]

[tex]\large\text{NEW EQUATION: \textsf{2h} }\mathsf{>}\large\textsf{ 18}[/tex]

[tex]\large\text{DIVIDE 2 to BOTH SIDES}[/tex]

[tex]\mathsf{\dfrac{2h}{2}>\dfrac{18}{2}}[/tex]

[tex]\large\text{CANCEL out: }\mathsf{\dfrac{2}{2}}\large\text{ because it gives you 1}[/tex]

[tex]\large\text{KEEP: }\mathsf{\dfrac{18}{2}}\large\text{ because it gives you your h-value is being compared to}[/tex]

[tex]\large\text{NEW EQUATION: }\mathsf{h > \dfrac{18}{2}}[/tex]

[tex]\mathsf{\dfrac{18}{2}}[/tex]

[tex]\mathsf{= 18\div 2}[/tex]

[tex]=\boxed{\mathsf{\large\textsf {\bf 9}}}[/tex]

[tex]\boxed{\boxed{\large\textsf{Answer: }\mathsf{\bf h > 9}}}\huge\checkmark\\\\\boxed{\boxed{\rm \bf It\ it\ an\ O P E N E D\ circle\ shaded}}\\\boxed{\boxed{\rm \bf to\ the\ right\ starting\ at\ point\ 9}}\checkmark[/tex]

[tex]\large\text{Good luck on your assignment and enjoy your day!}[/tex]

~[tex]\frak{Amphitrite1040:)}[/tex]

Problem:

[tex] \quad \quad \quad \quad\tt{2h - 3 > 15}[/tex]

Let's solve!

[tex] \quad \quad \quad \quad\tt{2h - 3 > 15}[/tex]

Add both sides by 3.

[tex] \quad \quad \quad \quad\tt{2h - 3 + 3 > 15 + 3}[/tex]

[tex]\quad \quad \quad \quad\tt{2h \: \: \cancel{ \color{red}- 3 + 3} \: > 15 + 3}[/tex]

[tex]\quad \quad \quad \quad\tt{2h > 18}[/tex]

Divide it by 2.

[tex]\quad \quad \quad \quad\tt{ \frac{2h}{2} > \frac{18}{2} }[/tex]

[tex]\quad \quad \quad \quad\tt{ \frac{ \cancel{ \color{red}2}h}{ \cancel{ \color{red}2}} > \frac{18}{2} }[/tex]

[tex]\quad \quad \quad \quad\tt{ h > \frac{18}{2} }[/tex]

[tex]\quad \quad \quad \quad\tt{ h > 9}[/tex]

Hence the answer is:

[tex]\quad \quad \quad \quad \boxed{\tt { \color{green}h > 9}}[/tex]

________

#LetsStudy

please reply within 10 minutes​

Answers

Answer:

H

Step-by-step explanation:

For F  - Median For Class 1 is 52.5 Median for Class 2 is 75 ( False )

For G - Range for class 2 is 75 Range for class 1 is 45.9 ( False )

For H - IQR for class 1 is 30.45 IQR for class 2 is 60 ( True )

For J - Minimum for Class 2 is 30 Minimum for Class 1 is 30 ( False )

A bag contains 3 yellow marbles and 6 blue marbles. You randomly select two marbles from the bag. What is the probability that both marbles are
yellow when you do not replace each marble before selecting the next marble? Write your answer as a decimal rounded to three decimal places.

Answers

1/12

explanation- the first draw the probability is 3/9 or 1/3 and the second draw would be either 2/8 or 3/8 depending on the first marble color. but the likely hood of two yellow marbles in a row would be 6/72 chances or 1/12.

HELPPPPPPPPPPPP
ind the possibility that a random selected point within the circle falls in the red shaded area

Answers

Answer:

25cm

Step-by-step explanation:

one the possibility 36 - 11 =25 the answer is 25

Whoever solves it correctly will get 32 points

Answers

Ur answer is c!!!!!!!

List these from least to greatest π2, 12, √80

Answers

Answer:

π2,√80,12

Step-by-step explanation:

π2= 6.28

√80= about 8

12=12

Hope I could help!

I NEED HELP RIGHT NOW!!PLEASE!! π∆π ¶×¶

Find the RATIO and the EXACT VALUE of the given Cot A.​

Answers

A right angled triangle with its side length is given. The sides of the triangle are 12ft , 13ft and 5ft. And we need to find out the value of cot A .

