Mathematics College

7n - 8n - 323
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Answer 1

Answer:

−n−323

Step-by-step explanation:

Related Questions

What Is It HomeWork*.

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Answer:

sumthing that we hate doing

Step-by-step explanation:ughhhhhhhhhh

The inequalities is 6 is greater than or equal to 6

Determine wheather the given lines are parallel or not. Write the reasons .

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Answer:

yes it is parallel because the alternate interior angles are equal

find the values of the six trigonometric functions for angle theta in standard position if a point with the coordinates (1, -8) lies on its terminal side

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Answer:

cosФ = [tex]\frac{1}{\sqrt{65}}[/tex] , sinФ = [tex]-\frac{8}{\sqrt{65}}[/tex] , tanФ = -8, secФ = [tex]\sqrt{65}[/tex] , cscФ = [tex]-\frac{\sqrt{65}}{8}[/tex] , cotФ = [tex]-\frac{1}{8}[/tex]

Step-by-step explanation:

If a point (x, y) lies on the terminal side of angle Ф in standard position, then the six trigonometry functions are:

cosФ = [tex]\frac{x}{r}[/tex]sinФ = [tex]\frac{y}{r}[/tex]tanФ = [tex]\frac{y}{x}[/tex]secФ = [tex]\frac{r}{x}[/tex]cscФ = [tex]\frac{r}{y}[/tex]cotФ = [tex]\frac{x}{y}[/tex]Where r = [tex]\sqrt{x^{2}+y^{2} }[/tex] (the length of the terminal side from the origin to point (x, y)You should find the quadrant of (x, y) to adjust the sign of each function

∵ Point (1, -8) lies on the terminal side of angle Ф in standard position

∵ x is positive and y is negative

→ That means the point lies on the 4th quadrant

∴ Angle Ф is on the 4th quadrant

∵ In the 4th quadrant cosФ and secФ only have positive values

∴ sinФ, secФ, tanФ, and cotФ have negative values

→ let us find r

∵ r = [tex]\sqrt{x^{2}+y^{2} }[/tex]

∵ x = 1 and y = -8

∴ r = [tex]\sqrt{x} \sqrt{(1)^{2}+(-8)^{2}}=\sqrt{1+64}=\sqrt{65}[/tex]

→ Use the rules above to find the six trigonometric functions of Ф

∵ cosФ = [tex]\frac{x}{r}[/tex]

∴ cosФ = [tex]\frac{1}{\sqrt{65}}[/tex]

∵ sinФ = [tex]\frac{y}{r}[/tex]

∴ sinФ = [tex]-\frac{8}{\sqrt{65}}[/tex]

∵ tanФ = [tex]\frac{y}{x}[/tex]

∴ tanФ = [tex]-\frac{8}{1}[/tex] = -8

∵ secФ = [tex]\frac{r}{x}[/tex]

∴ secФ = [tex]\frac{\sqrt{65}}{1}[/tex] = [tex]\sqrt{65}[/tex]

∵ cscФ = [tex]\frac{r}{y}[/tex]

∴ cscФ = [tex]-\frac{\sqrt{65}}{8}[/tex]

∵ cotФ = [tex]\frac{x}{y}[/tex]

∴ cotФ = [tex]-\frac{1}{8}[/tex]

Statements about regression
Which of the following are true about regression with one predictor variable (often called "simple regression")?
A. The total squared error divided by its degrees of freedom is the square of the standard error of estimate
B. The standardized regression coefficient, beta, has the same value as r, the estimated correlation
C. After conducting a hypothesis test to test that the slope of the regression equation is nonzero, you can conclude that your predictor variable, X, causes Y

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Answer:

Follows are the solution to this question:

Step-by-step explanation:

It is true because the square of the standard error of its estimate was its total square error divided only by the degree of freedom. It is true because Its coefficient with Standardized Regression, beta, will have the same value as r, the approximate similarity. It is false because Its slope b, of its equation of regression, will have the same value as r, the projected correlation.

A researcher wants to compare the heights of males between generations to see if they differ. To do this, he samples random pairs of males who are at least 18 years old and their fathers. He then splits them into a sample of fathers and a sample of sons. Suppose that data were collected for a random sample of 11 pairs, where each difference is calculated by subtracting the height of the son from the height of the father. Assume that the heights are normally distributed. The test statistic is t≈1.971, α=0.05, the corresponding rejection regions are t<−2.228 and t>2.228, the null hypothesis is H0:μd=0, and the alternative hypothesis is Ha:μd≠0.

Select all that apply:
a. Reject the null hypothesis.
b. Fail to reject the null hypothesis.
c. The conclusion of the hypothesis test is that there is sufficient evidence to suggest that the heights of males between generations are different.
d. The conclusion of the hypothesis test is that there is insufficient evidence to suggest that the heights of males between generations are different.

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Answer:

The correct option is

Option A and Option C

Step-by-step explanation:

From the question we are told that

The sample size of paired men is [tex]n_p = 11[/tex]

The test statistics is t≈1.971

The significance level is α=0.05

The rejection region is t<−2.228 and t>2.228

The null hypothesis is [tex]H_o :\mu_ d=0[/tex]

The alternative hypothesis is [tex]H_a :\mu_ d \ne 0[/tex]

Generally the degree of freedom is mathematically represented as

[tex]df = n_1 + n_2 - 2[/tex]

Here [tex]n_1[/tex] is the sample size of father which is [tex]n_1 = 11[/tex]

[tex]n_2[/tex] is the sample size of males who are at least 18 years old which is [tex]n_2 = 11[/tex]

[tex]df = 11 + 11 - 2[/tex]

=> [tex]df = 20[/tex]

Generally the critical values of α=0.05 from the t- distribution table at a degree of freedom of [tex]df = 20[/tex] for a two -tailed test is

[tex]t_{0.05 , 20 } = \pm 2.08596345 [/tex]

From the value obtained we see that the critical value is within the region of rejection hence

The decision rule is

Reject the null hypothesis

The conclusion is

The conclusion of the hypothesis test is that there is sufficient evidence to suggest that the heights of males between generations are different.

