A Class III two-lane highway is on level terrain, has a measured free-flow speed of 45 mi/h, and has 100% no-passing zones. During the peak hour, the analysis direction flow rate is 150 veh/h, the opposing direction flow rate is 100 veh/h, and the PHF-0.95. There are 5% large trucks and 10% recreational vehicles. Determine the level of service.
Answers
Answer:
LOS = A
Explanation:
Given all the parameters the level of service as seen from the attached graph
is LOS = A
To determine the LOS from the attached graph
calculate the trial value of Vp
Vp = V / PHF
= (100 + 150) / 0.95 = 263 pc/h
since the trial value of Vp = ( 0 to 600 ) pc/h . hence E.T = 1.7 , ER = 1
next we will calculate the flow rate
flow rate = 1 / [ ( 1 + PT(ET - 1 ) + PR ( ER - 1 ) ]
Fhr = 1 / 1.035 = 0.966 ≈ 1
next calculate the real value of Vp
Vp = V / ( PHF * N * Fhr * Fp )
= ( 100 + 150 ) / ( 0.95 * 2 * 1 * 1 )
Vp ≈ 126 pc/h/In
Next calculate the density
D = Vp / S = 126 / ( 45 * 1.61 ) = 1.74 pc/km/In
Related Questions
banana with an average mass of 0.15 kg and average specific heat of 3.35 kJ/kg · °C is cooled from 20°C to 5°C. The amount of heat transferred from the banana is
a.
62.1 kJ
b.
7.5 kJ
c.
None of these
d.
6.5 kJ
e.
0.85 kJ
f.
17.7 kJ
Answers
Answer:
The amount of heat transferred from the banana is (-)7.54 KJ
Explanation:
As we know,
[tex]Q = m*c*\Delta T[/tex]
Q = Amount of heat transferred
m = mass of banana
[tex]T_2 = 5[/tex] degree Celsius
[tex]T_1 = 20[/tex] degree Celsius
The amount of heat transferred from the banana =
[tex]0.15 * 3.35 * (5 -20)\\-7.54[/tex]KJ (negative sign represents reduction in heat energy)
14. The top plate of the bearing partition
I
a. laps the plate of the exterior wall.
b. is a single member.
c. butts the top plate of the exterior wall.
d. is applied after the ceiling joists are
installed.
Answers
Answer:
d. is applied after the ceiling joists are
installed.
A source current of 10 mA is supplied to a parallel circuit consisting of the following resistors three resistors, a 2200 a 500 and a 1KO. What is the source voltage required to
supply the current
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Can someone put each letter by the correct word for my automotive class !
Answers
Answer:
L = spindle
M = lower ball joint
part without the letter showing = steering knuckle
Explanation:
An air conditioning system is to be filled from a rigid container that initially contains 5 kg of saturated liquid at 24° Celsius the valve connecting this container to the air conditioning system is not open until the mass in this container is .25 Cal and the quality is going 506 at which time the valve is closed during this time only saturated liquid R134a flows from the container presuming that the process is isothermal wild the valve is open.
Required:
Determine the final quality of the R-134a in the container and the total heat transfer.
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ihjpr2 ywjegnak'evsinawhe2'qwmasnh ngl,;snhy
Answers
Answer:
ummm ok?
Explanation:
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░░░█▀▄▄▄█░▀▀░░ Bob the builder
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Identify the following formulas:
1. Slope Formula
2. Slope-Intercept Form
3. Standard Form
4. Point-Slope Formula
Answers
2. y=mx+b
3. Ax+By=C (I think)
4. y-y1=m(x-x1)
An FPC 4 m2 in area is tested during the night to measure the overall heat loss coefficient. Water at 60 C circulates through the collector at a flow rate of 0.06 l/s. The ambient temperature is 8 C and the exit temperature is 49 C. Determine the overall heat loss coefficient.
