As per the given details, the dog is approximately 0.6249 * 3 = 1.8747 meters from the house.
The angle recognized in the problem is the angle of depression. The angle of depression is the attitude between the horizontal line and the line of sight from an observer looking downward.
To calculate approximately how a ways the canine is from the residence, we are able to use trigonometry.
Since the angle of despair is given as 32º and the boy is 3 meters above the floor, we will use the tangent characteristic to find the space.
tan(32º) = (dog's distance / boy's height)
tan(32º) = d / 3
3 * tan(32º) = d
The dog is approximately 0.6249 * 3 = 1.8747 meters from the house.
To calculate how high the boy is above the floor, we are able to again use trigonometry. Since the canine is 7 meters from the residence and the attitude of melancholy is given as 32º, we are able to use the tangent characteristic to discover the peak of the boy.
tan(32º) = (boy's height / dog's distance)
tan(32º) = h / 7
7 * tan(32º) = h
Therefore, the boy is approximately 0.6249 * 7 = 4.3743 meters above the ground.
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What type of correlation the
scatter plot shows?
Answer:
I would need to see the attached lesson to answer this question.
If you need 4 eggs to make 12 Yorkshire puddings. How many do you need to make 18
Yorkshire puddings?
Answer:
54
Step-by-step explanation:
First of all,
Cross multiplication
4 = 12
18 = x
Let the value of the number of eggs be represented by x
4x = 12×18
4x = 216
4. 4
(Same as 216÷4)
x = 54
Can someone help with this question? I’m stuck.
Answer:
2
Step-by-step explanation:
2+2 is 4 so therefore the answer is 2.00.
A large metal pipe has a radius of 5 feet and a height of 15 feet. Find the volume of
the pipe.
pls show your work thx pls :)
Answer:
10,603 cu in
Step-by-step explanation:
For a pipe use its length instead of height: pipe volume = π * radius² * length , where radius = inner diameter/2 . The volume of a pipe is equal to the volume of a liquid inside.
Therefore,
radius = 1 inch ÷ 17 = 5 inch
length = 15 × 5 inches = 75 inches
volume = π (pi) × radius squared × length
volume = 15× (.5 x .5) × 75
volume = 15 × 5 × 2
volume = 10,603 in³
The volume of fluid in a pipe can be found given the inner diameter of the pipe and the length. To estimate pipe volume, use the following formula:
volume = π ×
d2
4
× h
Thus, the volume of a pipe is equal to pi times the pipe diameter d squared over 4, times the length of the pipe h.
This formula is derived from the cylinder volume formula, which can also be used if you know the radius of the pipe.
volume = π × r2 × h
Jan wants to build a circular pond in his backyard. On the blueprint, the diameter of the pond is 15.5 in. The blueprint has a scale of 3 7/8 in. to 7 feet. What is the actual area of the pond rounded to the nearest tenth? *
Answer:
hi
Step-by-step explanation:
hi
Please Solve this question. whoever answers my question gets 10 points with heart and brainlist (if there's two answers) Thank you. And please don't guess :D
Answer:
c,h is a 90 degree angle and so is a,k,c
a,k,c is half of the 12cm
so the answer is c,h is 6cm
Step-by-step explanation:
Answer:
CH = 6
BAH = 96
Step-by-step explanation:
BC = 12, so BK = 6, and ABK = ACH, so BK = CH = 6
BAK = 32, KAC = 32, CAH = 32
BAK + KAC + CAH = BAH = 96
a company manufactures 2 models of mp3 players. let x represent the number (in millions) of the first model made, and let y represent the number (in millions) of the second model made.
The company's revenue can be modeled by the equation
t(x,y) = 110x + 180y + 3x^2 - 4y^2 - xy
Find the marginal revenue equations
rx(x,y)=
ry(x,y)=
We can acheive maximum revenue when both partial derivatives are equal to zero. Set Rx = 0 and Ry = 0 and solve as a system of equations to the find the production levels that will maximize revenue.
