A 7500 kg truck traveling at 5.0 m/s east collides with a 1500 kg car moving
at 20 m/s in a direction 30 o

south of west. After collision, the two vehicles
remain tangled together. Find the speed and state the direction of car.

Answers

Answer 1

Since the collision is inelastic, both vehicle will move with a common velocity of 2.5 m/s in south east direction after collision.

Conservation of Linear Momentum

It states that, the sum of the momentum before collision is equal to the sum of the momentum after collision.

Given that a 7500 kg truck traveling at 5.0 m/s east collides with a 1500 kg car moving at 20 m/s in a direction 30° south of west. After collision, the two vehicles remain tangled together.

The given parameters are;

M1 = 7500 kgU1 = 5 m/sM2 = 1500U2 = 20 sin 30 = 10 m/sV = ?

The formula to find the speed will be

M1U1 - M2U2 = (M1 + M2)V

7500 × 5 - 1500 × 10 = (7500 + 1500)V

37500 - 15000 = 9000V

22500 = 9000V

V = 22500/9000

V = 2.5 m/s

Therefore, the common speed will be 2.5 m/s and the direction of the car will be toward the south east.

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Related Questions

Using the page from the Chart of the Nuclides, select a nuclide that is radioactive and decays (changes) to another nuclide by emitting an Alpha particle. Is the new element radioactive and if it is, how do you know that? If the new nuclide is radioactive, what does it decay to?

Do the same thing with a nuclide that emits a Beta particle.

If a rock contains 75% lead 206 (Pb206) and 25% uranium 238 (U238), how old is the rock? Explain how you determined the answer.

Is it possible to have a rock of that age on Earth, and what is the reason for your answer?

Answers

The age of the rock is 9 * 10^9 years and there is no rock that can be as old as this age on earth.

What is radioactive decay?

The term radioactive decay has to do with the process by which a radioactive nuclide disintegrates so as to obtain the daughter nucleus. The radioactive decay may occur by alpha or by beta radiation.

In this case, we are told that only 25% of the original uranium 238 isotope of half life 4.5 * 10^9 years still remains.

Using the formula;

0.693/[tex]t_{\frac{1}{2}[/tex] = 2.303/t log (No/N)

[tex]t_{\frac{1}{2}[/tex] = half life of the isotope

N= amount of isotope at time t

No = amount of isotope initially present

Then;

0.693/4.5 * 10^9 = 2.303/t log(No/0.25No)

1.54 * 10^-10 =  1.39/t

t = 1.39/1.54 * 10^-10

t = 9 * 10^9 years

There is no rock that is this much old since the average age of the earth is 4.5 billion years.

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is it true the greater the mass the greater the splash

Answers

Answer:If the momentum is large on the other hand, you will cause turbulences that make the water splash , So Yes

Explanation:

If you are given a measurement in scientific notation, how would you convert that into long form?

Answers

The number times itself the amount of times it is to the lower

5. If I shoot a cannonball (m = 4.5 kg) straight up from a cannon that exerts a force of 7000 N through a
barrel length of 4.00 meters, how high will the cannonball go?

Answers

With the use of formulas, the maximum height reached by the cannonball is 635.4 meters

Motion Under Gravity

The motion of an object under gravity is the vertical motion of the object under the influence of acceleration due to gravity.

If I shoot a cannonball (m = 4.5 kg) straight up from a cannon that exerts a force of 7000 N through a barrel length of 4.00 meters, the acceleration of the cannonball in the barrel can be calculated by using the formula

F = ma

Where

F = 7000 Nm = 4.5 Kga = ?

Substitute all the parameters into the formula

7000 = 4.5a

a = 7000/4.5

a = 1555.6 m/s²

By using the below formula, we will find the velocity at which the ball leaves the barrel.

Where

u = 0a = 1555.6 m/s²s = 4 m

v² = u² + 2as

v² = 0 + 2 × 1555.6 × 4

v² = 12444.4

v = √12444.4

v = 111.6 m/s

The same speed will be the initial velocity at the entrance of the barrel. How high will the cannonball go can be known by using the formula

v² = u² - 2gH

Where

v = 0 (at maximum height)u = 111.6 m/sg = 9.8 m/s²H = ?