Answers
Answer:
- 14.943 W/m^2K ( negative sign indicates cooling )
Explanation:
Given data:
Area of FPC = 4 m^2
temp of water = 60°C
flow rate = 0.06 l/s
ambient temperature = 8°C
exit temperature = 49°C
Calculate the overall heat loss coefficient
Note : heat lost by water = heat loss through convection
m*Cp*dT = h*A * ( T - To )
∴ dT / T - To = h*A / m*Cp ( integrate the relation )
In ( [tex]\frac{49-8}{60-8}[/tex] ) = h* 4 / ( 0.06 * 10^-3 * 1000 * 4180 )
In ( 41 / 52 ) = 0.0159*h
hence h = - 0.2376 / 0.0159
= - 14.943 W/m^2K ( heat loss coefficient )
An acid-base indicator is usually a weak acid with a characteristic color in the protonated (acid) and deprotonated (conjugate base) forms. In this assignment, you will monitor the color of an acetic acid solution containing Bromocresol Green as an indicator, as the pH is changed and then you will use your data to calculate the ionization constant, Ka, for the bromocresol green indicator and compare to an accepted value.
1. Start Virtual Chemlab, select Acid-Base Chemistry, and then select lonization Constants of Weak Acids from the list of assignments. The lab will open in the Titration laboratory. Bottles of 0.1104 M NaOH and 0.1031 M HAC (acetic acid) will be on the lab bench. The buret will be filled with the NaOH solution and a beaker containing 10.00 mL of the HAc solution will be on the stir plate. The stir plate will be on, Bromocresol Green indicator will have been added to the beaker, and a calibrated pH probe will also be in the beaker so the pH of the solution can be monitored.
2. What is the color and pH of the solution?
3. On the buret, the horizontal position of the orange handle is off for the stopcock. Open the stopcock by pulling down on the orange handle. The vertical position delivers solution the fastest with three intermediate rates in between (slow dropwise, fast dropwise, and slow stream). Turn the stopcock to the second position or fast drop-wise addition. Observe the color of the solution and close the stopcock when you observe the change in color by double clicking on the center of the stopcock.
4. What is the color and pH of the solution now?
5. Continue to add NaOH as before or at a faster rate. What is the final color and pH of the solution after all of the NaOH is added?
6. An acid-base indicator is usually a weak acid with a characteristic color in the protonated and deprotonated forms. Because bromocresol green is an acid, it is convenient to represent its rather complex formula as HBOG. HBOG ionizes in water according to the following equation:
HBOG + H2O = BCG + H3O+
(yellow) (blue)
The K. (the equilibrium constant for the acid) expression is:
Ka = [BCG-][H3O+]/[HBCG)
When [BCG-[ = [HBCG), then Ka = [H3O+). If you know the pH of the solution, then the [H3O+] and Ka can be determined.
What would be the color of the solution if there were equal concentrations of HBCG and BCG-?
What is the pH at the first appearance of this color?
What is an estimate for the Ka for bromocresol green?
Answers
A piston–cylinder device contains 0.8 kg of steam at 300°C and at pressure of 800 kPa. Steam is cooled at constant pressure until one-half of the mass condenses. The final temperature is
a.
178°C
b.
184°C
c.
195°C
d.
None of these
e.
167°C
f.
170°C
Answers
Answer:
d
Explanation:
d.
None of these
_____ can be defined as the rate at which work is done or the amount of work done based on a period of time. (2 Points) voltage power resistant current
Answers
Answer: Power
Explanation:
The rate at which work is done or the amount of work done based on a period of time is referred to as power.
Power can also be defined as the amount of energy that is being transferred per unit time. The unit of power is one joule per second or simply called the watt.
5. Which of these materials in a shop contain metals and toxins and can pollute the environment? A) Antifreeze B) Solvents C) Batteries D) All of the above
I say it's D) All of the above
Answers
Answer:
D
Explanation:
All of the above
Illinois furniture , Inc produces all types of coffee furniture the executive secretary is a chair that has been designed using ergonomics to provide comfort during long work hours the chair sells for $130 there are 480 minutes available during the day and the average daily demand has been 50 chairs there are eight tasks
Answers
This question is incomplete, the complete question is;
Illinois furniture , Inc produces all types of office furniture. The "Executive Secretary" is a chair that has been designed using ergonomics to provide comfort during long work hours the chair sells for $130. There are 480 minutes available during the day and the average daily demand has been 50 chairs. There are eight tasks.
TASK PERFORMANCE TIME( MIN ) TASK MUST FOLLOW TASK LISTED
A 4 ---------
B 7 ----------
C 6 A,B
D 5 C
E 6 D
F 7 E
G 8 E
H 8 F,G
1) What is the cycle time for operation?
2) What is the theoretical minimum number of workstation?
