A cleaning company charges a fixed amount for a house call and a second amount for each room it cleans the total cost to clean six rooms is $250 and the total cost to clean eight rooms is $320 how much would this company charge to clean two rooms

On solving the provided question, we can say that by equation 8 trainees are in group X

An equation is a mathematical formula that connects two assertions using the equal sign (=) to denote equivalence. In algebra, an equation is a mathematical statement that establishes the equivalence of two mathematical expressions. For instance, an equal sign separates the components 3x + 5 and 14 in the equation 3x + 5 = 14. A mathematical formula is used to explain the connection between two sentences on either side of a letter. Frequently, there is just one variable, which is also the symbol. for example, 2x - 4 = 2.

Let a be the number of trainees in group X

76*a + 70 (30 - a) = 30*74

76a + 2,100 - 70a = 2,220

6a = 120

a = 20

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The value of k is 3. We have to equal the distance between PA and PB and then solve the equation by squaring both side.

Given is that P(2k, k) is equidistance from A(-2, 4) and B(7, -5).

First, we try to understand what is distance formula between 2 points

let's suppose we have 2 points (x1, y1) and (x2, y2).

Find the distance between them.

The separation between two points the coordinates of two points in space are used in the formula. In coordinate geometry, a two-dimensional or three-dimensional space can be used to calculate the distance between two points using the distance formula. The Pythagoras theorem is also applied to the distance formula for two points.

The length of the line segment bridging two points on a plane is known as the distance between the points. d=√(x2 - x1)^2 + (y2 - y1)^2 is a common formula to calculate the distance between two points. This equation can be used to calculate the separation between any two locations on an x-y plane or coordinate plane.

Given that PA = PB.

First, find what is PA

[tex]\sqrt{(2k+2)^2 + (k-4)^2}[/tex]

Here we will use the formula of

(a + b)^2  = a^2 + 2ab + b^2

(a - b)^2 = a^2 -2ab + b^2

[tex]\sqrt{4k^2+8k + 4 + k^2 -8k + 16}[/tex]

[tex]\sqrt{5k^2+20}[/tex].

Now find what is PB.

[tex]\sqrt{(2k-7)^2 + (k+5)^2}[/tex]

[tex]\sqrt{4k^2 + 49 -28k + k^2 + 25 + 10k}[/tex]

[tex]\sqrt{5k^2 - 18k + 74}[/tex]

PA = PB.

[tex]\sqrt{5k^2 + 20 } = \sqrt{5k^2 -18k + 74}[/tex]

squaring both sides.

5k^2 + 20 = 5k^2 -18k + 74

18k  =  74-20

18k = 54

k = 3.

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Answer:

Don't join the points with lines

Make the numbers on the vertical axis larger

Label the axes

Step-by-step explanation:

Make all the points different colours → I don't think that would be useful. Unless the teacher asked you to in class, it's probably not a good answer.

Put the title on the bottom → Same. Unless the teacher asked you to in class, it's not really useful and probably not a good answer.

Don't join the points with lines → Teachers ask indeed not to do this, so I think it's a good answer. Most of the time they prefer students to use curves (hope it's the good translation).

Make the numbers on the vertical axis larger → Since both axes represent notes, it would be easier to compare with the same scale. If that's what the teacher meant, then I think it's correct.

Label the axes → This one is interesting, because right now we don't what they represent at all.

Hope it helps, good luck for your exercices :)

Answer:

not sure if I understand but I believe you are talking about writing it down

In any version of Microsoft Word, type m2, then highlight the 2. Now press and hold Ctrl and Shift, then press the + key and it will be changed to superscript and will look like this: m2

The basic parts of a circle include its diameter, circumference, radius, arc, chord, tangent, tangent, section, and segment.

the surface or circumference of a circle, ball, and other object measured in a straight line The radius and diameter of a circle are equal. The length of such a line. whatever radiating or radial component. A circle's chord is the line segment that connects any two locations on the circle's circumference. It should be remembered that a circle's diameter is defined as the lengthiest chord that runs across the center of the circle.

Here,

given

The letter "C" should be in the center.

radius=r=AC=CB

Diameter=d=2r=AB.

Therefore , the solution to the given problem of circle comes out to be ,the basic parts of a circle include its diameter, circumference, radius, arc, chord, tangent, tangent, sector, and segment.

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A) The frequencies and the relative frequencies of the observations are as follows,

Value __frequency (F)__Relative frequency (x)

0_____ 7 _______ 7/60 = 0.1167

1 _____ 12_ _____ 12/60 = 0.200

2 _____ 12_______ 12/60 = 0.200

3 _____ 14 _______ 14/60 = 0.2333

4 _____ 6 _______ 6/60 = 0.1000

5 _____ 3________ 3/60 = 0.0500

6 _____ 3 _______ 3/60 = 0.0500

7 _____ 1 _______  1/60 = 0.0167

8 _____ 1 ________ 1/60 = 0.0167

B)  What proportion of batches in the sample have at most five nonconforming transducers?

