A jogger runs north 6 km, 5 km east, and 4 km north again. Time is 1.9 hr. What is average velocity?

Answers

Answer 1

Answer:

Average velocity = 5.9 km/ hr (or 1.64 m/s).

Explanation:

Velocity = [tex]\frac{displacement}{time}[/tex]

It is a vector quantity and has an SI unit of m/s.

Displacement = [tex]\sqrt{x^{2} + y^{2} }[/tex]

x = 5 km east

y = 6 km north + 4 km north

  = 10 km north

So that,

Displacement = [tex]\sqrt{5^{2} + 10^{2} }[/tex]

                       = [tex]\sqrt{25 + 100}[/tex]

                       = [tex]\sqrt{125}[/tex]

                       = 11.1803

Displacement = 11.18 km = 11180 m

Time = 1.9 hr = 6840 seconds

Average velocity = [tex]\frac{11.180}{1.9}[/tex]

             = 5.8842

Average velocity = 5.9 km/ hr

The average velocity is 5.9 km/ hr (or 1.64 m/s).


Related Questions

2. A solenoid. Suppose the south end of a bar magnet was introduced to the right end of this solenoid at a constant velocity. What direction would you expect the induced magnetic field to be in?4. To decrease the magnitude of current induced in the inductor using a bar magnet, you could (select all that apply):a. Decrease the strength of the magnet.b. Decrease the velocity of the magnet going into the solenoid.c. Decrease the number of coils in the solenoid.d. Increase the cross sectional area of the solenoid.6. List the TWO values you need to record to measure a voltage on the oscilloscope

Answers

Answer:

2) deflection must be towards the negative side of the voltage.

4) the correct statements are: b and c

Explanation:

2) This question is based on Faraday's law of induction, when we introduce a magnet in a solenoid an induced current is produced that generates a voltage that is given by

           E = - N d [tex]\phi_{B}[/tex] / dt

where [tex]\phi_{B}[/tex] = B. A

The bold are vectors

Therefore, when applying this formula to our case, the induction lines of the magnetic field increase as we approach the solenoid, as the South pole approaches the lines are in the direction of the magnet, therefore the normal to the solenoid that has an outgoing direction and the magnetic field has 180º between them and the cos 180 = -1; consequently the deflection must be towards the negative side of the voltage.

4) From the Faraday equation we can see that the inductive electromotive force depends

* The magnitude of B that changes over time

* The area of ​​the loop that changes over time

* The angle between B and the area that changes over time

* A combination of the above

With this analysis we will review the different alternatives given

a) False. It takes a temporary change and an absolute value of B

b) True. As the speed decreases, the change in B decreases, that is, dB / dt decreases

c) True. The current is induced in each turn, if there is a smaller number the total current will be smaller

d) False. A temporary change of area is needed, in addition to increasing the area the current increases

We can see that the correct statements are: b and c

A swimmer bounces straight up from a diving board and falls feet first into a pool. She starts with a velocity of 4.00 m/s, and her takeoff point is 1.90 m above the pool.

Required:
a. What is her highest point above the board?
b. How long a time are her feet in the air?
c. What is her velocity when her feet hit the water?

Answers

Answer:

a = 1.152s

b = 0.817 m

c = 7.29m/s

Explanation: let the following

From the first equation of linear motion

V = u+at..........1

parameters be represented as :

t = Time taken

v = Final velocity

a = Acceleration due to gravity = 9.8m/s²

u = Initial velocity = 4 m/s

s = Displacement

V = 0

Substitute the values into equation 1

0 = 4-9.8(t)

-4 = -9.8t

t = 4/9.8

t = 0.408s

From : s = ut+1/2at^2.........2

S = 4×0.408+0.5(-9.8)×0.408^2

S= 1.632-4.9(0.166)

S = 1.632-0.815

S = 0.817m

Her highest height above the board is 0.817 m

Total height she would fall is 0.817+1.90 = 2.717 m

From equation 2

s = ut+1/2at^2

2.717 m = 0t+0.5(9.8)t^2

2.717 m = 0+4.9t^2

2.717 m = 4.9t^2

2.717/4.9 = t^2

0.554 =t^2

t =√0.554

t = 0.744s

Hence, her feet were in the air for 0.744+0.408seconds

= 1.152s

Also recall from equation 1

V= u+at

V = 0+9.8(0.744)

V = 7.29m/s

Hence, the velocity when she hits the water is 7.29m/s

Finally,

a = 1.152s

b = 0.817 m

c = 7.29m/s

A car is accelerated at a constant rate from 15 m/s to 25 m/s. It takes the car 6 s to reach its final speed. What is the car’s acceleration?

