Answer:
this is an example of acceleration
There is an attachment. There is an attachment on here.
Answer:
5 i think
Explanation:
A piece of iron of mass 200g and tempreture 300°C is dropped into 1.00 kg of water of tempreture 20°C. Predict the final equilibrium of the water.
Answer:
The final equilibrium T_{f} = 25.7[°C]
Explanation:
In order to solve this problem we must have a clear concept of heat transfer. Heat transfer is defined as the transmission of heat from one body that is at a higher temperature to another at a lower temperature.
That is to say for this case the heat is transferred from the iron to the water, the temperature of the water will increase, while the temperature of the iron will decrease. At the end of the process a thermal balance is found, i.e. the temperature of iron and water will be equal.
The temperature of thermal equilibrium will be T_f.
The heat absorbed by water will be equal to the heat rejected by Iron.
[tex]Q_{iron} = Q_{water}[/tex]
Heat transfer can be found by means of the following equation.
[tex]Q_{iron}=m*C_{piron}*(T_{i}-T_{f})[/tex]
where:
Qiron = Iron heat transfer [kJ]
m = iron mass = 200 [g] = 0.2 [kg]
T_i = Initial temperature of the iron = 300 [°C]
T_f = final temperature [°C]
[tex]Q_{water}=m*C_{pwater}*(T_{f}-T_{iwater})[/tex]
Cp_iron = 437 [J/kg*°C]
Cp_water = 4200 [J/kg*°C]
[tex]0.2*437*(300-T_{f})=1*4200*(T_{f}-20)\\26220-87.4*T_{f}=4200*T_{f}-84000\\26220+84000=4200*T_{f}+87.4*T_{f}\\110220 = 4287.4*T_{f}\\T_{f}=25.7[C][/tex]
An applied force is a force that is applied to an object by a person or another object.
True or False
Answer:
true
Explanation:
if the net force of 15 N is exerted on an encyclopedia to cause it to accelerate at a rate of 5 m/s2. what is the mass of the encyclopedia
Answer:
3 kg
Explanation:
F = ma
(15) = m(5)
m = 3 kg
Explain the difference between mass and weight and
how they are measured.
Answer:
Mass is a measure of how much force it will take to change that path. Mass depends on how much matter – atoms and so on – there is in an object; more mass means more inertia, as there is more to get moving. ... Weight, on the other hand, is a measure of the amount of downwards force that gravity exerts on an object
What is the normal force acting on the 7.50 kg box shown?
The answer would be 31 N. This is because Fn = 7.5*9.8*sin(25).
17. What is the position of the image formed by the converging lens of focal length of 12cm in
which the image formed is 1.5 times the size of the object and inverted?
A. 30 cm
B. 56 cm
C. 15 cm
D. 20 cm
Answer:
D is the correct answer
What reaction/soccur between an acid and base.
Answer:
neutralization reaction
Explanation:
The reaction of an acid with a base is called a neutralization reaction.
es una reacción química que ocurre entre un ácido y una base produciendo sal y agua. ... Se mezcla un ácido fuerte con una base fuerte: Cuando esto sucede, la especie que quedará en disolución será la que esté en mayor cantidad respecto de la otra.
wassup people of this wor;d
The ball in this activity could reach much greater speeds if not for the loss of energy in many different transformations. There is one major energy loss that is causing the ball to move more slowly, what is that energy? What force is acting upon the ball to create this loss of energy?
Please help quick!
Answer:
friction acts upon the ball when it is sliding down the slide and this action creates thermal energy
SILVER PACKAGE
The work done in lifting a 10 kg load of bricks to the top of a building 20 m high is (g = 9.8 ms-2
a) 98
b) 200 J
c) 980
d) 1960)
1. A ball is thrown straight up.if the launch velocity is 15 m/s, at what velocity will the ball return to the thrower's hand?
2. A boat moves across a river going 18 m/s. At the same time there is a current flowing at a right angle to the boat at 6 m/s. What is the resulting velocity of the boat?
