The distance traveled by the body in the given time is 1,250 m.
The given parameters;
mass of the body, m = 15 kgacceleration of the body, a = 4 m/s²time of motion, t = 25 sinitial velocity, u = 0The distance traveled by the body in the given time is calculated as follows;
[tex]s =ut + \frac{1}{2} at^2\\\\s = 0 \ + \ \frac{1}{2} (4)(25^2)\\\\s =1,250 \ m[/tex]
Thus, the distance traveled by the body in the given time is 1,250 m.
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what would happen if gravity were to stop everywhere?
Answer:
everything will float up and go up to space and die
Explanation:
gravity keeps us down and once it stops everything will float up. And if it were to stop everywhere everything and everyone will die and everything will be destroyed.
A rollercoaster car passes the hill which is 5.5m above the ground at speed 9.3m/s, and rolls over the second hill which is 2.5m above the ground, and heads toward the third hill which is 4.0 m higher than the first one. If the track is frictionless,
a. What maximum height will the car climb on the third hill? [h max = 9.9m, so car will climb the entire 9.5m hill]
b. Will the speed of the car on top of the hill 3 be lower or higher than its speed on the top of the hill one? [lower]
c. Calculate the speed of the car when it is 1m lower than the top of the third hill. [5.3m/s]
Would somebody kindly go over the questions :D
Answer:
Explanation:
Without friction, a roller coaster continuously converts potential energy to kinetic energy and back again. Total energy will be constant.
Let m be the mass of the car and ground level is the origin.
on the 5.5 m hill, total energy is
E = PE + KE
E = mgh + ½mv²
E = m(9.8)(5.5) + ½m(9.3)² = 97m J
a) The maximum height will occur when the total energy is all potential energy.
E = mgh
h = E/mg
h = 97m/m(9.8) = 9.9 m
As this value is greater than the height of the third hill at 5.5 + 4.0 = 9.5 m The car will cross the last hill with some remaining velocity in kinetic energy.
b) As 9.5 m is greater than 9.3 m, the 9.5 m hill will have more of the total energy of the system as potential energy, This mean there is less kinetic energy and therefore less velocity (and speed) on top of the 9.5 m hill.
c) KE = E - PE
KE = 97m - m(9.8)(9.5 - 1.0)
KE = 97m = 83.3m
KE = 13.7m = ½mv²
v² = √(2(13.7)
v = 5.2345...
v = 5.2 m/s
Give an example of intense aerobics activity. Prompt must be accurate.
Answer:
Explanation:
An example of an intense aerobic activity would be running/ sprinting sprinting targets six specific muscle groups: hamstrings, quadriceps, glutes, hips, abdominals and calves. Sprinting is a total body workout featuring short, high-intensity repetitions and long, easy recoveries.
A 5kg mass is pushed with a force of 10N for a distance of 2.5 meters. The work done is
W = 25 J
Explanation:
Work done on an object is defined as
[tex]W = Fd = (10\:\text{N})(2.5\:\text{m}) = 25\:\text{J}[/tex]
E TRUE OR FALSE: Write the word TRUE if the statement is correct, and FALSE if it is not. (3 points each). Write your answer on a separate sheet of paper. 1. Most EM waves has the same speed. 2. EM waves travel at the speed of 4x108 m/s. 3. Electromagnetic waves are transverse waves consisting of changing electric fields and changing magnetic fields. 4. Electromagnetic waves transfer energy through a vacuum. 5. A wave is a disturbance that transfers energy .what the answer?
Answer:
TRUE
FALSE
TRUE
TRUE
TRUE
TRUE
Explanation:
1. Most EM waves has the same speed. True
2. EM waves travel at the speed of 4x108 m/s. False
3. Electromagnetic waves are transverse waves consisting of changing electric fields and changing magnetic fields. True
4. Electromagnetic waves transfer energy through a vacuum. True
5. A wave is a disturbance that transfers energy. True
If the voltage across a 5-F capacitor is 2*e^-3
V find the current and the power
According to the table what was the hikers total displacement the graph has 4km 6km 4km 6km
Answer:
0
Explanation:
0 is the answer
two billiard balls moving along the same line hit each other head-on. each has a mass of 0.220 kg; one has an initial velocity of 1.84 m/s, the other an initial velocity of 0.530 m/s. if the collision is elastic, what are their final velocities? ignore friction.
Hi there!
