8
If you put 100 carbon atoms in a box. How many carbon atoms remain after 2 half-lives or
11460 years? (you might need to review half-lives to answer this question) *
(1 Point)
100 atoms
50 atoms
25 atoms
12 atoms

Answers

Answer 1

Answer:

25 atoms

Explanation:


Related Questions

NEED HELP ASAP!!!!
problem is shown in the attached image

Answers

Answer:

im sorry but what is the question please tell me in the comments s i can help you

Explanation:

What is it called when we have two gears connected by a chain in when large gear turns wants to small gear turns two or more times

Answers

You have to make sure you don’t use the first gear any more to be able to use the

which two technologies use waves to determine the location and velocity of objects
Lenses
X Rays
Sonar
Radar

Answers

One of the answers is X rays

Answer: sonar and radar

Explanation:

Picture

Witch statement about electric force is true?

Answers

Please give me the statement :)

Why does it make sense that a 9 Liter pot of boiling water has more heat than a 1.5 L pot of boiling water?

Answers

Explanation:

because 9 is more than 1.5 and the more water, the more heat

PLEASE HELP!!!!!!!!!

Answers

I think it’s Malleability

F = M x G

Find the force of gravity acting upon a 1500Kg Hippopatamus.

Answers

Answer:........... .. .....

I will mark brainliest !!

Answers

Answer:

i think its b

Explanation:

A skier rides horizontally off of a 200 meter high cliff. If he lands 25 meters away from the base of the cliff, how fast was he skiing as he went off the edge?

A. 0.91 m/s
B. 2.91 m/s
C. 3.91 m/s
D. 25.91 m/s

Answers

Answer:

the answers, the correct one is C,   v₀ₓ = vₓ = 3.91 m / s

Explanation:

This is a projectile launching exercise, in this case they indicate that when leaving the cliff it goes horizontally, therefore the initial vertical speed is zero, let's find the time to reach the base

        y = y₀ + [tex]v_{oy}[/tex] t - ½ g t²

at the base the height is zero (y = 0 m)

        0 = y₀ + 0 - ½ g t²

         t = √ (2y₀ / g)

         

we calculate

        t = √ (2 200 / 9.8)

        t = 6.389 s

with this time we calculate the horizontal speed

        v₀ₓ = x / t

        v₀ₓx = 25 / 6,389

        v₀ₓ = vₓ = 3.91 m / s

When checking the answers, the correct one is C

An airplane flies north at 300.0 km/h relative to the air and the wind is blowing south at 15.0 km/h. What is the airplane’s velocity relative to the ground? *

315 km/h North
15 km/h south
285 km/h North
300 km/h South

Answers

Answer:

285

Explanation:

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can somone pls help me??!! i’m very stuck

Answers

Answer:

b

Explanation:

A 5 kg ball is sitting on the floor without moving. What is the momentum of the ball?

Answers

Answer:

The ball has no momentum

Explanation:

The given parameters are;

The mass of the ball = 5 kg

The velocity of the ball = 0 (The ball is sitting on the floor without moving)

The momentum of the ball = The mass of the ball × Velocity of the ball

Therefore, the momentum of the ball = 5 kg × 0 m/s = 0

The momentum of the ball is zero, the ball has no momentum.

Which image shows both potential and kinetic energy?

A swing hangs straight down from a frame.

A swing hangs from a frame out at a 45 degree angle.

A swing hangs from a frame out at a 90 degree angle.

Answers

Answer:

The one in the middle

Explanation: i listened to the other person and i got it wrong, this is the answer for edge2020 sience review on energy!!!!

trust me its the middle one!!!!!

And everyone if ur not sure, like 100% sure about an answer dont answer at all cuz for 1: ur taking up a spot for others to answer. for 2: you could make people wrong. And for 3: its annoying. And 4: it makes stuff like this happen!

NOT ARGUEING IM JUST PUTTING MY THOUGHTS AND OPINIONS OUT THERE ;) many thanks.

Answer:

B. 45 degree

Explanation:

The sodium-potassium pump moves blank ions into the cell and blank ions out of the cell.

Answers

potassium ions into the cell and

outside

⇒ sodium ions out of the cell.