Answer:
1) The velocity of the ball return to the thrower's hand is -15 meters per second.
2) The resulting velocity of the boat is [tex]\vec v_{B} = 6\,\hat{i}+18\,\hat{j}\,\left[\frac{m}{s} \right][/tex].
Explanation:
1) Let suppose that ball experiments a free fall, that is an uniform accelerated motion, in which effects from gravity and Earth's rotation can be neglected. The velocity of the ball is represented by the following equations of motion:
Position
[tex]v_{o}\cdot t -\frac{1}{2}\cdot g\cdot t^{2} = 0[/tex]
[tex]t\cdot \left(v_{o}-\frac{1}{2}\cdot g\cdot t \right) = 0[/tex] (1)
Velocity
[tex]v = v_{o}-g\cdot t[/tex] (2)
Where:
[tex]t[/tex] - Time, measured in seconds.
[tex]g[/tex] - Gravitational acceleration, measured in meters per square second.
[tex]v_{o}[/tex] - Initial velocity of the ball, measured in meters per second.
[tex]v[/tex] - Final velocity of the ball, measured in meters per second.
From (1), we get the time when the ball returns to the thrower's hand:
[tex]v_{o}-\frac{1}{2}\cdot g\cdot t = 0[/tex]
[tex]t = \frac{2\cdot v_{o}}{g}[/tex]
And then we apply this result in (2):
[tex]v = v_{o}-g\cdot \left(\frac{2\cdot v_{o}}{g} \right)[/tex]
[tex]v = -v_{o}[/tex] (3)
Then, the velocity of the ball return to the thrower's hand is -15 meters per second.
2) The resulting velocity of the boat ([tex]\vec v_{B}[/tex]) is represented by the vectorial sum of the velocity of the boat relative to the river ([tex]\vec v_{B/R}[/tex]) and the velocity of the river ([tex]\vec v_{R}[/tex]), both measured in meters per second, that is:
[tex]\vec v_{B} = \vec v_{R}+\vec {v}_{B/R}[/tex] (4)
If we know that [tex]\vec v_{R} = 6\,\hat{i}\,\left[\frac{m}{s} \right][/tex] and [tex]\vec v_{B/R} = 18\,\hat{j}\,\left[\frac{m}{s} \right][/tex], then the resulting velocity of the boat is:
[tex]\vec v_{B} = 6\,\hat{i}+18\,\hat{j}\,\left[\frac{m}{s} \right][/tex]
The resulting velocity of the boat is [tex]\vec v_{B} = 6\,\hat{i}+18\,\hat{j}\,\left[\frac{m}{s} \right][/tex].
Uniform Circular Motion: You need to design a wheel for testing purposes such that its rim will have an acceleration of 1.5 g when the rim is moving at 37 m/s while spinning. What should be the diameter of this wheel?
Answer:
We want to have an acceleration of:
A = 1.5*g = 1.5*9.8m/s^2 = 14.7 m/s^2
When the rim is moving at 37m/s while spinning.
Now, in circular motion we have two accelerations.
Tangential acceleration, that is the one related to the change of speed, as we have a speed of 37m/s, we can assume that is constant, then the tangential acceleration is zero.
Centripetal acceleration, is the one related to the change in direction, is perpendicular to the velocity vector and is the one that allows the circular motion.
I suppose that in this problem we want to have a centripetal acceleration of 14.7m/s^2
The equation for the centripetal acceleration is:
Ac = v^2/r
Where v = velocity and r = radius.
then we must solve:
14.7m/s^2 = (37m/s)^2/r
r = (37m/s)^2/14.7m/s^2 = 93.13 m
At which temperature could air hold the most water vapor?