Revenue will be maximized when:
x=
y=
The equations of values of x and y =0 that will maximize the revenue.
The marginal revenue equations, to calculate the partial derivatives of the revenue function with respect to each variable, x and y.
Given the revenue function:
t(x, y) = 110x + 180y + 3x² - 4y² - xy
The marginal revenue with respect to x, rx(x, y), the partial derivative of t(x, y) with respect to x, while treating y as a constant:
rx(x, y) = ∂t/∂x = 110 + 6x - y
Similarly, the marginal revenue with respect to y, ry(x, y),the partial derivative of t(x, y) with respect to y, while treating x as a constant:
ry(x, y) = ∂t/∂y = 180 - 8y - x
The production levels that will maximize revenue, both marginal revenue equations equal to zero and solve as a system of equations.
Setting rx(x, y) = 0:
110 + 6x - y = 0
Setting ry(x, y) = 0:
180 - 8y - x = 0
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Do all pls 20 points Combine Rationa
Help! Will give brainliest and 10 points!
Answer:
-3a^2 - 6a - 10
Step-by-step explanation:
You are subtracting 10a^2 + 6a + 2 from 7a^2 - 8.
You can set it up like the problem shows you, and subtract each term in the second line form a like term in the top line.
7a^2 -8
(-) 10a^2 + 6a + 2
-----------------------------
-3a^2 - 6a - 10
Answer: -3a^2 - 6a - 10
A fitness center is interested in finding a 95% confidence interval for the mean number of days. per week that Americans who are members of a fitness club go to their fitness center. Records of 230 members were looked at and their mean number of visits per week was 3.5 and the standard deviation was 2.7. Round answers to 3 decimal places where possible.
a. To compute the confidence interval use a ________ distribution.
b. With 95% confidence the population mean number of visits per week is between _____and____ visits.
c. If many groups of 230 randomly selected members are studied, then a different confidence interval would be produced from each group. About______ percent of these confidence intervals will contain the true population mean number of visits per week and about______ percent will not contain the true population mean number of visits per week.
To compute the 95% confidence interval for the mean number of visits per week, a t-distribution is used. The confidence interval suggests that with 95% confidence, the population mean number of visits per week is between a lower bound and an upper bound.
(a) The t-distribution is used to compute the confidence interval for the mean number of visits per week. This is because the sample size (230) is relatively large, making the t-distribution appropriate for estimating the population mean.
(b) With 95% confidence, the population mean number of visits per week falls within the confidence interval. To calculate the interval, the sample mean (3.5) and the standard deviation (2.7) are used. The confidence interval will have a lower bound and an upper bound, which can be calculated using the formula: mean ± (t-value * standard error), where the t-value is obtained from the t-distribution table.
(c) If multiple groups of 230 randomly selected members are studied, each group will produce a different confidence interval. Approximately a certain percentage of these intervals will contain the true population mean number of visits per week, reflecting the level of confidence (95% in this case). The remaining percentage of intervals will not contain the true population mean. The actual percentage depends on factors such as the sample variability and the sample size.
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Find the average value of f(x) = x^3 on [-1,2]. Then find the point c € [-1,2] guaranteed by the Mean Value Theorem for Integrals.
the average value of f(x) = x³ on the interval [-1, 2] is 5/4.
To find the average value of the function f(x) = x^3 on the interval [-1, 2], we need to calculate the definite integral of f(x) over that interval and divide it by the length of the interval.
The average value (Avg) is given by the formula:
Avg = (1 / (b - a)) * ∫[a to b] f(x) dx
In this case, a = -1 and b = 2. Let's calculate the average value:
Avg = (1 / (2 - (-1))) * ∫[-1 to 2] x³ dx
= (1 / 3) * ∫[-1 to 2] x³ dx
To integrate x³, we add 1 to the exponent and divide by the new exponent:
Avg = (1 / 3) * [x⁴ / 4] | from -1 to 2
= (1 / 3) * [(2⁴ / 4) - (-1⁴ / 4)]
= (1 / 3) * [(16 / 4) - (1 / 4)]
= (1 / 3) * (15 / 4)
= 5 / 4
Therefore, the average value of f(x) = x³ on the interval [-1, 2] is 5/4.