Substitute all the parameters into the formula

0 = 111.6² - 2 × 9.8 × H

19.6H = 12454.56

H = 12454.56/19.6

H = 635.4 m

Therefore, the cannonball will go as high as 635.4 m

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A space station in deep space is spun like a giant
wheel to produce centrifugal force so the occupants
experience artificial gravity of one g. How does a
clock at the rim of the space station compare with
one residing at the hub? What does this say about
the behavior of a clock sitting on the surface of a
planet with a surface gravity of one g?

Answers

The behavior of a clock sitting on the surface of a planet with a surface gravity of one g says that rim clock always runs slower

Gravity is the principal force acting on a body in projectile motion when it is hurled at a specific angle. The power with which the body is originally thrown determines maximum height and how far it will travel. When an object moves in a projectile motion, there are numerous instances in daily life. For instance, a basketball player will obliquely toss the ball at a specific angle towards the direction of the hoop. The ball then rises and descends like a missile in the direction of the basket. Other sports like cricket, football, and soccer may demonstrate this.

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Describe a situation in which the median of a data set would be more useful than the mean

Answers

Answer:

mean extremely affect by the two level of values

highest and lowest points

A 9.25 kg bowling ball is hung on a 9.5 m long rope. It is then pulled back until the rope makes an angle of 35° with the vertical and released. Find the tension in the rope when the ball is at the lowest point. Give your answer in N and with 3 significant figures.

Answers

Answer:

123.6 N

Explanation:

I will try to answer this

Find height of the ball

  9. 5   - 9.5 cos 35  = 1.72 m   of potential energy

   PE = mgh    will be converted to KE at the bottom of the swing

     mgh = 1/2  m v^2

    sqrt( 2 gh )  = v      at the bottom = 5.81  m/s

then the tension is the mass times the acceleration of gravity PLUS the acceleration of circular motion  v^2 / r

F = ma

F = 9.25 kg ( 9.81 m/s^2 + 5.81^2 / 9.5 m/s^2 ) = tension = 123.6 N

(Let me know if this is incorrect, and I will research a bit more)

a nickel wire with a resistance of 25 Ω is connected across the terminals of a 3.0 v of a flashlight battery, how much current is in the wire?

Answers

The amount of current flowing in the wire, given that it has a resistance of 25 Ω and connected to a 3.0 V is 0.12 A

How do I determine the current in the wire?

From Ohm's law, we understood that the voltage, current and resistance are related according to the following formula:

Voltage (V) = Current (I) × resistance (R)

V = IR

With the above formula, we can obtain the current in wire. Details below.

The following data were obtained from the question:

Resistance (R) = 25 ΩVoltage (V) = 3.0 VCurrent (I) =?

Thus, the current can be obtained as follow:

Voltage (V) = Current (I) × resistance (R)

3 = Current × 25

Divide both sides by 25

Current = 3 / 25

Current = 0.12 A

Thus, we can conclude that the current in the wire is 0.12 A

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An 75-kilogram skier slides on waxed skis along a horizontal surface of snow at constant velocity while pushing with his poles. What is the horizontal component of the force pushing him forward? (1) 0.05 N (2) 40 N (3) 37 N (4) 4 N
[Use: Ff = µ Fn; remember Fn = Fg = mg]

Answers

The horizontal component of the force pushing him forward is 37 N.

What is force?

A force is an effect that can alter an object's motion according to physics. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.

Frictional force due to ice, F =   μN

Normal force N = mg = 75*9.8 = 735 N

Frictional force = 0.05*735 = 36.75 N

Coefficient of friction, μ for ice is 0.05

The horizontal component of the force pushing him forward is 37 N.

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why does kinetic energy have two maxitans minimum values during each oscillation?

Answers

Answer:

it has water

Explanation:

water is good

Which process is likely to happen more quickly: the physical weathering of rock by plant roots or the physical weathering of rock by the repeated thawing of water? Explain your answer

Answers

The physical weathering of rock by the repeated thawing of water is likely to happen more quickly than the physical weathering of rock by plant roots.