Answers

Answer:

1.67 m/s²

Explanation:

The car’s acceleration can be found by using the formula

[tex]a = \frac{v - u}{t} \\ [/tex]

where

v is the final velocity

u is the initial velocity

t is the time taken

a is the acceleration

From the question we have

[tex]a = \frac{25 - 15}{6} = \frac{10}{6} = \frac{5}{3} \\ = 1.666666...[/tex]

We have the final answer as

1.67 m/s²

Hope this helps you

24- What happens to a given mass of water as it is cooled from 4°C to zero?
(a) expands
(b) contracts
(c) vaporizes
(d) Neither expands, contracts, nor vaporizes.

Answers

Explanation:

A-It starts to expand. Hence ice and water of same weight has different volumes

Expansion happens to a given mass of water as it is cooled from 4°C to zero. Option A is correct.

What is temperature?

Temperature directs to the hotness or coldness of a body. In straightforward terms,

it is the method of finding the kinetic energy of particles within an entity. Faster the motion of particles more the temperature.

Water loses density when it is cooled from 4°C to 0°C. It turns out that the temperature at which liquid water has the most significant density is 4 degrees Celsius.

It will increase in size when heated or cooled. Since most liquids shrink when they are chilled, it is rare for water to expand when cooled to lower temperatures.

As a mass of water is cooled from 4°C to zero, expansion occurs.

Hence, option A is correct.

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Two solid spheres are made from the same material, but one has twice the diameter of the other. Which sphere will have the greater bulk modulus?

Answers

Answer:

It will be the same for both

Explanation:

from this question we have one similarity between these two spheres.

- they are both made from the same material,

The difference between both spheres is that:

- one of the spheres has its diameter to be twice as large as that of the other one.

We are to say the sphere with the greater bulk modulus.

If the material is the same thenthe Bulk modulus is also the same. It is not dependent on the material since it is a constant for that materia

Therefore the correct answer is:

It will be the same for both spheres.

Akia is balancing the equation Na + H2O NaOH + H2. He tries to find the coefficients that will balance the equation. How could he find the correct coefficients? by counting each individual atom and making sure the number of each kind of atom is the same in the reactants and the products by counting the total atoms and making sure the number of atoms in the reactants is the same as the number of atoms in the products by counting the total mass of each compound and making sure the reactants have more mass than the products by counting the mass of each atom and making sure the reactants are more massive than the products

Answers

Answer:

by counting each individual atom and making sure the number of each kind of atom is the same in the reactants and the products. - This is the answer.

Explanation:

Answer:

its A(by counting each individual atom and making sure the number of each kind of atom is the same in the reactants and the products

Explanation:

the resistance of a heater element is 1200 ohms and draws a circuit of 0.4 amperes calculate the voltage of the circuit​

Answers

Answer:

0.00033333333

Explanation:

If the particles were moving with a speed much less than c, the magnitude of the momentum of the second particle would be twice that of the first. However, what is the ratio of the magnitudes of momentum for these relativistic particles?

Answers

Answer:

p₂ / p₁ = 2 (v₁ / v₂)

Explanation:

The moment is a very useful concept, since it is one of the quantities that is conserved during shocks and explosions, for which it had to be redefined to be consistent with special relativity,

         p = m v / √[1+ (v/c)² ]

for the case of speeds much lower than the speed of light this expression is close to

         p = m v

 

In this exercise they indicate that the moment of the second particle is twice the moment of the first, when their velocities are small

        p₂ = 2 p₁

       p₂/p₁ = 2

in consecuense

       m v₂ = 2 m v₁

       v₂ = 2 v₁

consider particles of equal mass.

