Answer:
A divergent boundary occurs when two tectonic plates move away from each other. Along these boundaries, earthquakes are common and magma (molten rock) rises from the Earth's mantle to the surface, solidifying to create new oceanic crust. When two plates come together, it is known as a convergent boundary.
Explanation:
17.
A car is accelerated at 4.0 m/s2 from rest. How long does it take the car to reach a speed of 28 meters per second?
Answer:
t = 7 seconds
Explanation:
Given that,
The acceleration of a car, a = 4 m/s²
The initial velocity of the car, u = 0
Final velocity of the car, v = 28 m/s
We need to find how much time the car to reach a speed of 28 m/s. Using the definition of the acceleration of a car. It is given by :
[tex]a=\dfrac{v-u}{t}\\\\t=\dfrac{v-u}{a}\\\\t=\dfrac{28}{4}\\\\t=7\ s[/tex]
So, it will take 7 seconds to reach a speed of 28 m/s.
A projectile was launched horizontally with a velocity of 388 m/s, 2.89 m above the ground. How long did it take the projectile to hit the ground? Select one: 1.34 s 0.308 s 0.768 s 0.0744 s
Answer:
Explanation:
Given
Velocity = 388m/s
Height S = 2.89m
Required
Time
Using the equation of motion
S =ut+1/2gt²
2.89 = 388t+1/2(9.8)t²
2.89 = 388t+4.9t²
Rearrange
4.9t²+388t-2.89 =0
Factorize
t = -388±√388²-4(4.9)(2.89)/2(4.9)
t= -388±√(388²-56.644)/9.8
t = -388±387.93/9.8
t =0.073/9.8
t = 0.00744 seconds
The force on the projectile is constant throughout the flight *
True
False
Suppose a 125 N force is applied to a lawnmower handle at an angle of 35° with the ground and the lawnmower moves along the surface of the ground. If the lawnmower moves 56 m, how much work was done? (hint: use cos to find the x of force vector)
Answer:
Workdone is 5734.06Nm.
Explanation:
Given the following data;
Force applied = 125N
Angle = 35°
Distance = 56m
To find the workdone by the lawnmower, we would first of all find the horizontal component of the force applied.
[tex] Horizontal force, Fx = mgCosd[/tex]
Where;
Fx represents the horizontal force. m is the mass of an object. g is the acceleration due to gravity. d is the angle of inclination (theta).mg = weight = 125N
Substituting into the equation, we have;
[tex] Fx = 125 * Cos35[/tex]
[tex] Fx = 125 * 0.8192[/tex]
Fx = 102.39N
Workdone is given by the formula;
[tex] Workdone = force * distance[/tex]
[tex] Workdone = 102.39 * 56[/tex]
Workdone = 5734.06Nm
Therefore, the work done by the lawnmower is 5734.06Nm.
whoever hears this I want u to know that I am here for I will always be be and so will God. Things well get better I promise!! YOU have to go through the storm to get to the rainbow. TURN TO GOD he will always help u and he loves you and I do to and so does Jesus u got this. DONT GIVE UP and keep on pushing at the end it will all be worth it I promise AND GIVE YOUR LIFE TO JESUS he will help you
Answer:
Awe you too. God is gonna bless you more than anyone. You bring so much courage to the world and some people need to hear this because they are going through it but people like you are amazing and a blessing. Im thankful for this message and i hope you have the best life the Lord could ever give love. You keep on pushing and you will suceed.Explanation:
Answer:
You too :)
Explanation:
Which line represents a stationary object?
A. Line A
B. Line B
C. Line C
D. Line D
PLZ HELP
Line D represents a stationary object.
When an object is stationary, the line on the graph is horizontal.
When the object is stationary the gradient is?We know, that an object is stationary means the slope of its position-time graph is zero or its pt graph is a straight line parallel to the x-axis.
What is an example of a stationary object?The nest, or the resting place, is a stationary object, and one cannot put one's foot in front of it. A string is then tied from the head assembly to another stationary object.
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Anybody know the acceleration of the box
It looks like the diagram is telling you that there is a net force of 8 N + 4 N = 12 N pointed to the right. By Newton's second law, the magnitude of the net force F is equal to the mass m times the acceleration a :
F = m a
12 N = (4 kg) a
a = (12 N) / (4 kg)
a = 3 m/s²
Anyone play Among US?
Answer:
Yes
Explanation:
Its a good game.
Answer:
oof
Explanation:
The specific heat capacity of oxygen is 918 J/kg °C. The specific heat capacity of water is 4181 J/kg °C. Which substance will require more energy to raise its temperature by 1°C?