What are the answers to 11 and 12

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11. Is x=17
12.is x=11.43

A baseball organization has 209 players. It wants to buy sweatshirts or jackets for players’ warmups.

Warm-up Type Price
Sweatshirt $38
Jacket $50

What is the difference in the total price of the sweatshirts and the jackets for all 209 players?
Enter your answer in the box.

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Answer:

The answer is 2508

Step-by-step explanation:

(-8) X 2/3 i NEED the answer help me

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-5.33333333333

I used a calulator can I get brainliest please

CAN YOU PLS ANSWER THIS QUICK!!! WHAT IS THE ANSWER TO THIS MATH EQUATION??? GEOMETRY/COLLEGE!!!

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The answer is undefined

Find the general solution of y''' + 9y'' + y' − 111y = 0 if it is known that y1 = e−6x cos(x) is one solution.

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Answer:

[tex]\mathbf{y(x) = \dfrac{(c_1 + c_2) \ cos (x)}{e^{6x} }+ \dfrac{i(c_1 -c_2) \ sin (x)}{e^{6x}}+ c_3e^{3\ x}}[/tex]

Step-by-step explanation:

The objective of this question is to solve:

[tex]\dfrac{dy(x)}{dx}+ 9\dfrac{d^2y(dx)}{dx^2}+\dfrac{d^3y(x)}{dx^3}-111y(x) = 0 :[/tex]

Suppose the general solution is proportional to [tex]e^{\lambda x}[/tex] for [tex]\lambda[/tex] is constant; Then:

Let's replace [tex]y(x) = e^{\lambda\ x}[/tex] into the above equation:

i.e.

[tex]\dfrac{d^3}{dx^3}(e ^{\lambda x} )+ 9 \dfrac{d^2}{dx^2}(e ^{\lambda x} ) + \dfrac{d}{dx}(e ^{\lambda x} )- 111 \ e ^{\lambda x} = 0[/tex]

To Replace:

[tex]\dfrac{d^3}{dx^3}(e ^{\lambda x} )[/tex] with [tex]\lambda^3 e ^{\lambda x }[/tex]

[tex]\dfrac{d^2}{dx^2}(e ^{\lambda x} ) \ with \ \lambda^2 e^{\lambda\ x}[/tex]

[tex]\dfrac{d}{dx}(e ^{\lambda x} ) \ with \ \lambda e ^{\lambda \ x}[/tex]

Thus;

[tex]\lambda^3 e ^{\lambda x }[/tex] + [tex]9 \lambda^2 e^{\lambda\ x}[/tex] + [tex]\lambda e ^{\lambda \ x}[/tex] - 111 [tex]e ^{\lambda \ x}[/tex] = 0

[tex]e ^{\lambda \ x} (\lambda ^3 + 9 \lambda ^2 + \lambda - 111 )= 0[/tex]

∴

In as much as [tex]e^{ \lambda x}\neq 0[/tex] for any finite [tex]\lambda[/tex]; Then:

[tex]\lambda ^3 + 9 \lambda ^2 + 111 = 0[/tex]

By Factorization:

[tex](\lambda - 3) ( \lambda ^2 + 12 \lambda + 37) = 0[/tex]

[tex]\lambda = -6 + i \ or\ \lambda = -6 - i \ or \ \lambda = 3[/tex]

However;

The root [tex]\lambda = -6 \pm i[/tex] yield;

[tex]y_1 = (x) = c_1 e ^ {(-6+i)x}[/tex]

[tex]y_2 (x) = c_2e^{(-6-i)x}[/tex]

The root [tex]\lambda = 3[/tex] yield;

[tex]y_3(x) = c_3 e^{3x}[/tex]

∴

The general solution is:

[tex]y(x) = y_1(x) + y_2(x) + y_3(x) = \dfrac{c_1}{c^{(6-i)}x}+\dfrac{c_2}{c^{(6+i)}x}+ c_3e^{3x}[/tex]

Using Euler's Identity ;

[tex]e^{\alpha+i \beta} = e^\alpha \ cos (\beta ) + i \ e^\alpha \ sin ( \beta)[/tex]

[tex]y(x) = c_1 ( \dfrac{cos (x) }{e^{6x}}+ \dfrac{i \ sin x }{e^{6x} }) + c_2 ( \dfrac{cos (x)}{e^{6x}}- \dfrac{-i \ sin (x)}{e^{6x}})+c_3 e^{3x}[/tex]

[tex]\mathbf{y(x) = \dfrac{(c_1 + c_2) \ cos (x)}{e^{6x} }+ \dfrac{i(c_1 -c_2) \ sin (x)}{e^{6x}}+ c_3e^{3\ x}}[/tex]

HELP PLSSSSS AAAAAAAAAAAAAAAAAAAAAA ILL GIVE BRAINLIEST B(

Answers

Answer:

a(n) = (3/5)a(n-1), where a(1) = 10 and n is 2 or greater.

Step-by-step explanation:

determine the common factor...The first term (10) by 3/5 results in the given second term (6); the third term is 3/5 of the second term (6), resulting in 18/5 (equivalent to 36/10 or 3.6/1, or just 3.6. Resulting in a(n) = (3/5)a(n-1).

the third term is 3.6, which, if mult. by (3/5), produces 2.16, as expected.

Thus, the recursive formula for this geometric sequence is a(n) = (3/5)a(n-1).

This is good only for a(1) = 10 and n = 2, 3, ....

Hope this helps you

Answer: