100 Points} Name the following compounds from the structures given (images shown below)

1.

2.

3.

4.

5.

6.


Unfortunately, they're not multiple choice, so I have no possible answers to list, I believe 1. might be "2-methylhexane" but I'm unsure how to write the double bond that's shown in the structure, thanks! :)

Edit; the screenshots posted out of order, my apologies :(

When there are two bond pairs and one lone pair, the molecule will have a bent molecular shape.

The shape of a molecule depends on the orientation and number of electron pairs on the valence shell of the central atom in the molecule. This is based on the postulates of the valence shell electron pair repulsion theory.

When there are two bond pairs and one lone pair, the molecule will have a bent molecular shape.

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Answer:

df  dffdffdfd  dffd  ff d

Explanation:

df fd df f df df dfdf  f fdf  df df df fd

Answer: The energy of the products exceeds the activation energy threshold.

Explanation:

In the reverse reaction, the reactants of the forward reaction are now the products of the reverse reaction and vice versa.

This means that normally since you would need the energy of the reactants of the forward reaction to exceed the activation energy threshold, in the reverse reaction, the energy of the products would need to exceed the activation energy threshold.

Answer: is is true

Explanation:

Answer:

0.3371 moles

Explanation:

gold is 196.967 grams per mole

66.4 grams divided by 196.967 grams per mole =

0.3371 moles

Answer:

There is no air pollution

Explanation:

Unless there is a meltdown.

Nuclear plants generate far more power than coal plants

FUEL is needed....nuclear fuel

Leakage CAN happen.... see info on Three Mile Island or Cchernobryl (Ukraine)

Answer:

C. carbon-carbon double bond

Explanation:

A reaction in which two or more molecules combine together to result in the formation of a larger molecules then this type of reactions are known as addition reactions.

Usually compounds which contain a double bond undergo addition reactions.

For example, a compound with carbon-carbon double bond, carbonyl group, imine group etc undergo addition reaction.

Thus, we can conclude that in an addition reaction, carbon carbon double bond of the reactant is broken.

Carbon-carbon double bonds (unsaturations) are found in naturally occurring fatty acids.

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https://library.med.utah.edu/NetBiochem/FattyAcids/3_2.html

The complete equation will look thus: [tex]2HNO_3(aq) + Ba(OH)_2(aq) --- > Ba(NO_3)_2 + 2H_2O[/tex]

In order for equations to be balanced, the component atoms in the reactants and products must be the same in terms of number.

Thus, in the given equation, the number of H, N, O, and Ba atoms in the reactants and the products must be equal.

Therefore, the overall equation becomes:

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Answer:2HNO3 + Ba(OH)2 → Ba(NO3)2 + 2H2O

Explanation:

HNO3 + Ba(OH)2 = Ba(NO3)2 + H2O

This is what each element is....

H= 1+2=3                 H=2

N=1                          N=2

O=2+2=4                O=4+1=5

Ba=1                        Ba=1

Now to balance each side.....

H=2+2=4               H=2++2=4

N=2                       N=2

O=4+2=6              O=4+2=6

Ba=1                      Ba=1

The balanced equation is now

2HNO3 + Ba(OH)2 → Ba(NO3)2 + 2H2O

D

Explanation:

B/c both the hydrogen and chlorine have the same valance number so if a metal or non metal have the same valance number you should cancel out the numbers and you will have to put only the non metal or metals.

Answer:

Less expensive than natural fibers

Strong and long-lasting

Easily available

Easy to maintain

Dry up quickly

[tex]\\ \rm\Rrightarrow Density=\dfrac{Mass}{Volume}[/tex]

[tex]\\ \rm\Rrightarrow Volume=\dfrac{Mass}{Density}[/tex]

[tex]\\ \rm\Rrightarrow Volume=\dfrac{0.19}{0.0076}[/tex]

[tex]\\ \rm\Rrightarrow Volume=25cm³[/tex]

[tex]\\ \rm\Rrightarrow Volume=25mL[/tex]

Answer:  

Molecular polarity

Explanation:

tell me if im right

Answer:

A noble gas configuration of an atom consists of the elemental symbol of the last noble gas prior to that atom, followed by the configuration of the remaining electrons. So for sodium we make the substitution of (Ne) for the 1s22s22p6 part of the configuration. Sodium's noble gas configuration becomes (Ne) 3s1.

