Which is the length of the route between two points
Answer:
Can you show us the route and then I would be happy to help :)
Explanation:
A sky diver jumps out of a plane and reaches terminal velocity at 91 meters per second. How far will she fall in 35 seconds?
Can I get this answer quick!
whoever hears this I want u to know that I am here for I will always be be and so will God. Things well get better I promise!! YOU have to go through the storm to get to the rainbow. TURN TO GOD he will always help u and he loves you and I do to and so does Jesus u got this. DONT GIVE UP and keep on pushing at the end it will all be worth it I promise AND GIVE YOUR LIFE TO JESUS he will help you
Answer:
Awe you too. God is gonna bless you more than anyone. You bring so much courage to the world and some people need to hear this because they are going through it but people like you are amazing and a blessing. Im thankful for this message and i hope you have the best life the Lord could ever give love. You keep on pushing and you will suceed.Explanation:
Answer:
You too :)
Explanation:
While playing football, Chris runs 4.5 m at 20⁰ south of west. If an opponent was trying to tackle him how far west and south would he have to run to reach him?
Answer:
South = 1.5m
West =4.2m
Explanation:
Kindly see attached a rough draft of the situation
Step one
Given data
From the sketch the direction of the player is along the resultant of the triangle, corresponding to the Hypotenuse
Step two:
Hence for an opponent to tackle him towards the south, he must be at
sin θ= opp/hyp
sin 20=x/4.5
x=sin 20*4.5
x=0.342*4.5
x= 1.5m
Also, for an opponent to tackle him towards the south, he must be at
cos θ= adj/hyp
cos 20=y/4.5
y=cos 20*4.5
y=0.93*4.5
y= 4.2m
the photos below show four pairs of objects. which pair of objects is experiencing the greatest gravitational force.A. the person and dog B. The person and the ball C. the person and earth D. the person and the building
Answer:
C.
Explanation:
the earth has a high greavitational pull
Answer: C the person and earth
Explanation: I just answered it on a p e x
PLEASE HELP !
What is the acceleration of a ball that starts at rest and increases in speed
to 20 m/s in 45 seconds? *
The force on the projectile is constant throughout the flight *
True
False
17.
A car is accelerated at 4.0 m/s2 from rest. How long does it take the car to reach a speed of 28 meters per second?
Answer:
t = 7 seconds
Explanation:
Given that,
The acceleration of a car, a = 4 m/s²
The initial velocity of the car, u = 0
Final velocity of the car, v = 28 m/s
We need to find how much time the car to reach a speed of 28 m/s. Using the definition of the acceleration of a car. It is given by :
[tex]a=\dfrac{v-u}{t}\\\\t=\dfrac{v-u}{a}\\\\t=\dfrac{28}{4}\\\\t=7\ s[/tex]
So, it will take 7 seconds to reach a speed of 28 m/s.
A cannon is fired from the edge of a cliff, which is 60m above the sea. The cannonball's initial velocity is 88.3m/s and it is fired at an upward angle of 34.5° to the horizontal. Determine: (a) the time the ball is in the air: (b) the impact velocity: (c) the horizontal distance out from the base of the cliff that the ball strikes the water.
Answer:
a. 11.29 s b. 94.72 m/s at -39.8° c. 821.57 m
Explanation:
a. Using y - y₀ = ut - 1/2gt² where u = vertical component of velocity = v₀sinθ where v₀ = 88.3 m/s and θ = 34.5°, y₀ = + 60 m and y = water surface = 0 m, g = 9.8 m/s² and t = time it takes the cannon to reach the water surface.
So y - y₀ = ut - 1/2gt²
y - y₀ = (v₀sinθ)t - 1/2gt²
substituting the values of the variables into the equation, we have
0 - 60 = (88.3 m/s × sin34.5°)t - 1/2 × 9.8 m/s²× t²
- 60 = 50t - 4.9t²
So, 4.9t² - 50t - 60 = 0
Using the quadratic formula to find t,
[tex]t = \frac{-(-50) +/- \sqrt{(-50)^{2} - 4 X 4.9 X -60} }{2 X 4.9} \\t = \frac{50 +/- \sqrt{2500 + 1176} }{9.8} \\t = \frac{50 +/- \sqrt{3676} }{9.8} \\t = \frac{50 +/- 60.63 }{9.8} \\t = \frac{50 + 60.63 }{9.8} or t = \frac{50 - 60.63 }{9.8} \\t = \frac{110.63 }{9.8} or t = \frac{-10.63 }{9.8} \\t = 11.29 sor -1.085[/tex]
Since t cannot be negative, t = 11.29 s
b. We first need to find the impact vertical velocity component. Using
v = u - gt where u = initial vertical velocity component = v₀sinθ and t = 11.29 s and g = 9.8 m/s². So,
v = v₀sinθ - gt
= 88.3 m/s × sin34.5° - 9.8 m/s² × 11.29 s
= 50.01 m/s - 110.64 m/s
= -60.63 m/s
Since the horizontal velocity is constant u' = v₀cosθ = 88.3 m/s × cos34.5° = 72.77 m/s.