By the time their speeds increase they enter the relativistic regime

        p₂ = mv₂ /√(1 + v₂² /c²)

        p₁ = m v₁ /√(1 + v₁² / c²)

let's look for the relationship between these two moments

       p₂ / p₁ = mv₂ / mv₁   [√ (1+ v₁² / c²) /√ (1 + v₂² / c²)

       

from the initial statement

      p₂ / p₁ = 2 √(c² + v₁²) / (c² + v₂²)

we take c from the root

      p₂ / p₁ = 2 √ [(1+ v₁²) / (1 + v₂²)]

this is the exact result, to have an approximate shape suppose that the velocities are much greater than 1

      p₂ / p₁ = 2 √ [v₁² / v₂²] = 2 √ [(v₁ / v₂)²]

      p₂ / p₁ = 2 (v₁ / v₂)

we see the value of the moment depends on the speed of the particles

Assuming the acceleration due to gravity on the moon is exactly one-sixth of the acceleration due to gravity on Earth, what is the weight of the object on the moon?

Answers

I have assumed a weight of 120 N on Earth.

Answer:

The object weighs 20 N on the moon

Explanation:

Weight

The weight of an object depends on the mass m of the object and the acceleration of gravity g of the place they are in.

The formula to calculate the weight is:

W = m.g

If g_e is the acceleration of gravity on Earth, and g_m is the acceleration of gravity on the moon, we know:

[tex]g_m=1/6 g_e[/tex]

Dividing by ge:

[tex]g_m/g_e = 1/6[/tex]

An object of weight We=120 N on planet Earth has a mass of:

[tex]m = 120 / g_e[/tex]

Multiplying by gm:

[tex]m.g_m=120 g_m/g_e[/tex]

Substituting the ratio of accelerations of gravity:

[tex]m.g_m=120 * 1/6[/tex]

Since m.gm is the weight on the Moon Wm:

[tex]W_m=20~N[/tex]

The object weighs 20 N on the moon

Assuming the acceleration due to gravity on the moon is exactly one-sixth of the acceleration due to gravity on Earth, the weight of the object on the moon would be one-sixth of its weight on Earth.

Knowing an object's weight on Earth and applying the ratio of the acceleration caused by gravity on the moon to that on Earth will allow us to determine an object's weight on the moon.

Assume that the object's weight on Earth is W (in newtons).

On Earth, the acceleration due to gravity = 9.8 [tex]m/s^2[/tex].

On the moon, = (1/6) * 9.8 [tex]m/s^2[/tex] = 1.6333 [tex]m/s^2[/tex]

Weight = Mass * Acceleration due to gravity

Weight on the moon = W * (1/6)

Thus, the weight of the object on the moon would be one-sixth of its weight on Earth.

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A spaceship is accelerating at 1000 m/sec2 . How much force is required from the backthrusters to completely stop the spaceship?

Answers

Answer:

1000x Newton

Explanation:

Step one

given data

acceleration= 1000 m/s²

The question did not specify the mass of the mass of the space ship.

So, let's assume the mass is x kg

Step two:

Required is the force F in Newton

From Newtons first law, it states that a body will continue to be at rest or uniform motion unless acted upon by a force.

F=mass x Acceleration

F=ma

Substituting our given data we have

F=1000x Newton

A rifle of mass M is initially at rest but free to recoil. It fires a bullet of mass m and velocity v (relative to the ground). After firing, the velocity of the rifle (relative to the ground) is:_____.a. –mv.
b. –Mv/m.
c. –mv/M.
d. –v.
e. mv/M.

Answers

Answer: Option C) -mv / M is the correct answer

Explanation:

given that;

A rifle of mass M is initially at rest but free to recoil

velocity = v

using conversation of moment

pi = pf

i.e initial moment = final moment

But initial moment was zero (0) since everything  was rest but free to recoil

so

pi = pf

0 = mv + MV

V is the recoil velocity of the rifle

MV = -mv

V = -mv / M

Therefore Option C) -mv / M is the correct answer

A copper collar is to fit tightly about a steel shaft whose diameter is 6.0000 cm at 19°C. The inside diameter of the copper collar at that temperature is 5.9800 cm. To what temperature must the copper collar be raised so that it will just slip on the steel shaft, assuming the temperature of both the steel shaft and copper collar are raised simultaneously?

Answers

Answer:

T' = 865.15 °C

Explanation:

In order for the copper collar to just slip on the steel shaft the, assuming are heated simultaneously, we must find the final parameters of both and equate them. Because the final diameters of both must be same for the slipping to occur.