Answer:
1) the cycle time for operation is 9.6 min
2) the theoretical minimum number of workstation is 5
Explanation:
Given the data in the question;
production time per day = 480 minutes
average daily demand = 50
Given the data in the question;
1) cycle time for operation
this is simply referred to as the total time for the process from start to finish.
cycle time = production time per day / units demand per day
we substitute
cycle time = 480 min / 50
cycle time = 9.6 min
Therefore, the cycle time for operation is 9.6 min
2) theoretical minimum number of workstation.
theoretical minimum number of workstation = total task time / cycle time
Total task time = ( 4 + 7 + 6 + 5 + 6 + 7 + 8 + 6 ) = 49 min
∴ theoretical minimum number of workstation = 49 min / 9.6 min
theoretical minimum number of workstation = 5.104 ≈ 5
Therefore, the theoretical minimum number of workstation is 5
Explain biometric senser.
Answers
Biometric sensors are used to collect measurable biological characteristics from a human being, which can then be used in conjunction with biometric recognition algorithms to perform automated person identification.
Answer:
Biometric sensors are used to collect measurable biological characteristics (biometric signals) from a human being, which can then be used in conjunction with biometric recognition algorithms to perform automated person identification.
.If aligned and continuous carbon fibers with a diameter of 6.90 micron are embedded within an epoxy, such that the bond strength across the fiber-epoxy interface is 17 MPa, and the shear yield strength of the epoxy is 68 MPa, compute the minimum fiber length, in millimeters, to guarantee that the fibers are conveying an optimum fraction of force that is applied to the composite. The tensile strength of these carbon fibers is 3960 MPa.
Answers
Answer:
the required minimum fiber length is 0.80365 mm
Explanation:
Given the data in the question;
Diameter D = 6.90 microns = 6.90 × 10⁻⁶ m
Bond strength ζ = 17 MPa
Shear yield strength ζ[tex]_y[/tex] = 68 Mpa
tensile strength of carbon fibers [tex]6t_{fiber[/tex] = 3960 MPa.
To determine the minimum fiber length we make use of the following relation;
L = ([tex]6t_{fiber[/tex] × D) / 2ζ
we substitute our given values into the equation;
L = ( 3960 × 6.90 × 10⁻⁶) / (2 × 17 )
L = 0.027324 / 34
L = 0.000803647 m
L = 0.000803647 × (1000) mm
L = 0.80365 mm
Therefore, the required minimum fiber length is 0.80365 mm
The human eye, as well as the light-sensitive chemicals on color photographic film, respond differently to light sources with different spectral distributions. Daylight lighting corresponds to the spectral distribution of the solar disk, which may be approximated as a blackbody at 5800K. Incandescent lighting from the usual household bulb corresponds approximately to the spectral distribution of a black body at 2900K. Calculate the band emission fractions for the visible region, 0.47 mu m to 0.65 mum, for each of the lighting sources. Calculate the wavelength corresponding to the maximum spectral intensity for each of the light sources
Answers
Answer:
a) at T = 5800 k
band emission = 0.2261
at T = 2900 k
band emission = 0.0442
b) daylight (d) = 0.50 μm
Incandescent ( i ) = 1 μm
Explanation:
To Calculate the band emission fractions we will apply the Wien's displacement Law
The ban emission fraction in spectral range λ1 to λ2 at a blackbody temperature T can be expressed as
F ( λ1 - λ2, T ) = F( 0 ----> λ2,T) - F( 0 ----> λ1,T )
Values are gotten from the table named: blackbody radiation functions
a) Calculate the band emission fractions for the visible region
at T = 5800 k
band emission = 0.2261
at T = 2900 k
band emission = 0.0442
attached below is a detailed solution to the problem
b)calculate wavelength corresponding to the maximum spectral intensity
For daylight ( d ) = 2898 μm *k / 5800 k = 0.50 μm
For Incandescent ( i ) = 2898 μm *k / 2900 k = 1 μm
Which location sharing service offers items for users as a gaming component and also allows them to collectively link their check ins to publish a trip
Answers
Answer:
Gowalla
Explanation:
Gowalla is a Social networking service operating as a gaming component in which it includes the registration of users' cities. Such information is then saved and utilized during the fun activities on the platform such as meeting up with people nearby and discuss interesting things relating to them.
