Answers
Answer:
NK=12
Step-by-step explanation:
x^2 +9^2=15^2
x^2+81=225
subtract 81
x^2=144
x=12
(This is only for number 13, I don't know the answer to 14-16)
Using the Pythagoras theorem, the value of NK is 12.
What is the Pythagoras theorem?The sum of the squares of the lengths of the other two sides of a right triangle equals the square of the hypotenuse's length.
It is given that, NL=9, and KL=15.
Use the Pythagoras theorem,
[tex]& \Rightarrow {{15}^{2}}=N{{K}^{2}}+{{9}^{2}} \\ & \Rightarrow 225-81=N{{K}^{2}} \\ & \Rightarrow NK=\sqrt{144} \\ & \Rightarrow NK=12 \\[/tex]
Therefore, the value of NK is 12.
Learn more about the Pythagoras theorem, here
https://brainly.com/question/343682
Related Questions
What is the equation of the following line?
Answers
Answer:
Answer is F. y = 6x
Step-by-step explanation:
A bag contains 10 blue marbles, 7 white marbles, 6 red marbles, and 2 Green marbles. what is the probability of randomly selecting the blue marble?
Answers
Answer:
Step-by-step explanation:
Number of blue marbles = 10
Number of white marbles = 7
Number of Red marbles = 6
Number of Green marbles = 2
Total marbles = 10 + 7 + 6 + 2 = 25
Probability of selecting the blue marble = 10/25 = 2/5
I NEED HELPPP
PLEASEEEEEEEEEEEEEE
Answers
The dot plot below shows the number of movies rented last month by students in Ms. Underwood's class.
What is the median number of movies rented?
A.
4
B.
6
C.
3
D.
2
Answers
Answer:
the answer gonna be 3
Answer: I the answer is 3 100%
Step-by-step explanation: I took the test
Please help me with this question.
Answers
Answer:
A
Step-by-step explanation:
F(-2)= 4(-2)-1= -9
G(-2)= (-2)^2-3= 1
f(-2)-(g-2)= -9-1= -10
Ms. De Leon wants to produce different sets of test questions for her essay test. If she plans to do this by putting together 3 out of 5 questions she prepared, how many different sets of questions could she contruct?
A.10
B. 20
C. 60
D. 80
Answers
A 1/17th scale model of a new hybrid car is tested in a wind tunnel at the same Reynolds number as that of the full-scale prototype. The drag coefficient of the model is the same as that of the prototype. Assuming the model and prototype are both tested in air, find the ratio of the drag on the scale model (Fm) to the drag on the prototype (Fp), i.e., Fm/Fp. Since the size of the model is 1/17th of the size of the prototype, the projected area of the model is (1/17)2 of the projected area of the prototype. Round your answer to the nearest tenth.
Answers
Answer:
The ratio of the drag coefficients [tex]\dfrac{F_m}{F_p}[/tex] is approximately 0.0002
Step-by-step explanation:
The given Reynolds number of the model = The Reynolds number of the prototype
The drag coefficient of the model, [tex]c_{m}[/tex] = The drag coefficient of the prototype, [tex]c_{p}[/tex]
The medium of the test for the model, [tex]\rho_m[/tex] = The medium of the test for the prototype, [tex]\rho_p[/tex]
The drag force is given as follows;
[tex]F_D = C_D \times A \times \dfrac{\rho \cdot V^2}{2}[/tex]
We have;
[tex]L_p = \dfrac{\rho _p}{\rho _m} \times \left(\dfrac{V_p}{V_m} \right)^2 \times \left(\dfrac{c_p}{c_m} \right)^2 \times L_m[/tex]
Therefore;
[tex]\dfrac{L_p}{L_m} = \dfrac{\rho _p}{\rho _m} \times \left(\dfrac{V_p}{V_m} \right)^2 \times \left(\dfrac{c_p}{c_m} \right)^2[/tex]
[tex]\dfrac{L_p}{L_m} =\dfrac{17}{1}[/tex]
[tex]\therefore \dfrac{L_p}{L_m} = \dfrac{17}{1} =\dfrac{\rho _p}{\rho _p} \times \left(\dfrac{V_p}{V_m} \right)^2 \times \left(\dfrac{c_p}{c_p} \right)^2 = \left(\dfrac{V_p}{V_m} \right)^2[/tex]
[tex]\dfrac{17}{1} = \left(\dfrac{V_p}{V_m} \right)^2[/tex]
[tex]\dfrac{F_p}{F_m} = \dfrac{c_p \times A_p \times \dfrac{\rho_p \cdot V_p^2}{2}}{c_m \times A_m \times \dfrac{\rho_m \cdot V_m^2}{2}} = \dfrac{A_p}{A_m} \times \dfrac{V_p^2}{V_m^2}[/tex]
[tex]\dfrac{A_m}{A_p} = \left( \dfrac{1}{17} \right)^2[/tex]
[tex]\dfrac{F_p}{F_m} = \dfrac{A_p}{A_m} \times \dfrac{V_p^2}{V_m^2}= \left (\dfrac{17}{1} \right)^2 \times \left( \left\dfrac{17}{1} \right) = 17^3[/tex]
[tex]\dfrac{F_m}{F_p} = \left( \left\dfrac{1}{17} \right)^3[/tex]= (1/17)^3 ≈ 0.0002
The ratio of the drag coefficients [tex]\dfrac{F_m}{F_p}[/tex] ≈ 0.0002.