O A. 24°C (75°F)
B. 2°C (36°F)
C. 35°C (95°F)
O D. 13°C (55°F)
SUBMIT
Explanation:
35 maybe hope it's right
What made "Lunar Orbit Rendezvous" such an attractive method to get to the Moon that it was selected by NASA in July, 1962
Answer:
I don't know the answer
A swimmer jumps from a diving board into a pool. What would a graph of the swimmer's potential energy and total mechanical energy look like?(1 point)
Potential energy would increase, while total mechanical energy would remain constant.
Potential energy would remain constant, while total mechanical energy would increase.
Potential energy would decrease, while total mechanical energy would remain constant.
Potential energy would remain constant, while total mechanical energy would decrease.
Answer: Potential energy would decrease, while total mechanical energy would remain constant.
Explanation: I did the test and this was right.
The graph should represent the third option.
Potential energy & mechanical energy:The graph for the potential energy of the swimmer and the mechanical energy should be that there is a reduction of the potential energy and the mechanical energy should remain the same.
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How far did the football player run if it took them 30 s running at 25m/s?
Answer:
[tex]\boxed {\boxed {\sf 750 \ meters}}[/tex]
Explanation:
Distance can be found by multiplying the speed by the time.
[tex]d=s*t[/tex]
The speed is 25 meters per second. The time is 30 seconds.
[tex]s=25 \ m/s \\t= 30 \ s[/tex]
Substitute the values into the formula.
[tex]d=25 \ m/s * 30 \ s[/tex]
Multiply. Note the seconds, or "s" will cancel each other out.
[tex]d= 25 \ m * 30[/tex]
[tex]d= 750 \ m[/tex]
The football player ran 750 meters.
Analyze why force pairs do not cancel each other
Answer:
Action and reaction forces don't cancel each other out because they act on separate objects.
Explanation:
Action and reaction forces are always equal in magnitude, so it's not possible to exert more force on an object than it can exert back.
What does the triangle mean in physics?
In physics, the triangle symbol (∆) typically represents a change or difference in a particular quantity.
A triangle is often used to denote the difference between two values of a variable. For example, if we have two values of time, t1 and t2, the change or difference in time can be represented as Δt = t2 - t1, where Δt is the triangle symbol indicating the change in time. Similarly, it can be used to represent differences in other physical quantities such as displacement (∆x), velocity (∆v), or temperature (∆T). The triangle symbol (∆) is a shorthand notation commonly used in physics to indicate changes or differences.
In terms of change in displacement, the triangle symbol (∆) represents the difference between two positions or locations. It indicates the change in the object's position from an initial point to a final point.
For example, if an object initially starts at position x1 and then moves to position x2, the change in displacement (∆x) can be calculated as ∆x = x2 - x1. Here, ∆x represents the difference or change in the object's displacement.
The magnitude of ∆x gives the overall distance traveled by the object, and its sign indicates the direction of the displacement. A positive ∆x signifies a displacement in the positive direction (e.g., to the right or upward), while a negative ∆x represents a displacement in the negative direction (e.g., to the left or downward).
Therefore, The triangle symbol (∆) is commonly used in physics equations to denote changes or differences in various quantities, including displacement, velocity, time, and more. It helps us analyze and quantify the differences between two values of a physical quantity.
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can somone pls help asap???!!
The correct Answer: would be A B C E
Explanation:
Can i get brainlyest ?
Why is my life like this
Answer:
stop it get some help
:)
Explanation:
Answer:
My life be like oooh ahhh ooh ah
Which could most likely describe the three surfaces?
Surface 1 is ice, Surface 2 is gravel, and Surface 3
is blacktop.
Surface 1 is gravel, Surface 2 is ice, and Surface 3
is blacktop.
Surface 1 is blacktop, Surface 2 is gravel, and
Surface 3 is ice.
Surface 1 is blacktop, Surface 2 is ice, and Surface
3 is gravel.
Answer:
Surface 1 is blacktop, Surface 2 is gravel, and Surface 3 is ice.
Explanation:
Hope this helps! :]
Answer:
C. Surface 1 is blacktop, Surface 2 is gravel, and
Surface 3 is ice.
