Answer:
a. 2 kg*m/s
b. [tex]p_{T_{f}} = 0.5v_{f} = 2 kg*m/s[/tex]
c. 4 m/s
Explanation:
a. The momentum of the system ([tex]p_{Ti}[/tex]) before the blob of clay strikes the cart is:
[tex] p_{Ti} = p_{b} + p_{c} [/tex]
Where:
[tex]p_{b}[/tex] is the momentum of the blob clay
[tex]p_{c}[/tex] is the momentum of the car
[tex] p_{Ti} = m_{b}v_{b} + m_{c}v_{c} [/tex]
Since the car is initially at rest, [tex]v_{c}[/tex] = 0
[tex] p_{Ti} = 200 g*\frac{1 kg}{1000 g}*10 m/s + 0 = 2 kg*m/s [/tex]
b. The momentum of the system after they come together:
[tex]p_{T_{f}} = m_{b}v_{b} + m_{c}v_{c}[/tex]
Since they come together, [tex]v_{b}[/tex] =
[tex]p_{T_{f}} = v_{f}(m_{b} + m_{c}) = v_{f}(0.2 kg + 0.3 kg) = 0.5v_{f}[/tex] (1)
Because we do not have the final speed we can not calculate the final momentum.
c. We can find the speed of the clay and car by conservation of the momentum:
[tex] p_{i} = p_{f} [/tex]
The initial momentum of the system was founded in part "a" (p = 2 kg*m/s), so we have:
[tex] 2 kg*m/s = m_{b}v_{b_{f}} + m_{c}v_{c_{f}} [/tex]
Again, when they come together, the final speed is the same:
[tex] 2 kg*m/s = v_{f}(m_{b} + m_{c}) [/tex]
[tex] v_{f} = \frac{2 kg*m/s}{0.2 kg + 0.3 kg} = 4 m/s [/tex]
Now, since we found the final speed we can calculate the momentum of the system after they come together (equation 1):
[tex] p_{T} = 0.5v_{f} = 0.5 kg*4m/s = 2 kg*m/s [/tex]
I hope it helps you!
A water tank is filled with up to 3.5 m height.Calculate the pressure given by the tank at its bottom
Answer:
96.04Pa
Explanation:
height=3.5m
gravity=9.8%
density=9.8/3.5
=2.8
Preassure=h×g×d
=3.5×9.8×2.8
=96.04Pa
Water boils at 212°F. Which temperature is an equivalent temperature?
[tex]\mathrm {Hey, there!}[/tex]
Let's solve your problem:
We will convert your number, 212°F, to Kelvin and Celsius.
212°F is equal to 100° Celsius.
Now, let's do the Kelvin convert.
To convert Celsius to Kelvin, we have to add 273.5 to the amount of Celsius.
100° + 273.5 = 373.5
We have all our conversions. Finally, let's set them out.
Fahrenheit: 212°F
Celsius: 100°C
Kelvin: 373.5°K
it is harmful to settle near the airport why
005 (part 1 of 2) 10.0 points
A runner is jogging in a straight line at a
steady vr= 8.5 km/hr. When the runner is
L=6.4 km from the finish line, a bird begins
flying straight from the runner to the finish
line at vý= 17 km/hr (2 times as fast as the
runner). When the bird reaches the finish
line, it turns around and flies directly back to
the runner
What cumulative distance does the bird
travel? Even though the bird is a dodo, as-
sume that it occupies only one point in space
(a "zero" length bird). travels in a straight
line, and that it can turn without loss of
Speed
Answer:
7.53 km
Explanation:
We at given;
Speed of runner; v_r = 8.5 km/hr
Speed of bird; v_y = 17 km/hr
L = 6.4 km
We know that; time = distance/speed.
We are told that the bird starts from 6.4 km from the start and that it flies back to meet the runner after it reaches the finish line. If the total distance back to the runner is x, it means bird distance is 6.4 + (6.4 - x) = 12.8 - x
Thus;
Time of bird(t_y) = (12.8 - x)/17
Thus,
Time of runner(t_r) = x/8.5 hr
To find x, we have to equate the times of the runner and the bird.