X =  0.1167 +0.200 +0.200 +0.2333 +0.100

= 0.85

Relative frequency

A relative frequency is the ratio of the number of times a value of the data occurs in the set of all outcomes to the total number of outcomes.

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The triangle with side lengths given in the question can be classified as a scalene triangle.

A scalene triangle is a type of triangle in which none of its three given length of sides are equal. It can be differentiated from other types with respect to  this property.

A triangle is a plane shape which can be described by three sides and three measure of internal angles. Some other types of triangle are: equilateral, obtuse, isosceles etc. The sum of all internal angles of a triangle is 180^o

Considering the given length of sides in the question, it can be proven the the only type of triangle that can be formed is a scalene triangle. Therefore, the triangle can be classified as a scalene triangle.

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Developer has 627264 square feet land available.

The minimum permissible quantity of an asset that is accepted for purchasing.

How many lots the developer has as per question?

A developer wants to develop 18-acre property = 784080 square feet area

he notices that street and common area will take up about 20% of total area.

hence, the remaining area for developing works = 80%

the amount of land rest for the developer = 784080 ×80 /100

                                                                    = 627264 square feet.

there is a rule that minimum lot size is to be 10000 square feet for developing works,

the above amount 627264 square feet lot can the developer have on this property that is higher than the minimum lot value.

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Answer: yes, it uses the Associative Property

Step-by-step explanation:

[tex]10\frac{1}{12}[/tex]  is the distance between  [tex]-6\frac{1}{3}[/tex] and [tex]4\frac{5}{12}[/tex]

The length along a line or line segment between two points on the line or line segment.

Distance=√(x₂-x₁)²+(y₂-y₁)²

We need to find the distance between [tex]-6\frac{1}{3}[/tex] and [tex]4\frac{5}{12}[/tex]

The given fractions are mixed fractions we have to convert them to improper fractions

[tex]-6\frac{1}{3}[/tex] =-17/3

[tex]4\frac{5}{12}[/tex] =53/12

Now we have to find the difference

53/12-(-17/3)

53/12+17/3

53+68/12

121/12

[tex]10\frac{1}{12}[/tex]

Hence, [tex]10\frac{1}{12}[/tex]  is the distance between  [tex]-6\frac{1}{3}[/tex] and [tex]4\frac{5}{12}[/tex]

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Answer:

x - 4y = -4

Step-by-step explanation:

Equation of line in x-intercept and y-intercept form:

         [tex]\sf \boxed{\dfrac{x}{a}+\dfrac{y}{b}=1}[/tex]

Here a is x-intercept and b is y-intercept.

           a = -4 & b = 1

[tex]\sf \dfrac{x}{-4}+\dfrac{y}{1}=1\\\\\text{Mutiply the entire equation by (-4)},\\\\(-4)*\dfrac{x}{-4} + (-4)*\dfrac{y}{1}=1*(-4)\\\\\\x - 4y = -4[/tex]

Equation of line in standard form:

        x - 4y = -4

An expression to represent the sum of their ages is as follows.

g = 14 + L

If the ratio of the ages of X and Y is p:q and their sum is X, then the following formula can be used to calculate Y's age: Age of Y = Y/Total Ages x Total Ratios. Age of Y = (p+q) q x A.

Assume that L is Louannel's sister's age, m is Mark's age, and g is Gregory's age.

Gregory's age difference with his cousin Mark, who is 20 years older (m).

∴ g = 20 + m            .............(1)

Also given that Mark is 6 years younger than his sister Louanne(L)

∴ m = L - 6                ............(2)

Now, substituting m = L - 6 from (2) in (1),

∴ g = 20 + L - 6

∴ g = 14 + L

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Answer: 5.474 m

Step-by-step explanation:

first jump = 4.25

best jump = first jump * 1.12

winning jump = best jump *1.15

The point satisfies the equation ! 8 = 4 × (2)

Answer:

Yes

Step-by-step explanation:

If you plug in the numbers to the equation, you should get:

8 = 4(2)

Then,

8 = 8

therefore, (2,8) does satisfy the equation y = 4x.

The right Riemann sum for the given function is 2.5.

Firstly, we must find the width of each of the subintervals Δx,

We know n = 4, a = 0, b = 2

∴ Δx = b - a / n

Δx =  2 - 0 / 4

Δx = 1/2

The width of each rectangle is 0.5

Next, we must find the locations of the right endpoints of the rectangles -

x1 = a + Δx(1) = 0.5

x2 = a + Δx(2) = 1

x3 = a + Δx(3) = 1.5

x4 = a + Δx(4) = 2

Now that we have the width of each rectangle, Δx = 0.5, and the right endpoints for the rectangles, x1 = 0.5, x2 = 1, x3 = 1.5, x4 = 2.

we can compute the right Riemann sum.

