Answer:
Condensation reaction/ direct synthesis reaction
Explanation:
Combines simple molecules to form complex molecules producing water
How many grams are there in 1.8055 x 10^25 molecules of sodium sulfate? Hint: Convert to moles first
Answer:
4258.82 g of Na₂SO₄
Explanation:
From the question given above, the following data were obtained;
Number of molecules of Na₂SO₄ = 1.8055x10²⁵ molecules.
Number of mole of Na₂SO₄ =?
From Avogadro's hypothesis,
6.02×10²³ molecules = 1 mole
Therefore,
6.02×10²³ molecules = 1 mole of Na₂SO₄
Next, we shall determine the mass of 1 mole of Na₂SO₄. This can be obtained as follow:
1 mole of Na₂SO₄ = (23×2) + 32 + (16×4)
= 46 + 32 + 64
= 142 g
Thus,
6.02×10²³ molecules = 142 g of Na₂SO₄
Finally, we shall determine the mass of Na₂SO₄ that contains 1.8055x10²⁵ molecules. This can be obtained as follow:
6.02×10²³ molecules = 142 g of Na₂SO₄
Therefore,
1.8055x10²⁵ molecules
= (1.8055x10²⁵ × 142) / 6.02×10²³
= 4258.82 g of Na₂SO₄
Thus, 4258.82 g of Na₂SO₄ contains 1.8055x10²⁵ molecules
Calculate the final concentration of each of the following:
2.0 L of a 6.0 M HCl solution is added to water so that the final volume is 6.0 L
--
Water is added to 0.50 L of a 12 M NaOH solution to make a 3.0 L of a diluted NaOH solution
Answer:
1. 2 M
2. 2 M
Explanation:
1. Determination of the final concentration.
Initial Volume (V₁) = 2 L
Initial concentration (C₁) = 6 M
Final volume (V₂) = 6 L
Final concentration (C₂) =?
The final concentration can be obtained as follow:
C₁V₁ = C₂V₂
6 × 2 = C₂ × 6
12 = C₂ × 6
Divide both side by 6
C₂ = 12 / 6
C₂ = 2 M
Therefore, the final concentration of the solution is 2 M
2. Determination of the final concentration.
Initial Volume (V₁) = 0.5 L
Initial concentration (C₁) = 12 M
Final volume (V₂) = 3 L
Final concentration (C₂) =?
The final concentration can be obtained as follow:
C₁V₁ = C₂V₂
12 × 0.5 = C₂ × 3
6 = C₂ × 3
Divide both side by 3
C₂ = 6 / 3
C₂ = 2 M
Therefore, the final concentration of the solution is 2 M
Here are the atomic masses of hypothetical elements:
X = 13.25 amu
Y = 69.23 amu
Z = 109.34 amu
3.8 moles of X2Y5Z3 is equivalent to how many grams?
Enter your answer to zero decimal places (round to the ones place). Do
not include the units of "g", just the numerical answer.
Answer:
2663 g
Explanation:
We'll begin by calculating the molar mass Of X₂Y₅Z₃. This can be obtained as follow:
Molar mass of X₂Y₅Z₃ = (13.25×2) + (69.23×5) + (109.34×3)
= 26.5 + 346.15 + 328.02
= 700.67 g/mol
Finally, we shall determine the mass of 3.8 moles of X₂Y₅Z₃. This can be obtained as follow:
Molar mass of X₂Y₅Z₃ = 700.67 g/mol
Mole of X₂Y₅Z₃ = 3.8 moles
Mass of X₂Y₅Z₃ =?
Mass = mole × molar mass
Mass of X₂Y₅Z₃ = 3.8 × 700.67
Mass of X₂Y₅Z₃ = 2663 g
Therefore, the of 3.8 moles of X₂Y₅Z₃ is
2663 g
The pH of an acidic solution is 2.11. What is [H⁺]
Answer:
7.76 x 10^-3 M
Explanation:
pH = -log(x)
2.11 = -log (x)
10^-2.11 = 7.76x10^-3 M
Considering the definition of pH, the concentration [H⁺] is 7.76×10⁻³ M
You need to know that pH is the Hydrogen Potential. It is a measure of acidity or alkalinity that indicates the amount of hydrogen ions present in a solution or substance.