Thus;
x/8.5 = (12.8 - x)/17
Multiply both sides by 17 to get;
2x = 12.8 - x
2x + x = 12.8
3x = 12.8
x = 12.8/3
x = 4.27 km
Thus, cumulative distance traveled by bird is; 12.8 - 4.27 = 7.53 km
Which of the following equations is balanced?
a. 2Al2O3 -----> 3Al + 3O2
b. 3Al2O3 -----> 3Al + 2O2
c. 2Al2O3 -----> 4Al + 3O2
d. 2Al2O3 -----> Al + 3O2
Answer: c
Explanation:
The way to check which one is the correct one is to simply multiply and see if there are the same number of atoms in both sides for each element.
a. 2×2 atoms of Al ≠ 3×1 atoms of Al
2×3 atoms of O = 3×2 atoms of O
BOTH MUST BE EQUAL FOR IT TO BE ADJUSTED!!!!!
b. 3×2 atoms of Al ≠ 3×1 atoms of Al
3×3 atoms of O ≠ 2×2 atoms of O
c. 2×2 atoms of Al = 4×1 atoms of Al
2×3 atoms of O = 3×2 atoms of O
BOTH ARE EQUAL, CORRECT ANSWER!!!
d. 2×2 atoms of Al ≠ 1×1 atoms of Al
2×3 atoms of O = 3×2 atoms of O
I need help, worth 40 Points!
A plane flies due north (90° from east) with a velocity of 100 km/h for 3 hours. During this time, a steady wind blows southeast at 30 km/h at an angle of 315° from due east. After 3 hours, where will the plane’s position be relative to its starting point?
*Please try to fill the data table.
Answer:
thank you
Explanation:
Split up the two given velocity vectors into horizontal and vertical components.
Plane:
p = (100 km/h) (cos(90°) i + sin(90°) j ) = (100 km/h) j
Its direction is given, 90° relative to east.
Traveling for 3 hours with this velocity results in a displacement of
p * (3 h) = (300 km/h) (3h) j = (900 km) j
meaning that this velocity contributes to a north-facing displacement of 900 km.
Wind:
w = (30 km/h) (cos(315°) i + sin(315°) j ) ≈ (21.2 km/h) i + (-21.2 km/h) j
Its direction is also given, 315° relative to east.
After 3 h, this velocity contributes to a displacement of
w * (3h) ≈ (63.6 km) i + (-63.6 km) j
meaning if the plane had no velocity of its own but somehow stayed in the air, the wind would have pushed it about 63.6 km south and 63.6 km east, which translates to a net displacement of
√((63.6 km)² + (-63.6 km)²) = 90 km
due southeast.
Putting everything together, your table displacement table should read:
. | wind | plane
velocity | 30 | 100 ... km/h
direction | 90° | 315° ... relative to east
x | 63.6 | 0 ... km
y | -63.6 | 900 ... km
The resultant vector is the sum of these, r = p + w :
r ≈ (21.2 km/h) i + (78.8 km/h) j
After 3 h, the resultant displacement is
r * (3h) ≈ (63.6 km) i + (236.4 km) j
with magnitude
√((63.6 km)² + (236.4 km)²) ≈ 244.8 km
and direction θ such that
tan(θ) ≈ (236.4 km) / (63.6 km)
θ ≈ arctan(3.714) ≈ 74.9°
So the resultant table should read
xnet | 63.6 km
ynet | 236.4 km
magnitude | 244.8 km
theta | 74.9° relative to east
Please help me fast
Answer:
b I think. sorry if it's wrong
A submarine is built to dive to a depth of 90 m where the pressure in the water is about 1 MPa. The engineers want to build a window in the submarine, but the window can only take a force of 10 kN safely. What is the largest surface area window that can be used?
Answer:
The largest surface area window that can be used is [tex]A=0.01\ m^2[/tex]
Explanation:
Pressure
The pressure is defined as force per unit area. The SI unit for pressure is the Pascal (Pa), defined as Newton per square meter.
If a force F acts on a surface area A, the pressure is calculated as:
[tex]\displaystyle P=\frac{F}{A}[/tex]
The pressure at a depth of 90 m is P=1 Mpa= 1,000,000 Pa and the submarine's window can only take a force of F=10 kN=10,000 N.