Answer :]

This is an oxidation-reduction (redox) reaction:

S0 + 2 e- → S-II (reduction)

2 K0 - 2 e- → 2 KI (oxidation)

S is an oxidizing agent, K is a reducing agent.

Answer:

K

Explanation:

Here, in this reaction 2 moles of potassium react with 1 mole of sulfur to form 1 mole of potassium sulfide.

Let's compare the electronic configurations of both elements :

⇒ K = {2, 8, 8, 1}

⇒ K can attain noble gas configuration by losing one electron

⇒ K exists as : K⁺

⇒ S = {2, 8, 6}

⇒ S can attain noble gas configuration by the addition of 2 electrons

⇒ S exists as S²⁻

Now, we know that will lose protons when oxidized. Hence, here the substance which is oxidized is K

Answer:

224.1105 grams is the answer

The specific heat of the metal is calculated using the change in temperature, heat, and mass. The specific heat of the metal is 0.21 J/g °C.

Heat energy is a transfer of the energy lost by a system to the energy gained by another system. The calorimeter is used to measure the specific heat of the system.

Given,

Mass of metal = 500 gm

Temperature = 100 °C

Mass of water = 250 gm

Temperature = 40 °C

Specific heat of water = 4.184 J/g °C

The specific heat (c) of metal is calculated as:

Q = mC ΔT

and, Q (metal) = Q (water)

Substituting values in the above equation:

(500 )(c)(100) = (250)(4.184)(50-40)

50000 c = 10460

c = 0.21 J/g °C

Therefore, the specific heat of metal is 0.21 J/g °C.

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The standard enthalpy of formation (Δ[tex]H_f[/tex]) is a measure of the energy released or consumed when one mole of a substance is created under standard conditions from its pure elements.

Standard enthalpies (Δ[tex]H_f[/tex]) of formation for given reaction is 978.3 kJ

The standard enthalpy of formation is defined as the enthalpy change when one mole of a substance in the standard state (1 atm of pressure and 298.15 K) is formed from its pure elements under the same conditions.

Given reaction ;

[tex]N_2O_4(g) + 4H_2 (g) - > N_2(g) + 4H_2O(g)[/tex]

To Find : Δ[tex]H_f[/tex]

Δ[tex]H_f[/tex] = ∑np Δ[tex]H_f[/tex] (products) – ∑np Δ[tex]H_f[/tex] (reactants)

Δ[tex]H_f[/tex] = [1(Δ[tex]H_f[/tex] [tex]N_2[/tex]) + 4(Δ[tex]H_f[/tex] [tex]H_2O[/tex])] – [1(Δ[tex]H_f[/tex] [tex]N_2O_4[/tex]) + 4(Δ[tex]H_f[/tex] [tex]H_2[/tex])]

Δ[tex]H_f[/tex] = [1(0) + 4(-241.8)] – [1(+9.16) + 4(0)]

Δ[tex]H_f[/tex]  = [4(-241.8)] – [1(+9.16)] = 978.3 kJ

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42.4 ml is the volume in milliliters of the lead ball if a lead ball is added to a graduated cylinder containing 50.6 ml of water.

A tall narrow container with a volume scale is used especially for measuring liquids.

The graduated cylinder contains water

mL is a volume unit.

Water volume = 50.6 ml

The lead ball caused an increase in volume from 50.6 ml to 93.0 mL.