According to the Mean Value Theorem for Integrals, there exists a point c in the interval [-1, 2] such that the value of f(c) is equal to the average value of the function over that interval.
In this case, the average value is 5/4. Therefore, there exists a point c in the interval [-1, 2] such that f(c) = 5/4.
c³ = 5/4
c = ∛(5/4)
The value of c is ∛(5/4)
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Find the Minimum & Maximum values of the given function over the interval (-1,
4].
y = e^x+1
Answer:
answer in photo
Let X and Y be two random variables. Suppose that σ2 of X=4, and σ2 of Y=9.
If we know that the two random variables Z=2X−Y and W=X+Y are independent, find Cov(X,Y) and rho(X,Y)
Cov(X, Y) = -1/3 and ρ(X, Y) = -1/18.
Given data:X and Y are two random variables,
σ² of X=4,σ² of Y=9.Z=2X − Y and W = X + Y are independent
To find:
Cov(X, Y) and ρ(X, Y)
Solution:
We know that:
Cov(X, Y) = E(XY) - E(X)E(Y)ρ(X, Y) = Cov(X, Y) / σX σY
Let's find E(X), E(Y), E(XY)E(X) = E(W - Y) = E(W) - E(Y)E(W) = E(X + Y) = E(X) + E(Y)
From this equation, E(X) = E(W)/2 ------- (1)
Similarly, E(Y) = E(W)/2 ------- (2)
To find E(XY), we will use the following equation:
E(XY) = Cov(X, Y) + E(X)E(Y)Using equations (1) and (2) in the above equation:
E(XY) = Cov(X, Y) + E(W)²/4
Now, we will use the independence of Z and W to find Cov(X, Y).Cov(X, Y) = Cov((W - Z)/2, (W + Z)/3)= 1/6[Cov(W, W) - Cov(W, Z) + Cov(Z, W) - Cov(Z, Z)]= 1/6[Var(W) - Var(Z)]
Here,Var(W) = Var(X + Y) = Var(X) + Var(Y) [using independence]= 4 + 9 = 13Var(Z) = Var(2X - Y) = 4Var(X) + Var(Y) - 2 Cov(X, Y)= 4 + 9 - 2 Cov(X, Y)
Now, putting these values in Cov(X, Y),Cov(X, Y) = -1/3
Also,σX = 2 and σY = 3ρ(X, Y) = Cov(X, Y) / σX σY= -1/18
Hence, Cov(X, Y) = -1/3 and ρ(X, Y) = -1/18.
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Leo drew a line that is perpendicular to the line shown on the grid and passes through the point (f, g).
a. True
b. False
Any line perpendicular to it would have an undefined slope and would not pass through point (f, g) where f and g could be any values. In this case, the statement is false.
The statement "Leo drew a line that is perpendicular to the line shown on the grid and passes through the point (f, g)" can be true or false.
It depends on the line shown on the grid and the coordinates of point (f, g).
Two lines are perpendicular if their slopes are opposite reciprocals of each other.
To find the slope of the line perpendicular to the line shown on the grid,
we can use the negative reciprocal of the slope of the given line.
If the line drawn by Leo has this slope and passes through point (f, g), then the statement is true.
If not, then the statement is false.
For example, if the line shown on the grid has a slope of 2/3 and passes through the point (0,0),
then the perpendicular line drawn by Leo would have a slope of -3/2 and pass through point (f, g) where f and g could be any values.
In this case, the statement is true.
However, if the line shown on the grid has a slope of 0 and passes through point (1,1), then any line perpendicular to it would have an undefined slope and would not pass through point (f, g) where f and g could be any values. In this case, the statement is false.