Oxygen and water
Answer:
Water
Explanation:
Answer:
So, water has a specific heat of exactly 1.00 calorie per gram per °C. Because one calorie is equal to 4.18 J, it takes 4.18 J to raise the temperature of one gram of water by 1°C. In joules, water's specific heat is 4.18 J per gram per °C.
The answer is water.
Ahmad is riding his bicycle. He finds that he can accelerate from rest at 0.44 m/s^2 for 5 s to reach a speed of 2.2 m/s. The total mass of Christian and his bicycle is 54 kg. Later, he straps some cargo onto the back of his bicycle. The mass of the cargo is 12 kg.• Calculate the force that Christian can exert on his bicycle before picking up the cargo and exerts the same force on his bicycle.
Answer:
1) The force Christian can exert on his bicycle before picking up the the cargo is 529.74 N
2) The force Christian can exert on his bicycle after picking up the the cargo is 647.46 N
Therefore, Christian has to exert more force on his bike after picking up the cargo
Explanation:
The given parameters are;
The mass of Christian and his bicycle = 54 kg
The mass of the cargo = 12 kg
1) The force Christian can exert on his bicycle before picking up the the cargo = Mass of Christian and his bicycle × Acceleration due to gravity
∴ The force Christian can exert on his bicycle before picking up the the cargo = 54 kg × 9.81 m/s² = 529.74 N
2) The force Christian can exert on his bicycle after picking up the the cargo = (54 + 12) kg × 9.81 m/s² = 647.46 N
Therefore, Christian has to exert more force on his bike after picking up the cargo.
A flagpole 24 meters high casts a shadow 33 meters long. What is the distance between the tip of the shadow and flagpole? Round your answer to the nearest meter
Answer:
The distance between the tip of the shadow and flagpole is 40.80 m.
Explanation:
Let the flagpole be represented by AB and the shadow BC . We have to find the distance between C and A .
Considering the right angle CA is the hypotenuse .
Using the Pythagoras theorem
(Hypotenuse)² = (base)² + (perpendicular)²
CA= √(24)² + (33)²
CA= √576+1089
CA= 40.80 m
The distance between the tip of the shadow and flagpole is 40.80 m.
I will mark a brainluest, And good ponits, Please help me out
Answer:
gas, liquid and the last one is opaque solid
Explanation:
Answer:
gas, liquid and the last one is opaque solid
Explanation:
A cannon is fired from the edge of a cliff, which is 60m above the sea. The cannonball's initial velocity is 88.3m/s and it is fired at an upward angle of 34.5° to the horizontal. Determine: (a) the time the ball is in the air: (b) the impact velocity: (c) the horizontal distance out from the base of the cliff that the ball strikes the water.
Answer:
a. 11.29 s b. 94.72 m/s at -39.8° c. 821.57 m
Explanation:
a. Using y - y₀ = ut - 1/2gt² where u = vertical component of velocity = v₀sinθ where v₀ = 88.3 m/s and θ = 34.5°, y₀ = + 60 m and y = water surface = 0 m, g = 9.8 m/s² and t = time it takes the cannon to reach the water surface.
So y - y₀ = ut - 1/2gt²
y - y₀ = (v₀sinθ)t - 1/2gt²
substituting the values of the variables into the equation, we have
0 - 60 = (88.3 m/s × sin34.5°)t - 1/2 × 9.8 m/s²× t²
- 60 = 50t - 4.9t²
So, 4.9t² - 50t - 60 = 0
Using the quadratic formula to find t,
[tex]t = \frac{-(-50) +/- \sqrt{(-50)^{2} - 4 X 4.9 X -60} }{2 X 4.9} \\t = \frac{50 +/- \sqrt{2500 + 1176} }{9.8} \\t = \frac{50 +/- \sqrt{3676} }{9.8} \\t = \frac{50 +/- 60.63 }{9.8} \\t = \frac{50 + 60.63 }{9.8} or t = \frac{50 - 60.63 }{9.8} \\t = \frac{110.63 }{9.8} or t = \frac{-10.63 }{9.8} \\t = 11.29 sor -1.085[/tex]
Since t cannot be negative, t = 11.29 s
b. We first need to find the impact vertical velocity component. Using
v = u - gt where u = initial vertical velocity component = v₀sinθ and t = 11.29 s and g = 9.8 m/s². So,
v = v₀sinθ - gt
= 88.3 m/s × sin34.5° - 9.8 m/s² × 11.29 s
= 50.01 m/s - 110.64 m/s
= -60.63 m/s
Since the horizontal velocity is constant u' = v₀cosθ = 88.3 m/s × cos34.5° = 72.77 m/s.
