A 30.0-g object moving to the right at 20.5 cm/s overtakes and collides elastically with a 13.0-g object moving in the same direction at 15.0 cm/s. Find the velocity of each object after the collision. (Take the positive direction to be to the right. Indicate the direction with the sign of your answer.)

Answers

Answer 1

Let m₁ and m₂ be the masses of the two objects, and v₁ and v₂ their initial velocities. So

m₁ = 30.0 g = 0.0300 kg

m₂ = 13.0 g = 0.0130 kg

v₁ = + 20.5 cm/s = 0.205 m/s

v₂ = + 15.0 cm/s = 0.150 m/s

and we want to find v₁' and v₂', the final velocities of either object after their collision.

Momentum is conserved throughout the objects' collision, so that

m₁v₁ + m₂v₂ = m₁v₁' + m₂v₂'

where v₁' and v₂' are the first and second object's velocities after the collision.

Kinetic energy is also conserved, so that

1/2 m₁v₁² + 1/2 m₂v₂² = 1/2 m₁(v₁')² + 1/2 m₂(v₂')²

or

m₁v₁² + m₂v₂² = m₁(v₁')² + m₂(v₂')²

From the first equation (omitting units), we have

0.0300 • 0.205 + 0.0130 • 0.150 = 0.0300 v₁' + 0.0130 v₂'

0.0810 = 0.0300 v₁' + 0.0130 v₂'

81 = 30 v₁' + 13 v₂'

From the second equation,

0.0300 • 0.205² + 0.0130 • 0.150² = 0.0300 (v₁')² + 0.0130 (v₂')²

0.00155 ≈ 0.0300 (v₁')² + 0.0130 (v₂')²

1.55 ≈ 30 (v₁')² + 13 (v₂')²

Solving both equations simultaneously gives two solutions, one of which corresponds to the initial conditions. The other yields

v₁' ≈ + 0.172 m/s

and

v₂' ≈ + 0.227 m/s


Related Questions

Question below...............

Answers

Answer:

friction force

Explanation:

force of friction is opposite to the force applied it resist the motion

Figure 1 shows that the two vectors in different direction respectively. Determine the resultant for the two vectors ​

Answers

Answer:

15-45/2 = -7.5 downwards

Explanation:

cos(60) x 45 = z

z = 45/2

sin (30) x 70 = y

y = 15

15-45/ 2 = -7.5 downwards

20 cm long 10 cm wide and 5 cm thick as a mass of 500 g determine the greatest pressure that can be exerted by block on the flat surface?​

Answers

100000 Pascal

Explanation:

pressure= force/area

Max pressure= force/min area

so f=5

min area= 5×10^-5

5÷5*10^-5 = 100000pascal

A patient comes to an outpatient laboratory for a physician-ordered fasting test. The patient indicates that he forgot that the test was to be fasting and ate a candy bar 2 hours ago. The patient insists that you should draw the test because he cannot come back at another time. What should you do?

Answers

The patient eating a candy bar instead of fasting for the test should be told

that the test results will be wrong and he may receive a wrong diagnosis.

The medical practitioners told him to fast when coming for a reason and he

forgetting and eating something means the objective for the test may have

been defeated.

This is why it's best to explain to him about the consequences of his actions

which is likely getting a wrong result and diagnosis.

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knives, axe ,blades and nails are examples of

Answers

knives, axe ,blades and nails are examples of potential energy

or sharp objects

8. An airplane of mass 8500 kg dives has an altitude of 15,000 m. It then dives steeply to an
altitude of 11,000 m. What was the change in potential energy?

Answers

Answer:

333.5 MJ

Explanation:

ΔV = m·g·Δh

     = 8500 · 9.81 · (15000-11000)

     = 8500 · 9.81 · 4000

     = 333 540 000

     ≈ 333.5 ·10⁶J = 333.5 MJ

The change in potential energy is 333.5 MJ

What is Potential Energy?

Potential energy is defined as the energy possessed by an object because of its position relative to other objects, tension within itself, its electric charge, or other factors. Any object that is raised above its rest position has energy stored in it, so it is called potential energy because it has the potential to do work when released.