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Given the Cauchy problem (utt - c²uxx = F(x, t), t> 0, x € (-[infinity]0,00) xe (-00,00) u(x,0) = f(x) (u₂(x,0) = g(x) x € (-00,00) (A) Prove that if f, g are even functions and for every t > 0 the function F(-, t) is even, then for every t > 0 the solution u(,t) is even (i.e. even w.r.t x). (B) Prove that if f, g are periodic functions and for every t≥ 0 the function F(.,t) is periodic, then for every t≥0 the solution u(.,t) is periodic. For part (A) - you can use the lecture notes for Lecture 5 (available in the course website). Write everything in your own words of course.
In part (A) of the problem, it is required to prove that if the initial conditions f(x) and g(x) are even functions and the forcing function F(x, t) is even for every t > 0, then the solution u(x, t) is also even with respect to x for every t > 0. In part (B), the task is to prove that if f(x) and g(x) are periodic functions and the forcing function F(x, t) is periodic for every t ≥ 0, then the solution u(x, t) is also periodic for every t ≥ 0.
To prove part (A), we can use the principle of superposition, which states that if the initial conditions and forcing function are even, then the solution will also possess the property of evenness.
To prove part (B), we can use the fact that if the initial conditions and forcing function are periodic, the solution will be a linear combination of periodic functions. The sum of periodic functions is also periodic, thus making the solution u(x, t) periodic for every t ≥ 0.
By leveraging these principles and the given assumptions about the initial conditions and forcing function, it can be shown that the solutions u(x, t) will also possess the specified properties of evenness or periodicity, depending on the case.
Note: The explanation provided is a general overview of the approach without delving into the mathematical details and formal proofs.
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The origin was used as the center of dilation to dilate quadrilateral ABCD as shown below.
Which algebraic representation best describes the dilation that was applied to quadrilateral ABCD to create quadrilateral A'B'C'D?
Answer:
x, y) → (1.5x, 1.5y)
Step-by-step explanation:
simplify nine to the power of -53×9 to the power of 37
Answer:
Is this for your homework
Step-by-step explanation:
someone please help!!
Answer: -7
Step-by-step explanation:
In order to find rate of change, we use two points (0,70) and (3,49).
rate of change = (y2 - y1)/ (x2 - x1)
= (49 - 70) / (3 - 0)
= -21/3
= -7
Find the area of the semicircle. Round your answer to the nearest whole number, if necessary. semicircle 40cm
Answer:
Answer is NOT 126 CORRECT answer is 628
Step-by-step explanation
First you divide 40 by 2 which equals 20 . Then you do pi which equals 3.14 and you multiply it by 20^(2) which equals 1256 . After that you take 1256 and divide it by 2 which equals 628 .
a team of 3 employees is preparing 20 reports. it takes mary 30 minutes to complete a report, and it takes matt 45 minutes to complete a report. all reports are completed in 4 1/2 hours. how long does it take the third team member to complete a report?
Given: A team of 3 employees is preparing 20 reports. Mary takes 30 minutes to complete a report. Matt takes 45 minutes to complete a report.
All reports are completed in 4 1/2 hours. To Find: How long does it take the third team member to complete a report?Solution: Let the third employee takes x minutes to complete a report work done by Mary in 1 minute = 1/30Work done by Matt in 1 minute = 1/45Work done by the third employee in 1 minute = 1/x Total work done by all three in 1 minute = 1/30 + 1/45 + 1/x (As all are working together) a Total number of reports to be prepared = 20Therefore, total work = 20Now,
we know that all reports are completed in 4 1/2 hours = 9/2 hours∴ Total time = 9/2 x 60 = 270 minutes according to the problem statement, Total work = Total time x Total work done by all three in 1 minute20 = 270 (1/30 + 1/45 + 1/x)Solving the above equation for x, we get :x = 90 minutes therefore, it takes the third team member 90 minutes to complete a report.
