3. In a field of sugar beets in Georgia the net primary productivity is 120 grams/m^2/day, and the
respiration loss is 25%. The insolation energy is 800 calories/cm^2/day, and one gram of beets is
equivalent to 2,000 calories.
a. Find the gross productivity of the sugar beets.
b. Using the NPP, calculate the efficiency of photosynthesis for the sugar beets.

Answer and Explanation:

Available Data:

1) Find the gross productivity of the sugar beets.

We need to calculate the GPP, which equals NPP - Respiration rate. The respiration loss is 25% of the NPP. This is:

100% NPP--------------- 120 g/m²/day

25% NPP ----------------X = (25 x 120)/100 = 30 g/m²/day

Now that we know the values of NPP and respiration rate, we can calculate the GPP.

GPP = NPP - Respiration

GPP = 120 (g/m²/day) - 30 (g/m²/day)

GPP = 90 g/m²/day

GPP = 0.009 g/cm²/day

2) Using the NPP, calculate the efficiency of photosynthesis for the sugar beets.

% Efficiency of Photosynthesis = (NPP/Insolation Energy) X 100

We know the NPP, but this value is calculated in g/m²/day, while the Insolation energy is in g/cm²/day. We need to calculate the % Efficiency of Photosynthesis in cm. To do that, we must transform the information.

So if 1 m² = 10,000 cm², then:

10,000cm²----------120 grams/m²/day NPP

1 cm²---------------- (1 x 120) / 10,000 = 0.012 grams/cm²/day NPP

We also know that 1 gr beets = 2,000 cal, and that the Insolation energy is 800 calories/cm²/day

So we need to transform Insolation energy from calories/cm²/day to grams/cm²/day, so:

2,000 calories ----------------- 1 gr beet

800 calories/cm²/day---------X = 0.4 gr beet.

% Efficiency of Photosynthesis = (NPP/Insolation Energy) X 100

% Efficiency of Photosynthesis = (0.012 (gr/cm2/day) /0.4 (gr/cm2/day)) X 100

% Efficiency of Photosynthesis = 3 gr/cm2/day  

Why is chalk used on blackboards?

i dont know what to in this question

which levels of protein structure are expected to be altered as a result of the amino acid substitutions?
1. primary structure
2. secondary structure
3. tertiary structure
4. quaternary structure​

About _____ of people develop a serious condition in their phenotype as well as their genotype.

C2H60+
02 →
CO2+
H2O

15. Preservation focuses mainly on preserving resources so that they can be used by people a. True b. False​

Non renewable energy

Question 1
Which structure is outside the nucleus of a cell and contains
DNA?
A
chromosome
mitochondrion
B
gene
D
vacuole

3
A scientist mixes 2 grams of water and 6 grams of a powder. A new colored liquid is formed.
How many grams of the new colored liquid result?
(A)
(B)
2 grams
4 grams
6 grams
(C)
(D)
8 grams

Select all that apply. Which of the following are characteristics of eukaryotes? single- or multi-celled structure no distinct nucleus membrane-bound organelles cell(s) larger than prokaryotes