FOR COPPER COLLAR:

dc' = dc(1 + ∝c*ΔT)

where,

dc' = final diameter of copper ring

dc = initial diameter of copper ring = 5.98 cm

∝c = coefficient of linear expansion for copper = 16 x 10⁻⁶ °C⁻¹

ΔT = Change in Temperature

Therefore,

dc' = (5.98 cm)[1 + (16 x 10⁻⁶ °C⁻¹)ΔT]   ------------- equation (1)

FOR STEEL SHAFT:

ds' = ds(1 + ∝s*ΔT)

where,

ds' = final diameter of steel shaft

ds = initial diameter of steel shaft = 6 cm

∝s = coefficient of linear expansion for steel = 12 x 10⁻⁶ °C⁻¹

ΔT = Change in Temperature

Therefore,

dc' = (6 cm)[1 + (12 x 10⁻⁶ °C⁻¹)ΔT]   ------------- equation (2)

Comparing equation (1) and equation (2):

(5.98 cm)[1 + (16 x 10⁻⁶ °C⁻¹)ΔT] = (6 cm)[1 + (12 x 10⁻⁶ °C⁻¹)ΔT]

(5.98 cm/6 cm)[1 + (16 x 10⁻⁶ °C⁻¹)ΔT] = [1 + (12 x 10⁻⁶ °C⁻¹)ΔT]

0.9967 + (1.59 x 10⁻⁵ °C⁻¹)ΔT = 1 + (12 x 10⁻⁶ °C⁻¹)ΔT

1 - 0.9967 = [(15.9 -12) x 10⁻⁶ °C⁻¹]ΔT

0.0033/3.9 x 10⁻⁶ °C⁻¹ = ΔT

ΔT = 846.15 °C

but,

ΔT = T' - T = T' - 19°C = 846.15°C

T' = 846.15 °C + 19 °C

T' = 865.15 °C

What happens when calcium reacts with chlorine?
A. Electrons become delocalized among the atoms
B. Electrons are shared between the calcium atoms and the chlorine
atoms
C. Electrons move from the chlorine atoms to the calcium atoms,
D. Electrons move from the calcium atoms to the chlorine atoms,

Answers

When calcium reacts with chlorine. Electrons move from the calcium atoms to the chlorine atoms. Option D is correct.

What is a chemical reaction?

When one or more chemicals are transformed into one or more other compounds, a chemical reaction occurs.

In an ionic compound, calcium chloride is present. To build a complete outer shell of electrons, the calcium atom loses two electrons and each chlorine atom obtains one.


When calcium combines with chlorine, it forms calcium chloride. From the calcium atoms to the chlorine atoms, electrons travel.

Hence, option D is correct.

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A falling stone takes delta t = 0.32s to travel past a window 2.2m Tall. From what height above the top of the window did the stone fall?

Answers

Answer:

The height above the top of the window is 1.44 m

Explanation:

Given;

time of motion, t = 0.32 s

height traveled at the given time, h = 2.2m

determine the initial velocity of the stone;

h = ut + ¹/₂gt²

2.2 = u(0.32) + ¹/₂ x 9.8 x 0.32²

2.2 = 0.32u + 0.502

0.32u = 2.2 - 0.502

0.32u = 1.698

u = 1.698 / 0.32

u = 5.31 m/s

This initial velocity on top of the window becomes the final velocity from the height above the window.

v² = u² + 2gh

where;

u is the initial velocity of the stone from the height above the window;

5.31² = 0 + (2 x 9.8)h

19.6h = 28.196

h = 28.196/19.6

h = 1.44 m

Therefore, the height above the top of the window is 1.44 m

A velocity vector has magnitude 100.0 m/s and make an angle of 160o with the positive x-axis. Determine the x- and y-components of the vector.

Answers

Answer:

Vₓ = -93.96 m/s

Vy = 34.2 m/s

Explanation:

The x-component of the velocity vector can be given as follows:

Vₓ = V Cos θ

where,

Vₓ = x-component of velocity vector = ?

V = Magnitude of Velocity Vector = 100 m/s

θ = Angle with positive x-axis = 160°

Therefore,

Vₓ = (100 m/s)Cos 160°

Vₓ = -93.96 m/s

The y-component of the velocity vector can be given as follows:

Vy = V Sin θ

where,

Vy = y-component of velocity vector = ?

V = Magnitude of Velocity Vector = 100 m/s

θ = Angle with positive x-axis = 160°

Therefore,

Vy = (100 m/s)Sin 160°

Vy = 34.2 m/s

How do the magnetic fields of Uranus and Neptune suggest that the mantles inside those planets are fluid?