It can be expressed as:

P.E.= mgh

where, m is the mass of an object measured in grams 'g'

g is the acceleration due to gravity which is [tex]9.8 m/s^2[/tex]

h is the height measured in meter 'm'

Here,

the given information is

m= 8500kg

Δh= [tex]h_2 - h_1[/tex] = 15000-11000 = 4,000m

So, P.E. = 850 x 9.8 x 4000 = 333 540 000=  333.5 ·10⁶J = 333.5 MJ

Thus, the change in potential energy is 333.5 MJ

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A cylindrical rod formed from silicon is 16.8 cm long and has a mass of 2.17 kg. The density of silicon is 2.33 g/cm3 . What is the diameter of the cylinder

Answers

Answer:

We are given the length, the mass and the density of the cylinder. First let us calculate for the volume by dividing the mass by the density.

volume = mass /density

where mass = 2.17 kg = 2170 g, therefore:

volume = 2170 g / (2.33 g/cm^3)

volume = 931.33 cm^3

 

We know that the volume of a cylinder has the formula:

volume = π r^2 h

since h = 16.8 cm, therefore calculating for radius:

931.33 cm^3 = π r^2 (16.8 cm)

r^2 = 17.646 cm^2

r = 4.2 cm

 

Hence the diameter (d) is:

d = 2 r

d = 8.4 cm

Explanation:

The diameter of the cylindrical rod is approximately 0.382 cm.

To find the diameter of the cylindrical rod, we can use the formula for the volume of a cylinder and then solve for the diameter.

The formula for the volume of a cylinder is:

V = π[tex]r^{2}[/tex]h,

where V is the volume, r is the radius, and h is the height (or length) of the cylinder.

In this case, we know the length of the cylinder (h) is 16.8 cm. We need to find the radius (r) in order to calculate the diameter.

The mass of the cylinder can be related to its volume and density using the formula:

m = ρV,

where m is the mass, ρ is the density, and V is the volume.

Rearranging this formula, we can solve for V:

V = m / ρ.

Now we have two equations:

V = π[tex]r^{2}[/tex]h,

V = m / ρ.

Setting these two equations equal to each other, we can solve for r:

π[tex]r^{2}[/tex]h = m / ρ.

Substituting the given values:

π[tex]r^{2}[/tex] * 16.8 cm = 2.17 kg / (2.33 g/[tex]cm^3[/tex]).

Let's solve this equation for r:

[tex]r^{2}[/tex] = (2.17 kg / (2.33 g/[tex]cm^3[/tex])) / (π * 16.8 cm).

[tex]r^{2}[/tex]  ≈ 0.036775 [tex]cm^2[/tex].

Taking the square root of both sides:

r ≈ 0.191 cm.

Finally, we can find the diameter (d) by multiplying the radius by 2:

d ≈ 2 * 0.191 cm.

d ≈ 0.382 cm.

Therefore, the diameter of the cylindrical rod is approximately 0.382 cm.

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9
are things that you can achieve quickly.
O A.
Dreams
OB.
Long-term goals
O c.
Short-term goals
OD.
Plans

Answers

Answer:

d

Explanation:

A dreams

.......wkkwkwkwkwkwnwnsksk

Answer:

C. short term goal

Explanation:

took a midterm quiz on canvas, Hope this helps <3

1- A soccer ball was kicked from the ground with an initial speed of 12m/s at an
angle 32° above the horizontal. What are the x and y positions of the ball
0.50s after it is kicked?

Answers

Answer:

Y = 0.5 × 6.36 m/s = 3.18 meters

X = 0.5 × 10.18 m/s = 5.09 meters

Explanation:

X and Y components:

Y = 6.36 m/s

X = 10.18 m/s

Position after 0.5 seconds:

Y = 0.5 × 6.36 m/s = 3.18 meters

X = 0.5 × 10.18 m/s = 5.09 meters

The x and y positions of the ball 0.50s after it is kicked are 5.09 meter and  1.95 meter respectively.

What is velocity?

The rate at which a body's displacement changes in relation to time is known as its velocity. Velocity is a vector quantity with both magnitude and direction. SI unit of velocity is meter/second.

Given parameters:

Initial speed of the soccer ball at an angle 32° above the horizontal is: u = 12m/s.

Time interval: t = 0.50 second.

Now, x component of initial velocity = u cosθ = 12 × cos 32° m/s = 10.17 m/s.

y component of initial velocity = u sinθ = 12 × sin32° =6.36 m/s.

Hence,

after 0.50 s, x-position of the ball =  u cosθ t

= 10.17 × 0.50 meter

= 5.09 meter.

after 0.50 s, y-position of the ball =  u sinθ t -gt²/2

= 6.36 × 0.50 - (9.8×0.50²/2) meter

= 1.95 meter.

