Hi there!
We can begin by using the derived kinematic equation:
[tex]t = \sqrt{\frac{2h}{g}[/tex]
Plug in the given values and let g = 9.8 m/s²:
[tex]t = \sqrt{\frac{2(20)}{g}} = \boxed{2.02 s}[/tex]
Now, we can solve for its final velocity using the equation:
[tex]v_f = v_i + at[/tex]
It is dropped from rest, so vi = 0 m/s.
[tex]v_f = at[/tex]
[tex]v_f = 9.8(2.02) = \boxed{19.796 m/s}[/tex]
Answer:
a. The ball would reach the ground in approximately [tex]2.02\; \rm s[/tex].
b. The velocity of the ball right before landing would be approximately [tex]19.8\; \rm m\cdot s^{-1}[/tex].
(Assumptions: the ball was dropped with no initial velocity; air resistance on the ball is negligible; [tex]g = 9.81\; \rm m\cdot s^{-2}[/tex].)
Explanation:
Under these assumptions, the acceleration of this ball would be constantly [tex]a = g = 9.81\; \rm m\cdot s^{-2}[/tex] (same as the gravitational field strength) during the descent.
Displacement of the ball: [tex]x = 20.0\; \rm m[/tex].
Initial velocity of the ball: [tex]v_{0} = 0\; \rm m\cdot s^{-1}[/tex].
Let [tex]t[/tex] denote the duration of this descent.
The SUVAT equation [tex]x = (1/2)\, a\, t^{2} + v_{0}\, t[/tex] relates the known quantities [tex]a[/tex], [tex]x[/tex], and [tex]v_{0}[/tex] to the unknown [tex]t[/tex].
Substitute the known quantities into this equation and solve to find the value of [tex]t\![/tex]:
[tex]\displaystyle 20.0\; {\rm m} = \frac{1}{2}\times 9.81\; {\rm m\cdot s^{-2}} \times t^{2} + 0\; {\rm m \cdot s^{-1}} \times t[/tex].
[tex]\displaystyle 20.0\; {\rm m} = \frac{1}{2}\times 9.81\; {\rm m\cdot s^{-2}} \times t^{2}[/tex].
[tex]\displaystyle t^{2} = \frac{20.0\; \rm m}{(1/2) \times 9.81\; \rm m\cdot s^{-2}}[/tex].
Since [tex]t > 0[/tex]:
[tex]\begin{aligned}t &= \sqrt{\frac{20.0\; \rm m}{(1/2) \times 9.81\; \rm m\cdot s^{-2}}} \\ &\approx 2.01928\; \rm s\\ &\approx 2.02\; \rm s \\ & (\text{Rounded to 2 sig. fig.})\end{aligned}[/tex].
Since the acceleration of this ball is constant, the velocity of the ball right before landing would be:
[tex]\begin{aligned}v_{1} &= a\, t \\ &\approx 9.81\; \rm m\cdot s^{-2} \times 2.01928\; \rm s \\ &\approx 19.8\; \rm m \cdot s^{-1} \end{aligned}[/tex].
How to find resistance
Answer:
R = V/I
Explanation:
Example:
V = IR
R = V/I
If we were to use V = 120 and I = 0.25
R = 120/0.25
R = 480 Ohms
Your resistence would equal Ohms
i have science map and i dont know what ro answer please help me asap
Answer:
C
Explanation:
The correct answer is C because it puts equivalent measurements in the equivalent cup size. Both cups in answer C are the same measurement: 200 mL. The water in both cups is also the same measurement: 100 mL of 70 degrees Celsius. This is important because equivalent measurements for everything mean the experiment will be fair, equal, and accurate. If the measurements were not equal to each other, your experiment would not be as accurate.
HELP PLEASE
2. What is the potential energy of a 2000 g basketball that is stuck on the rim of a 3m hoop?
Answer:
[tex]U_g=58.86 J[/tex] or [tex]U_g=60 J[/tex]
Explanation:
Answer is attached. I do not know if you needed to use 9.81 or 10 for the acceleration due to gravity, so both solutions are attached.
How long will it take to travel 150km at an average speed of 40 km/h
Answer:
6,000 minutes
Explanation:
To calculate distance u multiply speed and time or speed and rate
Newton’s First Law of Motion applies to
1) objects at rest
2) objects in motion
3) both moving and non moving objects
4) objects that are accelerating
Answer:
3) both moving and non moving objects
Hope it helps:)
Real-life situations of microphones.