Hence, considering there are no available options, GOWALLA is the location-sharing service that offers items for users as a gaming component and also allows them to collectively link their check-ins to publish a trip
Cast irons containing graphite are formed under a metastable eutectic reaction. 2) ___ High carbon steels are easily welded. 3) ___ Hardenability refers to the ease with which a steel can be quenched to form pearlite. 4) ___ In the AISI system for designating steels, the first two numbers refer to the major alloying elements of the steel. 5) ___ Quenching hardens most steels while tempering increases the toughness.
Answers
Answer:
Stating which of the above is TRUE or FALSE;
1) True
2) False
3) False
4) True
5) True
Explanation:
1)True ___ Cast irons containing graphite are formed under a metastable eutectic reaction.
2) False___ High carbon steels are easily welded.
3) False ___ Hardenability refers to the ease with which a steel can be quenched to form pearlite.
4) True ___ In the AISI system for designating steels, the first two numbers refer to the major alloying elements of the steel.
5) True ___ Quenching hardens most steels while tempering increases the toughness.
Design a septic system with gravity flow subsurface soil adsorption for a three-bedroom house with two baths and a basement that is currently occupied by a family of four. The building site is depicted in topographic map A and in the cross sectional transects A3-C3, A2-C2, A1-C1. Based on an initial site investigation, soil percolation tests were conducted in areas C1 and A3 to assess their suitability as locations for the absorption bed. The pertinent data from these tests is given below.
Area Cl Water Level Drop in Inches per 30 Minute Interval Percolation Rate (min/in Hole 1 13.56.57.361.24.221.221.211.2 65 .92.75.71 2.2 1.781.1.78 63 65 3 2.441.46 1.02 7 4 51.85 1.5 .92.87.8 1.76.781.6 1.441.36.28 1.26 1.26 .78 .78.78 Average: Area A3 Water Level Drop in Inches per 30 Minute Interval Percolation Rate (min/in Hole 1 3 5 1.340.940.900.88 0.840.78 0.76 0.75 2 1.45 1.18 0.98 0.92 0.90.88 0.880.86 3 0.980.88 0.840.81 0.820.800.790.77 1.140.960.90.870.850.84 0.82 0.83 1.211.02 0.920.880.85 0.830.82 0.81 4 Average:
Your solution to this exercise should include the following and should be in accord with the State of Virginia "Sewage Handling and Disposal Regulations" (A summary of the appropriate regulations is available within the course notes):________.
a) The design of an appropriately sized septic tank. This design should include a fully labeled sketch that notes all appurtenances
b) The design for a complete gravity, subsurface trench drainfield system. Depict your system on the layout sketch for the site and note all setback distances. Discuss the reasons behind your choice of a location for the drainfield,
c) If you were to utilize a bed-based design, how would the surficial area of your drainfield change?
Answers
el protozoos es del reino protista?
Answers
Answer: Si (Yes)
Explanation:
Answer:
Protozoario o protozoo es un organismo unicelular y eucariota (con núcleo celular definido) perteneciente al Reino protista. Los protozoarios se encuentran junto con los protófitos o algas simples, generalmente acuáticas, dentro del Reino protista o también denominado Reino protoctista.
Explanation:
A private plane pilot is what kind of individual transportation position? professional level mid-level entry-level EPA-certified
Answers
Answer:
A private plane pilot is a mid-level position.
Explanation:
The six pilot certifications in the US are as follows:
Sport PilotRecreational PilotPrivate Plane PilotCommercial Plane PilotFlight InstructorAirline Transport PilotFrom this listing, it is evident that the Private Plane Pilot is in the mid of the line so it is a mid-level position.
An engineer is testing the shear strength of spot welds used on a construction site. The engineer's null hypothesis at a 5% level of signigicance, is that th mean shear strenfth of spot welds is at least 3.1 MPa. The engineer randomly selcts 15 Welds and measures the shear strength is 3.07 MPa with a sample standard deciation of 0.069 MPa. Which of the following statment is true?
a) The null hypothesis should not be rejected.
b) The null hypothesis should be rejected.
c) The alternate hypothesis should be rejected.
d) The null and alternate hypotheses are equally likely.
Answers
Answer:
b) The null hypothesis should be rejected.
Explanation:
The null hypothesis is that the mean shear strength of spot welds is at least
3.1 MPa
H0: u ≥3.1 MPa against the claim Ha: u< 3.1 MPa
The alternate hypothesis is that the mean shear strength of spot welds is less than 3.1 MPa.