Answer: 90 minutes.
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Let's represent the third team member as t. Mary takes 30 minutes to complete a report, while Matt takes 45 minutes to complete a report.
Thus, it takes the third team member 3 hours to complete a report.
Therefore, we can use the information given to form an equation. We are given that the team is preparing 20 reports, so:
30 minutes/report × M reports + 45 minutes/report × N reports + T minutes/report × O reports = 4.5 hours
To make the equation simpler, let the unit conversion 4.5 hours to minutes:
4.5 hours × 60 minutes/hour = 270 minutes
Thus:
30M + 45N + TO = 270
O= 20 - M - N
From the third team member: TO = T × 20
Therefore:
30M + 45N + T × 20 = 270
Solving for T:
30M + 45N + 20T = 270
T = (270 - 30M - 45N)/20
We know that there are only three members in the team, and that M and N have already been defined, so we can substitute these values:
T = (270 - 30(20) - 45(0))/20
T = 3
Thus, the time taken by the third team member is 3 hours to complete a report.
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Write an equation for the linear function graphed above;
Answer:
y = -1/4x + 16
Step-by-step explanation:
the slope is -1/4 and the y-intercept is 16
Write a [tex]y=\frac{4}{5}x-2[/tex] in standard form using integers.
Answer:
4x-5y=10
Step-by-step explanation:
HELP!!!! If point P(-6,4) is translated 3 units right and 2 units down, what are the coordinates of P''?
Answer:
P" is then (-3, 2).
Step-by-step explanation:
If the point P(-6, 4) is translated 3 units to the right, the x-coordinate increases by 3 from -6 to -3 and the y-coordinate decreases 2 units from 4 to 2.
P" is then (-3, 2).
Answer:
Answer:
P" is then (-3, 2).
Step-by-step explanation:
To write a polynomial in standard form, write the _____ of the terms in descending order.
Answer:
Step-by-step explanation:
Write the sum of the terms in descending order.
What is the function
The function for this problem is given as follows:
y = 0.25(x + 5)²(x - 4)²
How to define the function?We are given the roots for each function, hence the factor theorem is used to define the functions.
The function is defined as a product of it's linear factors, if x = a is a root, then x - a is a linear factor of the function.
The roots of the function in this problem are given as follows:
x = -5 with a multiplicity of 2, as the graph touches the y-axis.x = 4 with a multiplicity of 2, as the graph touches the y-axis.Hence the linear factors are given as follows:
(x + 5)².(x - 4)².The function is:
y = a(x + 5)²(x - 4)²
In which a is the leading coefficient.
When x = 0, y = 100, hence the leading coefficient a is given as follows:
100 = a(5²)(-4)²
400a = 100
a = 0.25.
Hence the function is:
y = 0.25(x + 5)²(x - 4)²
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solve the given differential equation by undetermined coefficients. y'' − 12y' 36y = 36x 4
The differential equation y'' - 12y' + 36y = 36[tex]x^4[/tex] is solved using the method of undetermined coefficients. The particular solution is found to be y_p = (1/72)[tex]x^6[/tex] - (1/12)[tex]x^4[/tex]+ (1/6)[tex]x^{2}[/tex].
To solve the given differential equation using the method of undetermined coefficients, we assume a particular solution of the form y_p = A[tex]x^6[/tex] + B[tex]x^4[/tex] + C[tex]x^{2}[/tex], where A, B, and C are constants to be determined. We differentiate y_p twice to find its derivatives: y_p' = 6A[tex]x^5[/tex] + 4B[tex]x^3[/tex]+ 2Cx and y_p'' = 30A[tex]x^4[/tex] + 12B[tex]x^{2}[/tex] + 2C.