Answers

Answer:

The surface must be a good absorber of light. Spectra of the planets proved that methane in the atmospheres of these planets is what absorbs red light.

Explanation:

A distant galaxy has a redshift z = 5.82 and a recessional velocity vr = 287,000 km/s (about 96% of the speed of light.) Notice that the equation z=vrcz=vrc does not hold true for recessional velocities approaching the speed of light. What is the distance to the galaxy in light years?

Answers

Answer: 4100 Mpc

Explanation:

Since H o = 70 km/s/Mpc

Redshift z = 5.82

Recessional velocity vr = 287,000 km/s

Then, the distance to the galaxy in light years will be:

= Recessional velocity / H o

= 287000 / 70

= 4100 Mpc

At high noon, the sun is almost directly above (about 2.0 degrees from the vertical) and a tall redwood tree casts a shadow that is 10m long. How tall is the redwood tree?

Answers

290m

The light always travels in a straight line.

At high noon, the ray from the sun is 2° from the vertical axis.

tan θ = (Opposite side)/(Adjacent side)

On applying above trigonometric formula, we get,

tan 2 = 10/h

0.035 = 10/h

∴ h = 10/0.035 = 290 m

A projectile is fired with an initial speed of 36.6 m/s at an angle of 42.2° above the horizontal on a long flat firing range. Determine (a) the maximum height reached by the projectile, (b) the total time in the air, (c) the total horizontal distance covered (that is, the range), and (d) the speed of the projectile 1.50 s after firing.

Answers

Answer:

Explanation:

a) Maximum height id expressed as;

H = u²sin² theta/2g

H = 36.6²(sin42.2)²/2(9.8)

H = 1,339.56(0.6717)/19.6

H = 899.81/19.6

H = 45.91m

Hence the maximum height is 45.91m

b) The Time of flight is the total time in air expressed as;

T = 2usin theta/g

T = 2(36.6)sin42.2/9.8

T = 73.2sin42.2/9.8

T = 49.17/9.8

T = 5.017secs

Hence the total time in air is 5.017scs

c) Range = U²sin2(theta)/g

Range = 36.6²sin2(42.2)/9.8

Range = 1,339.5(0.9952)/9.8

Range = 1,333.11/9.8

Range = 136.03m

Hence the range is 136.03m

d) USing the rime of flight formula;

T =2Usintheta/g

1.5 = 2Usin42.2/9.8

2Usin42.2 =1.5*9.8

2Usin42.2 = 14.7

U = 14.7/2sin42.2

U = 14.7/1.3434

U = 10.94m/s

Hence the speed of the projectile is 10.94m/s

In Figure 1 , an engine that delivers power P is attached to a pulley that lifts a box of mass m0 a vertical distance of y0 at a constant speed in time t0 . If, as shown in Figure 2 the engine again delivers power P , how long would it take the engine to raise a box of mass 3m0 the same vertical distance y0 at a constant speed?

Options:
1/3 t0
t0
root(3 t0
3t0
9t0

Answers

Answer:

t = 3 t₀

Explanation:

The formula for the power delivered by the engine can be given in terms of the change in the potential energy of the box as follows:

P = P.E/t = mgy/t

where,

P = Power delivered by the engine

m = mass of box lifted = m₀

g = acceleration due to gravity

y = vertical distance or height box covered = y₀

t = time taken = t₀

Therefore,

P = m₀gy₀/t₀

t₀ = m₀gy₀/P   -------------- equation (1)

Now, if we change the mass of box as:

m = 3m₀

y = y₀ (constant)

P = Constant

Then,

P = 3m₀gy₀/t

t = 3m₀gy₀/P

using equation (1):

t = 3 t₀

Answer:

t=3to

Explanation:

I took the quiz it is right

Is Geothermal Energy renewable? Why or why not? Use in your own words.

Answers

Yes, because it's from nature, sometimes nature renews it's sources.

Answer:

Yes, geothermal energy is a renewable energy resource because the water can be heated by pumping it through the rocks.

A scientist decides to replicate an experiment completed by another scientist. Which statement describes something that would not affect the results of the replicated experiment

Answers

Hi, you've asked an incomplete question. However, I provided some explanation about the replication process that scientists do.

Explanation:

Replication in research involves carefully repeating an original experiment to see whether the same result would be arrived at as in previous research experiments.