The new volume is the lead ball volume plus the original water volume :

Final volume = Vlead ball+ Water original volume

[tex]93.0 mL= V_(lead ball) +50.6 ml[/tex]

[tex]V_(lead ball) = 93.0 mL - 50.6 ml[/tex]

[tex]V_(lead ball) = 42.4 ml[/tex]

Hence, 42.4 ml is the volume in milliliters of the lead ball.

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Answer:

true

Explanation:

they can not be stored within the vesicles

the cut pieces will have their own north and south pole

The balloon must be heated to a temperature of 150 °C in order to have a volume of 6.00 L.

The volume of a gas is directly proportional to the temperature of the gas.

According to Charles' law: V1/T1 / = V2/T2

V1 =4.0 L

T1 = 9°C = (273. + 9) K = 282 K

V2 = 6.0 L

T2 = ?

T2 = V2×T1/V1

T2 = 6 × 282 / 4 = 423 K

423.2 K = 423 -273 = 150 °C

Therefore, the balloon must be heated to a temperature of 150 °C in order to have a volume of 6.00 L.

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Answer:

The signs of chemical change include changes in color, temperature, the production of light, changes in odor, and the formation of gases.

Answer: C. CO₂ and H₂O

Explanation:

Combustion reactions produce carbon dioxide and water.

The temperature is the same, so the amount of kinetic energy will also be the same.

The purpose of this process is to reduce the risk of having outliers of false results.

It is important to bear in mind that a good scientific experiment usually tests one independent variable at a time, and that is why it is important to keep all other potential variables constant and to use a control group.

Although, the experiment you are referring to in your question is missing the general principle when conducting an experiment is the running of multiple tests before coming up with an actual test result.

Therefore, when completing a science experiment it is important to run multiple tests like heating the substance several times until a constant mass value is obtained,  in other to ascertain the results. the reason why such process is undertaken is to reduce the risk of having outliers of false results.  

A scientific experiment involves several procedures and this depends on the type and purpose of the experiment.

for example ;

An experiment with the purpose of determining how the mass of an object reacts to heat will require the mass of the object to be recorded  after heating the object/substance several times.

Hence we can conclude that the purpose of the process is to reduce the risk of having outliers of false results.

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Suppose that 0.25M IBr in a flask,  the Kc at the given temperature is mathematically given as

Kc=0.00336814413

Generally, the equation for Chemical Reaction is mathematically given as

2IBr--->T2+8r_2

Therefore

K={I2*Br2}/IBR^2

K=x^2/(0.25-2x)^2

Kc=0.13M^2/0.224M^2

Kc=0.00336814413

In conclusion,  the Kc at the given temperature

Kc=0.00336814413

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In order to prepare a 50-fold diluted enzyme, 0.1 mL of the stock solution of the enzyme is taken and made up to 5.0 mL with 0.001M HCl.

Dilution is a process whereby a solution of lower concentration is prepared from one of a higher concentration.

Dilution is done by using the dilution formula below:

C1; Initial concentration of enzyme = 1 mg/mL

C2; Final concentration of enzyme = 1/50 mg/ml = 0.02 mg/ml

V1; Initial volume of enzyme = y

V2; Final volume = 5.0 ml

V1 = C2V2/C1

V1 =  0.02 * 5/1 = 0.1 mL

Therefore, in order to prepare a 50-fold diluted enzyme, 0.1 mL of the stock solution of the enzyme is taken and made up to 5.0 mL with 0.001M HCl.

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Answer:

1.67 moles Al₂O₃

Explanation:

To find the amount of aluminum oxide produced, you need to start with 5 moles FeO and multiply it by the mole-to-mole ratio displaying the relationship between moles FeO and moles Al₂O₃. This ratio incorporates the coefficients from the equation. Remember, make sure to write the ratio in a way that allows for the cancellation of moles FeO.

2 Al + 3 FeO ---> 3 Fe + 1 Al₂O₃

5 moles FeO          1 mole Al₂O₃
--------------------  x  ----------------------  = 1.67 moles Al₂O₃
                              3 moles FeO