We need to calculate the largest surface area of the window. We can solve the equation for A:
[tex]\displaystyle A=\frac{F}{P}[/tex]
Substituting:
[tex]\displaystyle A=\frac{10,000}{1,000,000}[/tex]
[tex]A=0.01\ m^2[/tex]
The largest surface area window that can be used is [tex]\mathbf{A=0.01\ m^2}[/tex]
Can someone Plzzz help meee.
solid...............
what is electricity
Answer:
Electricity is the flow of electrical power or charge. It is a secondary energy source which means that we get it from the conversion of other sources of energy, like coal, natural gas, oil, nuclear power and other natural sources, which are called primary sources.
On Planet X, an astronaut has maximum walking speed of 1.9 m/s. The astronaut's legs are each 1.3 m long. What is the constant of acceleration due to gravity on Planet X?
A. 8.3 m/s2
B. 2.8 m/s2
C. 3.8 m/s2
D. 1.1 m/s2
Answer:
Acceleration due to Gravity:
Explanation:
Here g is acceleration due to gravity. So C. 3.8 m/s2
Classify each resource as renewable or nonrenewable.
Answer:
coal: nonrenewable
geothermal energy: renewable
wind: renewable
natural gas: nonrenewable
Explanation:
Have a good day
Thanks
Answer:
coal is non-renewable, the wind is renewable, I belive natural gas is not but I'm not to sure with that one. geothermal energy is renewable.
Explanation:
List the three astronomical causes for the seasons
11. The professor who first
implemented a scientific approach in
order to investigate a problem, and
who is often referred to as ‘the father
of scientific methodology’, is:
a. Galileo
b. Democritus
c. Newton
d. Einstein
12. Which of the following adjustments
to a pendulum would affect the
period of oscillation?
a. Increasing the mass
b. Decreasing the length
c. Increasing the length
d. Increasing the angle of
displacement
13. The width of a desk was measured
using a meter ruler, which of the
following is the most appropriate
reading expressing the result?
a. 0.724 m
b. 0.7248 m
c. 0.72 m
d. 72 cm
Answer:Newton
Explanation:
Lead-202 has a half-life of 53,000 years. How long will it take for 15/16 of a sample of lead-202 to decay?
106,000 years
159,000 years
212,000 years
265,000 years
(Thank you very much :L)
Answer:
C. 212,000 years
Explanation:
believe me it's correct.....and you're welcome :)
for which colour of light is. the index of refraction of glass largest
Answer:
don't know sorry for the irreverent answer..
Answer:
The index of refraction varies with frequency, it doesn't change as light travels from one medium to another, As violet colour has the shortest wavelength and so the refractive index is maximum for it.
A sample contains 20 kg of radioactive material. The decay constant of the material is 0.179 per second. If the amount of time that has passed
is 300 seconds, how much of the of the original material is still radioactive? Show all work
Answer:
There are [tex]9.537\times 10^{-23}[/tex] kilograms of radioactive material after 300 seconds.
Explanation:
From Physics we know that radioactive materials decay at exponential rate, whose differential equation is:
[tex]\frac{dm}{dt} = -\lambda\cdot m[/tex] (1)
Where:
[tex]\frac{dm}{dt}[/tex] - Rate of change of the mass of the radioactive material, measured in kilograms per second.
[tex]m[/tex] - Current mass of the radioactive material, measured in kilograms.
[tex]\lambda[/tex] - Decay constant, measured in [tex]\frac{1}{s}[/tex].
The solution of the differential equation is:
[tex]m(t) = m_{o}\cdot e^{-\lambda\cdot t}[/tex] (2)
Where:
[tex]m_{o}[/tex] - Initial mass of the radioactive material, measured in kilograms.
[tex]t[/tex] - Time, measured in seconds.
If we know that [tex]m_{o} = 20\,kg[/tex], [tex]\lambda = 0.179\,\frac{1}{s}[/tex] and [tex]t = 300\,s[/tex], then the initial mass of the radioactive material is:
[tex]m(t) = (20\,kg)\cdot e^{-\left(0.179\,\frac{1}{s} \right)\cdot (300\,s)}[/tex]
[tex]m(t) \approx 9.537\times 10^{-23}\,kg[/tex]
There are [tex]9.537\times 10^{-23}[/tex] kilograms of radioactive material after 300 seconds.
