Answer:
v= 17.15 m/s
Explanation:
mass of the book=0.1 Kg
height above ground, h= 15 m
Using conservation of energy
Potential energy is converted into kinetic energy
[tex]mgh = \frac{1}{2}mv^2[/tex]
[tex]v=\sqrt{2gh}[/tex]
[tex]v=\sqrt{2\times 9.8\times 15}[/tex]
[tex]v=\sqrt{294}[/tex]
v= 17.15 m/s
Hence, the book will hit the ground at the speed of 17.15 m/s.
Which process causes Earth to act like a magnet?
O A. Convection of hot material in the mantle
O B. Flow of water due to gravitational energy
O C. Movement of ions in the core
O D. Shifting of the tectonic plates
SUBMI
Answer:movement of iron in core
Explanatio
Choose all the answers that apply. Force has _____.
efficiency
direction
time
magnitude
physical science is the connection between
A. atoms and cells
B. energy and life
C. matter and rocks
D. matter and energy
Answer:
d d d d d d s d. d d d d d df ff f f. f f f r r ff f f ff d f f f f f f f f f r. ff r f. r
6. As the sky diver's fall the______energy is converted into _______.
a. Energy is created and destroyed.
b. Energy is created but not destroyed.
C. Energy is not created but is destroyed.
d. Energy is neither created nor destroyed.
Answer: B
D makes no sense because energy is created so we can remove that. C also makes no sense because if energy is not created how did it get destroyed if there's no energy in the first place. This leaves us with a and B the correct answer is B because energy is created and cannot be destroyed.
Two points charge of 4\mu C and 2\mu C are placed at theopposite corners of a rectangle. What is the potential difference Va- Vb
Answer:
[tex]Va-Vb=168KV[/tex]
Explanation:
From the question we are told that
Two points charge of 4\mu C and 2\mu C
Generally we find the Va and Vb individually to find there difference
Given a rectangle with two equal sides each,Assume lengths for bot sides
Length L=0.3
Breath B=0.4
Diagonal D=[tex]\sqrt{0.3^2+0.4^2} =0.5[/tex]
at opposite sides
Mathematically Va can represented as
[tex]Va =k(\frac{4*10^_-_6}{0.3} +\frac{-2*10^_-_6}{0.5} )[/tex]
[tex]Va =9*10^9(\frac{4*10^_-_6}{0.3} +\frac{-2*10^_-_6}{0.5} )[/tex]
[tex]Va =9*10^9(0.00001333333-0.000004} )[/tex]
[tex]Va =84000V[/tex]
[tex]Va =84KV[/tex]
Mathematically Vb is represented as
[tex]Va =k(\frac{-4*10^_-_6}{0.3} +\frac{2*10^_-_6}{0.5} )[/tex]
[tex]Va =9*10^9(\frac{-4*10^_-_6}{0.3} +\frac{+2*10^_-_6}{0.5} )[/tex]
[tex]Va =9*10^9(-0.00001333333+0.000004} )[/tex]
[tex]Va =-84000V[/tex]
[tex]Va =-84KV[/tex]
Therefore
[tex]Va-Vb=84-(-84)\\Va-Vb=84+84\\Va-Vb=168KV[/tex]
as the temperature of a gas in a solid container increases what happens to the pressure exerted by the gas?
Which region contains the alkaline earth metal family of elements? A, B, C or D?
Answer:
B
Explanation:
B is the most likely region that contains alkaline earth family elements.
The alkaline earth metal family of elements is represented by B region in the figure.
What is alkaline earth metal?The alkaline earth metals are found on the periodic table in Group 2, which is on the far left side of the table between Group 1, the alkali metals, and Groups 3-12, the transition elements. This family is made up of six metals: beryllium, magnesium, calcium, strontium, barium, and radium.
What is periodic table?The periodic table, also known as the periodic table of the elements, is a tabular display of the chemical elements.
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4. What is the tan gential velocity of an object moving in a path of radius 2m with an angular velocity of
3rad/s.pls help me
Answer:
6m/s
Explanation:
The tangential velocity is the product of the linear velocity and the radius. This is expressed as;
v = wr
w is the angular velocity = 3rad/s
r is the radius = 2m
Substitute
v = 3 * 2
v = 6m/s
Hence the tangential velocity of the object is 6m/s
What average net force is required to accelerate a 3950 kg bus to a speed of 25m/s in 10.5 s?
Answer:
Explanation:
ACCELERATION = CHANGE IN VELOCITY
TIME TAKEN
∴ a = 25 - 0
10.5
∴ a = 50
21
by using f = ma,
we get , f = 3950 × 50
21
∴ A FORCE OF 9404.8 N IS NEEDED TO ACCELERATE A BUS OF 3950 KG.