The impact velocity is thus the resultant of the horizontal velocity and final impact velocity. So, V = √(v² + u'²)
= √((-60.63 m/s)² + (72.77 m/s)²)
= √((3676 m²/s² + 5295.48 m²/s²)
= √(8971.48 m²/s²
= 94.72 m/s
The angle θ = tan⁻¹(v/u') = tan⁻¹(-60.63 m/s ÷ 72.77 m/s) = tan⁻¹(-0.8332) = -39.8°
So the impact velocity is 94.72 m/s at -39.8°
c. The horizontal distance out from the base of the cliff that the ball strikes the water is the range, R = u't = 72.77 m/s × 11.29 s = 821.57 m
Please answer these three multiple choices!
Would appreciate a loooottttt today!!
Answer:
Q2 [ C ]
Q4 [ C]
Q5 [ C]
if u want the steps write a comment
A teacher asks students to identify which demonstrations show physical changes and which show chemical changes.
Which demonstration shows a physical change?
A. Baking soda is mixed with vinegar. The mixture bubbles.
B. A dish of water is placed in the freezer. The water turns solid.
Ο Ο Ο Ο
C. A piece of pH paper is dipped in clear ammonia. The paper turns from yellow to pink.
D. Hydrogen peroxide solution is dropped on a potato slice. The liquid bubbles and fizzes.
Answer:
B. A dish of water is placed in the freezer and turns solid
Explanation:
it is a physical change because it can return to its original state by physical means. the other options are chemical changes because things like color change, bubbles or fizzing, and odor change all indicate a chemical change and cannot return to the original state it was in before.
Help me plzzzz
Which product forms from a reaction between magnesium (Mg) and nitrogen
(N)?
A. MgN2
O B. Mg2N3
C. Mg3N2
O D. MgN
Answer:
C. Mg3N2
Explanation:
Magnesium has a positive 2 charge and nitrogen has a negative 3 charge. To completely balance it out, you need three magnesium’s and two nitrogen’s. The final charge for magnesium would be positive 6 and the final charge for nitrogen would be negative 6, this will make it neutral.
Answer:
C. Mg3N2
How I Know :
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Two blocks are arranged at the ends of a mass-less string as shown in the figure. The system starts from rest. When the 3.26 kg mass has fallen through 0.386 m, its downward speed is 1.28 m/s. What is the frictional force between the 4.52 kg mass and the table? (round your answer to the 4th decimal place)
Answer: 002 10.0points Two blocks are arranged at the ends of a massless string as shown in . 96 kg mass has fallen through 0 . 415 m, its downward speed is 1 . 25 m / s.
Explanation: I hoped that helped!!
Answer:
2.5 kg
Explanation:
why has adolescence been characterized as a time of "storm and stress"?
Answer:
Its A time when our bodies hormones go crazy therefore making us insecure, sometimes scared, and other feelings. That’s why
Explanation:
A cross- country skier moves from location A to location B to location C to location D. Each leg of the back and forth motion takes 1 minute to complete; the total time is 3 minutes . Wes =0 min t - 2min t = 3mim t = 1min 100 What is the distance travelled by the skier in the first 3 minutes? What is the net displacement of the skier in the first 3 minutes? - What is the displacement during the second minute? What is the displacement during the third minute?
Answer:
hello some parts of your question is missing attached below is the missing part
Answer :
a) 360 m
b) 120 m ( eastward )
c) -120 m ( westward )
d) 80 m ( eastward )
Explanation:
given data:
Each leg time = 1 minute
Total time = 3 minutes
t=0 t= 2 t = 3 t = 1
xo =0 x2 = 40 x3 = 120 x1 = 160
a) Distance travelled by skier in first 3 minutes
d = | x1 - xo | + | x2 - x1 | + | x3 - x2 |
= 160 + 120 + 80 = 360 m
b) net displacement in first 3 minutes
s = ( x1 -x0 ) + ( x2 - x1 ) + ( x3 -x2 )
= 120 m ( eastward )
c) displacement during the second minute
s1 = x2 - x1 = 40 - 160 = -120 m ( westward )
d) displacement during the third minute
s2 = x3 - x2 = 120 - 40 = 80 m ( eastward )
(a) The distance traveled by the skier in the first 3 minutes is 360.
(b) The displacement of the skier during the second minute is 120 west.
(c) The displacement of the skier during the third minute is 80 east.
The given parameters;
distance traveled in 1 min = 160 distance traveled in 2 min = 20distance traveled in 3 min = 120The distance traveled by the skier in the first 3 minutes is calculated as follows;
[tex]x = (120 - 40) + 120 + 160\\\\x = 360[/tex]
The displacement of the skier during the second minute is calculated as follows;
[tex]x= (x_2 - x_1)\\\\x = 40 - 160\\\\x = -120 \ \\\\x = 120 \ west[/tex]
The displacement of the skier during the third minute is calculated as follows;
[tex]x = (x_3 - x_2)\\\\x = 120 - 40\\\\x = 80 \ east[/tex]
"Your question is not complete, it seems to be missing the following information"
Learn more about distance and displacement here: https://brainly.com/question/17345815
If the astronaut from question #9 collides with a satellite and comes to a complete stop, where did his momentum go? Explain this in terms of conservation of momentum.