Question 13 (1 point)
The genetic material of an offspring of sexually reproducing organisms is best described as-
a
Ob
identical to that of the other offspring
a copy of the genetic material of the father.
a copy of The genetic material of the mother
genes from both parents, in unique combinations
ос
Od

Answers

genes from both parents, in unique combinations

The genetic material of an offspring of sexually reproducing organisms is best described as genes from both parents in unique combinations.

SEXUAL REPRODUCTION:

Sexual reproduction is a type of reproduction that involves two organisms (a male and a female).

The male organism produces a gamete called SPERM while the female organism produces a gamete called EGG. The gametes are produced via a process called MEIOSIS.

Meiosis is a process of cell division whereby genetically different daughter cells are produced. The genetic variation is attributed to a process called crossing over, which is the exchange of genetic material between non-sister chromatids of homologous chromosomes.

At the end of the fertilization process between male sperm and female egg, the genetic material of the offspring will contain genes from both parents in unique combinations.

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What is Humpty Dumpty's momentum if he has a mass of 56kg and is walking to the wall at a rate of 3 m/s? ​

Answers

Answer:

168

Explanation:

56 x 3

have a nice day

The space shuttle slows down from 1200 km/hr to 400 km/hr over 10 seconds. What is the space shuttles deceleration?

Answers

That's if the answer should be in m/s2.

A beam of electrons moving with a velocity Of 101 m/s
enters midway between two horizontal parallel plates which
Que 5cm long. 2cm apart and have pod Of V volt
applied between them - Calculate v if the beam is deflected
so that it just grazes the edge of the lower plate.(e/m = 1.8×10^11 c/kg)​

Answers

Answer:

Explanation:

electrical field in vertical direction = V / .02  , .02 is distance between plate and V is potential difference .

force on electrons = V x e / .02

acceleration of falling electrons

= V x e /( .02  x m )

= 50 x 1.8 x 10¹¹ V

a = 9 x 10¹² V .

Time to cover length of plate

t = .05 / 10⁷ = 5  x 10⁻⁹ s ,      velocity of electron = 10⁷ m /s .

vertical distance covered by electron s = .01 m with acceleration a in time t

s = 1/2 a t²

.01 = .5 x 9  V  x 10¹²  x ( 5 x 10⁻⁹ )²

10⁻² = 4.5 x 25  x 10⁻¹⁸ x 10¹² V

V = 10⁴ /  (4.5 x 25)

= 88.89 Volt .

An objec with a mass of 7 kg accelerates 5m/s2 when an unknown force is applied to it.what is the magnitude of the unknown force?

Answers

Answer:

35 N

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 7 × 5

We have the final answer as

35 N

Hope this helps you

Can two spheres of different diameters and different
masses have the same moment of inertia?

Answers

Answer:

NO

Explanation:

I=mr^2 this means moment inertia depends upon mass and square of radius or distance.

During a tennis match, a player serves the ball at 23.6 m/s, with the center of the ball leaving the racquet horizontally 2.37 m above the court surface. The net is 12 m away and 0.90 m high. When the ball reaches the net,
(a) does the ball clear it and
(b) what is the distance between the center of the ball and the top of the net? Suppose that, instead, the ball is served as before but now it leaves the racquet at 5.00° below the horizontal. When the ball reaches the net,
(c) does the ball clear it and
(d) what now is the distance between the center of the ball and the top of the net?

Answers

Answer:

a

Yes it clears

b

 [tex]b= 0.19 \ m[/tex]

c

 No it does not clear

d

[tex]z= 0.86 \ m[/tex]

Explanation:

From the question we are told that

  The speed at which the player serves the ball is [tex]v = 23.6 \ m/s[/tex]

  The height of the ball above the ground is  [tex]h = 2.3 7 \ m[/tex]

  The distance of the net is  [tex]d = 12 \ m[/tex]

   The height of the net is [tex]H = 0.9 \ m[/tex]

Generally the time taken for the ball to reach the net is mathematically represented as

     [tex]t = \frac{d}{v}[/tex]

=>  [tex]t = \frac{12}{23.6}[/tex]

=>  [tex]t = 0.508 \ s[/tex]

Generally the change in height of the ball after t is mathematically represented as

     [tex]\Delta h = ut + \frac{1}{2} gt^2[/tex]

Here u is the initial velocity which is zero given that the ball was at rest initially