This is one tailed test
The critical region Z(0.05) < ± 1.645
The Sample mean= x`= 3.07
The number of welds= n= 15
Standard Deviation= s= 0.069
Applying z test
z= x`-u/s/√n
z= 3.07-3.1/0.069/√15
z= -0.03/0.0178
z= -1.68
As the calculated z= -1.68 falls in the critical region Z(0.05) < ± 1.645 the null hypothesis is rejected and the alternate hypothesis is accepted that the mean shear strength of spot welds is less than 3.1 MPa
3.Which of the following drawings are matched with the project specifications to form the bulk of the contract document?
Answers
We are given a CSP with only binary constraints. Assume we run backtracking search with arc consistency as follows. Initially, when presented with the CSP, one round of arc consistency is enforced. This first round of arc consistency will typically result in variables having pruned domains. Then we start a backtracking search using the pruned domains. In this backtracking search we use filtering through enforcing arc consistency after every assignment in the search.
Which of the following are true about this algorithm?
a) If after a run of arc consistency during the backtracking searchwe end up with the filtered domains of allof the not yetassigned variables being empty, this means the CSP has nosolution.
b) If after a run of arc consistency during the backtracking searchwe end up with the filtered domain of oneof the not yetassigned variables being empty, this means the CSP has nosolution.
c) None of the above.
Answers
A tank has a gauge pressure of 552 psi. The cover of an inspection port on the tank has a surface area of 18 square inches. What is the total force the cover is experiencing.
Answers
Answer:
44197.55 N
Explanation:
From the question,
Pressure of the pressure guage (P) = Total force experienced by the cover (F)/Area of the cover (A)
P = F/A................ Equation 1
make F the subeject of the equation
F = P×A............... Equation 2
Given: P = 552 psi = (552×6894.76) = 3805907.52 N/m², A = 18 square inches = (18×0.00064516) = 0.01161288 m²
Substitute these values into equation 2
F = ( 3805907.52×0.01161288)
F = 44197.55 N
please help with my economics problem
Answers
Answer:
You first get a new job, and make a new company and then by amazon to traumatize Jeff Bezos after his divorce
Explanation:
You will be hiking to a lake with some of your friends by following the trails indicated on a map at the trailhead. The map says that you will travel 1.7 mi directly north, then 2.7 mi in a direction 36° east of north, then finally 1.7 mi in a direction 15° north of east. At the end of this hike, how far will you be from where you started, and what direction will you be from your starting point?
Answers
Explanation:
Explain two reason why it is important for DG08 Engineering to refer to electronic component pin configuration specifications when designing and building printed circuit boards?
Answers
Answer:
refer to aja
Explanation:
La probabilidad de que un nuevo producto tenga éxito es de 0.85. Si se eligen 10 personas al azar y se les pregunta si comprarían el nuevo producto, ¿cuál es la probabilidad de que por lo menos 8 adquieran el nuevo producto?
Answers
Answer:
La probabilidad pedida es [tex]0.820196[/tex]
Explanation:
Sabemos que la probabilidad de que un nuevo producto tenga éxito es de 0.85. Sabemos también que se eligen 10 personas al azar y se les pregunta si comprarían el nuevo producto. Para responder a la pregunta, primero definiremos la siguiente variable aleatoria :
[tex]X:[/tex] '' Número de personas que adquirirán el nuevo producto de 10 personas a las que se les preguntó ''
Ahora bien, si suponemos que la probabilidad de que el nuevo producto tenga éxito se mantiene constante [tex](p=0.85)[/tex] y además suponemos que hay independencia entre cada una de las personas al azar a las que se les preguntó ⇒ Podemos modelar a [tex]X[/tex] como una variable aleatoria Binomial. Esto se escribe :
[tex]X[/tex] ~ [tex]Bi(n,p)[/tex] en donde [tex]''n''[/tex] es el número de personas entrevistadas y [tex]''p''[/tex] es la probabilidad de éxito (una persona adquiriendo el producto) en cada caso.