A 47.5-g ball moves at 30.0 m/s. If its speed is measured to an accuracy of 0.20%, what is the minimum uncertainty in its position
Answer:
The minimum uncertainty in its position is 1.85 x 10⁻³² m.
Explanation:
Given;
mass of the ball, m = 47.5 g = 0.0475 kg
speed of the ball, v = 30 m/s
measuring accuracy of the speed, = 0.2% = 0.002
The uncertainty in measurement of momentum;
ΔP = mΔv
ΔP = (0.0475)(30 x 0.002)
ΔP = 2.85 x 10⁻³ kgm/s
The uncertainty in position is calculated as;
[tex]\delta x \geq \frac{h}{4\pi (\delta P)}[/tex]
where;
h is Planck's constant
[tex]\delta x \geq \frac{6.626 \ \times \ 10^{-34}}{4\pi (2.85 \ \times \ 10^{-3})} \\\\\delta x \geq 1.85 \ \times \ 10^{-32} \ m[/tex]
Thus, the minimum uncertainty in its position is 1.85 x 10⁻³² m.
As an object’s speed decreases, its kinetic energy (KE) ________.
As an object’s height increases, its gravitational potential energy (PEg) ________.
HELP ASAP!
Everything on screenshot.
Answer:
11. D
12. A
13. B
Explanation:
⚠️Please Help Me! I Need It Now!⚠️
Answer:
A. They are moving at 60 mph
Explanation:
When looking at the car on the track pass by, the people inside appear to be moving at the same speed as the car. So if the car is going 60 mph, the people instead will appear as though they are moving at 60 mph as well.
A solid sphere of radius R carries a fixed, uniformly distributed charge q. Obtain an expression for the magnitude of the electric field created by the sphere at a point P outside the sphere.
Answer:
The electric field outside the sphere will be [tex]\dfrac{qr}{4\pi\epsilon_{0}R^3}[/tex].
Explanation:
Given that,
Radius of solid sphere = R
Charge = q
According to figure,
Suppose r is the distance between the point P and center of sphere.
If [tex]\rho[/tex] be the volume charge density,
Then, the charge will be,
[tex]q=\rho\times\dfrac{4}{3}\pi R^3[/tex].....(I)
Consider a Gaussian surface of radius r.
We need to calculate the electric field outside the sphere
Using formula of electric field
[tex]\oint{\vec{E}\cdot \vec{dA}}=\dfrac{Q}{\epsilon_{0}}[/tex]
[tex]E\times4\pi r^2=\dfrac{\rho\dotc \dfrac{4}{3}\pi r^3}{\epsilon_{0}}[/tex]
Put the value from equation (I)
[tex]E\times4\pi r^2=\dfrac{qr^3}{\epsilon_{0}R^3}[/tex]
[tex]E=\dfrac{qr}{4\pi\epsilon_{0}R^3}[/tex]
Hence, The electric field outside the sphere will be [tex]\dfrac{qr}{4\pi\epsilon_{0}R^3}[/tex].
detergents are used to clean the clothes why
Answer:Detergent mixes with water to remove dirt and oil from clothes. Water can't remove oil and dirt from clothes. Detergent cleans by causing a chemical reaction with water to force dirt and debris out of clothing. Detergents work with water to loosen the dirt trapped in the material of clothing and clean them away.
Explanation:May i plz have brainlist only if u wanna give me brainlist though have an nice day!
Q2. You push a crate up a ramp with a force of 10 N. Despite your pushing, the crate slides down the ramp 4 m. How much work did you do
Answer:
40 J
Explanation:
From the question given above, the following data were obtained:
Force (F) = 10 N
Distance (s) = 4 m
Workdone (Wd) =?
Work done is simply defined as the product of force and distance moved in the direction of the force. Mathematically, we can express the Workdone as:
Workdone = force × distance
Wd = F × s
With the above formula, we can obtain the workdone as follow:
Force (F) = 10 N
Distance (s) = 4 m
Workdone (Wd) =?
Wd = F × s
Wd = 10 × 4
Wd = 40 J
Thus, 40 J of work was done.
An 85 kg man stands in a very strong wind moving at 15 m/s at torso height. As you know, he will need to lean in to the wind, and we can model the situation to see why. Assume that the man has a mass of 85 kg, with a center of gravity 1.0 m above the ground. The action of the wind on his torso, which we approximate as a cylinder 50 cm wide and 90 cm long centered 1.2 m above the ground, produces a force that tries to tip him over backward. To keep from falling over, he must lean forward.