The impact velocity is thus the resultant of the horizontal velocity and final impact velocity. So, V = √(v² + u'²)
= √((-60.63 m/s)² + (72.77 m/s)²)
= √((3676 m²/s² + 5295.48 m²/s²)
= √(8971.48 m²/s²
= 94.72 m/s
The angle θ = tan⁻¹(v/u') = tan⁻¹(-60.63 m/s ÷ 72.77 m/s) = tan⁻¹(-0.8332) = -39.8°
So the impact velocity is 94.72 m/s at -39.8°
c. The horizontal distance out from the base of the cliff that the ball strikes the water is the range, R = u't = 72.77 m/s × 11.29 s = 821.57 m
Can y’all please help
Answer:
The cat's speed when it slid off the table was 2.53 m/s
Explanation:
Horizontal Motion
When an object is thrown horizontally at a speed v, from a height h, it describes a curved path ruled by gravity, until it hits the ground.
the range or maximum horizontal distance traveled by the object can be calculated as follows:
[tex]\displaystyle d=v\cdot\sqrt{\frac {2h}{g}}[/tex]
The situation described in the problem fits into the concept of a horizontal launch when the cat slides off the table and gets to the ground some distance ahead.
It's given the range as d=1.3m and the height h=1.3 m, thus we can find the cat's speed by solving the equation for v:
[tex]\displaystyle v=d\cdot\sqrt{\frac {g}{2h}}[/tex]
Where [tex]g=9.81\ m/s^2[/tex]
Substituting values:
[tex]\displaystyle v=1.3\cdot\sqrt{\frac {9.81}{2\cdot 1.3}}[/tex]
[tex]\displaystyle v=1.3\cdot\sqrt{\frac {9.81}{2.6}}[/tex]
Calculating:
v = 2.53 m/s
The cat's speed when it slid off the table was 2.53 m/s
which factor is needed to describe velocity but is not needed to describe speed
Answer:
Magnitude and direction describe velocity
However if there is only magnitude its mean it is speed.
Fun : probably you have seen speed movie. It could not have director because if speed is directed then it will be velocity lol..
8
If you put 100 carbon atoms in a box. How many carbon atoms remain after 2 half-lives or
11460 years? (you might need to review half-lives to answer this question) *
(1 Point)
100 atoms
50 atoms
25 atoms
12 atoms
Answer:
25 atoms
Explanation:
18) Why do you think divergent plate boundaries and transform fault boundaries only occur at places where the crust is the same on both plates?
Answer:
A divergent boundary occurs when two tectonic plates move away from each other. Along these boundaries, earthquakes are common and magma (molten rock) rises from the Earth's mantle to the surface, solidifying to create new oceanic crust. When two plates come together, it is known as a convergent boundary.
Explanation:
If the astronaut from question #9 collides with a satellite and comes to a complete stop, where did his momentum go? Explain this in terms of conservation of momentum.
Answer:
m v ´- MV = (m + M) v ’
Explanation:
If the astronaut initially has a speed v the satellite has a speed V, we can define a system that is formed by the two bodies, therefore the forces during the collision are internal, so the momentum is conserved
initial instant. Before the crash
p₀ = m v - MV
final instatne. After the crash, we have two cases
1) inelastic shock
m_f = (m + M) v '
p₀ = p_f
m v ´- MV = (m + M) v ’
2) elastic collision with the astronaut's velocity, zero in this case the moment remains
m v - MV = mv ’+ Mv’
also the kinetic energy is conserved
mv'2 + M V2 = mv'2 + m v'2
with these two equations we can find the speed of the cars
A teacher asks students to identify which demonstrations show physical changes and which show chemical changes.
Which demonstration shows a physical change?
A. Baking soda is mixed with vinegar. The mixture bubbles.
B. A dish of water is placed in the freezer. The water turns solid.
Ο Ο Ο Ο
C. A piece of pH paper is dipped in clear ammonia. The paper turns from yellow to pink.
D. Hydrogen peroxide solution is dropped on a potato slice. The liquid bubbles and fizzes.
Answer:
B. A dish of water is placed in the freezer and turns solid
Explanation:
it is a physical change because it can return to its original state by physical means. the other options are chemical changes because things like color change, bubbles or fizzing, and odor change all indicate a chemical change and cannot return to the original state it was in before.
if a truck goes 30 kilometers in 30 minutes what is the average speed
Answer:
60 km per hour
Explanation:
if you drive for 30 min and go 30km then if you drive for 60 min(1hr) then you would have driven 60km.