Computing the sum of the areas of the rectangles:

∑Δx f(x) =  ∑ 0.5f(xi)

= 0.5 f(x1) + 0.5 f(x2) + 0.5 f(x3) + 0.5 f(x4)  

= 0.5 (0.5) + 0.5 (1) + 0.5 (1.5) + 0.5 (2)

= 2.5

[tex]\int\limits^2_0 {x^{3} } \, dx[/tex]   ≈ 2.5

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Using PEMDAS to solve the algebraic expression, the value is 2

Mathematical operations are operations that involve the manipulation of numbers, variables, and/or equations. Examples of mathematical operations include addition, subtraction, multiplication, division, exponentiation, and root extraction.

In this problem, we can use PEMDAS to solve this algebraic expression.

[(3/5 + 0.425 - 0.005) ÷ 0.1] / [30.5 + 1/6 + 3 (1/3)] + [6(3/4) + 5(1/2)] / 26 ÷ 3(5/7)] - 0.05

This will become;

[10.2 / 34] + [12.25 / 7] - 0.05

Dividing and adding the numbers will give us;

(0.3 + 1.75) - 0.05 = 2

The value is 2

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On solving the provided question, we can say that - here in the equation, [tex]x^2- x = 4[/tex]

An equation is a formula in mathematics that joins two statements with the equal symbol = to represent equality. The definition of an equation in algebra is a mathematical statement proving the equality of two mathematical expressions. In the equation 3x + 5 = 14, for instance, the terms 3x + 5 and 14 are separated by an equal sign. The link between two phrases on either side of a letter is expressed mathematically. There is often only one variable, which is also the symbol. instance: 2x - 4 Equals 2.

so, x = 2

therefore

[tex]x^2- x \\6-2\\4[/tex]

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The correct option is D. 1 − 0. 125 is NOT  the correct way to find the value of fraction 5/8.

Consider the given options;

A. 5÷8

5÷8 = 5/8 (correct)

B. 5⋅0. 125

5*0.125 = 0.625

5*0.125 = 5/8 (correct)

C. 0. 5+0. 125

5+0. 125 = 0.625

5+0. 125 = 5/8 (correct)

D. 1−0. 125

1−0. 125 = 0.785

1−0. 125 = 7/8 (not correct)

Thus, option D is not the correct way to solve the equation.

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The correct question is attached.

Answer: 27.5

Step-by-step explanation:

[tex](x-3)2 = 49\\x-3 = \frac{49}{2} \\x-3 = 24.5\\x = 24.5 + 3\\x = 27.5[/tex]

So the only boundary point of [0,∞) and (0,∞) is 0 itself. It is in [0,∞), so that set is closed. It is not in (0,∞), so that set is open.

In mathematics, a (real) interval is a set of real numbers that contains all real numbers lying between any two numbers of the set. For example, the set of numbers x satisfying 0 ≤ x ≤ 1 is an interval which contains 0, 1, and all numbers in between. Other examples of intervals are the set of numbers such that 0 < x < 1, the set of all real numbers

the set of nonnegative real numbers, the set of positive real numbers, the empty set, and any singleton (set of one element).

Real intervals play an important role in the theory of integration, because they are the simplest sets whose "length" (or "measure" or "size") is easy to define. The concept of measure can then be extended to more complicated sets of real numbers, leading to the Borel measure and eventually to the Lebesgue measure.

Intervals are central to interval arithmetic, a general numerical computing technique that automatically provides guaranteed enclosures for arbitrary formulas, even in the presence of uncertainties, mathematical approximations, and arithmetic roundoff.

So the only boundary point of [0,∞) and (0,∞) is 0 itself. It is in [0,∞), so that set is closed. It is not in (0,∞), so that set is open.

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The translation of the coordinate points on the graph by linear displacement in comparison of original points ( x , y ) get translated to     ( x + h,  y + k ) where h ∈R , k ∈R.

As given in the question,

Let us consider original coordinate point on a given graph be ( x ,y ).

Translation represents the change in the linear displacement or the location without changing the shape and size.

Shift of the point may be horizontally or vertically.

Let 'h' and 'k' be the horizontal and vertical shift.

If the horizontal shift is right then it is represented by x + h

If the horizontal shift is left then it is represented by x - h

If the vertical shift is up then it is represented by y +k

If the vertical shift is down then it is represented by y - k.

Therefore, the translation of the coordinate points on a given graph represented by original points ( x , y ) get translated to ( x + h,  y + k ) where h ∈R , k ∈R.

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The domain and range of the function on the graph are:

Remember that for any function y = f(x), we define the domain as the set of possible inputs (possible values of x) and the range is the set of the possible outputs of the function (possible values of y).