Answer:
Microphones are used in many applications such as telephones, hearing aids, public address systems for concert halls and public events, motion picture production, live and recorded audio engineering, sound recording, two-way radios, megaphones, radio and television broadcasting.
If a 5.00 kg box slides down a ramp inclined at 60.0° above the horizontal, what is the
acceleration of the box
Answer:
A 70 kg box is slid along the floor by a 400 n force. The coefficient of friction between the box and the floor is 0. 50 when the box is sliding
waht is pascal law?
Answer:
P=\frac{F}{A}
P = pressure
{F} = force
{A} = area
Explanation:
Find the mass of the second object if the force of gravity between the two objects is 0.128N. The mass of the first object is 1300 kg and the 2 objects are 0.23 m apart.
Considering the Law of Universal Gravitation, the mass of the second object is 78090.19 kg.
The Law of Universal Gravitation is a law that states that bodies, by the simple fact of having mass, experience a force of attraction towards other bodies with mass, called gravitational force.
This law establishes that every particle attracts any other particle with a force directly proportional to the product of the masses of both and inversely proportional to the square of the distance that separates them:
[tex]F=G\frac{m1m2}{r^{2} }[/tex]
where m1 and m2 are their masses; r the distance between them and G a universal constant that is called the constant of gravitation.
In this case, you know:
F= 0.128 NG=6.67× 10⁻¹¹ Nm²/kg²m1= 1300 kgm2= ?r= 0.23 mReplacing:
[tex]0.128 N=6.67x10^{-11}\frac{Nm^{2} }{kg^{2} } \frac{1300 kg m2}{(0.23 m)^{2} }[/tex]
Solving:
[tex]0.128 N=1.639x10^{-6}\frac{N}{kg }x m2[/tex]
m2=0.128 N ÷ 1.639×10⁻⁶ [tex]\frac{N}{kg}[/tex]
m2=78090.19 kg
In summary, the mass of the second object is 78090.19 kg.
Learn more:
https://brainly.com/question/858421?referrer=searchResultshttps://brainly.com/question/2347945?referrer=searchResultsPLEASE ANSWER ASAP
A 5 kg bowling ball traveling at 2 m/s hits a motionless 10 kg bowling ball. If the smaller ball bounces back at a speed of -1 m/s, what will be the speed of the larger ball after the collision?
Hi there!
Recall the conservation of momentum:
m1v1 + m2v2 = m1v1' + m2v2'
Let m1 = 5 kg ball and m2 = 10 kg ball
Since m2 is at rest, we can rewrite:
m1v1 = m1v1' + m2v2'
Plug in the given values:
5(2) = 5(-1) + 10v2'
Solve for v2':
10 = -5 + 10v2'
15 = 10v2'
15/10 = 1.5 m/s
We know that,
m1v1 + m2v2 = m1v1' + m2v2'
5 x 2 + 0 = 5 x -1 + 10 x v2'
10= -5 +10 x v2'
15 = 10 x v2'
v2' = 15/10
v2' = 1.5 m/s
hence , the speed of the larger ball after the collision will 1.5m/s
What force would be required to accelerate a 1,100 kg car to 0. 5 m/s2? N.
Answer:
550 NExplanation:
The force acting on an object given it's mass and acceleration can be found by using the formula
force = mass × acceleration
From the question
mass = 1100 kg
acceleration = 0.5 m/s²
We have
force = 1100 × 0.5 = 550
We have the final answer as
550 NHope this helps you
Answer:
If your filling in the blank on edge then its 550
Explanation:
What event has inspired your life so far? How has this event changed you?
Easy pts! I will give Brainliest. :)
NEED ANSWER ASAP!
Which statement about a converging lens is not correct?
A ray parallel to the principal axis of the lens is refracted through the principal focus.
B All rays of light refracted by the lens pass through the principal focus.
C The distance between the centre of the lens and the principal focus is the focal length
D The principal focus of the lens is a point on the principal axis.
Geometric optics allows you to find which the correct answer about which false statement is:
B) All rays of light refracted by the lens pass through the principal focus.
