A flagpole 24 meters high casts a shadow 33 meters long. What is the distance between the tip of the shadow and flagpole? Round your answer to the nearest meter

Answer:

It would go out the bottom hole faster.

Explanation:

It goes down the bottom hole faster because the water would get poured out the bottom before they even flipped the water bottle.

Answer:

It will find a worm when it hits the ground and starts Johnny sins fvcl<ing the worm

Answer:

Force = 533.33N

Explanation:

Given the following data;

Power = 40000watt

Velocity = 75m/s

To find the force;

[tex] Power = force * velocity [/tex]

Making force the subject of formula, we have;

[tex] Force = \frac {Power}{velocity}[/tex]

[tex] Force = \frac {40000}{75} [/tex]

Force = 533.33N

1 Less  and 2 greater!

Answer:

Neon (Ne), chemical element, inert gas of Group 18 (noble gases) of the periodic table, used in electric signs and fluorescent lamps. Colourless, odourless, tasteless, and lighter than air, neon gas occurs in minute quantities in Earth's atmosphere and trapped within the rocks of Earth's crust.

Explanation:

I am smart

Answer:

It is a Noble gas and its group is 18 or 8a and its period is 2.

Explanation:

the reason behind my answer is group is the column and the period is the row.

Answer:

c

Explanation:

impulse Is the product of force and distance so it's generally formula

The impulse should be equivalent to the option c.  a force applied to an object for a period of time.

Impulse of force represent the product of the resultant force ΣF and also the duration of the force Δt when the force should be constant. Also it should be lead to the changed to motion and changes to momentum

Therefore, The impulse should be equivalent to the option c.  a force applied to an object for a period of time.

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Answer:

2800kg

Explanation:

Answer:

-15?

Explanation:

Answer:

Explanation:

Answer:

please mark me as brainlest

11/28/20      2:14 pm   name tom

hello i hope this is what you needed

What does seafloor spreading result in?

Explanation:

Seafloor spreading occurs at divergent plate boundaries. As tectonic plates slowly move away from each other, heat from the mantle's convection currents makes the crust more plastic and less dense. The less-dense material rises, often forming a mountain or elevated area of the seafloor. Eventually, the crust cracks.

Answer:

Explanation:

Given

Height S = 8.4m

Initial velocity u = 24m/s

Required

Time it will take to reach the ground

Using the equation of motion

S = ut +1/2gt²

8.4 = 24t + 1/2(9.8)t²

8.4 = 24t+4.9t²

4.9t²+24t - 8.4 = 0

Multiply through by 10

49t²+240t-84 = 0

Factorize

t = -240±√240²-4(49(-84)/2(49)

t = -240±√57600+16464/98

t = -240±√74064/98

t = -240±272.15/98

t = 32.15/98

t = 0.328seconds

Hence it takes 0.328seconds before it lands on the ground below.

b) The horizontal distance is the range expressed as;

R = u²/g

R = 27²/9.8

R = 729/9.8.

R = 74.39m

a. The time it took before the motorcycle stunt driver lands on the ground below is 1.31 seconds.

b. The distance from the base of the cliff that the motorcycle stunt driver traveled while in  the air is 31.44 meters.

Given the following data:

We know that the acceleration due to gravity (g) of an object on planet Earth is equal to 9.8 [tex]m/s^2[/tex]

a. To determine how long (time) it took before the motorcycle stunt driver lands on the ground below:

At maximum height, time is given by the formula:

[tex]Time = \sqrt{\frac{2H}{g} }[/tex]

Where:

Substituting the given parameters into the formula, we have;

[tex]Time = \sqrt{\frac{2\times 8.4}{9.8} }\\\\Time = \sqrt{\frac{16.8}{9.8} }\\\\Time =\sqrt{1.7413}[/tex]

Time = 1.31 seconds.

b. To determine how far (distance) away from the base of the cliff the motorcycle stunt driver traveled while in  the air:

[tex]Horizontal\;distance = horizontal\;speed \times time\\\\Horizontal\;distance = 24 \times 1.31[/tex]

Horizontal distance = 31.44 meters.

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Answer:

TRUE

Explanation:

The answer is true.

Balance forces acting on a body will not change the motion of the body because the body experiences no net resultant force in one direction. When any body experiences equal forces with opposite directions, the net force or the resultant force experience by the body is zero.

In case of an unbalanced forces, there is a net force acting in one direction and so it causes the body to change in its state of motion in the direction of the net force.

true

think of a hurricane , for it to move it needs energy from the water (warm water).and one it gets on land which has less specific heat in it the hurricane ends

Answer:

True

Explanation:

Edge 2022

Answer:100 g of ca

Explanation:

Where are the answer choices

Answer: 18.8 m/s

Explanation:

A skateboarder rolls horizontally off the top of a staircase and lands at the bottom. The staircase has a horizontal length of 12.0 m with a vertical drop of 2.00 m. We can ignore air resistance.