Here :-

Base = 12 ft .Perpendicular = 5ft. Hypotenuse = 13ft.

We know :-

[tex]\tt\implies cot \theta = base / perpendicular [/tex]

Substitute the respective values :-

[tex]\tt\implies cot \theta = base / perpendicular\\\\\tt\implies\boxed{\red{\tt cot A = 12/5 }}[/tex]

Hence the required answer is 12/5.

I need answers asap. ​

Answers

J. The wonderful answer is J

During which time interval is the squirrel traveling at the fastest speed?


1–2 min

2–3 min

5–6 min

8–9 min

Answers

I think that the answer is 8-9min

For a new year's party 911 red balloons, 910 green balloons and 915 white balloons were used What is the total number of balloons used?​

Answers

the total balloon are used is 2736

What is the perimeter of the triangle? Show your work.
Y
12
9

Answers

Answer:

36

Step-by-step explanation:

So to find the last angle first. The formula is a power 2+b power 2=c power 2

So 9 power 2 is 81 and 12 power 2 is 144

144+81=225

the square root of 225 is 15. So x is 15

No we just have to do 9+12+15=36.

36 is the perimeter

An online music store offers 2 downloads for $7.50. Another online music store offers 12 downloads for $20.20 which store offers the better deal

Answers

Answer:

the second store has the better deal.

Step-by-step explanation:

12 ÷ 2 = 6

7.5 × 6 = 45

20.2 < 45

Liam puts 40$ in savings in March and 175% of this amount in savings in April. How much does Liam put in savings in April?

Answers

Answer:

$70

Step-by-step explanation:

You want 175% of $40.

175% as a decimal = 1.75

1.75 times 40 = 70

Therefore Liam put $70 in savings in April

Answer:

70

Step-by-step explanation:

Multiply 40$ by 175% :)

Ken recorded the weights (in pounds) of 78 boxes. He created a box plot of his data. What is the interquartile range of Ken’s data?

A) 8

B) 10

C) 17

D) 48

Answers

The answer is d 48 I just took the test

The interquartile range(IQR) of the recorded weight of ken is calculated as 17 pounds.

What is the interquartile range of a data?

The interquartile range(IQR) = third quartile(Q3) - first quartile(Q1)

The third quartile of in the box plot given is : 56 pounds

The third quartile of the data as represented in the box plot given :

39 pounds

The interquartile range(IQR) of ken's data = 56 - 39

= 17 pounds

Hence, The interquartile range(IQR) of the recorded weight of ken is calculated as 17 pounds.

Find more information about the interquartile range here

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Find the volume of a pyramid with a square base, where the perimeter of the base is
9.9 cm and the height of the pyramid is 8.6 cm. Round your answer to the nearest
tenth of a cubic centimeter.

Answers

The volume of a pyramid with a square base is 17.6 cubic centimeter.

Given the following data;

Perimeter of base = 9.9 cmHeight of pyramid = 8.6 cm

To find the volume of a pyramid with a square base;

Mathematically, the volume of a pyramid with a square base is given by the formula;

[tex]V = A(\frac{h}{3})[/tex]

Where;

V is the volume of a pyramid with a square baseA is the area of the square base.h is the height of the pyramid.

First of all, we would determine the length of sides of the square base from its perimeter;

[tex]Perimeter \ of \ square = 4s\\\\9.9 = 4s\\\\s = \frac{9.9}{4}[/tex]

s = 2.475 cm

Next, we would determine the area of the square;

[tex]Area \ of \ a\ square = s^{2} \\\\Area \ of \ a\ square = 2.475^{2}[/tex]

Area of a square = 6.126 cm

Now, we would use the above value to find the volume of a pyramid with a square base.

Substituting the values into the formula, we have;

[tex]V = 6.126*(\frac{8.6}{3})\\\\V = 6.126*2.867[/tex]

Volume, V = 17.6 cubic centimeter

Therefore, the volume of a pyramid with a square base is 17.6 cubic centimeter

Find more information here: https://brainly.com/question/16627760

Find the mean of this data set: 2, 5, 5

Answers

Answer:

Mean = 4

Step-by-step explanation:

[tex]Mean = \frac{\sum x}{n} = \frac{2 + 5+ 5}{3} = \frac{12}{3} = 4[/tex]

Answer:

4

Step-by-step explanation:

Mean is average, so you would add every number up, then divide by the numbers you have, So 2+5+5 divided by 3 would be 4

A radio station broadcasts a signal over an area with a 120-mile diameter. The population density of the area is 100 people per square mile.