Answer:
60
Explanation:
hope this helps
(NEED HELP ASAP)
In a lab investigation one group of students (group a) measures the speed of a 0.1 toy car to be 2.5 m/s at the bottom of a ramp another group of students (group b) measures the speed of the car to be 3 m/s at the bottom of the ramp the cars starting position at the top of the ramp is 1 m high.
a. what is the potential energy of the car at the beginning of the experiment before it's speed is measured?
b. Calculate the kinetic energy of the car for group a.
C. Calculate the kinetic energy for the car for group b.
Answer:
a = 0.98J
Explanation:
PE = mgh
PE = 0.1 x 9.8 x 1
PE = 0.98J
(a) The potential energy of the car at the beginning of the experiment is 9.8(m) J.
(b) The kinetic energy of the car for group a is 3.125(m) J.
(c) The kinetic energy of the car for group b is 4.5(m) J.
Potential energy of the car at the beginning of the experimentThe potential energy of the car is calculated as follows;
P.E = mgh
where;
m is mass of the carg is accleration due to gravityh is height of the carP.E = m x 9.8 x 1
P.E = 9.8(m) J
Kinetic energy of the car for group aK.E = ¹/₂mv²
K.E = ¹/₂ x m x (2.5)²
K.E = 3.125(m) J
Kinetic energy of the car for group bK.E = ¹/₂mv²
K.E = ¹/₂ x m x (3)²
K.E = 4.5(m) J
Learn more about kinetic energy here:https://brainly.com/question/25959744
#SPJ2
A flagpole 24 meters high casts a shadow 33 meters long. What is the distance between the tip of the shadow and flagpole? Round your answer to the nearest meter
Answer:
The distance between the tip of the shadow and flagpole is 40.80 m.
Explanation:
Let the flagpole be represented by AB and the shadow BC . We have to find the distance between C and A .
Considering the right angle CA is the hypotenuse .
Using the Pythagoras theorem
(Hypotenuse)² = (base)² + (perpendicular)²
CA= √(24)² + (33)²
CA= √576+1089
CA= 40.80 m
The distance between the tip of the shadow and flagpole is 40.80 m.
Lily can run 100 m in 10s. How fast was her average speed?
Answer:
The answer is 10 m/sExplanation:
The average speed can be found by using the formula
[tex]v = \frac{d}{t} \\ [/tex]
d is the distance
t is the time taken
From the question we have
[tex]v = \frac{100}{10} \\ [/tex]
We have the final answer as
10 m/sHope this helps you
9. According to statistical theory, 68% of your measurements of time should fall within the range of and of therefore about 3 of your 5 measurements should satisfy this condition. How many of your measurements fall within this range? Are your errors random according to this theory?
Answer:
Yes
Explanation:
Yes, this is a random error generating because of statistical constraint. We only have finite number of data points. As per this, if we plot our observation we will get a gaussian (inverse bell ) shaped curve with mean equal to central value.
How to calculate mass
Answer:
The mass can be calculated by dividing the net force acting on an object by the acceleration of the object. When talking about net force, we use the units kilogram meter per second squared. This is also known as a Newton. The units for acceleration is meters per seconds squared, and the units for mass are kilograms.
Answer:
[tex]vd=m[/tex] - volume times density
Explanation:
d = density
v = volume
m = mass
density = mass divided by volume.
multiply both sides by volume to find mass.
For brainliest !!!!!!! Do it
Answer and Explanation:
Using a = F/m, we get:
Acceleration for Road A = 480/62 = ~7.74 m/s^2
Acceleration for Road B = 240/62 = ~3.87 m/s^2
Acceleration for Road C = 600/62 = ~9.68 m/s^2
If the net force becomes higher than 600N and the mass stays constant, the acceleration will increase proportionally to how much the force increases and the acceleration will be greater than the acceleration when the force is 600N.
I hope this helps! :)
The specific heat capacity of oxygen is 918 J/kg °C. The specific heat capacity of water is 4181 J/kg °C. Which substance will require more energy to raise its temperature by 1°C?
Oxygen and water
Answer:
Water
Explanation:
Answer:
So, water has a specific heat of exactly 1.00 calorie per gram per °C. Because one calorie is equal to 4.18 J, it takes 4.18 J to raise the temperature of one gram of water by 1°C. In joules, water's specific heat is 4.18 J per gram per °C.
The answer is water.
Anyone play Among US?
Answer:
Yes
Explanation:
Its a good game.
Answer:
oof
Explanation:
Two blocks are arranged at the ends of a mass-less string as shown in the figure. The system starts from rest. When the 3.26 kg mass has fallen through 0.386 m, its downward speed is 1.28 m/s. What is the frictional force between the 4.52 kg mass and the table? (round your answer to the 4th decimal place)
Answer: 002 10.0points Two blocks are arranged at the ends of a massless string as shown in . 96 kg mass has fallen through 0 . 415 m, its downward speed is 1 . 25 m / s.