Utilizando los datos ⇒ [tex]X[/tex] ~ [tex]Bi(10,0.85)[/tex]
La función de probabilidad de la variable aleatoria binomial es :
[tex]p_{X}(x)=P(X=x)=\left(\begin{array}{c}n&x\end{array}\right)p^{x}(1-p)^{n-x}[/tex] con [tex]x=0,1,2,...,n[/tex]
Si reemplazamos los datos de la pregunta en la función de probabilidad obtenemos :
[tex]P(X=x)=\left(\begin{array}{c}10&x\end{array}\right)(0.85)^{x}(0.15)^{10-x}[/tex] con [tex]x=0,1,2,...,10[/tex]
Nos piden la probabilidad de que por lo menos 8 personas adquieran el nuevo producto, esto es :
[tex]P(X\geq 8)=P(X=8)+P(X=9)+P(X=10)[/tex]
Calculando [tex]P(X=8), P(X=9)[/tex] y [tex]P(X=10)[/tex] por separado y sumando, obtenemos que [tex]P(X\geq 8)=0.820196[/tex]
Por definición de variable aleatoria binomial, la probabilidad de que por lo menos 8 adquieran el nuevo producto es 0.8202.
En primer lugar, debes saber que la Probabilidad es la mayor o menor posibilidad de que ocurra un determinado suceso.
En otras palabras, la probabilidad establece una relación entre el número de sucesos favorables y el número total de sucesos posibles.
Por otro lado, una variable aleatoria es una función que asocia un número real, perfectamente definido, a cada punto muestral.
Una variable aleatoria es discreta si los números a los que da lugar son números enteros.
Finalmente, una distribución binomial es una distribución de probabilidad discreta que describe el número de éxitos al realizar n experimentos independientes entre sí, acerca de una variable aleatoria.
La expresión para calcular la distribución binomial es:
P(X=x)=( [tex]n\\ x[/tex] ) pˣ qⁿ⁻ˣ
Donde:
n = Número de ensayos/experimentos x = Número de éxitos p = Probabilidad de éxito q = Probabilidad de fracaso (1-p)Recordar que:
( [tex]n\\ x[/tex] )= [tex]\frac{n!}{x!(n-x)!}[/tex]
donde el signo de exclamación representa el símbolo de factorial, es decir el producto de todos los números enteros positivos desde 1 hasta n.
En este caso, sabes que la probabilidad de que un nuevo producto tenga éxito es de 0.85 y se eligen 10 personas al azar. Entonces se define la siguiente variable aleatoria:
X= '' Número de personas que adquirirán el nuevo producto de 10 personas a las que se les preguntó ''
Suponiendo que hay independencia entre cada una de las personas al azar a las que se les preguntó, es posible usar una variable aleatoria Binomial. Siendo n el número de personas entrevistadas (en este caso, 10 personas) y p la probabilidad de éxito (una persona adquiriendo el producto, en este caso 0.85) en cada caso, la expresión a utilizar queda expresada como:
P(X=x)=( [tex]10\\ x[/tex] ) 0.85ˣ (1-0.85)¹⁰⁻ˣ
P(X=x)= [tex]\frac{10!}{x!(10-x)!}[/tex] 0.85ˣ (0.15)¹⁰⁻ˣ
Se desea calcular la probabilidad de que por lo menos 8 adquieran el nuevo producto. Siendo 10 las personas elegidas al azar, puede ser que sean 8,9 o 10 las personas que adquieran un nuevo producto. Entonces la probabilidad deseada es calculada como:
[tex]P(X\geq 8)= P(X=8) + P(X=9) + (P=10)[/tex]
Entonces:
[tex]P(X\geq 8)=[/tex] [tex]\frac{10!}{8!(10-8)!}[/tex] 0.85⁸ (0.15)¹⁰⁻⁸ + [tex]\frac{10!}{9!(10-9)!}[/tex] 0.85⁹ (0.15)¹⁰⁻⁹ + [tex]\frac{10!}{10!(10-10)!}[/tex] 0.85¹⁰ (0.15)¹⁰⁻¹⁰
Resolviendo:
[tex]P(X\geq 8)=[/tex] [tex]\frac{10!}{8!2!}[/tex] 0.85⁸ (0.15)² + [tex]\frac{10!}{9!1!}[/tex] 0.85⁹ (0.15)¹ + [tex]\frac{10!}{10!0!}[/tex] 0.85¹⁰ (0.15)⁰
[tex]P(X\geq 8)=[/tex] 45×0.85⁸×(0.15)² + 10×0.85⁹×(0.15)¹ + 1×0.85¹⁰×(0.15)⁰
[tex]P(X\geq 8)=[/tex] 0.2759 + 0.3474 + 0.1969
[tex]P(X\geq 8)=[/tex] 0.8202
Finalmente, la probabilidad de que por lo menos 8 adquieran el nuevo producto es 0.8202.
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