For most scientists today, in other to avoid anything that would erroneously affect the results of the replicated experiment they usually follow the same procedures as carried by the previous researchers.

what makes the ball stop on rolling after somtime​

Answers

A ball stops because the surface on which it rolls resists its motion. So the ball stops because of friction.

Question 5 of 5
What is a definite sign of overtraining?
O A. Depression
B. Declining athletic performance
O C. A ravenous appetite
O D. Big bursts of energy
( the answer is B. i just put it on here because i didn’t see it and i got it correct :)

Answers

Answer : B. Declining athletic performance

What average force is required to stop an 1100-kg car in 8.0s if the car is travelling at 95km/h?

Answers

Answer: 13062.5 N

What average force is required to stop an 1100-kg car in 8.0 s if it is traveling at 95 km/h? i got the answer to be 13062.

Answer:

The answer is 13062.5 Newtons (N).

Explanation:

The mass of the car is 1100 kg.

The acceleration is 95 km/h.

Using this information, we can use Newton's 2nd Law, F=MA.

1100 kg * 95km/h = 104500 N

Because the answer wants average force, we need to divide the answer by 8 seconds, giving us 13062.5 N.

104500 N / 8 seconds = 13062.5 N (avg force).

1. A spring extends by 10 cm when a mass of 100 g is attached to it. What is the spring constant? (Calculate your answer in N/m)10N/m



2. What will be the extension of this spring if the load is a) 4N and b) 75 g?

Answers

Answer:

1) k = 10 [N/m]

2) a-) x = 0.4 [m]

b)  x = 0.075 [m]

Explanation:

To be able to solve this type of problems that include springs we must use Hooke's law, which relates the force to the deformed length of the spring and in the same way to the spring coefficient.

F = k*x

where:

F = force [N] (units of Newtons]

k = spring constant  [N/m]

x = distance = 10 [cm] = 0.1 [m]

Now, the weight is equal to the product of the mass by the gravity

W = m*g = F

where:

m = mass = 100 [g] = 0.1 [kg]

g = gravity acceleration = 10 [m/s²]

F = 0.1*10 = 1 [N]

Now clearing k

k = F/x

k = 1/0.1

k = 10 [N/m]

2)

a ) if the force is 4 [N]

clearing x

x = F/k

x = 4/10

x = 0.4 [m]

m = 75 [g] = 0.075 [kg]

W = m*g = F

F = 0.075*10 = 0.75 [N]

x = .75/10

x = 0.075 [m]

List Five examples from daily life in which you see periodic motion caused by a pendulum
(Marking Brainliest)

Answers

Answer:

by a rocking chair, a bouncing ball, a vibrating tuning fork, a swing in motion, the Earth in its orbit around the Sun, and a water wave.

Explanation:

An ant can run at an average speed of 0.083 meters per second, calculate how long it would take an ant to run 100 meter dash in seconds and in minutes

Answers

Answer:

The time taken by the ant is 1204.82 seconds or 20.08 minutes

Explanation:

Given:

Speed of the ant (s) = 0.083 m/s

Distance traveled by the ant (D) = 100 m

We know that distance traveled by a body is equal to the product of the speed of the body and the time taken for its travel.

Let the time taken by the ant be 't' seconds.

Now, as per the formula:

Distance = Speed × Time

⇒ 100 m = 0.083 m/s × t

⇒ [tex]t = (100\ m)/(0.083\ m/s)[/tex]

[tex]\therefore t=1204.82\ s[/tex]

Now, we know that,

60 seconds = 1 minute

So, 1 second = [tex]\frac{1}{60}\ min[/tex]

Therefore, [tex]1204.82\ s = \frac{1204.82}{60}=20.08\ min[/tex]

Hence, the time taken by the ant is 1204.82 seconds or 20.08 minutes




You are standing on a circular track that is 332 m long. You begin jogging at the start line and keep jogging until you complete a full lap and stop at the same point you

started at.

ard

• What is your final displacement?

Answers

Answer:

Zero.

Explanation:

By definition, the displacement is the difference between the final position and the initial position, so independent from the distance traveled (in this case a full lap), since the initial and final position are the same, the net displacement is just Zero.

_______mirrors or lenses always produce smaller images.​

Answers

Answer:

The images produced by a convex mirror are smaller than the object it reflects. The image produced by a concave lens is always virtual. The image in a convex mirror is always upright and is smaller than the object.

Explanation:

:)

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