Since the collision is elastic, we must also satisfy the following condition:
Ei = Ef, or:
KEi = KEf
Begin by writing an expression for momentum. (p = mv) Remember that one ball's direction is negative; in this instance, we can let the second ball be moving LEFT.
mv1 + mv2 = mvf1 + mvf2
0.220(1.84) + 0.220(-.530) = 0.220(vf1 + vf2)
0.2882/0.220 = vf1 + vf2
1.31 = vf1 + vf2
Now, we can express this as a conservation of energy:
1/2mv1² + 1/2mv2² = 1/2mvf1² + 1/2mvf2²
Plug in values and simplify:
0.403315 = 1/2m(vf1² + vf2²)
Simplify further:
3.6665 = vf1² + vf2²
Use the equation derived from momentum above and solve for one variable:
vf2 = 1.31 - vf1
Plug in this expression for vf2:
3.6665 = vf1² + (1.31 - vf1)²
Expand:
3.6665 = vf1² + 1.7161 - 2.62vf1 + vf1²
Simplify:
1.9504 = -2.62vf1 + 2vf1²
Solve for vf1 using a graphing calculator:
vf1 = -0.53 m/s or 1.84 m/s; we must figure out which one is correct.
Since v1 is heading to the right initially with a velocity of 1.84 m/s, we know that the ball's velocity could not have stayed the same in both magnitude and direction, so the final velocity must be -0.53 m/s.
Now, we can solve for the velocity of the other ball (initial of 0.53 m/s):
vf2 = 1.31 - (-0.53) = 1.84 m/s.
Now, you could have also made the connection that when two balls of the SAME MASS experience an ELASTIC collision, the velocities are simply "exchanged" from one to another. I just used this more "extensive" method to prove this.
A 100 N crate is being pulled at a constant velocity by a rope a 30 degrees to the horizontalas depicted in the diagramFind the force of friction Show your work and explain your reasoning in two to sentences
Answer:
Explanation:
As the velocity is constant, Net force is zero. This means that the friction force must equal the applied force in the horizontal direction.
Ff = Fcosθ
if we had a coefficient of kinetic friction μ, we could quantify the friction force more precisely.
μN = Fcosθ
μ(mg - Fsinθ) = Fcosθ
μmg = Fcosθ + μFsinθ
100μ = F(cos30 + μsin30)
F = 100μ / (cos30 + ½μ)
Ff = 100μcos30 / (cos30 + ½μ)
A 100 N create is being pulled at a constant velocity by a rope a 30 degrees to the horizontal as depicted in the diagram given in question the force of friction Ff = 100μcos30 / (cos30 + ½μ).
What is force?
A force in physics is an effect that has the power to alter an object's motion. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.
As the velocity is constant, Net force is zero. This means that the friction force must equal the applied force in the horizontal direction.
Ff = Fcosθ
if we had a coefficient of kinetic friction μ, we could quantify the friction force more precisely.
μN = Fcosθ
μ(mg - Fsinθ) = Fcosθ
μmg = Fcosθ + μFsinθ
100μ = F(cos30 + μsin30)
F = 100μ / (cos30 + ½μ)
Ff = 100μcos30 / (cos30 + ½μ)
the force of friction Ff, is 100μcos30 / (cos30 + ½μ).
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Help pls!
A 3 kg mass is raised a distance of 14 m above the earth by a vertical force of 93 N.
The final kinetic energy of the mass, to 3 significant figures, if it was originally at rest is:
[tex] \large★·.·´¯`·.·★ {Answer}★·.·´¯`·.·★[/tex]
As we know that Kinetic Energy is the Energy that is possessed by a moving object. and if the object is at rest then it doesn't have velocity therefore there is no kinetic Energy.
In the numerical terms we can express it as : -
[tex] \sf0.00 \: \: joules[/tex][tex]꧁ \: \large \frak{Eternal \: Being } \: ꧂[/tex]
This is two or more elements chemically combined in a fixed ratio.
Example: water, carbon dioxide, sodium chloride
Which item is not a solid-state component?
an integrated circuit
a vacuum tube
a diode
a transistor
Answer:
a vacuum tube is NOT a solid state component
Pendulum makes 12 complete swings in 8 seconds, what are its frequency and period on earth
Hi there!
We can begin by finding the period of the pendulum.
[tex]T = \text{ # of complete swings / seconds} = 12 / 8 = \boxed{\text{1.5 sec}}[/tex]
The frequency is simply the reciprocal of the period, so:
[tex]f = \frac{1}{T} = \frac{1}{1.5} = \frac{2}{3}Hz \text{ or } \boxed{0.67 Hz}[/tex]
Clothes stick together when you pull them out of the dryer because
clothing is a conductor.
clothing is an inductor.
they are not charged.
of static electricity.
