A cone has a radius of 4.96 cm and a volume of 102 cm³
The question is asking for an estimate so I rounded the values that I have
Can anyone use MY working out (1 mark) to solve the rest of the question pls?

Answer:

Below

Step-by-step explanation:

Answer:

B) 3 1/3

Step-by-step explanation:

To divide the fractions, simply follow these steps.

First, flip the second fraction, so that the numerator is the denominator, and the denominator is the numerator. Change the division sign into a multiplication:

(2/3)/(1/5) = (2/3) * (5/1)

Next, multiply straight across:

(2/3) * (5/1) = (2 * 5)/(3 * 1) = 10/3

Finally, simplify. Change the improper fraction into a mixed:

10/3 = 3/3 + 3/3 + 3/3 + 1/3 =  3 1/3

B) 3 1/3 is your answer.

~

Answer:

I got 3 1/3

Step-by-step explanation:

Also to divide fractions do.  Keep Change and Flip

Keep the first fraction, flip the divide sign to the multiply sign.  Then flip the other fraction.  Then multiply

Answer:

it is B and E

Step-by-step explanation:

The table shows a proportional relationship between the milliliters (\text{mL})(mL)left parenthesis, start text, m, L, end text, right parenthesis of red paint and milliliters of yellow paint to make a certain shade of orange.

Paint mixtures

Red (\text{mL})(mL)left parenthesis, start text, m, L, end text, right parenthesis Yellow (\text{mL})(mL)left parenthesis, start text, m, L, end text, right parenthesis

10.510.510, point, 5 282828

7.57.57, point, 5 202020

999 242424

? ?

A row of values is missing in the table.

Which of the following mixtures of paint could be used as the missing values in the table?

Choose 2 answers:

Choose 2 answers:

(Choice A)

A

1.25\,\text{mL}1.25mL1, point, 25, start text, m, L, end text red and 5\,\text{mL}5mL5, start text, m, L, end text yellow

(Choice B)

B

1.5\,\text{mL}1.5mL1, point, 5, start text, m, L, end text red and 4\,\text{mL}4mL4, start text, m, L, end text yellow

(Choice C)

C

8\,\text{mL}8mL8, start text, m, L, end text red and 3\,\text{mL}3mL3, start text, m, L, end text yellow

(Choice D)

D

7\,\text{mL}7mL7, start text, m, L, end text red and 16\,\text{mL}16mL16, start text, m, L, end text yellow

(Choice E)

E

4.5\,\text{mL}4.5mL4, point, 5, start text, m, L, end text red and 12\,\text{mL}12mL12, start text, m, L, end text yellow

Answer:

14.86854, or 15

Step-by-step explanation:

Answer:

it will 5 because 0 has all factor other than 0 and 5 has two factor 1 and 5 So hcf of 0 and 5 will 5

Answer:

[tex]\ell=\frac{77}{4}[/tex]

Step-by-step explanation:

Because these two cones are similar, we can set up the following proportion:

[tex]\frac{11}{4}=\frac{\ell}{7}[/tex]

Solving, we get:

[tex]\ell=\frac{7\cdot11}{4},\\\ell=\fbox{$\frac{77}{4}$}[/tex].

Step-by-step explanation:

Hey there!

According to the question, you need to find out the distance from your friend's house to school.

Firstly figure out the coordinate of your school and school. Then use formula of distance.

So, we find the coordinates as (7,7) and (5,0).

So, x 1 = 7 y1= 7

x 2 = 5 y2 = 0

~ Use distance formula.

[tex]d = \sqrt{( {x2 - x1)}^{2} + ( {y2 - y1)}^{2} } [/tex]

~ Put all values.

[tex]d = \sqrt{ {(5 - 7)}^{2} + ( {0 - 7)}^{2} } [/tex]

~ Simplify it.

[tex]d = \sqrt{ {( - 2)}^{2} + {( - 7)}^{2} } [/tex]

[tex]d = \sqrt{4 + 49} [/tex]

[tex]d = \sqrt{53} [/tex]

D= 7.280

Therefore, the distance between your friend's house and your school is 7.3 units.