How does repeated thawing of water causes the rock to weather?

First, the physical weathering of rock is usually caused by water (which can come from rain or erosion), ice, plant roots, and even animals. These agents ensure the rock is broken down into smaller particles or sizes.

So, the thawing of water ensures continuous freezing and melting of water which allows water in the form of ice to build up in the cracks of rocks after expanding on freezing. This makes the rock breaks apart due to the pressure that is built in the crack.

However, physical weathering from the root of plants is slower compared to that of the repeated thawing of water. Though both processes needed time, but it will take more time for the roots in a crack. For the plant roots to get cracks to grow into, it needs repeated thawing of water to create that crack or other agents of rock weathering to create the crack.

In summary, repeated thawing of water makes rocks more susceptible to chemical and biological weathering. The weathering of rock by plant roots will need the plant to grow and survive in the first place, which might take more time.

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A horizontal pipe 10.0 cm in diameter has a smooth reduction to a pipe 5.00 cm in diameter. If the pressure of the water in the larger pipe is 8.00  104 Pa and the pressure in the smaller pipe is 6.00  104 Pa, at what rate does water flow through the pipe?

Answers

The volume flow rate at which the water flows is 0.0188 m³/s

How to find what rate does water flow through the pipe?

Since the horizontal pipe 10.0 cm in diameter has a smooth reduction to a pipe 5.00 cm in diameter and If the pressure of the water in the larger pipe is 8.00 × 10⁴ Pa and the pressure in the smaller pipe is 6.00 × 10⁴ Pa, since we require the rate at which water flows through the pipe, we use Bernoulli's equation at constant height to find the speed of flow.

What is Bernoulli's equation?

Bernoulli's equation governs flows through pipes. It is given by

P₁ + ρgh₁ + 1/2ρv₁² = P₂ + ρgh₂ + 1/2ρv₂² where

P₁ = pressure at point 1, h₁ = height at point 1, v₁ = speed at point 1, P₂ = pressure at point 2, h₂ = height at point 2, and v₂ = speed at point 2

With h₁ = h₂, the Bernoulli's equation becomes

P₁ + 1/2ρv₁² = P₂ + 1/2ρv₂²

Using the volume flow rate equation

Q = A₁v₁ = A₂v₂ where

A₁ = cross- sectional area at point 1 = πd₁²/4 where d₁ = diameter at point 1v₁ = speed at point 1, A₂ = cross- sectional area at point 2 and d₂ = diameter at point 1 = πd₂²/4v₂ = speed at point 2

So, A₁v₁ = A₂v₂

(πd₁²/4)v₁ = (πd₂²/4)v₂

d₁²v₁ = d₂²v₂

Making v₂ subject of the formula, we have

v₂ = d₁²v₁/d₂²

v₂ = (d₁/d₂)²v₁

Substituting v₂ into the Bernoulli equation, we have

P₁ + 1/2ρv₁² = P₂ + 1/2ρv₂²

P₁ + 1/2ρv₁² = P₂ + 1/2ρ(d₁/d₂)⁴v₁²

Making v₁ subject of the formula, we have

1/2ρv₁² - 1/2ρ(d₁/d₂)⁴v₁² = P₂ - P₁

1/2ρ[1 - (d₁/d₂)⁴]v₁² = P₂ - P₁

v₁² = √{2(P₂ - P₁)/ρ[1 - (d₁/d₂)⁴]}

Given that

P₁ = pressure in larger pipe = 8.00 × 10⁴ Pa d₁ = diameter of larger pipe = 10.0 cmP₂ = pressure in smaller pipe = 6.00 × 10⁴ Pa d₂ = diameter of smaller pipe = 5.00 cmρ = density of water = 1000 kg/m³