Uranus (mass = 8.68 x 1025 kg) and its moon Miranda (mass = 6.59 x 1019 kg) exert a gravitational force of 2.28 x 1019 N on each other. How far apart are they? cs [?] x 10?'m Coefficient (green) Exponent (yellow) Enter
Answer:
Explanation:
F = GMm/d²
d = √(GMm/F)
d = √(6.674e-11(8.68e25)(6.59e19) / 2.28e19)
d = 1.29398e8 = 1.29 x 10^8 m center to center
Answer:
1.29 x 10^8 m apart
Explanation:
Works in Acellus!
Can anyone help me with question 10 a.
Answer:
it's ahfdfhhh hhgfdjjjjuyggffdddcff
Water has higher specific heat than aluminum. This is all what you should know to answer following questions. An aluminum rod of mass 1 kg at temperature of 80^0C is placed into 1l of water of temperature 10^0C . there is no heat exchange with surroundings. Which material experiences greater change in temperature while system is reaching the thermal equilibrium
Answer:
The Aluminum
Explanation:
With a larger specific heat, water requires more heat to raise its temperature by a temperature degree.
In this system, with equal masses of water and aluminum, the heat moving from the aluminum lowering its temperature by one degree is not sufficient to raise the water temperature by one degree.
What is the meaning of eddy currents in electromagnetic series?
Answer:
currents which circulate in conductors like swirling eddies in a stream in electromagnetic series....
what is the velocity of this graph between points a and b? 0.0m/s 2.5m/s 5.0m/s 6.0m/s?
Answer:
Pick c is the right one
Explanation:
5.0m/s
what two things make up an ionic bond?
A 0,9 -kg object attached to the end of a string swings in a vertical circle (radius = 75 cm). At the top of the circle the speed of the object is 6,5 m/s. What is the magnitude of the tension in the string at this position?
I need your help with this question, it’s my final exam for physics
Answer:
●Bx=Bcos40
Bx=10 × 0.76
Bx=7.6
●By=Bsin40
By=10×0.64
By=6.4
Hope it will help you.
tell types of instruments
Answer:
Instrument Use
Accelerometer Measures acceleration
Altimeter Measures altitude of an aircraft
Ammeter Measures electric current in ampere
Anemometer Measures wind speed
A magnesium ion has a charge of +2 and an oxygen ion has a charge of –2. What is the chemical formula of the compound made of these ions? (correct answer gets brainliest)
A) Mg2O2
B) MgO
C) MgO2
D) Mg2O
What happens to the iron in the coilgun if the electricity in the coil was turned on
A clothes dryer in a home draws a current of 10 amps when connected on a special 220-volts household circuit.what is the resistance of the dryer?
Answer:
22Ω
Explanation:
if V ⇒ voltage
I ⇒ current
R ⇒ resistance
V = IR
220 = 10 x R
220 / 10 = R
22 = R
A 1300 watt hair blow dyer is designed to operate on 120 Volts. How much current does the dryer require
Answer:
10.83 Amperes
Explanation:
if A ⇒ current
W = VA
1300 = 120 x A
1300 / 120 = A
10.83 = A
The volume of a toy car was calculated by displacing water. The water
rose by 20ml when the object was placed into the graduated cylinder. The balance showed the toy car had a
mass of 500grams. Calculate the density of the toy car
Answer:
D = 25g/cm³
Explanation:
1ml = 1cm³
D = m/V
D = 500g/20cm³
D = 25g/cm³
Nikolai is using a hand-operated grain mill to grind wheatberries into flour. The mill is operated by spinning a fly-wheel with radiusR= 23 cm, which has a handle attachedto the outer edge. After grinding for a few minutes at a con-stant angular speedωi, he lets go of the handle and allows themechanism to come to rest as it undergoes constant angularacceleration. This happens over the course oft= 0.50 s, andthe flywheel undergoes a quarter of a rotation during this time.What is the linear tangential accelerationaof the handle as itcomes to rest? For the limits check, investigate what happenstoaas the time required to stop the flywheel becomes small(t→0).
Answer:
Explanation:
α = Δω/t = (0 - ωi)/0.50 = -2ωi rad/s²
ωf² = ωi² + 2αθ
θ = (ωf² - ωi²) / 2α
2π/4 = (0² - ωi²) / (2(-2ωi))
2π/4 = ωi / 4
ωi = 2π rad/s
α = -2(2π) = -4π rad/s²
a = rα = 0.23(-4π) = 0.92π m/s² ≈ -2.89 m/s²
as the time to stop approaches zero, acceleration goes toward infinity.
calculate the surface area of a box whose mass is 200 kg and exerts a pressure of 100 Pascal on the floor.
Answer:
Explanation:
If 2×2 is 4 so 1 kg can be 1 gram if it belive on it self some people change