7.
Potassium-42 has a half-life of 12.4 hours. How much of an 848 gram sample of potassium-42 will be left after 62.0 hours?

Answers

Answer 1
Hello! I found this when I searched it up on the app Socratic! Hope this helps!
7.Potassium-42 Has A Half-life Of 12.4 Hours. How Much Of An 848 Gram Sample Of Potassium-42 Will Be
Answer 2

The required amount of potassium-42 left after 62.0 hours is 26.5 grams.

Given that,
Potassium-42 has a half-life of 12.4 hours. How much of an 848-gram sample of potassium-42 will be left after 62.0 hours is to be determined.

What is the half-life of the element?

The half-life of the element is defined as the time span in which the element grows or decays half of its whole composition of growth and decay.

Here,
Amount left of the potassium after 62 hours is given as,
A = 848 [1 / 2 ] ⁶²/¹²°⁴
A = 26.5 gram

Thus, the required amount of potassium-42 left after 62.0 hours is 26.5 grams.

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Step-by-step explanation:

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Answer:

Answer should be...

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Answers

Answer:

$562.50

Step-by-step explanation:

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I hope this helped and was right, have a nice day

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Answer:

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Step-by-step explanation:

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Answer:

I know right! There so annoying!!

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Answer:

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Answer:

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Step-by-step explanation:

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Answer:

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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Answer:

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Answers

Answer:

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Step-by-step explanation:

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Answers

Answer:

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Answers

✧ [tex] \underline{ \underline{ \pink{\large{ \tt{E \: X \: P \: L\: A \: N \: A \: T \: I \: O \: N}}}}}: [/tex]

Part 1 :

☃ [tex] \underline{ \large{ \sf{Vertical \: Line \: Test}}} : [/tex] ⇾ All the relations are not functions. We can determine ( identify ) whether a relation is function or not by drawing a vertical line intersecting the graph of the relation. This is called the vertical line test.

If the vertical line intersects the graph of a relation at one point , the relation is a function.If it cuts at more than one point , it is not a function. It means that if there are more points of the graph of a relation of a vertical line , same first component ( pre - image ) has more images ( second component ) which is not the function by definition.

( See the attached picture )

In the picture ' 1 ' , The vertical line ( dotted line ) cuts the graph at one point ( P ). Thus the graph represents a function.In the picture ' 2 ' , The vertical line ( dotted line ) cuts the graph at two points P & Q. So, the graph does not represent a function.

Part 2 :

☂ The set of all the images of the elements of domain under the function ' f ' is called the range of a function. In other words , the set of second components of a function is called range. We are given the function :

{(–2, 0), (–4, –3), (2, –9), (0, 5), (–5, 7)}

The above numbers [ in bold ] are the range of given function. Now, If we arrange these numbers in ascending order, we get ( -9 , -3 , 0 , 5 , 7 ).

Hence , Choice B [ {y | y = –9, –3, 0, 5, 7} ] is correct.

♕ Hope I helped! ♡

☄ Have a wonderful day / night ! ☼

✎ [tex] \underbrace{ \overbrace{ \mathfrak{Carry \: On \: Learning}}}[/tex] ☥

▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁

Sample Response:

The vertical line test is a way to determine if a relation is a function. This test determines if one input has exactly one output on the graph. If any vertical line passes through more than one point on the graph, then the relation is not a function because two different outputs have the same input.

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Answers

Answer:

hi

Step-by-step explanation:

100+20 is equal to 120

have a nice day

Answer:

I think what you are looking for is 120

HEEEEEEEEEEEEEELLLLLLLLLLLLLLLLLLPPPPPPPPPPPPPPPPPP MEEEEEEEEEEEEEEEEEEEEEEEEEEEEEE PLLLLLLLLLLLLLLLLEEEEEEEEEEEEEAAAAAAAAAAAAASSSSSSSSSSSSSSSSEEEEEEEEEEEEEEE

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Answer:

x = 12

Step-by-step explanation:

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Answer:

what's the question for this?

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33

Step-by-step explanation:

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Answers

Answer:

The answer is "[tex]\frac{5}{3}[/tex]"

Step-by-step explanation:

[tex]A_n={\frac{13}{5},\frac{18}{8},\frac{23}{11},\frac{28}{14},\frac{33}{17},..................\frac{8+5n}{2+3n}}\\\\[/tex]

[tex]\to A_n=\frac{8+5n}{2+3n}\\\\\to \lim_{n \to \infty} A_n = \lim_{n \to \infty} \ \frac{8+5n}{2+3n}= \lim_{n \to \infty} \ \frac{\frac{8}{n}+5}{\frac{2}{n}+3}=\frac{0+5}{0+3}=\frac{5}{3}[/tex]

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