2 3X Find the solution set for each of the following equations. a 20x² + 10x -8=0 b x² − 8x + 15 = 0 3X C​

Answers

Answer 1

The Solution set of the given quadratic equations are

1. x = 5 or x = 3

2. x= -3/2 or x =  5

What is quadratic equation?

A Quadratic equation is an algebraic expression in which highest degree of the given variable is 2.

Formula used as x² +ax + b = (x + c)(x + d)

Where 'a' is the sum 'c' and 'd' and 'b' is the product of 'c' and 'd'

According to the information, Factorize all the given quadratic equations we get;

1. x² - 8x + 15 =0

Now Split middle term of quadratic equation using formula we get,

 x² - 5x - 3x + 15 =0

⇒ x(x- 5) -3(x - 5) =0

⇒(x -5)(x - 3) =0

⇒ x- 5 =0 or x - 3 =0

⇒ x= 5 or x = 3

2. 20x² + 10x -8=0

Now Split middle term of quadratic equation using formula we get,

10x² + 5x - 4 = 0

⇒ 2x(x-5) +3(x-5)=0

⇒(2x+3)(x-5)=0

⇒2x+3 =0 or x-5 =0

⇒ x= -3/2 or x=5

Hence, the solution set are

1. x = 5 or x = 3

2. x= -3/2 or x =  5

Learn more about quadratic equation here

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Step-by-step explanation:

kiop

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Answer:

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Answer:

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Step-by-step explanation:

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Answers

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Step-by-step explanation:

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Answers

9514 1404 393

Answer:

  L'(3, -6)

Step-by-step explanation:

The reflection over the y-axis is modeled by the transformation ...

  (x, y) ⇒ (-x, y)

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Answers

Answer:

[tex](\dfrac{25}{1024})^x[/tex]

Step-by-step explanation:

The given expression is :

[tex](\dfrac{32}{5})^{-2x}[/tex]

We need to rewrite it in the form of [tex]A^x[/tex].

We know that, [tex](\dfrac{1}{x})^{-a}=x^a[/tex]

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[tex](\dfrac{32}{5})^{-2x}=(\dfrac{5}{32})^{2x}\\\\=(\dfrac{5^2}{32^2})^x\\\\=(\dfrac{25}{1024})^x[/tex]

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Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

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