A horizontal force of 5.0-N accelerates a 4.0-kg mass, from rest, at a rate of 0.50 m/s^2 in the positive direction. What friction force acts on the mass

Answer:2000kg

Explanation:

Convert it

Answer:

I believe it to be option A

Explanation:

Answer:

I think it is the answer A

Explanation:

Alcohol won't stimulate the central nervous system and the peripheral nervous system because the fact that the brain and the nervous system are affected can lead to many consequences: disorders of vision, hearing, motor coordination ...

Alcohol will therefore have a damaging effect, it will therefore sedate the nervous system.

Answer:A

Explanation:sedates

Answer:

7.97 N

Explanation:

[tex]f = m g sin(\alpha) = 2 * 9.8 * sin(24) = 7.97 N[/tex]

Answer:the answer is C aluminum foil

Explanation:

Answer:

Explanation:

The force engine exert on the car can be found by using the formula

[tex]f = \frac{w}{d} \\ [/tex]

w is the workdone

d is the distance

From the question we have

[tex]f = \frac{520}{260} = 2 \\ [/tex]

We have the final answer as

Hope this helps you

Answer:

zero

Explanation:

no distance has moved while holding the sheet...so no distance means no workdone..no workdone means no power...

Answer:

70.6N

Explanation:

Given parameters:

Impulse  = 494Ns

Time  = 7s

Unknown:

Force applied = ?

Solution:

To solve this problem, we use the formula of impulse;

      Impulse = Force x time

Now insert the parameters and solve;

       494  = Force x 7

            Force  = [tex]\frac{494}{7}[/tex]  

          Force  = 70.6N

Answer/Explanation:

When serving the primary serve, remain behind the benchmark between the middle imprint and the correct sideline. The ball is hit corner to corner into the administration box on the opposite side of the net, on the contrary side of the middle imprint from which the worker is serving.

Answer:

8.6m

Explanation:

Step one:

given data

we are given two displacement vectors of magnitudes 5 and 7m

Let us assume they are in the same direction and they are acting perpendicular to each other.

Step two:

The magnitude of the vector sum is the resultant vector

which is  found by

R^2=5^2+7^2

R^2= 25+49

R^2=74

R=√74

R=8.6m

Answer:

B. some isotopes are stable and others are unstable. unstable isotopes decay by emitting various subatomic particles and radiation.

Explanation:

test gave me the answer so yeah :/ XD

Answer:

1)1*20=20

2)-30/3=- -10

3)velocity of the object 1=v1=4*V2

4) kg m/ s

5) momentum of the system= 12 kg m/ s

Answer:

Use the stairs

Explanation:

This is easier because if you go on the stairs you can rest if you get tired but if you go on the inclined plane then the weight of the jugs will make you slower than you already are and you may end up going back down instead of up where you wanna go.

Answer:

Velocity is the rate at which the position changes. The average velocity is the displacement or position change per time ratio.

Explanation:

Answer:

The velocity of an object is the rate of change of its position with respect to a frame of reference, and is a function of time. Velocity is equivalent to a specification of an object's speed and direction of motion (e.g. 60 km/h to the north).

Other units: mph, ft/s

In SI base units: m/s

Explanation:

i dont know if this helps.

Answer:

Explanation:

Potential energy, which is the energy a body assumes at a position, can be calculated using the formula:

P.E = m × g × h

Where;

m = mass (kg)

g = acceleration due to gravity (10m/s²)

h = height (m)

Answer:

y = 160t - 16t²

Explanation:

Using y = ut -1/2gt² where y = height of heavy rock above the ground, u = initial launch velocity of rock = 160 ft/s, g = acceleration due to gravity = 32 ft/s² and t = time.

So, substituting the values of the variables into y, we have

y = (160 ft/s)t -1/2 × 32 ft/s² × t²

y = (160 ft/s)t - (16 ft/s²)t²

y = 160t - 16t²

So, the height function is y = 160t - 16t²

Answer:

yes

Explanation:

Answer:

y e p  

Explanation:

Answer:

v = 24.49[m/s]    

Explanation:

We must remember that kinetic energy can be calculated by means of a mathematical expression, which relates kinetic energy to mass and velocity

[tex]E_{kin}=\frac{1}{2}*m*v^{2} \\[/tex]

where:

Ekin = kinetic energy = 12000 [J]

m = mass = 40 [kg]

v = velocity [m/s]

[tex]12000=\frac{1}{2} *40*v^{2}\\24000=40*v^{2}\\600=v^{2}\\v=\sqrt{600}\\v=24.49[m/s][/tex]

Answer:

4.44 m/s^2

Explanation:

A 15-kg wagon is pulled to the right across a surface by a tension of 100 newtons at an angle of 30 degrees above the horizontal. A frictional force of 20 newtons to the left acts simultaneously.The acceleration of the wagon 4.44 m/s².

The rate at which an item changes its velocity is known as acceleration, a vector quantity. If an object's velocity is changing, it is acceleration.

Given in the question a 15 kg wagon is pulled to the right across a surface by a tension of 100 newtons at an angle of 30 degrees above the horizontal. A frictional force of 20 newtons to the left acts simultaneously, then the acceleration is  4.44 m/s².