How many people are within receiving distance of the broadcast signal?

Use 3.14 for pi.

Answers

Answer:

1,130,400 people

Step-by-step explanation:

Find the area of the broadcasting area, using the circle area formula.

Since the diameter is 120 miles, the radius will be 60 miles.

Use the circle area formula, plug in 60 as r, and plug in 3.14 as pi:

A = [tex]\pi[/tex]r²

A = (3.14)(60²)

A = 11304

So, the area is 11304 square miles

To find how many people are in receiving distance, multiply this by 100, since there are 100 people per square mile.

11304(100)

= 1,130,400

So, 1,130,400 people are within receiving distance of the signal.

Answer:

1,130,400

Step-by-step explanation:

write three rational numbers between 1. -1 and 1 2. -4 and-3​

Answers

Answer:

1. -1/2 1/2 1/4

2. -3.5 -3.6 -3.7

3. -1/10 -1/11 -1/12

hope this helps

have a good day :)

Step-by-step explanation:

Using the figure show, find the missing values. Round each value. Every time I put this up people get it wrong

Answers

Answer:

I'm sorry, I can help you with only this one :( ∠F = 44°

Step-by-step explanation:

∠F = 180° - (46° + 90°) = 44°

z2+4z-165=(z-11)(z+-15)

Answers

Answer: look at the picture

Step-by-step explanation: Hope this help :D

My number 4752512944

Answers

Answer:

no thanks for your number

Step-by-step explanation:

Have a great day

hey! pls help i’ll give brainliest

Answers

Answer:

landslide

Step-by-step explanation:

Answer:

I believe that the answer might be the second one

Volcanic Eruption

The spinner shown has congruent sections. The spinner is spun 63 times. What is a reasonable prediction for the number of times the spinner will land on a section that is shaded red?​

Answers

Answer:

36 times

Step-by-step explanation:

Given

[tex]Red = 4[/tex]

[tex]Total = 7[/tex]

[tex]n = 63[/tex]

See attachment

Required

Predicted number of times to land on red

First, we calculate the probability of landing on red

[tex]Pr = \frac{Red}{Total}[/tex]

[tex]Pr = \frac{4}{7}[/tex]

The predicted number of red is the =n calculated as:

[tex]Red = Pr * n[/tex]

[tex]Red = \frac{4}{7}*63[/tex]

[tex]Red = 4 * 9[/tex]

[tex]Red = 36[/tex]

Please help me with this one??

Answers

Answer:

Y =-25x +225

Step-by-step explanation:

First you can count the gradient first. Use then you can count y intercept

find all the possible of x for which of the below is true:

[tex] \frac{2x}{x + 3} + \frac{3}{x - 3} = \frac{8}{x^{2} - 9 } [/tex]

Answers

Answer:

x = [tex]\frac{1}{2}[/tex] , x = 1

Step-by-step explanation:

Given

[tex]\frac{2x}{x+3}[/tex] + [tex]\frac{3}{x-3}[/tex] = [tex]\frac{8}{x^2-9}[/tex] ← denominator is a difference of squares

[tex]\frac{2x}{x+3}[/tex] + [tex]\frac{3}{x-3}[/tex] = [tex]\frac{8}{(x+3)(x-3)}[/tex]

Multiply through by (x + 3)(x - 3) to clear the fractions

2x(x - 3) + 3(x + 3) = 8 ← distribute left side and simplify

2x² - 6x + 3x + 9 = 8

2x² - 3x + 9 = 8 ( subtract 8 from both sides )

2x² - 3x + 1 = 0 ← in standard form

(2x - 1)(x - 1) = 0 ← in factored form

Equate each factor to zero and solve for x

2x - 1 = 0 ⇒ 2x = 1 ⇒ x = [tex]\frac{1}{2}[/tex]

x - 1 = 0 ⇒ x = 1

Please help me after this one I have one more

Answers

Answer:

3    2/21

Step-by-step explanation:

used a calculator

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