Hope it helps....

you need to find out the distance from your friend's house to school.

Firstly figure out the coordinate of your school and school. Then use formula of distance.

So, we find the coordinates as (7,7) and (5,0).

So, x 1 = 7 y1= 7

x 2 = 5 y2 = 0

~ Use distance formula.

~ Put all values.

~ Simplify it.

D= 7.280

Therefore, the distance between your friend's house and your school is 7.3 units

Answer:

Cost of 1 egg = x = $0.89

Cost of 1 sausage = y = $0.74

Step-by-step explanation:

Let the:

Cost of 1 egg = x

Cost of 1 sausage = y

A breakfast menu lists:

3 eggs with 2 sausage for $4.15

3x + 2y = 4.15......Equation 1

4 eggs with 1 sausage for $4.30 .

4x + y = 4.30...... Equation 2

y = 4.30 - 4x

We substitute 4.30 - 4x for y in Equation 1

3x + 2(4.30 - 4x) = 4.15

3x + 8.6 - 8x = 4.15

3x - 8x = 4.15 - 8.6

-5x = -4.45

x = -4.45/-5

x = $0.89

Solving for y

y = 4.30 - 4x

y = 4.30 - 4(0.89)

y = 4.30 - 3.56

y = $0.74

Therefore,

Cost of 1 egg = x = $0.89

Cost of 1 sausage = y = $0.74

Answer:

First one is 4x = 24

Second one is x = 6

This one is 6

Answer:

Add 3 to both sides of the equation:

4x − 3 + 3 = 21 + 3

4x = 24

Divide both sides of the equation by 4:

4x/4 = 24/4

x = 6

The number line represents x-values, so the solution is at 6.

The line with the red colour dotted 6

Step-by-step explanation:

Answer:

angle v equals 75.8 degrees

Step-by-step explanation:

since the lines parallel, then angle u and angle v would be the same as they are alternate interior angles. you can also subtract 180 with angle w to find angle v as well (180 - 104.2 = 75.8)

Answer:

[tex]1,008\:\mathrm{cm^2}[/tex]

Step-by-step explanation:

The total surface area of this triangular prism consists of three rectangles and two triangles. Adding the areas of each of these shapes allows us to find the total surface area of this 3D figure:

Area of both triangles:

[tex]2\cdot \frac{1}{2}\cdot12\cdot 14=168\:\mathrm{cm^2}[/tex]

Area of all three rectangles:

[tex]15\cdot 20 +13\cdot 20+14\cdot 20=840\:\mathrm{cm^2}[/tex]

Therefore, the total surface area of this figure is:

[tex]840+160=\fbox{$1,008\:\mathrm{cm^2}$} \: \checkmark[/tex]

Answer: -1

Step-by-step explanation: A typical quadratic equation is [tex]ax^{2} +bx+c[/tex] and the maximum value formula is -b/2a, so let plug it in -4/2(-4) which equals 1/2. Then let plug 1/2 into the equation,

-4(1/2)^2+4(1/2)-2=

    -1+2-2=

          -1

Answer:

Step-by-step explanation:

Nose

Answer:

Step-by-step explanation:

1 : 3 : : 4: x

Multiply 1 and x and multiply 3 and 4

x = 12

Answer:

[tex]\approx 26.16\:\mathrm{m}[/tex]

Step-by-step explanation:

Let [tex]h[/tex] be the height of the tree. In reference to the tree and bird, a right triangle is formed. We can write the following trig function for that right triangle:

[tex]\tan28^{\circ}=\frac{h}{15},\\h=15\tan28^{\circ},\\h\approx 7.98\:\mathrm{m}[/tex].

Now we can use this to find the hypotenuse of this triangle (the distance between the cat and the bird):

Let the distance between the cat and bird be [tex]k[/tex]. Then,

[tex]7.98^2+15^2=k^2,\\k\approx 16.99\:\mathrm{m}[/tex]. This is one side of the triangle that is formed by the cat, bird, and mouse.