Required:
a. What is the magnitude of the torque provided by the wind force? Take the pivot point at his feet. Assume that he is standing vertically.
b. At what angle to the vertical must the man lean to provide a gravitational torque that is equal to this torque due to the wind force?
Answer:
a) [tex]T= 72.9 Nm[/tex]
b) [tex]\Theta = 5 \textdegree[/tex]
Explanation:
From the question we are told that
Mass 85kg
Speed 15m/s
Center of gravity 1.0m
Cylinder 50 cm wide and 90 cm long centered 1.2 m above the ground
a)Generally equation for force is given by
[tex]F = 0.5 p A v^2[/tex]
Mathematically solving for force exacted
[tex]F = 0.5*1.2*0.9*0.5*15^2[/tex]
[tex]F= 60.75 N[/tex]
Mathematically solving for torque
Torque,
[tex]T = r * F[/tex]
[tex]T=1.2*60.75[/tex]
[tex]T= 72.9 Nm[/tex]
b)Generally in solving for [tex]\theta[/tex]
[tex]Tan\theta = Torque/(Mass * Gravity)[/tex]
[tex]Tan\theta = (72.9)/(85 * 9.8)[/tex]
[tex]\Theta = 5 \textdegree[/tex]
Bro help me
Explain how an object with a higher temperature can have less thermal energy than an object with a lower temperature. ASAP
The total energy of all the particles makes up thermal energy. This implies that larger objects with slower-moving particles at low temperatures can have more energy than smaller ones with higher temperatures.
What is thermal energy?Thermal energy is the sum of the energies of all the particles. This implies that larger objects at low temperatures can have more energy than smaller ones at higher temperatures due to slower-moving particles.
These molecules and atoms move more quickly when something is heated, providing it with more thermal energy. Compared to cold water, hot water has more thermal energy.
Therefore, molecules and atoms in colder objects move more slowly and have less thermal energy than those in warmer ones. The ability of particles to transfer energy increases with speed.
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Waves transport
over distances.
A. solids
B.
liquids
C.
gases
D.
energy
Answer:
d)energy
Explanation:
Waves can transfer energy over distance without moving matter the entire distance. For example, an ocean wave can travel many kilometers without the water itself moving many kilometers. The water moves up and down—a motion known as a disturbance. It is the disturbance that travels in a wave, transferring energy.
WILL GIVE BRAINLIEST TO THE CORRECT ANSWER
Estimate the net force needed to accelerate a 1000-kg car from rest.
AND
Estimate the weight of a 1000-kg car that is accelerating at 3m/s/s.
Answer:
See the answers below.
Explanation:
We can solve both problems using Newton's second law, which tells us that the sum of forces on a body is equal to the product of mass by acceleration.
∑F =m*a
where:
F = force [N] (units of newtons)
m = mass = 1000 [kg]
a = acceleration = 3 [m/s²]
[tex]F = 1000*3\\F=3000[N][/tex]
And the weight of any body can be calculated by means of the mass product by gravitational acceleration.
[tex]W=m*g\\W=1000*9.81\\W=9810 [N][/tex]
What is constant of a spring if there is 150 j when stretched 0.25 m?
Identify the velocity-versus-time plot(s) that correspond to motion under a constant, non-zero acceleration.
Answer:
See explanation
Explanation:
The question is incomplete because the images were not attached but I will try to help you as much as possible.
Constant acceleration implies that the velocity increases uniformly with time.
The graph of constant acceleration is a straight line graph having a slope. The slope of the graph is constant at any point along the straight line.
The image attached shows a velocity-time graph depicting constant acceleration.
This cantilever beam is loaded by two point loads. If the moment of inertia of the beam is 5.0*10-6 m4 and the modulus of elasticity is 210 GPa, the maximum deflection of the beam is:
Answer:
The answer is i just need the 5 pt sowwry bro hope you have luck finding it ;]
Explanation:
you prolly alr found it but it doesnt really matter
the combined focal length of two thin lens is 24 cm and the focal length of one converging lens is 8
cm what is the focal length of the other
Answer: f = -12 cm
Explanation: Combined lenses is an array of simple lenses with a common axis. The combination is useful for correction of optical aberrations which cannot be corrected by simple lenses.