What are the solutions to 2(x+1^2)=18
Answers
Answer:
2( x + 1) = 18
2x + 2 = 18
2x = 16
x = 16/2 = 8
Solve for x:
2x + 9 = 3
Answers
Answer:
x = -3
Step-by-step explanation:
2x + 9 = 3
2x = 3 - 9
2x = -6
x = -3
Answer:
- 3
Step-by-step explanation:
given
2x + 9 = 3
2x = 3 - 9
2x = - 6
x = - 6/2
x = - 3
hope it helps :)
The dot plots show the numbers of children’s books purchased by customers at two different bookstores on one day.
Which statement is supported by the information in the dot plots?
A) The mean of the data for Store 1 is greater than the mean of the data for Store2
B) The mode of the data for Store 2 is greater than the mode of the data for Store1
C) The median of the data for Store 2 is greater than the median of the data for Store1
D) The range of the data for Store 1 is greater than the range of the data for Store2
Answers
Answer:
A
Step-by-step explanation:
since mean is the most annoying to calculate I went through and did everything else, the range is the same as both charts go 0-6. The median is is the middle number which means store 1 has a higher number of 3' s but our option says store 2 is greater and B is the mode, the number that shows up the most.
What is the area of the parallelogram?
Answers
Answer:
im not 100 percent sure but i think its
140 inches squared
Step-by-step explanation:
Find mean & margin of error if 28.4 < µ < 38.8
Answers
Answer:
The mean is of 33.6
The margin of error is of 5.2.
Step-by-step explanation:
Confidence interval concepts:
A confidence interval has two bounds, a lower bound and an upper bound.
A confidence interval is symmetric, which means that the point estimate used is the mid point between these two bounds, that is, the mean of the two bounds.
In this question:
Lower bound: 28.4
Upper bound: 38.8
Mean
(28.4+38.8)/2 = 33.6.
The mean is of 33.6
Margin of error:
(38.8 - 28.4)/2 = 5.2
The margin of error is of 5.2.
Use the remainder theorem to determine which of the following is not a factor of x^3-5x^2-x+5
Answers
Answer:
The answer is A
Step-by-step explanation:
x to the power of 1 is the lowest x and when you multiply -5 and -5 you get 5 so the answer is A.
Joe wants his overall test average to be 85%. What score would he need on his next test if the test scores he has so far are: 70%, 105%, 75%, 90%, 90%?
Answers
Answer:
He would need a score of 0.8 = 80%.
Step-by-step explanation:
Average score:
The average score is the sum of all scores divided by the number of tests.
What score would he need on his next test if the test scores he has so far are: 70%, 105%, 75%, 90%, 90%?
Combining with the next text, there will be 6, and the sum will be: 0.7 + 1.05 + 0.75 + 0.9 + 0.9 + x = 4.3 + x.
Joe wants his overall test average to be 85%.
So
[tex]\frac{4.3 + x}{6} = 0.85[/tex]
[tex]4.3 + x = 5.1[/tex]
[tex]x = 5.1 - 4.3 = 0.8[/tex]
He would need a score of 0.8 = 80%.
Find the Perimeter of this figure. I do y get it
Answers
Answer:
56m
Step-by-step explanation:
5+7+5+11+7+16+5
= 56
Solve the equation below.
Answers
Answer:
D
Step-by-step explanation:
Just divide by 2/3
How many odd numbers are between 10 and 50?
Answers
Answer: 19 odd numbers: 11 , 13, 15, 17 , 19, 23, 25, 27, 29, 31, 33 , 35, 37, 39, 41, 43, 45, 47, 49
Hope that helped! :)
Help pleaseeeeeeeeeeee
Answers
Answer:
3Step-by-step explanation:
When looking at a graph, the greatest speed will be the steepest part. Even though one line is further than another, does not mean it is faster.
what's the distance between (-9,-6) and (-2,-2)
Answers
Answer:
the distance formula is square root (x2-x1)^2 + (y2-y1)^2
7^2 + 4^2 = 49+16 = 65
squarroot of 65 = 8.06
Step-by-step explanation:
Step-by-step explanation:
The distance formula is [tex]\sqrt{(x_{2} -x_{1} )^{2} +(y_{2} -y_{1} )^{2} }[/tex]. I don't provide answers for problems like these but will give the equations.