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PLEASE HELP I NEED TO PASS THIS CLASS ​

Answers

Can you please tell me what is the problem that we need to answer?

Answer:

I think that the answer is 4.318 as a=f/p

QUESTION 5 When an instrument is sounded together with a turning fork of frequency 260Hz , 2 beats are heard. When the same instrument is sounded with a fork of frequency 256H2, , 6 beats are heard. Find the frequency of the instrument .​

Answers

Answer:

Explanation:

4126h2.

Why does the sky appear red and yellow during sunsets.
1. The reds and yellows are caused by the Sun's light having to pass through dust particles near closer to the horizon than when the Sun is higher in the sky.

2. At sunset the prismatic effect of the atmosphere at low angles produces longer red and yellow wavelengths.

3. At sunset blue light is scattered by air molecules at higher altitudes. The longer red and yellow wavelengths must travel further through the atmosphere when the Sun is near the horizon. At some point the reds and yellows finally scatter in the lower atmosphere causing the reds and yellows.

4. The red and yellows are appear at sunset because the light must pass through more atmosphere which slows down the wavelength frequency turning it to slower red and yellow frequencies.

Answers

Answer:

The answer should be 3-At sunset blue light is scattered by air molecules at higher altitudes. The longer red and yellow wavelengths must travel further through the atmosphere when the Sun is near the horizon. At some point the reds and yellows finally scatter in the lower atmosphere causing the reds and yellows.

Answer:

3. At sunset blue light is scattered by air molecules at higher altitudes. The longer red and yellow wavelengths must travel further through the atmosphere when the Sun is near the horizon. At some point the reds and yellows finally scatter in the lower atmosphere causing the reds and yellows.

A person is pushing a box with 5 N to the right while another person pushes with 10 N to the left, what is the net force on the box?

Answers

Answer:

Fnet = 5 Newton

Explanation:

Fnet = 10 N - 5 N

Fnet = 5 N

what were your preparetion before going the different physical fitness test?​

Answers

Answer:

Avoid heavy strenuous exercise for the 24 hours prior to testing. Do not exercise at all on the day of testing to ensure you are well rested. Wear appropriate clothing for the conditions (e.g. shorts/track pants and t-shirt/singlet/sports top) and non-slip athletic footwear with laces securely fastened

A 12.0 kg box resting on a horizontal, frictionless surface is attached to a 5.00 kg weight by a thin, light wire that passes over a frictionless pulley (Figure 1). The pulley has the shape of a uniform solid disk of mass 2.60 kg and diameter 0.500 m. A) After the system is released, find the tension in the horizontal segment of the wire. B) After the system is released, find the tension in the vertical segment of the wire. C) After the system is released, find the x-component of the acceleration of the box. D) After the system is released, find the x- and y-components of the force that the axle exerts on the pulley.

Answers

Answer:

Explanation:

Assuming x direction is horizontal any y direction is vertical

As the moment of inertia of the pulley is I = (½)mR²

The pulley mass will appear as ½ its actual mass in the system.

F = ma

5.00(9.81) = (5.00 + 2.60/2 + 12.0)a

a =  49.05 / 18.3

a = 2.6803278...

a = 2.68 m/s²

A) T = 12.0(2.68) = 32.16... = 32.2 N

B) T = 5.00(9.81 - 2.68) = 35.65 = 35.7 N

C) aₓ = 2.68 m/s²

D) Fx = 32.2 N

   Fy = 35.7 + 2.60(9.81) = 61.2 N

A)The tension in the horizontal segment of the wire will be  32.2 N

B)The tension in the vertical segment of the wire will be 35.7 N

What is acceleration?

Acceleration is defined as the rate of change of the velocity of the body. Its unit is m/sec².It is a vector quantity. It requires both magnitudes as well as direction to define.

The given data in the problem is;

m is the mass box resting on a horizontal  =12.0 kg

the uniform solid disk of mass of 2.60 kg

d is the diameter = 0.500 m.