Mathematically, pH is calculated as the negative base 10 logarithm of the activity of hydrogen ions:
pH= - log [H⁺]
The numerical scale that measures the pH of substances includes the numbers from 0 to 14. The pH value 7 corresponds to neutral substances. Acidic substances are those with a pH lower than 7, while basic substances have a pH higher than 7.
In this case, being pH= 2.11, you can replace this value in the definition of pH:
2.11= -log [H⁺]
Solving:
[H⁺]= 10⁻² ¹¹ M
[H⁺]= 7.76×10⁻³ M
Finally, the concentration [H⁺] is 7.76×10⁻³ M
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The solution you identified in question (1) acts as a buffer due to reactions that occur within the solution when an acid or a base is added. Write the net ionic chemical equation for the reaction that occurs within this buffer solution when HCl(aq) is added. (Phase labels should be included in all net ionic chemical equations.)
Answer:
The answer is "[tex]\bold{CH_3COO^{-} \ (aq) + H^{+}\ (aq) \longrightarrow CH_3COOH \ (aq)}[/tex]"
Explanation:
When [tex]HCI[/tex] is added in the chemical equation it reacts with sodium acetate so, it will give the following chemical equation:
[tex]CH_3COONa\ (aq) + HCl\ (aq)\longrightarrow CH_3COOH\ (aq) + NaCl\ (aq)\\\\[/tex]
In this, the [tex]CH_3COOH[/tex] is a weak acid so, it not completely dissociated.
[tex]CH_3COONa \ (aq) \ \ and \ NaCl[/tex] were strong electrolytes they are completely dissociated.
The [tex]HCl[/tex] is a strong acid so, it is completely dissociated So, the net ionic equation is:
[tex]CH_3COO^{-} \ (aq) + H^{+}\ (aq) \longrightarrow CH_3COOH \ (aq)[/tex]
Thorium-236 has a half life of 10.0 minutes.If I have 250 grams of Thorium-236 , how many half lives will have taken place after 50.0 minutes?
Answer:
5 half lives
Explanation:
Given that
Thorium - 236 contains the half-life of 10.0 minutes
And there is 250 grams
We need to find out the number of half lives that took place after 50.0 minutes
As in the question
1 half life is 10 minutes
So for 50 minutes, it would be
= 50 minutes × 1 half life ÷ 10 minutes
= 5 half lives
Explain why bicarbonate soda would be the best option to treat a bee sting?
soda is fuzzy and can help heal the swell caused by a bee sting
A student thermally decomposed a 0.150 gram sample of impure potassium chlorate. Manganese dioxide was used as a catalyst in the reaction. The student collected 43.60 mL of oxygen gas over water in a eudiometer. Potassium chloride was the other product of the reaction. The temperature and pressure at collection time were 20.00 oC and 762.10 mm Hg respectively. The water level in the eudiometer was 4.22 cm below the outside water level in the beaker.
1) What is the corrected pressure of the dry oxygen gas?
2) What is the volume in mL, of the dry oxygen gas at STP conditions?
3) How many molecules of oxygen were collected?
4) what is the percent purity of the original potassium chlorate sample?
Answer:
1. Vapor pressure of dry oxygen gas = 747.68 torr
2. Volume at STP = 39.97 mL
3. Number of oxygen gas molecules = 1.074 × 10²¹ molecules
4. Percent purity of KClO3 = 97.3 %
Explanation:
The balanced equation for the reaction is given below :
2 KClO3 (s) ------> 2 KCl (s) + 3 O2 (g)
1) Since the water level in the eudiometer was below the outside water level in the beaker,
Vapor pressure of dry oxygen gas = Total pressure + pressure due to difference in water levels - vapor pressure of water
Vapor pressure of water at 20 °C is 17.535 mm (torr).
Pressure due to difference in water level = 4.22 cm × 10mm/cm / 13.534 (13.534 is the density of mercury) = 3.118 mm (torr).
Vapor pressure of dry oxygen gas = 762.10 torr + 3.118 torr - 17.535 torr
Vapor pressure of dry oxygen gas = 747.68 torr
2) P₁ = 747.68 torr; V₁ = 43.60 ml; T1 = 20 °C + 273.15 = 293.15 K
P₂ = 760 torr; T₂ = 273.15 K; V₂ = ?