What is the volume of a rectangular prism that is 250 centimeters by 2 meters by 1.4 meters in cubic meters?
(A) 5.9m
(B) 252.8m
(C) 7m
(D) 700m
Answers
Answer:
your answer is 7 meters
I hope it's helps you ❤️
AB = 5, AP = 4, and DP = 12, then find the length of PC
Answers
Answer:
[tex]PC = 0.333[/tex]
Step-by-step explanation:
Given
[tex]AB = 5[/tex]
[tex]AP = 4[/tex]
[tex]DP =12\\[/tex]
See attachment
Required
Find PC
When two chords intersect, the product of the segments are always equal.
In chord DC, the segments are DP and PC
In chord AB, the segments are AP and PB
So:
[tex]DP * PC = AP * PB[/tex]
This gives:
[tex]12 * PC = 4 * PB[/tex] --- (1)
In chord AB, we have:
[tex]AB = AP + PB[/tex]
Make PB the subject
[tex]PB = AB - AP[/tex]
This becomes
[tex]PB = 5 - 4[/tex]
[tex]PB = 1[/tex]
[tex]12 * PC = 4 * PB[/tex] --- (1) becomes
[tex]12 * PC = 4 * 1[/tex]
[tex]12 * PC = 4[/tex]
Make PC the subject
[tex]PC = \frac{4}{12}[/tex]
[tex]PC = 0.333[/tex]
measure of each exterior angle of a regular 30-gon?
7. An exterior angle of a regular polygon measures 22.5°. How many sides does it have?
8. An interior
Answers
Answer:
I'm not sure would love to help but dont know the answer
3.294e6 standard form
Answers
Answer:
3.294
Step-by-step explanation:
The management of KSmall Industries is considering a new method of assembling a computer. The current assembling method requires a mean time of 66 minutes with a standard deviation of 3.0 minutes. Using the new method, the mean assembly time for a random sample of 24 computers was 61 minutes.
a. Using the 0.10 level of significance, can we conclude that the assembly time using the new method is faster?
b. What is the probability of a Type II error? (Round "Critical values" to 2 decimal places and round your final answer to 4 decimal places.)
Answers
Answer:
Part a:
Since the calculated z= 8.1649 falls in the critical region z < ± 1.28 we reject H0 and conclude that the assembly time using the new method is faster.
Part b:
P (Type II Error)= 0.6628
Step-by-step explanation:
The null and alternate hypothesis are
H0: μ1 ≥ μ2 against the claim Ha: μ1 < μ2
This is left tailed test
The critical region for this test at 0.10 ∝ is z < ± 1.28
The test statistic
z= x1-x2/ s/√n
z= 66-61/ 3/√24
z= 5/0.61238
z= 8.16486
Since the calculated z= 8.1649 falls in the critical region z < ± 1.28 we reject H0 and conclude that the assembly time using the new method is faster.
Part b:
P (Type II Error) = P ( accept H0/ H0 is false)
z ( ∝)= X-u/s/√n
1.28= X-61/0.61238
X= 61.7838
So I will incorrectly fail to reject the null as long as a draw a sample mean that greater than 61.7838
The probability of a Type II error is given by
P (z> 61.7838-66/24)
P (z>- 0.42161)
From the tables
P (z>- 0.42161)= 0.6628
Find all the missing elements : C=120degrees
b= 5
c=11
Answers
Answer:
A = 36.8°
B = 23.2°
a = 7.6
Step-by-step explanation:
Given:
C = 120°
b = 5
c = 11
Required:
Find A, B, and a.
Solution:
✔️To find B, apply the Law of Sines
[tex] \frac{sin(B)}{b} = \frac{sin(C)}{c} [/tex]
Plug in the values
[tex] \frac{sin(B)}{5} = \frac{sin(120)}{11} [/tex]
Cross multiply
Sin(B)*11 = sin(120)*5
Divide both sides by 11
[tex] sin(B) = \frac{sin(120)*5}{11} [/tex]
[tex] sin(B) = \frac{sin(120)*5}{11} [/tex]
Sin(B) = 0.3936
B = [tex] sin^{-1}(0.3936) [/tex]
B = 23.1786882° ≈ 23.2° (nearest tenth)
✔️Find A:
A = 180° - (B + C) (sum of triangle)
A = 180° - (23.2° + 120°)
A = 36.8°
✔️To find a, apply the Law of sines:
[tex] \frac{sin(A)}{a} = \frac{sin(B)}{b} [/tex]
Plug in the values
[tex] \frac{sin(36.8)}{a} = \frac{sin(23.2)}{5} [/tex]
Cross multiply
a*sin(23.2) = 5*sin(36.8)
Divide both sides by sin(23.2)
[tex] a = \frac{5*sin(36.8)}{sin(23.2) [/tex]
a = 7.60294329 ≈ 7.6 (nearest tenth)
High point question. SAT prep
Answers
Answer:
[tex] log_{a}(a) \ + log_{a}( {10}^{ - 4} ) = 1 + \frac{ - 4}{ log_{10}(a) } = 1 + \frac{ - 4}{b} = \frac{b - 4}{b} [/tex]
................................................................................................................................................................................