A)The tension in the horizontal segment of the wire will be  32.2 N

The acceleration is found as;

[tex]\rm F = ma \\\\ a= \frac{49.05}{18.3} \\\\ \rm a= 2.68 \ m/sec^2[/tex]

The tension in the horizontal segment of the wire is found as;

T=ma

T= 12.0 ×2.68

T=32.2 N

Hence the tension in the horizontal segment of the wire will be  32.2 N

B)The tension in the vertical segment of the wire will be 35.7 N

T=m(g-a )

T= 5.00 × (9.8-2.68)

T=35.7 N

Hence the tension in the vertical segment of the wire will be 35.7 N

C)  the x-component of the acceleration of the box. will be 2.68 m/s².

aₓ = 2.68 m/s²

D)The x- and y-components of the force that the axle exerts on the pulley will be 32.2 and 61.2 N respectively.

Fx = 32.2 N

Fy = 35.7 + 2.60(9.81) = 61.2 N

Hence the x- and y-components of the force that the axle exerts on the pulley will be 32.2 and 61.2 N respectively.

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3. pinapatupad ng inyong lungsod ang pagpapanatili ng mga tao sa bahay sa araw ng Linggo
dahil sa nararanasang pandemya. Alin ang dapat gawin ng mga mamamayan?
a. Maagang pumunta sa dagat at doon magpalipas ng maghapon.
b. Magpunta sa simbahan at doon manatili sa buong araw.
a Pumunta sa kamag anak sa kabilang lungsod.
d. Manatili sa loob ng bahay sa buong araw.

Answers

Answer:

d because u now

Explanation:

sana makatulong

2. Conner flips a coin up in the air (to determine if he or his sister needs to do the dishes) at an upward velocity of 4.00 m/s. He fails to catch it on the way down and it falls down an additional 1.6 m to the floor. Calculate the maximum height and maximum magnitude (could be positive or negative) velocity of the coin.

Answers

Answer:

5.6

Explanation:

Not so sure

The coefficient of kinetic friction for a 22 kg bobsled on a track is 0.10. What force is required to push it down a 5.0 degree incline and achieve a speed of 62 km/h at the end of 75 m

Answers

Hi there!

We must begin by converting km/h to m/s using dimensional analysis:

[tex]\frac{62km}{1hr} * \frac{1hr}{3600sec}*\frac{1000m}{1km} = 17.22 m/s[/tex]

Now, we can use the kinematic equation below to find the required acceleration:

vf² = vi² + 2ad

We can assume the object starts from rest, so:

vf² = 2ad

(17.22)²/(2 · 75) = a

a = 1.978 m/s²

Now, we can begin looking at forces.

For an object moving down a ramp experiencing friction and an applied force, we have the forces:

Fκ  = μMgcosθ  = Force due to kinetic friction

Mgsinθ = Force due to gravity

A = Applied Force

We can write out the summation. Let down the incline be positive.

ΣF = A + Mgsinθ - μMgcosθ

Or:

ma = A + Mgsinθ - μMgcosθ

We can plug in the given values:

22(1.978) = A + 22(9.8sin(5)) - 0.10(22 · 9.8cos(5))

A = 46.203 N

which statement is true about heat and light energy

Answers

Answer:

statements?

Explanation:

)Suppose you have two insulated buckets containing the same amount of water at room temperature. You also happen to have two blocks of metal of the same mass, both at the same temperature, warmer than the water in the buckets. One block is made of aluminum and one is made of copper. You put the aluminum block into one bucket of water, and the copper block into the other. After waiting a while you measure the temperature of the water in both buckets. Which is warmer

Answers

The water in the bucket containing the aluminium block is warmer than the bucket containing the copper block.

The specific heat is the amount of heat needed or required to elevate the temperature of 1 gram of a substance by 1° C.

At standard conditions;

the specific heat of aluminium = 0.215 cal/gm/° Cthe specific heat of copper = 0.0923  cal/gm/° C

We know that:

Heat loss by the metal block = Heat gained by the water bucket

Therefore, since the specific heat of aluminium is higher than that of copper, the water bucket containing aluminium block will be warmer than the bucket containing the copper block.  

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does gravity cause a change in an objects movement

Answers

Answer:

yes

Explanation:

because gravity moves things

A spring has a length of 0.200 m when a 0.300-kg mass hangs from it, and a length of 0.750 m when a 1.95-kg mass hangs from it. (a) What is the force constant of the spring

Answers

Answer:

Explanation:

The change in force = 9.81(1.95 - 0.300) = 16.2 N

The change in length is 0.750 - 0.200 = 0.550 m

K = ΔF/Δx = 16.2/0.550 = 29.4 N/m

Light bulbs produce useful energy in the form of light and waste energy in the form of heat. What kind of light bulb would you use
to incubate eggs?