Substituting the values of the variables into the equation, we have

v₁ = √{2(P₂ - P₁)/ρ[1 - (d₁/d₂)⁴]}

v₁ = √{2(6.00 × 10⁴ Pa - 8.00 × 10⁴ Pa)/1000 kg/m³[1 - (10.0 cm/5.0 cm)⁴]}

v₁ = √{2(- 2.00 × 10⁴ Pa)/1000 kg/m³[1 - 2⁴]}

v₁ = √{(- 4.00 × 10⁴ Pa)/1000 kg/m³[1 - 8]}

v₁ = √{(- 4.00 × 10⁴ Pa)/1000 kg/m³[-7]}

v₁ = √{(40.0 × 10³ Pa)/7 × 10³ kg/m³}

v₁ = √{(40.0/7 Pam³/kg}

v₁ = √{5.7143 Pam³/kg}

v₁ = 2.39 m/s

Since the volume flow rate Q = A₁v₁ = (πd₁²/4)v₁

Given that

d₁ = diameter of larger pipe = 10.0 cm =  0.1 m and v₁ = speed in larger pipe = 2.39 m/s

Substituting the values of the variables into the equation, we have

Q = (πd₁²/4)v₁

Q = π(0.1 m)²/4 × 2.39 m/s

Q = π × 0.01 m²/4 × 2.39 m/s

Q = π × 0.0239 m³/s/4

Q = 0.0751 m³/s ÷ 4

Q = 0.0188 m³/s

So, the water flows at a rate of 0.0188 m³/s

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Assuming a constant acceleration and no slipping of tires, estimate the coefficient of static friction needed for a drag racer to cover 1.4 km in 15 s , starting from rest.

Answers

The coefficient of static friction needed for a drag racer to cover the given distance is 1.27.

What is the acceleration of the slipping tires?

The magnitude of the acceleration of the slipping tires is calculated by applying the kinematic equation for average distance travelled by the slipping tires as shown below.

s = ut + ¹/₂at²

where;

u is the initial velocity of the slipping tires = 0t is the time of motion of the slipping tiresa is the average acceleration of the slipping tiress is the average distance moved by the slipping

s = 0 + ¹/₂at²

s = ¹/₂at²

at² = 2s

a = 2s/t²

a = (2 x 1,400 m) / (15 s)²

a = 12.44 m/s²

The coefficient of static friction needed for a drag racer to cover the given distance is calculated as;

μ = a/g

where;

g is acceleration due to gravity = 9.81 m/s²

μ = 12.44 / 9.81

μ =  1.27

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When Galileo Galilei was alive, most scientists believed that heavy objects fall to Earth faster than light objects. Galileo conducted an experiment and found that objects of the same size and shape fall to Earth at the same speed, no matter their mass. What did Galileo most likely have to do in order to convince other scientists that his observations were correct?
A.
Keep the results to himself and wait for other scientists to conduct similar experiments.
B.
Conduct an experiment in which he tries to force one object to fall faster than a lighter object.
C.
Repeat the experiment multiple times in front of witnesses.
D.
Publish the results of the experiment.

Answers

Answer:

b. Is the answer because It depends on what Galileo Galilea thinks :,-)

Galileo most likely have to do this in order to convince other scientists that his observations were correct, is repeats the experiment multiple times in front of witnesses. So the correct option is C.

Galileo probably had to repeat his tests multiple times in front of witnesses to present convincing proof to other scientists rather than keeping the results to himself, making an object fall faster, or just publicizing his results.

Scientific certainty is produced by repeating an experiment and observing the outcomes, which is still regarded as a key component of the scientific method in modern times.

Galileo would have benefited from documenting his procedures and conclusions in a way that allowed other scientists to replicate his experiment and confirm his findings, even though it wasn't mentioned in your multiple-choice answers.

This concept is largely covered by the peer-review procedure used in contemporary science. So the correct option is C.

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A bicycle wheel (a hoop) of radius 0.6 m and mass 5 kg is rotating at 4.00
rev/sec. After 25 sec the wheel comes to a stop because of friction. What is the
angular acceleration of the wheel?

Answers

The angular acceleration of the wheel 0.16 rad/sec².

What is acceleration?

The rate at which an item changes its velocity is known as acceleration, a vector quantity. If an object's velocity is changing, it is acceleration.

