a car is moving due south for 4hr and covered a distance of 144km what is the velocity of the car?​

Answers

Answer 1

Answer:

velocity ,V=?,T=4hr,Distance ,144km,

V=distance divide by time

=144/4=36km/hr


Related Questions

What is the instruments used to measure light intensity, wind intensity and relative humidity ​

Answers

Answer:

we use : photometer to measure light intensity

:Anemometer to measure wind intensity

:Hygrometer to measure relative humidity

What is the ideal temperature for a lithium-ion battery?.

Answers

Answer:

16 to 25 degrees f

Explanation:

Se lanza un balón verticalmente hacia arriba con una velocidad de 72 km/h. ¿Qué altura recorrió dicho cuerpo después de 0.05 minutos? (g = 10m/s2)

Answers

Usando la información contenida en la pregunta, la distancia que recorre la bola hacia arriba es de 15 m.

Velocidad inicial = 20 m / s

Tiempo= 3 s

Aceleración por gravedad =  10 ms-2

Velocidad final = 0 m / s

Usando la ecuación;

h = u t - 1 / 2 g t 2

h = (20 × 3) - 1/2 × 10 × (3) ^ 2

h = 60 - 45

h = 15 m

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A 800N mountain climber scales a 140m cliff. How much work is done by the mountain climber?

Answers

Answer:

112 [kJ]

Explanation:

1) related formula is: A=F*S, where A - required work [J], F - force [N], S - distance [m].

2) according to the formula above: A=140*800=112000[J]=112 [kJ]

Answer:

112000 J

Explanation:

800N x 140m

When waves are closer together, the distance between them is _________, therefore the waves have __________ wavelength.

Answers

Answer:

less' shorter

Explanation:

be cuase science

Answer:

The answer is D.

Explanation:

When waves are closer together, the distance between them is less, therefore the waves have longer wavelength.

What is the rotational inertia of the bug-rod-spheres system about the horizontal axis through the center of the rod

Answers

Answer:

C) 5ML^2

Explanation:

2 Spheres of mass M

Bug's mass 3M

Rod length 2L, radius L

Find Rotational Inertia I

I=Σmr^2

I=(3M+M+M)L^2

I=5ML^2

The rotational inertia of the bug-rod-spheres system about the horizontal axis through the center of the rod is 5ML².

Rotational inertia of the system

The rotational inertia of the system is determined by summing all the masses together and multiply with the radius.

I(t) = Σmr²

Where;

m is the massr is the radius

I(t) = Inertia of the 2 spheres + inertia of the bug

I(t) = (M + M)L²  + (3M)L²

I(t) = 2ML² + 3ML²

I(t) = 5ML²

Thus, the rotational inertia of the bug-rod-spheres system about the horizontal axis through the center of the rod is 5ML².

Complete question is below:

There are 2 Spheres of mass M and Bug's mass 3M. The Rod length is 2L, radius L.

Learn more about rotational inertia here: https://brainly.com/question/14001220

Acceration is a change in motion over time:
True False

Answers

The answers is definitely true for a fact

A 2kg water balloon is flying at a rate of 4m/s^2. With what force will it hit its target?

Answers

Explanation:

F=m×a

m=2kg

a=4m/s^2

F=2kg×4m/s^2

F=8N

A 2 kg water balloon is flying at a rate of 4 m/s². Force with which balloon will hit its target is 8 Newton.

What is force?

A force is a push or pull upon an object resulting from the object's interaction with another object. Whenever there is body with some mass than there is force.

Given in the question mass and acceleration of balloon, force is given as

F = m*a

m = 2 kg

a = 4 m/s²

F = 2 kg×4 m/s²

F = 8 N

A 2 kg water balloon is flying at a rate of 4 m/s². Force with which balloon will hit its target is 8 Newton.

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What is the scientific name for a push or a pull?

Answers

Answer:

thats a force

Explanation:

Answer:

force

Explanation:

the definition of a push or pull is force

BEFORE COLLISION
MASS = 4200 kg
MASS = 990 kg
V = 10 m/s
AFTER COLLISION
V = ?
V = 2 m/s
What is the velocity after the crash?

Answers


Anyways the answer is x=2

Initial kinetic energy KE = 1/2 m1v12 + 1/2 m2v22 = joules. The following calculation expects you to enter a final velocity for mass m1 and then it calculates the final velocity of the other mass required to conserve momentum and calculates the kinetic energy either gained or lost to make possible such a collision.