To find the domain we need to look at the horizontal axis. The minimum is at x = -2 with a colored circle, so x = -2 belongs to the domain.

The largest value is at x = 1, now with an open circle, then this value does not belong to the domain. Thus the domain is:

D: [-2, 1)

For the range we need to look at the vertical axis, the minimum is at zero and the maximum at 4, then the range is:

R: [0, 4]

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The best option regarding the solutions of the trigonometric equation 2sin(θ) + 1 = 0 in this problem is given as follows:

d. θ = 330º + 360ºn, θ = 210 + 360ºn.

The trigonometric equation for this problem is defined as follows:

2sin(θ) + 1 = 0

Then, isolating the sine, we have that:

2sin(θ) = -1

sin(θ) = -1/2.

The values of theta for which the sine is of negative 1/2 are given as follows:

θ = 210º, θ = 330º.

(as the sine is negative for the third and fourth quadrant, hence we have to find the equivalent angle to 30º in each of these quadrants).

One entire lap over the unit circle is equivalent to 360º, hence adding 360º n times to any of these solutions is also a solution to the trigonometric equation, meaning that option d is correct.

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TLDs are the most common type of domain name and are typically three or more characters after the final dot in a domain name. ccTLDs are two-letter domains that represent a specific country or region.

Domain names are used to identify websites on the internet. There are two main types of domain names: top-level domains (TLDs) and country code top-level domains (ccTLDs).

TLDs are the most common type of domain name and are typically three or more characters after the final dot in a domain name. Examples of TLDs include .com, .org, .net, .edu, and .gov.ccTLDs are two-letter domains that represent a specific country or region. Examples of ccTLDs include .us for the United States, .au for Australia, .ca for Canada, .uk for the United Kingdom, and .fr for France.

When registering a domain name, users should choose a TLD or ccTLD that best suits their needs. For example, if they are targeting a global audience, they should consider a .com TLD. If they wish to target a specific country, they should consider a ccTLD.

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On solving the question, sum of exterior angle is 360 degree. Hence, the value of x is 120°.

The exterior angle of a triangle is equal to the sum of its two opposite interior angles, according to the external angle theorem. Remember that the total external angle, measured from each vertex, is always 360°. Alternatively stated, d + e + f = 360°.The angle that is created between a triangle's extended side and one of its sides is known as the external angle. A triangle has a total of 360 degrees in its outside angles.

x + ( x+6) +114 = 360

2x = 240

x = 120

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The value of x to the nearest degree will be 112°.

The circle is a closed two dimensional figure , in which the set of all points is equidistance from the center.

We have to given that;

There are three angles are shown in figure.

That is,

⇒ 59°, 108°, and 81°.

Now, We know that;

Sum of all four angles is 360°.

So, We can formulate;

⇒ 59° + 108° + 81° + x = 360°

⇒ 248° + x = 360°

⇒ x = 360° - 248°

⇒ x = 112°

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The length x of JK is 3.6 units

Here, quadrilaterals ABCD and JKLM are similar.

We know that the corresponding sides of similar triangles are in proportion.

So, by definition of similar triangles,

AB/JK = BC/KL = CD/LM = AD/JM

To find:  the length x of JK

So, consider an equation

AB/JK = AD/JM

Substitute the length of each side in above equation.

4/x = 2/1.8

(4 × 1.8)/x = 2

(4 × 1.8)/2 = x

x = 2 × 1.8

x = 3.6

Therefore, the length of JK = 3.6 units

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Answer:

Given that ,

738 students wore red while 162 students wore green.

Therefore , total number of students ,

[tex]\dashrightarrow \: 738 + 162 \\ \dashrightarrow \: 900[/tex]

Now , 738 students out of 900 wore red.

So , percentage of students who wore red ,

[tex]\dashrightarrow \: \frac{738}{9\cancel{00}} \times \cancel{100} \\ \\ \dashrightarrow \: \cancel\frac{738}{9} \\ \\ \dashrightarrow \: 82\%[/tex]

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The graph of tan(x/4) < 1/5 over the interval 0<= x<=2pi radians is attached. An approximate solution to the trigonometric inequality tan(x/4)<1/5 over the interval 0<= x<=2pi radians is 0 <= x < 0.7896.

y = 1/5 is a horizontal straight line parallel to x-axis.

Plot of tan(x/4)<1/5 over the interval 0<= x<=2pi radians is attached. The shaded region is the solution.

tan(x/4) < 1/5

Taking tan inverse on both sides

tan⁻¹(tan(x/4)) < tan⁻¹(1/5)

x/ 4 <  tan⁻¹(1/5)

Multiplying by 4 on both sides

x < 4tan⁻¹(1/5)

x < 0.7896

Applying the limits of intervals

0 <= x <= 2pi ≈ 6.28

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