Answer:
m v ´- MV = (m + M) v ’
Explanation:
If the astronaut initially has a speed v the satellite has a speed V, we can define a system that is formed by the two bodies, therefore the forces during the collision are internal, so the momentum is conserved
initial instant. Before the crash
p₀ = m v - MV
final instatne. After the crash, we have two cases
1) inelastic shock
m_f = (m + M) v '
p₀ = p_f
m v ´- MV = (m + M) v ’
2) elastic collision with the astronaut's velocity, zero in this case the moment remains
m v - MV = mv ’+ Mv’
also the kinetic energy is conserved
mv'2 + M V2 = mv'2 + m v'2
with these two equations we can find the speed of the cars
PLEASE HELP !
What is the acceleration of a ball that starts at rest and increases in speed
to 20 m/s in 45 seconds? *
Why is it difficult to climb on a mountain through vertical path than a curved path
Answer:
a curved path generally goes around all hills and higherpoints in a trail, unlike a straight path which would take you through every single terrain there is on the mountain.
For a less steep slope, less power is needed by the vehicle. The concept is that it will be easier for one to exert less control and that too for a more extended period. So the roads of the mountains are always made curvy and not straight.
Building a road on or around mountains is no simple task. Roads built on mountainsides take weeks, even months of planning and surveying just to determine where to put them. From there, the task becomes even more dangerous and hands-on, but with the help of some heavy machinery and months of work, roads are paved and finished for commuters.Roads are built on mountains by carefully surveying the region, then methodically cutting or blasting into the mountain's side. From there, roads are mapped and paved before being finished and ready for commuters to use.In this article, we'll look at the process of roads being built on mountains and all of the careful steps that go into planning a mountain road. Additionally, we'll answer some commonly asked questions about building roads on mountains.Learn more about mountain roads
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the photos below show four pairs of objects. which pair of objects is experiencing the greatest gravitational force.A. the person and dog B. The person and the ball C. the person and earth D. the person and the building
Answer:
C.
Explanation:
the earth has a high greavitational pull
Answer: C the person and earth
Explanation: I just answered it on a p e x
How to calculate mass
Answer:
The mass can be calculated by dividing the net force acting on an object by the acceleration of the object. When talking about net force, we use the units kilogram meter per second squared. This is also known as a Newton. The units for acceleration is meters per seconds squared, and the units for mass are kilograms.
Answer:
[tex]vd=m[/tex] - volume times density
Explanation:
d = density
v = volume
m = mass
density = mass divided by volume.
multiply both sides by volume to find mass.
Lily can run 100 m in 10s. How fast was her average speed?
Answer:
The answer is 10 m/sExplanation:
The average speed can be found by using the formula
[tex]v = \frac{d}{t} \\ [/tex]
d is the distance
t is the time taken
From the question we have
[tex]v = \frac{100}{10} \\ [/tex]
We have the final answer as
10 m/sHope this helps you
(4.81•10^3)+(7.913•10^5)
in scientific notation
Answer:
796110
Explanation:
(4.81)(1000)+7.913(105)
=4810+7.913(105)
=4810+(7.913)(100000)
=4810+791300
=796110
can somone pls help me??!! i’m very stuck
Answer:
graph b
Explanation:
graph a isnt constant
graph c is slower (less steep slope)
graph d is slowing down (starts high ends low)
FREEE POINTS
COME HELP NOW!!!
Which of these statements about heating up water on Earth's surface is true?
Water heats up faster than land.
Water heats up by convection from Earth.
Water heats up by conduction from the sun.
Water heats up to a lower temperature than land.
Answer:
number 2
Explanation:
the 2 one is right
* 1 po
What are the health benefits of having muscular strength and endurance?
Answer:
i can`t help without showing me the choses
Explanation:
While playing football, Chris runs 4.5 m at 20⁰ south of west. If an opponent was trying to tackle him how far west and south would he have to run to reach him?
Answer:
South = 1.5m
West =4.2m
Explanation:
Kindly see attached a rough draft of the situation
Step one
Given data
From the sketch the direction of the player is along the resultant of the triangle, corresponding to the Hypotenuse
Step two:
Hence for an opponent to tackle him towards the south, he must be at
sin θ= opp/hyp
sin 20=x/4.5
x=sin 20*4.5
x=0.342*4.5
x= 1.5m
Also, for an opponent to tackle him towards the south, he must be at
cos θ= adj/hyp
cos 20=y/4.5
y=cos 20*4.5
y=0.93*4.5
y= 4.2m