If acceleration of a body starting from the rest is 0.5m/s^2 how long will it take the body to travel 400m(if u are genius answer this)​

Answers

Answer:

[tex]\huge\boxed{\sf t = 40\ seconds}[/tex]

Explanation:

Given data:

Acceleration = a = 0.5 m/s²

Initial Velocity = Vi = 0 m/s

Distance = S = 400 m

Required:

Time = t = ?

Formulas used:

2 formulas

Third Equation of motion (2as = Vf²-Vi²)First Equation of motion (Vf = Vi + at)

Solution:

Using third equation of motion firstly

2as = Vf²-Vi²

2(0.5)(400) = Vf² - 0²

400 = Vf²

Taking sqrt

Vf = 20 m/s

Now, Using First equation of motion:

Vf = Vi + at

20 = 0 + 0.5t

0.5 t = 20

Divide both sides by 0.5

t = 40 seconds

[tex]\rule[225]{225}{2}[/tex]

Hope this helped!

~AH1807

a uniform metre rule of mass 100g balances at the 40cm mark when a mass X is placed at the 10cm mark what is the value of x.pls help I don't know how to solve it​

Answers

Answer:

The fulcrum of the metre stick is at the 40 cm mark

100 g * 10 cm = 1000 g-cm clockwise torque

x * 30 cm = 1000 gm-cm = counterclockwise torque for balance

X = 1000 / (40 -10) = 1000 / 30 = 33.3 gm  at 10 cm to balance

what is radiation?....​

Answers

Answer:

the emission of energy as electromagnetic waves or as moving subatomic particles, especially high-energy particles which cause ionization.

is called radiation

Answer:

Radiation is energy that comes from a source and travels through space at the speed of light

Explanation:

I hope it's help u

The product of pressure and volume of any gas equals a constant, k. What variable(s) must not change in order for the value of k to remain constant

Answers

The variable is temperature

What is the force on a 2kg object that is moving right at 6 m/s2?
0 3.0N
Ο ΟΝ
.33N
12.0N

Answers

Answer:

12N

Explanation:

By Newton second law force is the product of the mass of the object times it's acceleration. That makes it [tex]2\cdot 6 kg \cdot m/s^2 = 12 N[/tex]

I need help in question 7, a and b.

Answers

Answer:

The graph for 7a is shown in the attachment. For question 7b she walks a distance of 16 meters. (m)

Explanation:

3. Would prudent to do an observatory M 82 for this class?​

Answers

Answer: Yes,

If you need any other thing let me know, I'll still be on

Explanation:

if the magntidude of the sum and difference of two non zero vectors A and B is equal. what can we say about the two vectors ​

Answers

Answer:

A + B = B - A

The above equation must hold for the sum and difference to be zero.

How can one of the vectors not be zero?????

Help plz????????? Giving out Brainly

Answers

Answer:

Answer should be (B)

Explanation:

If the forces on an object are balanced (or if there are no forces acting on it), this is what happens: a stationary object stays still. a moving object continues to move at the same speed and in the same direction.

ALSO: forces acting upon an object are balanced, then the object will maintain its state of motion. To maintain the state of motion is to keep the current speed and direction. But if the forces are not balanced, the object will change its state of motion.

You push a 24.7 kg toy wagon at a speed of 9.7. What is the momentum of the wagon?

Answers

Answer:

Momentum = 239.59 kg·m/s

Explanation:

Mass x Velocity = Momentum

Two towers of height 40 m and 30 m respectively support a transmission line conductor at water crossing. The horizontal distance between the towers is 300 m. If the tension in the conductor is 1590 kg, find the clearance of the conductor at a point mid-way between the supports. Weight of conductor is 0·8 kg/m. Bases of the towers can be considered to be at the water level.

Answers

The sag in the tensioned cable depends on the weight of the cable and

the applied tension.