The acceleration of the wagon 4.44 m/s².

To learn more about acceleration refer to the link:

brainly.com/question/12550364

#SPJ2

Answer:

68.88 m/s

Explanation:

downstream speed = 8+1.9=9.9 m/s

upstream speed = 8-1.9= 6.1 m/s

Therefore, total time taken would be 260/9.9+260/6.1 = 26.26+42.62 =

68.88 m/s

Given that,

Mass of yo-yo, m = 0.5 kg

Radius of the path, r = 2 m

Speed of the object, v = 3 m/s

To find,

The centripetal force acting on the yo-yo.

Solution,

The formula for the centripetal force is given as follows :

[tex]F=\dfrac{mv^2}{r}\\\\F=\dfrac{0.5\times (3)^2}{2}\\\\F=2.25\ N[/tex]

So, the magnitude of centripetal force acting on the y-yo is 2.25 N.

Answer:

θ = 26.6°

Explanation:

Formula for maximum height is;

h = u²sin²θ/2g

We are told maximum height is 25 m, thus;

u²sin²θ/2g = 25 - - - - (eq 1)

Formula for horizontal range is;

R = u²sin2θ/g

In Mathematics, sin2θ = 2sinθcosθ

So; R = 2u²sinθcosθ/g

R = 2u²sinθcosθ/g

We are given Horizontal range = 200 m.

Thus;

2u²sinθcosθ/g = 200 - - - - (eq 2)

Divide eq 1 by eq 2 to get;

200/25 = 4cosθ/sinθ

8 = 4cosθ/sinθ

4/8 = sinθ/cosθ

0.5 = tan θ

θ = tan^(-1) 0.5

θ = 26.6°

Answer:

i think its D

Explanation:

Answer:

The building is 176.4 meters high.

Explanation:

We use the formula for kinematics of an accelerated object (in this case acceleration of gravity):

Distance travelled = 1/2 g  t^2

Distance travelled = 1/2 9.8  (6)^2 = 176.4 meters

Answer:

The moment of inertia of disc about own axis is 1 kg-m².

Explanation:

Given that,

Mass of ring m= 1 kg

Moment of inertia of ring at diameter [tex](I_{r})_{d}=1\ kg\ m^{2}[/tex]

The radius of metallic ring and uniform disc both are equal.

So, [tex]R_{r}=R_{d}[/tex]

We need to calculate the value of radius of ring and disc

Using theorem of perpendicular axes

[tex](I_{r})_{c}=2\times (I_{r})_{d}[/tex]

Put the value into the formula

[tex](I_{r})_{c}=2\times1[/tex]

[tex](I_{r})_{c}=2\ kg\ m^2[/tex]

Put the value of moment of inertia

[tex]MR_{r}^2=2[/tex]

[tex]R_{r}^2=\dfrac{2}{M}[/tex]

Put the value of M

[tex]R_{r}^2=\dfrac{2}{1}[/tex]

So, [tex]R_{r}^2=R_{d}^2=2\ m[/tex]

We need to calculate the moment of inertia of disc about own axis

Using formula of moment of inertia

[tex]I_{d}=\dfrac{1}{2}MR_{d}^2[/tex]

Put the value into the formula

[tex]I_{d}=\dfrac{1}{2}\times1\times2[/tex]

[tex]I_{d}=1\ kg\ m^2[/tex]

Hence, The moment of inertia of disc about own axis is 1 kg-m².

Answer:

Force = -50000 Newton

Explanation:

Given the following data;

Initial velocity, u = 30 m/s

Final velocity, v = 20 m/s

Time = 0.2secs

Mass = 1000 kg

First of all, we have to solve for its acceleration.

Acceleration = (v - u)/t

Substituting into the equation, we have

Acceleration = 20 - 30)/0.2

Acceleration = -10/0.2

Acceleration = -50m/s²

To find the force;

Force = mass * acceleration

Force = 1000 * (-50)

Force = -50000 Newton. The value of the force is negative because it stopped the motion of the car.

Therefore, the barrier applied a force of -5,0000 Newtons to stop the car.

Answer: -50000

Explanation:

Answer:

air resistance and gravity.

Explanation:

When the ball is falling down at terminal velocity, the velocity is constant.

This means that the net force acting on the ball will be zero (there is no acceleration)

In this situation, there are only two forces that can act on the ball.

The gravitational force, that pulls the ball down.

The air resistance which opposes to the movement of the ball and increases in magnitude as the velocity of the ball increases.

Then there is a point where the velocity of the ball is such that the air resistance is equal in magnitude to the acceleration, and then the net force becomes zero.

Then the two forces that need to be included in this diagram are the air resistance and gravity.

Answer:

P = 271 nW

Explanation:

       [tex]I = \frac{P}{A} =\frac{P}{4*\pi *r^{2} } (1)[/tex]

       [tex]P = I*4*\pi *r^{2} = 6.0e-10 W/m2 * 4 * \pi *(6m)^{2} =271 nW (2)[/tex]

Answer:

This is very true

Explanation:

The force from impact can easily change it to expanse in a different direction.

I hope this helped you very much :)