The net acceleration that objects get as a result of the combined action of gravity and centrifugal force is known as the Earth's gravity, or g. It is a vector quantity whose strength or magnitude is determined by the norm and whose direction correlates with a plumb bob.

Given in the question,

angular acceleration = 4/25

angular acceleration = 0.16 rad/sec²

The angular acceleration of the wheel 0.16 rad/sec².

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Pedro feels his best after chatting with a friend and discussing new ideas with his teammates. Which function do these preferred activities show? A. Thinking B. Introversion C. Knowing D. Extroversion

Answers

The fact that Pedro likes to talk to people means that Pedro is an extrovert.

Who is an extrovert?

We define an extrovert as a person that is able to interact very much freely with other people. It is one of the kinds of temperaments that a person can have. We know that people that can have very different temperament types and these are the things that determine the behavior of a person.

Thus, a person acts in accordance with the kind of temperaments that a person has. Just as we can see in the person of Pedro. We are told in his case that the person Pedro would always like to talk with is friends and the team mates which suggests that he must like to associate with other people.

From our definition of the person of Pedro in the lines that are above, we can say the Pedro is an extrovert.

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Determine the distance that a car recovers after 5 seconds if it travels at a speed of 10m/s.​​

Answers

We first apply the data to the problem.

Data:

V = 10m/sT = 5sD = ?

Then, we apply the formula that is.

Formula:

D = V • T

Finally we develop the problem.

Developing:

D = (10m/s) • (5s)D = 50m

The car travels a distance of 50 meters.

A point mass of 0.5 kg moving with a constant speed of 5m/s on an elliptical track experiecnces an outward force oof 10N when at either endpoint of the major axis and a a=similar force of 1.25N at each end of thr minor sxis.How long are the axes of the ellipse?

Answers

The length of the axes of the eclipse are 1.25cm and 10cm.

How are the length of the eclipse found?

With the formula, F = (mv²)/r

where F = force

m = mass

v = velocity and

r = diameter/length

To find how long the axes of the eclipse are at an outward force of 10N and a similar force of 1.25N:

For F₁ = 10N

10 = (0.5 x 5²)/r

10 = 12.5/r, cross multiply

r = 12.5/10 = 1.25cm

For F₂ = 1.25N

1.25 = (0.5 x 5²)/r

1.25 = 12.5/r, cross multiply

r = 12.5/1.25 = 10cm

The lengths of the eclipse are found by dividing the product of the mass and velocity by the first and second forces to get 1.25cm and 10cm

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Two stars, one twice as massive as the other, are 1.0 light-year (ly) apart. One light year is the distance light travels in one year at the speed of light, 3.00×10^8m/s. The gravitational potential energy of this double-star system is −6.5 ×10^34J.
Q: What is the mass of the lighter star?

Answers

The mass of the lighter star is 2.15 x 10³⁰ kg.

What is the mass of the light star?

The mass of the lighter star is obtained by applying the formula force gravitational potential energy between the two stars.

According to Newton's law of universal gravitation, every two objects in the universe attracts each other with a force that is directly proportional to the product of their masses and inversely proportional to the square of the distance between the two objects.

U = F x r

U = Gm₁m₂/r²   x   r

U = Gm₁m₂/r

where;

G is universal gravitation constantm₁ is the mass of the first starm₂ is the mass of the second starr is the distance between the two stars

r = 3 x 10⁸ m/s  x 3.154 x 10⁷ s/yr

r = 9.46 x 10¹⁵ m

let the lighter star = m₁

then, the heavier star = 2m₁

U = (G x m₁ x 2m₁)/r

U = 2Gm₁²/r

Ur = 2Gm₁²

m₁² = Ur/2G

m₁ = √(Ur/2G)

m₁ = √(6.5 x 10³⁴ x 9.46 x 10¹⁵ / 2 x 6.626 x 10⁻¹¹)

m₁ =  2.15 x 10³⁰ kg

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You observe an X-ray source to vary on a timescale
of 0.001 seconds. What is the upper limit for the
size of the X-ray emitting region? What is the mass
of a black hole with a Schwarzschild radius of this
size?