................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................
The groundhog population of Punxsutawny, Pennsylvania is closely monitored each year. Two years ago the population decreased by 12%. Last year the number of groundhogs increased by 6%. This year the population also increased by 9%. What was the percentage increase/decrease of groundhogs over these three years? Round your answer to the nearest tenth of a percentage poin
Answers
Answer:
There was a increase of 1.7% over these three years
Step-by-step explanation:
Multipliers:
For a decrease of a%, we multiply by: [tex]\frac{100-a}{100}[/tex]
For a increase of a%, we multiply by: [tex]\frac{100+a}{100}[/tex]
What was the percentage increase/decrease of groundhogs over these three years?
Decrease of 12%(multiplication by 0.88).
Increase of 6%(multiplication by 1.06).
Increase of 9%(multiplication by 1.09).
After these three years:
0.88*1.06*1.09 = 1.017
1.017 - 1 = 0.017
0.017*100% = 1.7%
There was a increase of 1.7% over these three years
Nettlefield primary school have you heard
Answers
Answer:
No, I have not heard. Give me brainliest plz, I neeeeeeeeeeed it to level up
Step-by-step explanation:
Brand A and brand B of frozen green beans both list a weight of 32 ounces on their bags. Because of variability in the manufacturing process, the bags often contain slightly more, or less, than 32 ounces of green beans. An inspector takes a random sample of 25 bags of green beans of each type and records their weights. The weights and their relative frequencies are summarized in the histograms. 2 histograms comparing brand A and brand B of green beans. The median weight for brand B is less than the median weight of brand A. Which of the following is a true statement when comparing the bags of green beans? The median weight for both types is between 32.1 and 32.2 ounces. The median weight for both types is between 32.0 and 32.1 ounces. The median weight for brand B is less than the median weight of brand A. The median weight for brand B is greater than the median weight of brand A.
Answers
Answer:
The answer is: B.)32.0–32.1 ounces
Step-by-step explanation:
Got it right on my test
The true statement is The median weight for both types is between 32.0 and 32.1 ounces.
What is data?Data is referred to as a collection of information gathered by observations, measurements, research, or analysis. It may comprise facts, figures, numbers, names, or even general descriptions of things. Data can be organized in the form of graphs, charts, or tables for ease in our study.
Given:
Brand A and brand B of frozen green beans both list a weight of 32 ounces on their bags.
The median weight for brand B is less than the median weight of brand A.
So, if both brands weigh 32 ounces then the median weight for both types is between 32.0 and 32.1 ounces.
Learn more about data here:
https://brainly.com/question/10980404
#SPJ6
NASA is conducting an experiment to find out the fraction of people who black out at G forces greater than 6. In an earlier study, the population proportion was estimated to be 0.3 . How large a sample would be required in order to estimate the fraction of people who black out at 6 or more Gs at the 80% confidence level with an error of at most 0.03
Answers
Answer:
A sample of 383 would be required.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of [tex]\pi[/tex], and a confidence level of [tex]1-\alpha[/tex], we have the following confidence interval of proportions.
[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]
In which
z is the zscore that has a pvalue of [tex]1 - \frac{\alpha}{2}[/tex].
The margin of error is:
[tex]M = z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]
In an earlier study, the population proportion was estimated to be 0.3.
This means that [tex]\pi = 0.3[/tex]
80% confidence level
So [tex]\alpha = 0.2[/tex], z is the value of Z that has a pvalue of [tex]1 - \frac{0.2}{2} = 0.9[/tex], so [tex]Z = 1.28[/tex].
How large a sample would be required in order to estimate the fraction of people who black out at 6 or more Gs at the 80% confidence level with an error of at most 0.03?
A sample of n is needed.
n is found when M = 0.03. So
[tex]M = z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]
[tex]0.03 = 1.28\sqrt{\frac{0.3*0.7}{n}}[/tex]
[tex]0.03\sqrt{n} = 1.28\sqrt{0.3*0.7}[/tex]
[tex]\sqrt{n} = \frac{1.28\sqrt{0.3*0.7}}{0.03}[/tex]
[tex](\sqrt{n})^2 = (\frac{1.28\sqrt{0.3*0.7}}{0.03})^2[/tex]
[tex]n = 382.3[/tex]
Rounding up:
A sample of 383 would be required.