Geometric optics studies the formation of images using the light geometric properties of optical systems, the main expression for this is:
[tex]\frac{1}{f} = \frac{1}{p} + \frac{1}{q}[/tex]
Where f is the focal length, p and q the distance to the object and the image respectively.
There are some points of special interest:
Object at infinity (p = ∞). In this case of the expression we see that the image is at the focal length. Image at infinity (q = ∞). In this case the object is at the focal point.
Let's analyze the claims.
A) True. A parallel ray comes from infinity and the image is formed at the focal point.
B) False. The image point is given by the expression above and depends on the distance to the object.
C) True. This is the definition of focal length.
D) True. All distances are measured from the main axis.
In conclusion, using geometric optics we can find that the correct answer about which false statement is:
B) All rays of light refracted by the lens pass through the principal focus.
Learn more about geometric optics here: brainly.com/question/2548694
A force acts on an object. Which option describes an action that could prevent the object from moving
Answer:
Friction or tension
Explanation:
Friction stops an object from moving in the presence of force
Tại sao khi bị sì hơi quả bóng bay sẹp lại?
Answer:
what is this language??
help with this question
Answer:
D and B.
Explanation:
The wavelength must be taken from the same corresponding point. D and B are both at the crests of a wave, with no other crests in between, which means the distance between them is equal to one wavelength.
What might be an example of newtons second law of motion
Answer:
Pushing a car and a truck
Explanation:
which forces have physicists shown to be the same force under conditions of very high temperature, as confirmed by experiments in particle accelerators?
Answer:
the electromagnetic and weak forces
Explanation:
If F = 4.0 N and m = 2.0 kg, what is the magnitude a of the acceleration for the block shown below? The surface is frictionless. *
The magnitude of the acceleration of the block is 3.5 [tex]\bold{m/s^2.}[/tex]
The correct option is (C) 3.5 [tex]\bold{m/s^2.}[/tex]
What do you mean by acceleration?Acceleration is the rate of change of velocity with time.
By Newton’s Second law
This law establishes the relationship between the net applied force on an object with the resultant acceleration. For a constant magnitude of force, the more is the mass of the object, the lesser will be its acceleration.
Given,
The mass of the block is 2.0 kg.
The force in the horizontal direction on the block is [tex]\bold{4.0 N + 4.0 N \cos 40{}^\circ.}[/tex]
a is the acceleration in the horizontal direction.
The acceleration for the block can be determined using Newton’s Second law,
[tex]\begin{aligned} \Sigma F&=ma \\ F+F\cos 40{}^\circ &=ma \\ a&=\frac{F\left( 1+\cos 40{}^\circ \right)}{m} \\ &=\frac{4.0\text{ N}\left( 1.766 \right)}{2.0\text{ kg}} \\ &=3.5\text{ m/}{{\text{s}}^{2}} \end{aligned}[/tex]
Thus, the acceleration is 3.5 [tex]\bold{m/s^2.}[/tex]
Learn more about acceleration, here:
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Science Questions :)
Answer:
The box will move diagonally down to the right
I would like to know if it would be m/s² or just m/s and explain why. thanks
It will be
[tex] {m/s}^{2} [/tex]
I am just explaining with the units only, because you want to know the accurate unit.
[tex] \frac{m/s}{s} \\ = \frac{m}{s} \times \frac{1}{s} \\ = \frac{m}{s \times s} \\ = \frac{m}{ {s}^{2} } \\ = {m/s}^{2} [/tex]
Hope you understood.
Do comment if you have any query.
A taxi is travelling at 20 m/s. Its driver accelerates with acceleration 5 m/s2 for 4 s. What is its new velocity?
Please find attached photograph for your answer.
Hope it helps.
Do comment if you have any query.
An object with a mass of 90 grams, moving at a constant velocity of 6 meters per second, has __________. A. A momentum of 540 gram meters per second B. An acceleration of 10 meters per second squared C. A momentum of 90 gram meters per second D. An acceleration of 6 meters per second squared Please select the best answer from the choices provided. A B C D.
Answer: 540 g m/s.
Explanation:
Answer: A.
A momentum of 540 gram meters per second!
Explanation: On Edge!!
A deer runs 5 km through the woods in 9 min and then walks 7 km in 2 hours. Find its average speed in km/h.
please answer this don't go on the one which is choosed coz i bymistakely choosed it
Answer:
(B) B is travelling fastest
Explanation:
slope of xt graph = speed.