So

     [tex]\Delta h = 0* t + \frac{1}{2} * 9.8 * 0.50 8^2[/tex]

=>  [tex]\Delta h =1.28 \ m[/tex]

Generally the new height of the ball is mathematically evaluated as

      [tex]s= h-\Delta h[/tex]

=>   [tex]s = 2.37 - 1.28[/tex]

=>   [tex]s = 1.09 \ m[/tex]

From the value obtained we see that [tex]s > H[/tex] hence the ball clears the net

Generally the distance between the center of the ball and the top of the net is mathematically represented as

      [tex]b = s - H[/tex]

=>   [tex]b = 1.09 - 0.90[/tex]

=>   [tex]b= 0.19 \ m[/tex]

Given that the ball makes an angle of [tex]5^o[/tex] with the horizontal  , the velocity along the x-axis is  

      [tex]v_x = v cos(5)[/tex]

=>   [tex]v_x = 23.6 cos(5)[/tex]

=>   [tex]v_x = 23.5 \ m/s[/tex]

The velocity along the y-axis is  

      [tex]v_y = v sin(5)[/tex]

=>   [tex]v_y = 23.6 sin(5)[/tex]

=>   [tex]v_y = 2.06 \ m/s[/tex]      

Generally the time taken for the ball to reach the net is

      [tex]t = \frac{d}{v_x}[/tex]

=>   [tex]t = \frac{12}{23.5}[/tex]

=>   [tex]t =0.508 \ s[/tex]

Generally the change in height of the ball after t seconds is  

     [tex]c = v_yt + \frac{1}{2}gt^2[/tex]

=>  [tex]c = 2.06 * 0.508 + \frac{1}{2}* 9.8 * 0.508 ^2[/tex]

=>  [tex]c = 2.33[/tex]

Generally the new height of the ball after time t seconds is  

     [tex]e = h - c[/tex]

=>   [tex]e = 2.37 - 2.33[/tex]

=>   [tex]e = 0.04 \ m[/tex]

From the value obtained we see that [tex]e < H[/tex] hence the ball does not clear the net

Generally the distance between the center of the ball and the top of the net is mathematically represented as

      [tex]z = H-e[/tex]

=>   [tex]z = 0.90 - 0.04[/tex]

=>   [tex]z= 0.86 \ m[/tex]

   

(a) Yes, the ball clears the net.

(b) The distance between the center of the ball and the top of the net is 0.203 m.

(c) No, the ball does not clear the net.

(d) Now, the distance between the center of the ball and the top of the net is -0.85 m.

What is a Projectile motion?

When any object or body is launched with some initial velocity and making some angle with the horizontal, the body travels in a parabolic path. It is known as the projectile motion.

Given,

The horizontal distance traveled by the ball is 12 m.

The height of the top of the net is 0.90 m.

The height of the horizontal launch of the ball is 2.37 m.

The time for the horizontal motion of the projectile that is the ball is,

[tex]\begin{aligned} {{v}_{0x}}&={{S}_{x}}t \\ t&=\dfrac{{{S}_{x}}}{{{v}_{0x}}} \\ &=\dfrac{{{S}_{x}}}{{{v}_{0}}\cos 0{}^\circ } \\ &=\dfrac{{{S}_{x}}}{{{v}_{0}}} \end{aligned}[/tex]

The equation for the vertical motion of the projectile can be solved by substituting the above result.

[tex]\begin{aligned} y&={{y}_{0}}+{{v}_{0y}}t-\frac{1}{2}g{{t}^{2}} \\ y&={{y}_{0}}+\left( {{v}_{0}}\sin 0{}^\circ \right)\left( \frac{{{S}_{x}}}{{{v}_{0x}}} \right)-\frac{1}{2}g{{\left( \frac{{{S}_{x}}}{{{v}_{0x}}} \right)}^{2}} \\ \left( 0.90\text{ m}+h \right)&=\left( 2.37\text{ m} \right)+0-\frac{1}{2}\left( 9.8\text{ m/}{{\text{s}}^{2}} \right){{\left( \frac{12\text{ m}}{23.6\text{ m/s}} \right)}^{2}} \\ h&=2.37\text{ m}-\text{1}\text{.267 m}-0.90\text{ m} \\ &=0.203\text{ m} \end{aligned}[/tex]

Now, consider the case when the ball is thrown with an angle [tex]\bold{5^{\circ}}[/tex] with the horizontal.