What is the skater's initial horizontal velocity?

Answer: 18.8 m

Answer:

800 kg

Explanation:

I just did it :)

Answer:

5 m/s²

Explanation:

Given:

v₀ = 0 m/s

v = 40 m/s

t = 8 s

Find: a

a = (v − v₀) / t

a = (40 m/s − 0 m/s) / 8 s

a = 5 m/s²

you stole point from me, if you really didn't know the answer you shouldn't have wasted time.

Answer:

2.72m/s²

Explanation:

Given parameters;

Mass of box  = 27.8kg

Force on box  = 75.7N

Unknown:

Acceleration  = ?

Solution:

Force is the product of mass and acceleration;

   Force  = mass x acceleration

Now insert the parameters and solve;

    75.7  = 27.8 x a

       a = [tex]\frac{75.7}{27.8}[/tex]  = 2.72m/s²

Answer:

a transverse wave is a moving wave whose oscillations are perpendicular to the direction of the wave or path of propagation

Explanation:

wave oscillate along paths at right angles to the direction of the wave’s advance.

Explanation:

Answer:

the acceleration of gravity is 1.62

Explanation:

w=mg

141=87g

141/87=87g/87

1.62=g

Answer:

341.46miles

Explanation:

Find the diagram attachment.

To get the displacement D, we will use the cosine rule as shown;

D² = 200²+150²-2(160)(400)cos65°

D² = 40000+22500-128000cos65°

D² = 62500+54095.14

D² = 116595.14

D = √116595.14

D= 341.46 miles

Hence the plane final displacement is 341.46miles

Answer:

50 represent the initial fee or cost added to the total cost

Explanation:

y=150x + 50

y represents the total cost and

x represents the number of hours she spends at the home.

Just like the slope intercept form y=mx + b; where m is the slope of the rate of  150 per hour and y is the total cost.

50 represent the initial fee or cost added to the total cost; in order words, 50 is the b value or where the cost is at 0 hours.

Y is what she charges just to make the trip and show up.

The patient owes her that 50 as soon as she rings the doorbell, before she spends any time there.

Answer:

B is your answer

Explanation:

C, D, and A are true and protons are located inside the nucleus and electrons are located outside the nucleus which means B is your answer.

Explanation:

Step one:

given data

mass of red cart m1=0.5kg

initial velocity u1 of red cart=50cm/s

mass of blue cart m2=0.5kg

initial velocity u2 of blue cart= 0cm/s

final velocity v2 of blue cart= 40cm/s

final velocity v1 of red cart= 10cm/s

Step two:

Momentum values red cart before and after the collision.

Before collision

P1=m1u1

P1=0.5*50

P1=25kg•cm/s

After collision

P2=m1v1

P2=0.5*10

P2=5kg•cm/s

Change in momentum= P1-P2=25-5= 20kg•cm/s

Momentum values blue cart before and after the collision.

Before collision

P1=m1u1

P1=0.5*0

P1=0 kg•cm/s

After collision

P2=m1v1

P2=0.5*40

P2=20kg•cm/s

Change in momentum= P1-P2=0-20= -20kg•cm/s

The total momentum of the system of the carts before collision is 25 kgcm/s.

The total momentum of the system of the carts after collision is 25 kgcm/s.

The change in momentum of the red cart is -20 kgcm/s.

The change in momentum of the blue cart is 20 kgcm/s.

The given parameters;

The momentum of the red cart before collision is calculated as follows;

[tex]P_r_1 = m_1u_1\\\\P_r_1 = 0.5 \times 50\\\\P_r_1 = 25 \ kgcm/s[/tex]

The momentum of the blue cart before collision is calculates as follows;

[tex]P_b_1 = m_2 u_2\\\\P_b_1 = 0.5 \times 0\\\\P_b_1 = 0 \ kgcm/s[/tex]

The momentum of the red cart after collision is calculated as follows;

[tex]P_r_2 = 0.5 \times 10\\\\Pr_2 = 5 \ kgcm/s[/tex]

The momentum of the blue cart after collision is calculated as follows;

[tex]P_2b_2 = 0.5 \times 40\\\\P_2b_2 = 20 \ kgcm/s[/tex]

The total momentum of the system before and after collision is calculated as follows;

[tex]P_1 = 25 \ kgcm/s \ + \ 0 = 25 \ kgcm/s\\\\P_2 = 5 \ kgcm/s \ + \ 20 \ kgcm/s = \ 25 \ kgcm/s[/tex]

The change in momentum of the red cart is calculated as follows;

[tex]\Delta P_r = Pr_2 - Pr_1\\\\\Delta P_r = 5 - 25 = - 20 \ kgcm/s[/tex]

The change in momentum of the blue cart is calculated as follows;

[tex]\Delta P_b = P_b_ 2 - P_b_1\\\\\Delta P_b = 20 - 0 \ = \ 20 \ kgcm/s[/tex]

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