Answers

X-ray mass can be determined by formula

kari ann is pulling a bookcase across her bedroom floor. what are three reasons that she might find it hard to accelerate the bookcase? (hint: link to both labs as well as newton's 1st law)

Answers

Three reasons why it may be difficult to accelerate the bookcase are;

1) Inertia that acts on the book case

2) Frictional force that prevents the book case from moving

3) The weight of the book  case.

Why is there difficulty in moving the suitcase?

We know that the Newton law states that a body would tend to remain at a state of rest or uniform motion unless it is acted upon by unbalanced forces. When the book lies without movement it is acted upon by its weight and the reaction which are exactly balanced. The inertia is the reluctance of the book to move.

As the book begins to move when pull, the friction that is acting on the pull would also militate against the forward motion of the book as it acts in the opposite direction.

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A car of mass 1500kg travelling at a velocity of 10 m/s crashes into the back of a moving car of mass 1500kg travelling at a velocity of 5 m/s. The vehicles move together after the impact Calculate their velocity?​

Answers

Answer:

M1 V1 + M2 V2 = (M1 + M2) V

Conservation of momentum where V is speed of combined vehicles

V = (1500 * 10 + 1500 * 5) / (1500 + 1500) = 7.5 m/s

3. An object released from rest at time t = 0 slides down a frictionless incline a
distance of 1 m during the first second. The distance traveled by the object
during the time interval from t = 2 s to t = 3 s is:
(A) 1 m
(B) 2 m (C) 3 m
(D) 4 m (E) 5 m

Answers

The distance traveled by the object during the time interval from t = 2 s to t = 3s is 3m. Option C.

From the formula d = ½ at2 the displacement is proportional to the square of time. If you run twice as far from the rest, the displacement will quadruple (or 4m). Since the object has already moved 1 m in the first second, the remaining 3 m have moved in time intervals from 1 to 2 seconds.

This means that the velocity and net force in the direction normal to the plane must be zero. Assuming the plane is frictionless means that the plane exerts no force on the block parallel to the surface. For angular frictionless tilt, the acceleration is the result of the gravitational acceleration multiplied by the sine of the angle.

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Two arrows are fired horizontally with the same speed of 30.0 m/s. Each arrow has a mass of 0.100 kg. One is fired due east and the other due south. Find the magnitude and direction of the total momentum of this two-arrow system. Specify the direction with respect to due east.

Why do we have to do square root of the Momentum, also at the last to find the direction why we do Tan^-1. Please explain.

Answers

Answer:

P = P1 + P2     where P is a vector quantity

P1 = P2 = .10 kg * 30.0 m/s = 3 kg-m/sec

P = (p1^2 + p2^2)^1/2      add vectors and find magnitude of resultant

p = (3.0^2 + 3.0^2)^1/2 = 4.24      length of resultant vector

Since vectors are at right angles p is the length of the hypotenuse

tan θ = 3.0 / 3.0 = 1      where theta is measured with respect to the positive x-axis and will be below that axis

θ = tan^-1 1 = 45 deg      (45 degrees below positive x-axis)

One can find the value of tan θ from the length of the x-y vectors and from tan θ obtain θ

a block of mass m=9.0kg and speed V and is behind a block of mass M=27 kg and speed of 0.50m/s, as shown in the figure. the surface is fricitonless, and the blocks suddenly collide and couple. after the collision, the blocks have a common speed of 0.90 m/s. how much kinetic energy of the blocks is lost due to the collision?

Answers

The kinetic energy of the blocks that is lost due to the collision is 8.64 J.

What is the initial speed of the smaller block?