The horizontal component of the initial velocity is [tex]\bold{v_0 \cos 5{}^\circ.}[/tex]

The vertical component of the initial velocity is [tex]\bold{v_0 \sin 5{}^\circ.}[/tex]

For the horizontal distance traveled by the ball in this case, the time taken can be calculated as below,

[tex]\begin{aligned} {t}'&=\frac{{{{{S}'}}_{x}}}{{{{{v}'}}_{0x}}} \\ &=\frac{12\text{ m}}{\left( 23.6\text{ m/s} \right)\cos 5{}^\circ } \\ &=0.51\text{ s} \end{aligned}[/tex]

Now, the vertical distance above the ground, y’, traveled by the projectile till reaching the net can be determined as,

[tex]\begin{aligned} {y}'&={{{{y}'}}_{0}}+{{{{v}'}}_{0y}}{t}'-\frac{1}{2}g{{{{t}'}}^{2}} \\ &=0\text{ m}-\left( \left( 23.6\text{ m/s} \right)\sin 5{}^\circ \right)\left( 0.51\text{ s} \right)-\frac{1}{2}\left( 9.8\text{ m/}{{\text{s}}^{2}} \right){{\left( 0.51\text{ s} \right)}^{2}} \\ &=-1.05\text{ m}-1.28\text{ m} \\ &=-2.32\text{ m} \end{aligned}[/tex]

The height above the top of the net can be determined by adding the above result with (2.37 m - 0.90 m) which is the height of the net’s top relative to the launch position.

[tex]\begin{aligned} {h}'&=\left( 2.37\text{ m}-0.90\text{ m} \right)+{y}' \\ &=\left( 2.37\text{ m}-0.90\text{ m} \right)-2.32\text{ m} \\ &=-0.85\text{ m} \end{aligned}[/tex]

Thus, the distance between the center of the ball and the top of the net is -2,32 m.

When the ball leaves the racquet at 5.00° below the horizontal, the distance between the center of the ball and the top of the net is -0.85 m.

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Explain why clear-cutting is a more destructive method of wood harvesting than selective cutting.

Answers

Answer:

Clear-cutting eliminates all trees leaving none behind to maintain soil fertility or house native animals.

Explanation:

edge 2022

A forestry/logging practice known as clear-cutting, clear felling, or clear-cut logging involves consistently cutting down the majority or all of the trees in a given region. Foresters utilize it to cultivate particular types of forest ecosystems and to advance particular species, in addition to harvesting shelter wood and seed trees.

What is deforestation?

The removal of a forest or tree stands from land before it is used for a purpose other than as a forest is known as deforestation or clearing of forests. The use of forest land for urban, agricultural, or ranch purposes is referred to as deforestation. In tropical rainforests, there is the greatest concentration of deforestation. Forests currently cover about 31% of the Earth's land area. With half of that loss occurring in the previous century, this is a third less forest cover than there had before agriculture's growth.

As a result of clear-cutting, no trees are left to protect the topsoil or serve as a haven for wildlife. In turn, this causes soil erosion and soil fertility to be destroyed, as well as the removal of the trees required to produce seeds for natural forest development to continue. Animal populations are also pushed out of their natural habitats by clear-cutting, forcing them to look for new homes.

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Christina drives her moped 7 kilometers North. She stops for lunch and then drives 5 kilometers East.

What distance did she cover? Please include the number and unit.

What was the magnitude of her displacement? Please include the number and unit.

What was the direction of her displacement? Please abbrieviate (N, S, E, W, etc.)

Answers

Explanation:

Given that,

Christina drives her moped 7 kilometers North. She stops for lunch and then drives 5 kilometers East. At first she traveled North and then East. They are perpendicular to each other.

Total path traveled = distance covered by an object

D = 7 km + 5 km = 12 km

Shortest path covered = Displacement

[tex]d=\sqrt{7^2+5^2} \\\\d=8.6\ km[/tex]

For direction :

[tex]\tan\theta=\dfrac{d_y}{d_x}\\\\\tan\theta=\dfrac{7}{5}\\\\\theta=\tan^{-1}(\dfrac{7}{5})\\\\\theta=54.46^{\circ}[/tex]

She is moving in the direction of 54.46 degrees.