A. low-efficiency light bulbs, because they produce more light

B. low-efficiency light bulbs, because they produce more heat

C. high-efficiency light bulbs, because they produce more heat

D. high-efficiency light bulbs, because they produce more light

Answers

Answer:

C) high efficiency light bulbs, because they produce more heat

Light bulbs produce useful energy in the form of light and waste energy in the form of heat, the kind of light bulb would you use to incubate eggs are low-efficiency light bulbs, because they produce more heat, therefore the correct answer is option B.

What is thermal energy?

It can be defined as the form of the energy in which heat is transferred from one body to another body due to their molecular movements, thermal energy is also known as heat energy.

The type of light bulb you would use to incubate eggs is a low-efficiency light bulb since they produce more heat; consequently, option B is the right response. Light bulbs produce useful energy in the form of light and waste energy in the form of heat.

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Heat is transferred from molecules with more kinetic energy to molecules with _________kinetic energy.

Answers

Answer:

low

Explanation:

the higher the kinetic energy, the More the vibration of molecules, thus heat is more on the side with highly vibrating molecules

How do mechanical waves compare with electromagnetic waves?

Answers

Answer:

Main Difference Between Mechanical and Electromagnetic waves

A wave is composed of some kind of disturbance that propagates. We can classify waves into many different types based on their properties. One of the properties of the waves depends on whether they need a medium to propagate or not. The primary difference between electromagnetic and mechanical waves is also based on this property. Mechanical waves need a medium, while electromagnetic waves do not need a medium to propagate. Electromagnetic waves can travel through a vacuum. The other differences between mechanical and electromagnetic waves are given below:

Electromagnetic waves can travel through a vacuum, that is an empty space, whereas mechanical waves cannot. They need a medium to travel such as water or air. Ripples in a pond are an example of mechanical waves whereas electromagnetic waves include light and radio signals, which can travel through the vacuum of space.

Mechanical waves can be classed as elastic waves because their transmission depends on the medium's (water, air etc.) elastic properties.

Electromagnetic waves are caused because of the varying magnetic and electric fields. They are produced by the vibration of the charged particles.

Because of these differences, the speed of each type of wave varies significantly. Electromagnetic waves travel at the speed of light but mechanical waves are far slower.

                                                                            Have a wonderful day!

                                                                                                ~Lillith of brainly~


Carrie is driving a car. Which factors determine the kinetic energy of her car
at this point

Answers

Answer:

The two main factors that affect kinetic energy are mass and speed.

Explanation:

Kinetic energy is the energy that is caused by the motion. The kinetic energy of an object is the energy or force that the object has due to its motion. Your moving vehicle has kinetic energy; as you increase your vehicle's speed, your vehicle's kinetic energy increases.

Have a great day! :D

How long do elephants live?

Answers

65 years but anything can happen to them
I’m not really sure but I hope this helps
The average lifespan of an elephant is 60-70 years

How much force is required to raise a 0.2 kg mass?

Answers

Answer:

1.96 N

Explanation:

⇒This is your full answer

An airplane accelerates from a speed of 33 m/s at the constant rate of 3.0 m/s2 over a distance of 500 m. What the final velocity?​

Answers

Answer:

Explanation:

v² = u² + 2as

v² = 33² + 2(3.0)(500)

v² = 4089

v = 63.9452...

v = 64 m/s

SOMEONE HELP! If I don't get this done i will fail, I have been trying for hours.

p.s. both questions have no answer choices.

1. If a baseball has a mass of 0.075kg and is traveling with an acceleration of 25 m/s2. What is the force that the baseball will hit the bat?

````````````````````````````````````````

2. Given the force diagram of the basketball, what can you tell about the basketball motion? (Diagram below)



Thanks in advance!!

Answers

Answer:

1. The baseball will hit the bat at a force of 1.875 Newtons (N)

2. The basketball is being pushed to roll to the right of its original position with an applied rightward force. There is a force of friction to the left, a normal force of the floor acting upwards on the ball, and a gravity force of the Earth acting downwards on the ball.

Explanation:

1. To calculate force, you just have to multiply mass (m) and acceleration (a). F = m * a --> F = 0.075kg * 25 m/s^2 = 1.875 N.

2. Use your knowledge of different types of forces and free-body diagrams to come to this conclusion.

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