A diver runs horizontally off the end of a diving board with an initial speed of 1.95 m/s. If the diving board is 2.00 m above the water, what is the diver's speed just before she enters the water
Answer:
V = 6.56 m/s
Explanation:
in order to find the speed of the diver before she enters we need to find the vertical component of its final velocity by using 3rd equation of motion:
2gh = Vy² - V₀y²
where,
g = 9.8 m/s²
h = height = 2 m
Vy = Vertical Component of Final Velocity = ?
V₀y = Vertical Component of Initial Velocity = 0 m/s
Therefore,
2(9.8 m/s²)(2 m) = Vy² - (0 m/s)²
Vy = √39.2 m²/s²
Vy = 6.26 m/s
Assuming negligible air friction, the x-component of the final velocity will be the same as the initial velocity:
Vₓ = V₀ₓ = 1.95 m/s
Hence, the final velocity will be:
V = √(Vₓ² + Vy²)
V = √[(1.95 m/s)² + (6.26 m/s)²]
V = 6.56 m/s
The components of a 15-meters-per-second velocity at an angle of 60.° above the horizontal are (1) 7.5 m/s vertical and 13 m/s horizontal (2) 13 m/s vertical and 7.5 m/s horizontal (3) 6.0 m/s vertical and 9.0 m/s horizontal (4) 9.0 m/s vertical and 6.0 m/s horizontal
Answer:
13 m/s vertical and 7.5 m/s horizontal
Explanation:
❤️
The vertical and horizontal components of a projectile is required.
The correct option is (2) 13 m/s vertical and 7.5 m/s horizontal
u = Initial velocity of projectile = 15 m/s
[tex]\theta[/tex] = Angle of projectile = [tex]60^{\circ}[/tex]
The horizontal component
[tex]u_x=u\cos \theta\\\Rightarrow u_x=15\cos60^{\circ}\\\Rightarrow u_x=7.5\ \text{m/s}[/tex]
The vertical component
[tex]u_y=u\sin \theta\\\Rightarrow u_x=15\sin60^{\circ}\\\Rightarrow u_x=13\ \text{m/s}[/tex]
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What is an electromagnetic wave?
A. An induced electric current
B. Vibrating electric and magnetic fields
C. Oscillating electric current
D. An electromagnet
2. An object is moving with an initial velocity of 12 m/s. It accelerates at a rate of 1.5 m/s^2 over a distance of 40 m. What is its new velocity?
Answer:
16.2 m/s
Explanation:
2ad=Vf^2-Vi^2
2 (1.5) (40) = Vf^2 -(12)^2
Vf= 16.2 m/s
When an 8 V battery is connected to a resistor, a 2 A current flows in the resistor. What is the resistor's value?
Ο Α. 2Ω
Ο Β. 4 Ω
Ο C. 8Ω
Ο D. 16 Ω
Answer:
B
Explanation:
V=IR I= curren V=volt R=resistor
8=2.R 8/2=R R=4
A bugatti chiron travels 116 m/s for 10 seconds.how far did it travel
Answer:
V= 1,160 m
Explanation:
formula:
V= V* T
remplazamos:
V= 116m /s * 10s
V= 1,160 m
Answer:
V= 1,160 m
Explanation:
Please identify the type of inference happening at letter A and the type of interference happening at letter B. If this was a sound wave, which (A or B) do you think would be louder and why?
Answer:
B i think
Explanation:
B because it travels in the same wavelentgh.............
[tex]gjkrejktg[/tex]
Type A is constructive interference and Type B wave gives destructive interference. The constructive interference would be louder.
What is interfernece?Interference can be described as a natural phenomenon that occurs at every place and at every moment. Interference can be defined as the phenomenon in which two waves superpose to produce the resultant wave of the lower, higher, or same amplitude. Light waves are produced randomly by most of the sources.
The interference of light from the soap bubble which reflects colors when illuminated by a light source. The starting point of the wave produced may be a maximum or a minimum, and there is no way to predict which phase the wave will start.
Interference can either be constructive interference or destructive interference. Constructive interference occurs when the crest of one wave falls on the crest of another wave and the amplitude is maximum.