Explanation:
HELP MEH QUICK PLEASE
Which of the following is a source of direct current (D/C)? *
A) a radio wave
B) a wall socket
C) a generator
D) a battery
Answer:
D) a Battery
Explanation:
The best real-life example of direct current is a battery. Batteries have positive and negative terminals on a battery, the electrons in the wires will begin to flow to produce a current.
(Need Help) (ASAP)
You are at the Grand canyon standing at the edge of a ledge 1,857 m high. you have a mass of 61 kg you decide to take a selfie to share with your science teacher when you get home witch causes you to wonder...
a. How much gravitational potential energy do you have standing on the edge of this cliff?
b. If you were to trip and fall mid selfie, your stored potential energy would be converted to kinetic energy, as you are in motion period assume that all of the GPU calculated in part A would be converted to kinetic energy when you fall period if so, how fast would you be feeling?
Answer: Considering the gravitational field strength being 9.8...
A) 1,120,875J
B) 191.70m/s (2 DP)
Explanation:
explained in pic
You are at the Grand canyon standing at the edge of a ledge 1,857 m high. you have a mass of 61 kg you decide to take a selfie to share with your science teacher when you get home witch causes you to wonder,
a. The gravitational potential energy you have standing on the edge of this cliff is 1,120,875J.
b. If you were to trip and fall mid selfie, your stored potential energy would be converted to kinetic energy, as you are in motion period assume that all of the GPU calculated in part A would be converted to kinetic energy when you fall period if so, it was felt to be fast as 191.70m/s.
What is Gravitational Potential Energy?
Gravitational potential energy is the potential energy with respect to the gravitational force. To possess gravitational potential energy, the object to be placed in a position in the gravitational field.
According to the question,
Gravitational potential energy = mgh
As given here, h = 1857 m
m = 61
Substituting the given formula,
Gravitational potential energy = 61 × 9.8 × 1875
=1,120,875 J.
Here, As Gravitation potential energy gained, the Kinetic energy lost.
So, Kinetic Energy K.E = 1,120,875 J.
As we know the formula,
K.E = 1/2 mv²
v² =K.E / (1/2 m)
= 1,120,875 × 2 / 61
v² =36,750
v = [tex]\sqrt{36750}[/tex]
= 191.702 m/s.
The speed was calculated as 191.702 m/s.
Thus,
a. The gravitational potential energy you have standing on the edge of this cliff is 1,120,875J.
b. If you were to trip and fall mid selfie, your stored potential energy would be converted to kinetic energy, as you are in motion period assume that all of the GPU calculated in part A would be converted to kinetic energy when you fall period if so, it was felt to be fast as 191.70m/s.
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What is a Super Massive Black Hole?
Answer:
I dont really know much but i know that it swallow anything it comes across in space.
Desde un rascacielos de 300 m de altura se lanza un objeto con una velocidad inicial de 50 m/s. Calcula el tiempo que transcurre hasta que llega al suelo y con qué velocidad llega en cada uno de los casos: a) Si se lanza verticalmente hacia arriba. b) Si se lanza verticalmente hacia abajo. c) Si se lanza horizontalmente (En este caso calcular también la distancia al edificio cuando llega al suelo) d) Si se lanza con un ángulo de 30o (Calcular también distancia al edificio)
Answer:
a) t = 14.2 s , v = -92 m / s , b) v = - 59.16 m / s , t = 0.916 s
c) t = 7.75 s , x = 387.5 m
d) t = 10.64 s , x = 463.9 m , v = 92.2 m / s
Explanation:
This is an exercise in kinematics, suppose we take the upward direction as positive
a) is thrown up vertically.