Slope of B is greater than a and c.
BRAINLIST PLS
6. Explain a change that you can make in your diet to further your overall health.
Answer:
“Eat more delicious whole-food plants at every meal and snack. Fruits, vegetables, whole grains, nuts and seeds are packed with nutrients and contain satisfying fiber that is good for digestion, disease prevention and sustained energy.
Explanation:
A child is stationary on a swing.(a)The child is given a push by his brother to start him swinging.His brother applies a steady force of 84 N over a distance of 0.25 m.(i) Calculate the work done by this force.(2)..............................................................................................................................................(ii) State how much energy is transferred by this force.(1)..............................................................................................................................................(iii) After several more pushes, the child has a kinetic energy of 71 J.The mass of the child is 27 kg.Show that the velocity of the child at this point is about 2.3 m/s.(2)(iv) Which one of these quantities changes in both size and direction while he is swinging?Put a cross ( ) in the box next to your answer.(1)Ahis gravitational potential energyBhis momentumCthe force of gravity acting on himDhis kinetic energy
Answer:
Work done = Fs
Explanation:
(i) W = Fxs
= 84N x0.25m
= 21 Joules
(ii) Ek = 1/2mv^2
71 = 1/2×27×v^2
71×2/27 = v^2
v = 23m/s
The work done by this force is 21 Joule.
Energy transferred by the force is 21 Joule.
The boy's momentum changes periodically, that is, in both size and direction.
What is force?An external force is an agent that has the ability to change the resting or moving condition of a body. It has a direction and a magnitude. So, it is a vector quantity. Newton is the SI unit of force (N).
(i) Given parameter:
Steady force applied by his brother, F = 84 N.
Displacement, d = 0.25 m.
The work done by this force, W = F.d = 84×0.25 = 21 Joule.
(ii) Amount of work done is transferred by this force as an energy. So, amount of energy transferred by the force is 21 Joule.
(iii) Given parameter:
Mass of the child, m= 27 kg.
Kinetic energy, E = 71 J.
Let, velocity of the child = v, then kinetic energy is,
E = 1/2 × mv²
⇒ v = √(2E/m)
= √(2×71/27)
= 2.3 m/s.
Hence, the velocity of the boy is 2.3 m/s. (proved).
(iv) During swing, his velocity changes periodically. That's why, his momentum changes periodically, that is, in both size and direction.
Learn more about force here:
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A crate of mass 50kg is pulled up a rough inclined plane, inclined at an angle of 60° to the horizontal. Determine the total work done in moving the crate to the top of the inclined 200m high.
Answer:
Wc = m*g = 50kg * 9.8N/kg = 490 N = Wt.
of crate.
Fc = 490N 60o = Force of crate.
Fp = 490*sin60 = 424.4 N. = Force
parallel to incline.
Fv = 490*cos60 = 245 N. = Force perpendicular to the incline.
Ff = u*Fv = u*245 = Force of friction.
Fap-Fp-Ff = m*a
Fap-424.4-u*245 = m*0 = 0
Fap = 424.4 + 245u. = Force applied.
L = 200m/sin60 = 231 m. = Length of
incline.
Work = Fap * L=(424.4+245u) * 231.
Explanation:
hello could some one please help me wit these
Answer:
1.D 2.A 3.A 4.B 5.C 6.A 7.A 8.A
Explanation:
Answer:
Question one is: kinetic energy
Question two is: tin
Question three is: zinc
Question four is: compression stroke
Question five is: second law of thermodynamics
Question six is: Convection
Question seven is: refrigerater
Explanation:
The next page called use vocabulary
the answers:
Question twenty three is: Heat engine
Question twenty four is: Thermodynamics
Question twenty five is: solar collector
Question twenty six is: specific heat capacity
Question twenty seven is: a conductor
Question twenty eight is: it's total energy increasing
Question thrity is: internal combustion engine
Question thrity one is: Exhaust stroke
Question thrity two is: plastic
Question thrity three: I don't know this one sorry!
Question thrity four is: Temperature
Question thrity five is: Heat
Hope his helps!!! <3
The spark plugs are threaded into the top of each cylinder and provide a place for the spark to jump within the ________.
Answer:
"the spark plug gap"
The plug provides a gap between the input voltage and the ground supplied by the car chassis.