The clearance midway between the support is approximately 29.34 meters

Reasons:

The given parameters are;

Height of the towers are; h₁ = 40 m and h₂ = 30 m

Horizontal distance between the towers, l = 300 m

The tension in the conductor, T = 1,590 kg

Weight of the conductor, w = 0.8 kg/m

Required:

The clearance space of the conductor mid-way between the support

Solution:

The distance, x₁, to the lowest point on the conductor, from the tower, h₁, is given by the formula;

[tex]\displaystyle x_1 = \mathbf{ \frac{l}{2} -\frac{T \cdot h}{w \cdot l}}[/tex]

Where;

h = h₂ - h₁ = 40 m - 30 m = 10 m

Which gives;

[tex]\displaystyle x_1 = \frac{300}{2} -\frac{1590 \times 10}{0.8 \times 300} = \mathbf{83.75}[/tex]

The sag at the lowest point is give by the formula;

[tex]\displaystyle d_1 = \mathbf{ \frac{W \cdot x_1^2}{2 \cdot T}}[/tex]

Therefore;

[tex]\displaystyle d_1 = \frac{0.8 \times 83.75^2}{2 \times 1590} = \frac{4489}{2544} \approx 1.765[/tex]

The lowest point sag, s₁ = 30 m - 1.765 m = 28.235 m

The distance of the midpoint from the lowest point, x, is therefore;

[tex]\displaystyle x = \frac{l}{2} - x_1 = \frac{300}{2} - 83.75 = \mathbf{ 66.25}[/tex]

Which gives;

[tex]\displaystyle d_x = \frac{0.8 \times 66.25^2}{2 \times 1590} = \frac{53}{48} \approx 1.104[/tex]

The clearance midway between the support ≈ 28.235 + 1.104 ≈ 29.34

The clearance midway between the support ≈ 29.34 m

Learn more about overhead lines sag calculations here:

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(50 POINTS!!) 3. Make a model that shows the forces acting on two blocks on a flat, frictionless surface:
a. A 1 N block at rest
b. A 1 N block with 2 N of force applied in one horizontal direction
Include arrows to represent the forces and labels to indicate the magnitude of each force. Use your model to compare and explain the motion of each block.

Answers

The change in position of an object is known as motion. Force is external that causes a body to change its position

For a body is to be at rest, the sum of all the forces acting on the object must be zero

For a 1N block to be at rest, the normal force acting opposite to the weight must also be 1N.

For 1 N block with 2 N of force applied in one horizontal direction, the image of the body is as shown in the attachment

Learn more about force here: https://brainly.com/question/20955770

Answer:

In short terms. the 1N block at rest will stay still and the 1N block with 2N applied will move forward.

Help meeeeeeeeeeeeee

Answers

837474838/$77777uujj

Analyze the effects on a passenger riding in a car traveling at
50 km/h that collides head-on with a solid object.

Answers

Without:

The passenger will get seriously injuredColliding with the windshield at 50km/hCould result in death

With safety:

The seatbelt holds tge passengers body back so they dont collide with anythingTheir head is cushioned by the airbagThe passenger might get minor injuries but nothing serious will happen

What is the magnitude of the total displacement of the school bus.

Answers

Answer:

400 or 500

Explanation:

Plz help ⭐..................

Answers

Answer:

where in the world is the image????..

what is the meaning of life?

Answers

Answer:

the condition that distinguishes animals and plants from inorganic matter, including the capacity for growth, reproduction, functional activity, and continual change preceding death.

Explanation:

hope this helps

How are typhoons formed?
Need help! ​

Answers

Answer:

typhoon forms when winds blow into areas of the ocean where the water is warm. These winds collect moisture and rise, while colder air moves in below. This creates pressure, which causes the winds to move very quickly. The winds rotate, or spin, around a center called an eye.

25 n object requires a 5. 0 n to start moving over a horizontal surface. What is the coefficient of static friction?.

Answers

Answer:

μ=1/5=0.2

Explanation:

using the formula

Fs=Fn*μ

Where

Fs is the static force

Fn = Normal force

μ= coefficient

so if Fn=25n

and it requires 5 n to start moving, means the max Fs is 5n

5=25μ

μ=5/25

μ=1/5=0.2

You find a rock that is about 20 grams large. This rock contains about 10 grams of Uranium-235 and 10 grams of the element it decays into (Thorium-231). The half life of Uranium-235 is 700 million years. How old is this rock?

Answers

The age of the given rock is 700 million years.

The given parameters;

original mass of the rock, = 20 gmass of the rock remaining after decay, = 10 ghalf life of Uranium, [tex]t_{1/2}[/tex] = 700 years

age of the rock ----------------------------- mass remaining

0 [tex](t_0)[/tex]  -------------------------------------------  20 g

1 half life ([tex]1 \ t_{1/2}[/tex] ) ------------------------------ 10 g

Age of the rock [tex]= t_{1/2} - t_0 = 700 \ - 0 = 700 \ million \ years[/tex]

Thus, the age of the given rock is 700 million years.

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