Using the general gas equation = P₁V₁/T₁ = P₂V₂/T₂
V2₂= P₁V₁T₂ / P₂T₁
V₂ = (747.68 × 43.60 × 273.15 ) / (760 × 293.15)
V₂ = 39.97 ml
Volume of dry oxygen gas at STP = 39.97 mL
3) Volume of oxygen gas at STP 39.97 mL = 0.03997 L
Number of moles of oxygen gas in 0.03997 L = volume of gas at STP /molarvolume at STP
Number of moles of oxygen gas = 0.03997/22.4 L
Number of molecules of oxygen gas = 0.03997/22.4 L × 6.03 × 10²³ molecules
Number of oxygen gas molecules = 1.074 × 10²¹ molecules
e) Number of moles of oxygen gas = 0.03997/22.4 = 0.001784 moles
From the equation, mole ratio of oxygen gas and potassium chlorate is 3 : 2
Moles KClO3 = 2/3 × 0.001784 moles = 0.001189 moles
Molar mass of KClO3 = 39 + 35.5 + 3 × 16 = 122.5 g
Actual mass of KClO3 decomposed = 122.5 grams × 0.001189 mole = 0.146 grams
Percent purity = (actual mass KClO3 decomposed / sample mass of impure KClO3) × 100%
Percent purity = (0.146/0.150) × 100% = 97.3 %
CH4 +2H2S = CS2+ 4H2
If the reaction shifts to the right what are the products?
If the reaction shifts to the right, which chemicals decrease in The process?
If the reaction shifts to the left what are the products?
If the reaction shifts to the left, which chemicals decrease in the process?
what are the physical properties of matter?
Answer:
Physical properties are typically things you can detect with your senses.
Explanation:
21. What are the individual ion
22. If the C2H302 ion concentration in a solution is 0.554 M, what is the concentration of
Ca(C2H2O2)2?
Answer:
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Explanation:
vugjb oh in luv ug ug yf fyi dxezw f f g gjhc ydzt
Laughing gas can decompose into nitrogen and oxygen
Nitrous oxide decomposes into nitrogen and oxygen, according to 2 N2O (g) -> 2 N2 (g) + O2 (g). ... In an experiment, a stream of N2O is passed through a tube 25 mm in diameter and 20 cm long. The flow rate of the gas is 0.75 L/min.
What is the molarity of a solution containing 7.47 moles of solute in 4.31 liters of
solvent?
Answer:
1.73 M
Explanation:
Molarity is moles per liter, so we need to divide 7.47 moles by 4.31 liters to get the molarity of the solution.
7.47/4.31 ≈ 1.73 M
how many liters of N2 gas is needed to produce 500 L NH3?
what would be the observation when pineapple juice is dipped in a red litmus paper
Answer:
red litmus paper change into blue when it is dipped into Pineapple juice.
hope it helps
The red litmus paper will stay red when dipped in pineapple juice.
What are acids and bases?Acids are substances that can donate a proton to another substance. A base is a substance that can accept a hydrogen ion from an acid.
Acidic substances are often characterized by their sour taste. An acid commonly can be energetically favorable after a loss of H⁺ ion and is also known to turn blue litmus paper into red.
Bases are generally recognized for their bitter taste and slippery texture. A base that can dissolve in water is also referred to as alkali and is also known to turn red litmus paper into blue.
The pH value of the pineapple juice lies between 2.5 to 3.9. Therefore, it is acidic in nature as the pH of acidic substances lies in the range of 0 to 7. So the red litmus paper will stay red in pineapple juice.
Learn more about acids and bases, here:
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what reaction type is
4+22⟶4+22
Answer: [tex]CF_{4} + 2Br_{2} \rightarrow CBr_{4} + 2F_{2}[/tex] is a single replacement reaction.
Explanation:
A chemical reaction in which one element of a compound is replaced by another element is called single replacement reaction.
For example, [tex]CF_{4} + 2Br_{2} \rightarrow CBr_{4} + 2F_{2}[/tex]
Here, fluorine element in the compound [tex]CF_{4}[/tex] is replaced by the element bromine.
Therefore, it is a single replacement reaction.
Thus, we can conclude that [tex]CF_{4} + 2Br_{2} \rightarrow CBr_{4} + 2F_{2}[/tex] is a single replacement reaction.
1) Heat is the ______ of energy and a unit is ____.
A: Measure; Joule
B: Measure; Kelvin
C: Movement; Kelvin
D: Movement; Joule
2) ______ is the internal energy of particles and when this motion is measured, the unit used is ___.