The initial speed of the smaller block is calculated by applying the following equation.

m₁u₁  +  m₂u₂ = v(m₁ + m₂)

where;

m is the mass of the blocksu is the initial velocity of the blocksv is the common velocity of the blocks after the collision

9u₁ + 27(0.5) = 0.9(9 + 27)

9u₁ + 13.5 = 32.4

9u₁ = 18.9

u₁ = 18.9/9

u₁ = 2.1 m/s

The total initial kinetic energy of the blocks is calculated as follows;

K.Ei = ¹/₂m₁u₁²  +  ¹/₂m₂u₂²

K.Ei = ¹/₂(9)(2.1)²    +    ¹/₂(27)(0.5)²

K.Ei = 23.22 J

The final kinetic energy of the blocks is calculated as follows;

K.Ef = ¹/₂(m₁ + m₂)v²

K.Ef = ¹/₂(9 + 27) x (0.9)²

K.Ef = 14.58 J

The change in the kinetic energy of the block is calculated as;

ΔK.E = K.Ef  -  K.Ei

ΔK.E = 14.58 J   -   23.22 J

ΔK.E = -8.64 J

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A red 8-kg ball that is going 3-m/s collides with a 2-kg blue ball that is at rest. The blue
ball then goes 6-m/s. What is the red ball's speed?

Answers

Answer:

Explanation:

Given:

m₁ = 8 kg

V₁ = 3 m/s

m₂ = 2kg

V₂ = 0

V₂' = 6 m/s

__________

V₁' - ?

m₁V₁ + m₂V₂ = m₁V₁' + m₂V₂'

8·3 + 2·0 = 8·V₁'  + 2·6

24 = 8·V₁' + 12

24 - 12 = 8·V₁'

12 = 8·V₁'

V₁' = 12 / 8 = 1.5 m/s

What work is done by a forklift raising a 583 kg box a distance of 1.2 m?

Answers

The work that is done by a forklift raising a 583 kg box a distance of 1.2m is 699.6N.

How to calculate work done?

Work refers to the measure of energy expended in moving an object. It is most commonly calculated by multiplying the force by the distance.

This means that no work is done if the object does not move. This means that the work done can be calculated as follows:

Work done = Force × distance

According to this question, a forklift raises a 583kg box over a distance of 1.2m. The work done can be calculated as follows:

Work done = 583kg × 1.2m

Work done = 699.6N

Therefore, 699.6N is the force required to lift the box.

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What is the argument by analogy(regarding other minds) and what is an objection against it?

Answers

The  argument by analogy (regarding other minds) and the objection against it is that:

Bertrand Russell's "Comparison of Other Minds" aims to demonstrate the existence of minds other than his own by introspection and analogy; he thinks that by doing so, you can observe other people's activities and confidently conclude that they share your thoughts. It is  all the time possible to make conclusions this way.

What supports Russell's claim that there are other minds?

Russell thinks there are other minds due to the fact that he can see behaviors in others that are similar to his own without giving them any conscious thought. He contends that thoughts are the root of all behavior, but what happens when a thought results in a reaction that one forces upon oneself.

Therefore, the traditional philosophical defense of the existence of other minds is the argument from analogy, which, as persuasively put forth by John Stuart Mill, a 19th-century empiricist, claims that since one's body and outward behavior are observably similar to those of others, one is justified by analogy in thinking that others have feelings similar to one's own and are not just automatons with similar bodies and outward behaviors.

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a hoop with radius r, mass m and moment of inertia mr^2 rolls along a surface without slipping, at a constant velocity v. What is the angular momentum of the hoop about its center of mass?

Answers

mvr³  is the angular momentum of the hoop about its center of mass

L=mvr=Iω

L= angular momentum

m= mass

v=velocity

r= radius

L=mvr

L=mr²×r×v

L=mvr³

A characteristic known as angular momentum describes the rotating inertia of an item or set of objects when they are moving along an axis that may or may not pass through them. The Earth possesses spin angular momentum from its daily rotation around its axis and orbital angular momentum from its yearly revolution around the Sun. Since angular momentum is a vector quantity, its full representation calls for the identification of both a magnitude and a direction. An object in orbit has an angular momentum that is proportional to its linear momentum times the perpendicular distance r from the center of rotation to a line drawn through the center of gravity of the object, or just mvr.

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A coffeemaker has a resistance of 120 and draws a current of 10 A. What power does it use?

Answers

P = I²R = (10 A)² (120 Ω) = 120 000 Watts = 120 kW

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