Select all the correct answers.
Which situations describe an elastic collision?
(A) Two glass marbles bounce off each other.
(B) Rodrick flops onto his sofa and sinks into the cushion.
(C) A tossed water balloon flattens when it lands on the grass.
D) A bowling ball knocks over five pins.

Answers

I believe there are two correct answers, and those answers are A and D

What is the difference
between interplanting and intercropping?

Answers

Answer:

Interplanting is the practice of planting a fast-growing crop between a slower-growing one to make the most of your garden space. ... Intercropping enables you to boost the health of all plants because it can enhance soil fertility and cooperation among different plants.

Intercropping refers to large, often commercial, farming operations and is the procedure of planting alternating crop rows. Growing two or more crops in close proximity is known as intercropping.

What is interplanting?

Starting to grow two or more crops in close vicinity is known as intercropping.

The most common goal of intercropping is to increase yield on a given plot of land by utilizing resources that would otherwise go unused by a single crop.

Intercropping is the cultivation of more than one crop in the same space at the same time. Intercropping is the simultaneous planting of two or more species in a mixture, or the interplanting of one species during the growth of another.

The terms are frequently and regionally used interchangeably. Intercropping is the practice of planting alternating crop rows in large, often advertising, farming operations.

Thus, this is the difference between intercropping and interplanting.

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An airplane is flying with velocity of 70km\hr in north east direction .The wind is blowing 30km\hr from north to south.What is the resultant displacement of the aeroplane in 4 h

Answers

Answer:

The resultant displacement of the airplane in 4 hours is 212.8 km.

Explanation:

The components of the airplane's velocity and wind's velocity are:

Airplane:

[tex] v_{a_{x}} = v_{a}cos(45) = 70 km/h*cos(45) = 49.50 km/h [/tex]

[tex] v_{a_{y}} = v_{a}sin(45) = 70 km/hsin(45) = 49.50 km/h [/tex]

Wind:

[tex] v_{w_{x}} = 0 [/tex]

[tex] v_{w_{y}} = v_{w} = -30 km/h [/tex]

Now, to know the new velocity of the airplane we to find the result vector:

[tex] v_{x} = v_{a_{x}} + v_{w_{x}} = 49.50 km/h + 0 = 49.50 km/h [/tex]

[tex]v_{y} = v_{a_{y}} + v_{w_{y}} = 49.50 km/h - 30 km/h = 19.50 km/h[/tex]  

Now, the magnitude of the new speed of the airplane is:

[tex] v_{a} = \sqrt{v_{x}^{2} + v_{y}^{2}} = \sqrt{(49.50 km/h)^{2} + (19.50 km/h)^{2}} = 53.20 km/h [/tex]

Finally, after 4 hours the resultant displacement of the airplane is:

[tex] x = v*t = 53.20 km/h*4 h = 212.8 km [/tex]

Therefore, the resultant displacement of the airplane in 4 hours is 212.8 km.

I hope it helps you!                                        

a 5 kg mass is accelerated at a rate of 2.5 m/s/s. what is the force that is exerted on this object

Answers

Answer:

12.5 N

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 5 × 2.5

We have the final answer as

12.5 N

Hope this helps you

I need help I do test I scared

Answers

Answer:

i think the answer is #3. :)

A stone falls freely from rest for 8.0s what is it final velocity

Answers

Is that the full question?

A 4 kg jug of juice is pulled forward across a horizontal breakfast table, by a 12 N forward-directed force. A frictional force also impedes the jug's motion. What is the coefficient of kinetic friction between the table and jug, if the jug accelerates to the right at 2 m/s^2 ?

A 0.08
B 0.1
C 0.2
D 0.3

Answers

Answer:

0.1

Explanation:

According to equation of motion;

\sum F = ma

m is the mass of the body

a is the acceleration

\sum F = Fm - Ff (along the horizontal)

Fm is the moving force

Ff is the frictional force

Given;

Fm = 12N

Ff = nR = nmg

Ff = n(4)(9.8)

Ff = 39.2n

Substitute the given value into the expression above;

Fm - Ff = ma

12 - 39.2n = 4(2)

-39.2n = 8-12

-39.2n = -4

n = 4/39.2

n = 0.1

Hence the coefficient of kinetic friction between the table and jug is 0.1

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