Let's use the equation
y = y₀ + v₀ t - ½ g t²
When reaching the ground y = 0, the initial height is y₀ = 300 m and the initial velocity is v₀ = + 50m / s, to simplify we use g = 10 m /s² as the value of the acceleration of gravity, for a more exact calculation we can must use 9.80 m /s²
0 = y₀ + v₀t - ½ g t²
½ 10 t² - 50 t - 300 = 0
Let's solve the quadratic equation
t² - 10 t - 60 = 0
t = [10 ±√ (10² + 4 60)] / 2
t = [10 ± 18.4] / 2
t₁ = 14.2 s
t₂ = -4.2 s
since time must be a positive quantity, the correctors result t = 14.2 s
the speed at this point is
v = v₀ - g t
v = 50 - 10 14.2
v = -92 m / s
the sign indicates that the body is going down
b) in this case the initial velocity is vo = -50 m / s
let's calculate the velocity on the ground
v² = v₀² - 2g (y-y₀)
v² = 50 2 - 2 10 ((0- 300)
v² = 3500
v = + - 59.16 m / s
as the body is going down the correct sign is the negative
v = - 59.16 m / s
the time it takes to arrive is
v = v₀ - g t
t = (v₀ - v) / g
t = (-50 + 59.16) / 10
t = 0.916 s
c) the velocity is horizontal (vox = 50 m / s), this implies that the vertical velocity is zero voy = 0
y = y₀ + v₀ t - ½ g t²
0 = 300 + 0 - ½ 10 t²
t = √ (2 300/10)
t = 7.75 s
the horizontal displacement at this time is
x = v₀ₓ t
x = 50 7.75
x = 387.5 m
d) as it is thrown with an angle let's find each component of the velocities
v₀ₓ = v₀ cos 30
[tex]v_{oy}[/tex] = v₀ sin 30
v₀ₓ = 50 cos 30 = 43.3 m / s
v_{oy} = 50 sin 30 = 25 m / s
we look for the time of descent
y = y₀ + v_{oy} t - ½ g t²
0 = y₀ + v_{oy} t - ½ g t²
0 = 300 + 25 t - ½ 10 t²
t² - 5t - 60 = 0
we solve the second degree equation
t = [5 ±√ (5² + 4 60)] / 2
t = [5 ± 16.28] / 2
t₁ = 10.64 s
t₂ = -5.64 s
since the time must be positive the result is t = 10.64 s
the range on the x axis is
x = v₀ₓ t
x = 43.6 10.64
x = 463.9 m
the ground speed is
v_{y} = [tex]v_{oy}[/tex] - g t
v_{y} = 25 - 10 10.64
v_{y} = -81.4 m / s
speed is
v = √ (v₀ₓ² + v_{y}²)
v = √ (43.3² + 81.4²)
v = 92.2 m / s
Two forces of magnitude 40N and 70N acts on an object calculate and write the resultant force acting on the object and the resultant a
direction of force when both the force act in opposite direction
A) 70N in the direction of lesser force
B) 110N,opposite direction
C) 30N,in the direction of the greater force
D) 30N in the direction of lesser force
Explanation:
Required Answer70N-40N=30N
30N in lesser forceWhat is the life cycle of our sun?
Answer:
the sun is currently a mian sequence star
and will remain so for another 4-5 billion
Can you please help I’m sorry I promise this is the last time
Answer:
?
Explanation:
Helppppppppppp I’ll give brainliest
Answer:
[tex] \boxed{(i).... 40cm}\\ \boxed{(ii).... 18cm}\\ \boxed{(iii).... 7.5N
}\\ [/tex]
Explanation:
[tex](i).... \\ the \: weight \: of \: the \: rod \: acts \: at \: the \: center \\ which \: is \: the \: half \: of \: 80cm = 40cm \\ (ii).... \\ let \: the \: distance \: be \: \boxed{d}...then \: 22 + d = 40 \\ d = 40 - 22 = 18cm \\ (iii).... \\let \: the \: weight \: of \: the \: metal \: rod \: be \: \boxed{ w} \\ taking \: the \: moment \: about \: the \: string \to \\ 15 \times (22 - 13) = 18w \\ 18w = (9)(15) \\ 2w = 15 \\ w = 7.5N[/tex]
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