When two lenses are in contact and are thin, focal lengths are related as:
[tex]\frac{1}{F} =\frac{1}{f_{1}} +\frac{1}{f_{2}}[/tex]
If there is a distance between the lenses, the focal length will be:
[tex]\frac{1}{F} =\frac{1}{f_{1}} +\frac{1}{f_{2}} -\frac{d}{f_{1}f_{2}}[/tex]
Since the lenses in the question above are thin and in contact, the focal length of one of them will be:
[tex]\frac{1}{F} =\frac{1}{f_{1}} +\frac{1}{f_{2}}[/tex]
[tex]\frac{1}{f_{2}} =\frac{1}{f_{1}} -\frac{1}{F}[/tex]
[tex]\frac{1}{f_{2}} =\frac{1}{8} -\frac{1}{24}[/tex]
[tex]\frac{1}{f_{2}} =\frac{-2}{24}[/tex]
[tex]f_{2}=[/tex] -12
The focal length of the other lens is -12 cm, with the negative sign meaning it's a converging lens.
Question 3 (1 point)
here were 2cars racing a quarter mile. The green car had a mass of 1200kg and crossed the finish line with a velocity of 53m/s. The red car had
a mass of 1100Kg and crossed the finish line with a velocity of 55m/s.,Which car had the great momentum?
Black car
Blue car
Green car
Red car
Answer:
The green car had the greatest momentum
Explanation:
Momentum
Momentum can be defined as "mass in motion" and is calculated as the product of the mass of the object by its velocity.
Being v the magnitude of the velocity and m the mass of the object, the momentum is calculated with:
p = mv
The green car had a mass of m1=1200 kg and crossed the finish line at v1=53 m/s. Hence, its momentum was:
p1 = 1200 Kg * 53 m/s = 63600 Kg.m/s
The red car had a mass of m2=1100 kg and crossed the finish line at v2=55 m/s. Hence, its momentum was:
p2 = 1100 Kg * 55 m/s = 60500 Kg.m/s
Since p1 > p2, then the green car had the greatest momentum
You push your friend, whose mass is 54kg, down a hill so she can go sledding. Her acceleration is 3m/s2. Calculate the amount of force you applied to your friend.
Answer:
18 newtons
Explanation:
Divide weight by speed
A skateboarder traveling at 10.4 m/s starts getting chased by a grumpy dog. The skateboarder speeds up with a constant acceleration for 39m over a 3.3s. We want to find the acceleration of the skateboarder over the 3.3s time interval. Which kinematic formula would be most useful to solve for the target unknown?
a. V= Vo+a(t)
b. X= (V+Vo/2)t
c. X= Vo(t)+1/2at^2
d. V^2 = Vo^2 +2ax
e. X= vt-1/2at^2
Answer:
c)X= Vo(t)+1/2at^2
Explanation:
From the question we are told that
initial speed u=10.4
displacement d= 39
time t=3.3s
accelaration a=?
Generally the best equation in solving for Acceleration is given to be
X= Vo(t)+1/2at^2
Mathematically
[tex]X= Vo(t)+1/2at^2[/tex]
[tex]39=10.4t+\frac{a}{2} *3.3^2[/tex]
[tex]5.445a=39-34.32[/tex]
[tex]a=39-34.32/5.445[/tex]
[tex]a=4.68/5.445[/tex]
[tex]a=0.86m/s^2[/tex]
A constant net force of 345 N is applied to slide a heavy stationary
couch across the floor. If the force is contact with the couch for 1.5 seconds,
then what is the change in momentum of the couch
Answer:
P = 517.5 [kg*m/s]
Explanation:
We must remember that momentum is defined as the product of force by the time of force duration.
[tex]P=F*t[/tex]
where:
P = momentum [kg*m/s]
F = force [N]
t = time [s]
[tex]P=345*1.5\\P=517.5[kg*m/s][/tex]
Why are some forms of speech not protected by the First Amendment?
because they support different religious views
because they could cause harm to others
because they criticize the government
because they are expressed in writing
Answer:
because they could cause harm to others
Explanation:
The "First Amendment" gives people the right to freedom of: religion, expression, press and assembly. However, the government has the right to censor one's speech if it could cause harm to others. Such speech falls under "unprotected category." This category includes the following: Defamation, Perjury, Blackmail, Plagiarism, True Threats, Child P.ornography, Obscenity, Solicitations to Commit Crime, Fighting Words, Incitement of Imminent Lawless Action. These forms of speeches are meant to harm other people, thus, they are not protected by the First Amendment.
Answer:
because they could cause physical harm to others
Explanation:
Took the test..
The first five harmonics for a vibrating string are shown in Figure24.13.a.For each harmonic, identify the number of wavelengths represented.b.For each harmonic, identify the number of nodes and antinodes that are present (include the ends of the string in your count).c.Which of the five harmonics has the highest natural frequency?d.Make a drawing that shows what the sixth harmonic would look like.