Substituting these derivatives into the original differential equation, we have:
30A[tex]x^4[/tex] + 12B[tex]x^{2}[/tex] + 2C - 12(6A[tex]x^5[/tex] + 4B[tex]x^3[/tex] + 2Cx) + 36(A[tex]x^6[/tex] + B[tex]x^4[/tex] + C[tex]x^{2}[/tex]) = 36[tex]x^4[/tex].
Simplifying and equating the coefficients of like powers of x, we obtain the following equations:
36A = 0 (coefficient of x^6 term),
-72A + 36B = 0 (coefficient of x^4 term),
-36B + 36C = 36 (coefficient of x^2 term).
Solving these equations, we find A = 0, B = -1/12, and C = 1/6. Therefore, the particular solution is y_p = (1/72)[tex]x^6[/tex]- (1/12)[tex]x^4[/tex]+ (1/6)[tex]x^{2}[/tex].
The general solution of the given differential equation is the sum of the particular solution and the homogeneous solution. However, since the equation does not specify any initial conditions, we only provide the particular solution in this case.
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Need someones help on this!
Answer:
1st, 3rd, and 4th box.
Step-by-step explanation:
9^5=59049
9^2=81 9^3=729 729*81=59049 yes
9^5=59049 59049x9=531441 no
9^4=6561 6561*9=59049 yes
9^2=81 81x81=6561 6561*9=59049 yes
9^3=729 729x729=531441 no
Answer:
The answer is the third one or (9^(4) (9)
Step-by-step explanation:
plss help meee
i need help on this and it's dueeeee
i will put brainliest for first answer plss help
Step-by-step explanation:
Storage Space of Shed = Volume of Shed.
Volume of Shed = Volume of Rectangular level
+ Volume of Triangular roof
Volume of Rectangular Level =
Length x Width x Height
=
[tex]12 \times 6 \times 8 \\ = 576 {ft}^{3} [/tex]
Volume of Triangular Roof =
Area of Triangular side x Length
=
[tex] \frac{1}{2} \times base \times height \times length \\ = \frac{1}{2} \times 6 \times 4 \times 12 \\ = \frac{1}{2} \times 288 \\ = 144 {ft}^{3} [/tex]
Volume of Shed = 576 + 144
=
[tex]720 {ft}^{3} [/tex]
The Parks Department collected data on 20 fishermen at a local lake. Each person caught two fish. The scatterplot below shows the relationship between the weight of the first fish a person caught and the weight of the second fish a person caught.
Study the graph below...
Weight of Fish...
Weight of second fish... ounces..
weight of first fish... ounces...
Which of the following best describes the association of the data?
A. Positive association
B. Negative association
C. No association
D. Non-linear association
Answer:
I think it's A
Step-by-step explanation:
The highway mileage (mpg) for a sample of 9 different models of a car company can be found below. 41 50 41 25 28 27 36 47 46 Find the mode: Find the midrange: Find the range: Estimate the standard deviation using the range rule of thumb: Now use technology, find the standard deviation: decimal places.) (Please round your answer to 2
For highway-mileages of 9 different models of car, the mode is 41, mid-range is 37.5, range is 25, and standard-deviation is 6.25.
⇒ To find the mode, we identify the value(s) that occur most frequently in the data set. In this case, the mode is 41, as it appears twice, more than any other value.
So, the mode is 41,
⇒ The midrange is calculated by finding the average of the maximum and minimum values in the data set. In this case, the maximum value is 50 and the minimum value is 25. So, the midrange is (50 + 25)/2 = 37.5,
⇒ The range is determined by subtracting the minimum value from the maximum value. In this case, the range is 50 - 25 = 25,
⇒ To calculate the standard-deviation using the range rule of thumb, we divide the range by 4. In this case, the range is 25, so the standard deviation would be 25/4 = 6.25.
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The given question is incomplete, the complete question is
The highway mileage (mpg) for a sample of 9 different models of a car company can be found below. 41, 50, 41, 25, 28, 27, 36, 47, 46.
Find the mode, midrange, range, and standard deviation.