A: Heat; Joule
B: Thermal Energy; Kelvin
C: Thermal Energy; Joule
D: Heat; Kelvin
Answer:
Q1) B
Q2) C
Kelvin is the SI unit of temperature.
A 27.5g piece of aluminum sits in a room and cools. It loses 6120.0 J of heat. If the initial
temperature of aluminum is 157.3°C, what is the final temperature? The specific heat
capacity of aluminum is 0.900 J/gºC.
Answer:
[tex]T_2= -90.0°C[/tex]
Explanation:
Hello!
In this case, according to the given description of how the temperature changes for aluminum in agreement to the loss of heat of 6120.0 J, we can use the following equation:
[tex]Q=mC\Delta T=mC(T_2-T_1)\\\\[/tex]
Thus, by knowing Q, m, C and the initial temperature, we are able to obtain:
[tex]T_2=T_1+\frac{Q}{mC}\\\\T_2=157.3\°C+\frac{-6120.0J}{27.5g*0.900 J/g\ºC}\\\\T_2= -90.0°C[/tex]
Regards!
A chemistry student heated 2.255 g of oxygen gas in the presence of 5.145
Answer:
a
Explanation:
What type of molecule is 2-methylpentene?
O A. Alkane
O B. Branched alkene
O C. Alkyne
O D. Cyclic
Answer:
B. Branched Alkene
HOPE THIS HELPS :-)
Bears stop coming to a river ecosystem where they have been eating many fish each day. The fish the bears eat normally eat smaller fish, which eat plants along the river bottom.
What happens to the ecosystem?
Both the larger and the smaller fish populations grow quickly but then die out because the plant life is insufficient for them all to eat.
The larger fish population will drop first, and the smaller fish population will grow quickly. The plants will die off because too many of the smaller fish are eating them.
The larger fish population explodes at first, and the smaller fish population begins to drop. Eventually, the river runs out of smaller fish so larger fish die out, and the plant population grows.
The smaller fish population begins to eat more plants and to grow. The larger fish have more food to eat so their population is able to grow, too.
Answer:
The larger fish population explodes at first, and the smaller fish population begins to drop. Eventually, the river runs out of smaller fish so larger fish die out, and the plant population grows.
Explanation:
A body system is a group of organs that work together to keep the organism
alive. How does the respiratory system help to keep an organism alive?
A. The respiratory system helps the organism respond to its
environment.
B. The respiratory system helps the organism absorb nutrients from
its environment.
O C. The respiratory system takes in oxygen and releases carbon
dioxide.
O D. The respiratory system carries oxygen to the organism's cells.
Answer:The lungs expel the carbon dioxide and bring in new oxygen-containing air. Only when both systems are working together can oxygen and carbon dioxide be successfully exchanged between cells and environment. There are many other examples of this cooperation in your body.
Explanation:
Hope it will help
Question:
A body system is a group of organs that work together to keep the organism
alive. How does the respiratory system help to keep an organism alive?
A. The respiratory system helps the organism respond to its
environment.
B. The respiratory system helps the organism absorb nutrients from
its environment.
O C. The respiratory system takes in oxygen and releases carbon
dioxide.
O D. The respiratory system carries oxygen to the organism's cells.
Answer:
O C. The respiratory system takes in oxygen and releases carbon
dioxide.
Explanation:
Breathing uses chemical and mechanical processes to bring oxygen to every cell of the body and to get rid of carbon dioxide. Our body needs oxygen to obtain energy to fuel all our living processes. Carbon dioxide is a waste product of that process
Hope This Helps?
20 grams of hydrogen fluoride gas, HF, is dissolved in 0.5 liters of solution. Determine the molarity (M).
Answer:
40
Explanation:
M = n/v hope this helps :b
During energy conversions, some energy is always lost as _____.
heat
electricity
chemical energy
light
Answer:
electricity
Explanation:
I know this because I am currently learning about this and remember doing it
What is the total number of Joules lost when 10. grams of water at 80.°C is cooled to 60.°C?
Answer:
[tex]\boxed {\boxed {\sf 836.8 \ Joules \ lost}}[/tex]
Explanation:
Since we are given the mass and change in temperature, we should use the following formula for heat.
[tex]q= mc \Delta T[/tex]
In this formula, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature.
We know the mass of the water is 10 grams. We will have to look up water's specific heat, because it is not given. It is 4.184 J/g °C.