The right triangle formed by the tree, cat, and mouse shares the height [tex]h[/tex] with the other right triangle, as we found earlier. Let [tex]l[/tex] represent the hypotenuse of this triangle or the distance between the cat and mouse. We then have the following trig function:

[tex]\sin 40^{\circ}=\frac{7.98}{l},\\l=\frac{7.98}{\sin40^{\circ}}\approx 12.41\:\mathrm{m}[/tex]. This is another side of the triangle that is formed by the cat, bird, and mouse.

The triangle that is formed by the cat, bird, and mouse has shares an angle of [tex]125^{\circ}[/tex] with the base of the auxiliary pyramid. The other angles, however, are not shared.

Since we have two sides and the angle between these two sides, we can use the Law of Cosines to find the other side (the distance between the mouse and bird). The Law of Cosines is given by:

[tex]m^2=k^2+l^2-2kl\cos M[/tex], where [tex]m[/tex] is the distance between the bird and the mouse and the other variables are defined above.

Plugging in values, we get:

[tex]m^2=16.99^2+12.41^2-2\cdot16.99\cdot12.41\cdot\cos 125^{\circ}[/tex]

Solving, we get:

[tex]m\approx \fbox{$26.16\:\mathrm{m}$}[/tex].

Answer:

The equation of the graph is;

y = 4·x

Step-by-step explanation:

The coordinates of two points, (x₁, y₁), and (x₂, y₂) respectively on the straight line graph are;

(-3, 12), and (2, 8)

The slope, m, of the straight line graph is given as follows;

[tex]Slope, \, m =\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}[/tex]

Therefore, by substitution of the values, we have;

[tex]Slope, \, m =\dfrac{8-(-12)}{2-(-3)} = \dfrac{8 + 12}{2 + 3} =\dfrac{20}{5} = 4[/tex]

The equation of the graph in point slope form is therefore;

(y - 8) = 4×(x - 2)

y = 4·x - 8 + 8 = 4·x

y = 4·x.

Answer:

20 bc if 8 men took 10 hours then 4 men would take double the time

Answer:

ha ha is it math question seriously or riddle if riddle the wall is already built by men they non time is taken by men.

Answer:

k= -50/p

Step-by-step explanation:

Answer is worked out in the photo above.

Answer:

C

There's clusters of data around the indicated points.

Answer:

QS = 17 units

Step-by-step explanation:

Given:

R located at QS

QR = 10

RS = 7

Find:

Measure of QS

Computation:

QS = QR + RS

QS = 10 + 7

QS = 17 units

Answer:

131˙

Step-by-step explanation:

Supplementary angles are angles that add up to 180˙. If you subtract 49 from 180, you get 131.

Brainliest? Maybe?

Answer:

11388.8

Step-by-step explanation:

Answer:

11,388.8

Step-by-step explanation:

if 14,236 = 100℅

X. = 80℅

14,236*80℅ divided by 100℅

X= 11,388.8

Domain is the input value, The x value)

The arrows on the graphed line mean the line continues in that direction,

There is arrows on both ends so the domain would be negative infinity to infinity.

The answer is B.

Answer:

B

Step-by-step explanation:

Answer:

Solve the system of equations:

x= -3

y= -4

Step-by-step explanation:

This is right if x went with 11/17:

11/17x

I didn't know if they were separated or not

Answer:

62miles/1hr

Step-by-step explanation:

In order to get the rate of change I divided 124 miles by 2 hours to get 62 miles.

Answer: [tex](y-y_1)=m(x-x_1)\ or \ (y-y_2)=m(y-y_2)[/tex]

Step-by-step explanation:

Point slope form: [tex](y-b)=n(x-a)[/tex] , where n=slope , (a,b) is the point through which line passes.

If slope of the line = m and line passes through [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex] :-

[tex](y-y_1)=m(x-x_1)\ or \ (y-y_2)=m(y-y_2)[/tex]

So, the equivalent equations are :

[tex](y-y_1)=m(x-x_1)\ or \ (y-y_2)=m(y-y_2)[/tex]