In destructive interference, when the crest of one wave falls on the trough of another wave and the amplitude is minimum. The phase and displacement of these waves are not the same.
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What would be the y-component of a velocity vector that had a
magnitude of 37m/s in a direction 30° from the x-axis?
Answer:
18.5 m/s
Explanation:
Just did it on EdPuzzle
The y-component of a velocity vector that had a magnitude of 37 m / s in a direction 30° from the x - axis would be 18.5 m / s .
What is a vector quantity?The quantities that contain the magnitude of the quantities along with the direction are known as the vector quantities.
Examples of vector quantities are displacement, velocity acceleration, force, etc.
As given in the problem we have to find out the y-component of a velocity vector that had a magnitude of 37 m / s in a direction 30° from the x - axis.
The y-component of a velocity vector = 37 × sin 30
= 18.5 m / s
Thus , y-component of a velocity vector that had a magnitude of 37 m / s in a direction 30° from the x - axis would be 18.5 m / s.
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Opal is making a list of the uses of electromagnetic radiation. Which of the following should Opal NOT include in her list?
A. A man using a microwave to boil water
B. A submarine using sonar to locate a ship
C. A girl using a remote control to change television channels
D. A hospital using an X-ray machine to take a picture of a broken bone
Answer:
A.
Explanation:
A man using a microwave to boil water
Answer:
d
Explanation:
A roller coaster is travelling 1 m/s at the top of the track. At the bottom of the track, 5 seconds later, it is travelling 36 m/s. What is the average acceleration?
7.2 m/s2
0.14 m/s2
36 m/s 2
7 m/s2
Answer:
7m/s²
Explanation:
Given parameters:
Velocity at the top = 1m/s
Velocity at the bottom = 36m/s
Time = 5s
Unknown:
Average acceleration = ?
Solution;
Acceleration is the rate of change of velocity with time. It is expressed as;
A = [tex]\frac{v -u}{t}[/tex]
v is the velocity at the top
u is the velocity at the bottom
t is the time taken
Now, insert the parameters and solve;
A = [tex]\frac{36 - 1}{5}[/tex] = 7m/s²
Given values:
Top velocity,
v = 1 m/sBottom velocity,
u = 36 m/sTime,
t = 5 sThe acceleration is:
→ [tex]A = \frac{v -u}{t}[/tex]
By putting the values,
[tex]= \frac{36-1}{5}[/tex]
[tex]= \frac{35}{5}[/tex]
[tex]= 7 \ m/s^2[/tex]
Thus the answer above i.e., "option d" is correct.
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A person with a weight of 120 lbs. is standing on a scale. What force is the
scale exerting on the person? *
O Olbs up
O 60 lbs up
O 120 lbs up
240 lbs up
Those 4 numbers are the answer choices plz help
Answer:
The answer is 120lbs
Explanation:
because the scale exerts enough force to equal out to 0 and since the person is putting 120lbs onto the scale it then pushes back enough force to keep them up
The upward force acting on the body is 534 N which is equal to 240 lbs in the upward direction, hence, option d is correct.
What is force?Force is an external agent acting on a body to change it from the state of motion or rest. There are various kind of forces namely, gravitational force, magnetic force, nuclear force etc.
Gravitational force is the force by which an object attracts other objects to its center of mass. Gravitational force depends on the mass of the object and the distance from the surface of earth.
The weight of the person is 120 lbs.
1 Kg = 2.2 lbs
120 lbs = 54.5 Kg.
The force acting on the body by their weight = mg = 54.5 Kg × 9. 8 m/s².
= 534 N.
Hence, 534 N is 240 lbs (534 /2.2 ) of force upward.
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The average velocity of an object over 6.0 seconds interval is 2 m/s what is the total distance traveled and M by the object doing this time interval
Answer:
The answer is 12 mExplanation:
The distance covered by an object given it's velocity and time taken can be found by using the formula
distance = velocity × time
From the question we have
distance = 2 × 6
We have the final answer as
12 mHope this helps you
A car drives 400 meters in 5 seconds. What is the cars speed in m/s?
Answer:
80/1
Explanation:
to figure out the answer of how many miles/meters per second divide the meters/miles by the second
so 400÷5 would be 80
80 meters per second
hope this helps :))