Let's find the change in temperature. This is the difference of the final and initial temperature. The water started at 80 °C and cooled to 60°C.
ΔT= final temperature - initial temperature ΔT= 60° C - 80°C ΔT= -20 °CNow we have values for each variable.
m= 10 gc= 4.184 J/g°C ΔT= -20°CSubstitute the values into the formula.
[tex]q= 10 \ g * 4.184 \ J/g \textdegree C * -20 \textdegree C[/tex]
Multiply the first 2 numbers. The units of grams will cancel each other out.
[tex]q= 41.84 \ J/ \textdegree C * -20 \textdegree C[/tex]
Multiply again. This time, the degrees Celsius cancel.
[tex]q= -836.8 \ J[/tex]
A total of 836.8 Joules are lost.
An organism is living in a rapidly changing environment. Sexual reproduction is advantageous to an organism in this situation because–
sexual reproduction produces more offspring than asexual reproduction within a given time period.
sexual reproduction produces offspring with more variation, some of which may be better adapted to a new environment.
sexual reproduction requires more time to complete, allowing the environment to become more stable.
offspring produced by sexual reproduction grows to maturity more rapidly.
Answer:
sexual reproduction produces offspring with more variation, some of which may be better adapted to a new environment.
Explanation:
this allows more of the organisms to survive a change in the environment
Answer:
sexual reproduction produces offspring with more variation, some of which may be better adapted to a new environment.
Explanation:
A compound containing phosphorus and oxygen has a molar mass of 157.9 g/mol and an empirical formula of PO3 .
Answer: The molecular formula of the compound is [tex]P_2O_6[/tex]
Explanation:
The molecular formula is the chemical formula that tells about the number of atoms of each element present in a compound. Molecular formula and empirical formula can also be the same when the number of atoms is in the simplest whole-number ratio.
To calculate the molecular formula, the number of atoms of the empirical formula is multiplied by a factor known as valency that is represented by the symbol, 'n'.
[tex]n=\frac{\text{Molecular mass}}{\text{Empirical mass}}[/tex] ...(1)
Given empirical formula is [tex]PO_3[/tex]
Empirical mass = [tex][(1\times 30.97) + (3\times 15.99)]=78.94 g/mol[/tex]
Molecular mass = 157.9 g/mol
Plugging values in equation 1:
[tex]n=\frac{157.9 g/mol}{78.94g/mol}\\\\n=2[/tex]
Molecular formula of the compound becomes [tex]P_{2\times 1}O_{2\times 3}=P_2O_6[/tex]
Hence, the molecular formula of the compound is [tex]P_2O_6[/tex]
3. Bacteria communicate with each other through electronic pulses.
O True
O False
Answer:
All in All, All in All.
Explanation:
Describe one way that carbon and silicon are alike.
ASAP
Answer:
they have the same density
7.In the oxidation of ethane: 2 C2H6 + 7 02 + 4CO2 + 6H2O how many
liters of O2 are required to react with 90 grams of ethane?
Answer:
If reaction is taking place at room temperature and pressure(rtp)
= 360 litres of O₂ at rtp
If reaction is taking place at standard temperature and pressure(stp):
= 336 litres of O₂ at stp
Explanation:
2C₂H₆ + 70₂ → 4CO₂ + 6H₂O
1 mole of C₂H₆ = (12 × 2) + (1 × 6) = 24 + 6 = 30g
2 moles of C₂H₆ = 30 × 2 = 60g
From the equation:
1 mole of 0₂ reacts with 2 moles of C₂H₆
1 mole of 0₂ reacts with 60g of C₂H₆
? moles of 0₂ react with 90g of C₂H₆
[tex]\frac{90}{60}[/tex]= 1.5 moles of O₂
Considering condition of reaction taking place whether room temperature and pressure(rtp) or standard temperature and pressure(stp)
If room temperature and pressure(rtp):
1 mole of 0₂ occupies 24 liters/24000 cm³/ 24 dm³ of O₂
1.5 moles of O₂ occupies (24 × 1.5) litres of O₂
= 360 litres of O₂ at rtp
If standard temperature and pressure(stp):
1 mole of 0₂ occupies 22.4 liters/22400 cm³/ 22.4 dm³ of O₂
1.5 moles of O₂ occupies (22,4 × 1.5) litres of O₂
= 336 litres of O₂ at stp