Explanation: I hoped that helped!!
Answer:
2.5 kg
Explanation:
A boy throws a steel ball straight up. Consider the motion of the ball only after it has left the boy's hand but before it touches the ground, and assume that forces exerted by the air are negligible. For these conditions, the force(s) acting on the ball is (are):
a) a downward force of gravity along with a steadily decreasing upward force.
b) a steadily decreasing upward force from the moment it leaves the boy's hand until it reaches its highest point; on the way down there is a steadily increasing downward force of gravity as the object gets closer to the earth.
c) an almost constant downward force of gravity along with an upward force that steadily decreases until the ball reaches its highest point; on the way down there is only a constant downward force of gravity.
d) an almost constant downward force of gravity only.
e) none of the above. The ball falls back to the ground because of its natural tendency to rest on the surface of the earth.
Answer:
c) an almost constant downward force of gravity along with an upward force that steadily decreases until the ball reaches its highest point; on the way down there is only a constant downward force of gravity.
Explanation:
When the boy throws the ball upward, there are two forces acting on the ball. First one is the force of gravity, which is constant and equal tot he weight of the ball, acting down. The second force is the force with which the boy throws the ball. This force acts upward and decreases as the ball moves up. This force becomes zero when the ball reaches highest point.
While, on its way down the ball has only one force acting on it. That force is the constant force of gravity acting downward. This gravity force is equal to the weight of the ball.
Hence, the correct option is:
c) an almost constant downward force of gravity along with an upward force that steadily decreases until the ball reaches its highest point; on the way down there is only a constant downward force of gravity.
The force acting on the ball is an almost constant downward force of gravity along with an upward force that steadily decreases until the ball reaches its highest point; on the way down there is only a constant downward force of gravity. Thus the option C is the correct option.
Given,
Force exerted by the air is negligible.
Now the forces acting on the ball after the realese,
Gravity- This force acts on the body and will remain constant until the ball is in the air. This force is equal to the weight ([tex]W[/tex]) which is equal to the product of the mass [tex]m[/tex] and the gravitational force [tex]g[/tex] of the earth.
[tex]W=mg[/tex]
Force applied by the boy- This is the force by which the boy through the ball. This will act upward and keep on decreasing as the ball moves upward. This force becomes zero when the body reaches the highest point.Now after reaching the highest point, the ball starts to come down. In this case, only one force will act on it which is the gravity force and this is equal to the weight of the body.
Hence, the force acting on the ball is an almost constant downward force of gravity along with an upward force that steadily decreases until the ball reaches its highest point; on the way down there is only a constant downward force of gravity. Thus the option C is the correct option.
For more about the gravity follow the link below-
https://brainly.com/question/1479537
why has adolescence been characterized as a time of "storm and stress"?
Answer:
Its A time when our bodies hormones go crazy therefore making us insecure, sometimes scared, and other feelings. That’s why
Explanation:
* 1 po
What are the health benefits of having muscular strength and endurance?
Answer:
i can`t help without showing me the choses
Explanation:
A researcher may use a two-tailed test to evaluate a directional hypothesis.
Please select the best answer from the choices provided
OT
OF
Answer:
true
Explanation:
just took the test
Answer:
True
Explanation:
A construction worker accidentally drops a brick from a high scaffold. a. What is the brick's velocity after 4.0 s? b. How far does the brick fall during this time?
Answer:
A. 39.2 m/s
B. 78.4 m
Explanation:
Data obtained from the question include:
Time (t) = 4 s
Acceleration due to gravity (g) = 9.8 m/s²
A. Determination of the brick's velocity.
Time (t) = 4 s
Acceleration due to gravity (g) = 9.8 m/s²
Velocity (v) =?
v = gt
v = 4 × 9.8
v = 39.2 m/s
Thus, the brick's velocity after 4 s is 39.2 m/s
B. Determination of how far the brick fall in 4 s.
Time (t) = 4 s
Acceleration due to gravity (g) = 9.8 m/s²
Height (h) =?
h = ½gt²
h = ½ × 9.8 × 4²
h = 4.9 × 16
h = 78.4 m
Thus, the brick fall 78.4 m during the time.
The velocity after 4 seconds is 40 m/s and the height is 80 m.
From the equations of motion under gravity;
v = u + gt
V = final velocity of the brick
u = initial velocity of the brick
g = acceleration due to gravity = 10 ms-2
t = time taken
Note that, u = 0 m/s because the brick was dropped from a height.
v = 0 + 10(4)
v = 40 m/s
The height is obtained from;
h = ut + 1/2 gt^2
u = 0 m/s because the brick was dropped from a height.
h = 1/2 gt^2
h = 1/2 × 10 × (4)^2
h = 80 m
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