A man pushes a 10-kg block 10 m, along a rough, horizontal
surface with a 40-N force directed 37° below the horizontal. If
the coefficient of kinetic friction is 0.2, calculate the total
work done on the block

Answers

Answer 1

Answer:

hope you can understand

A Man Pushes A 10-kg Block 10 M, Along A Rough, Horizontalsurface With A 40-N Force Directed 37 Below

Related Questions

Which type of electromagnetic radiation is used to keep food warm?
O A. Infrared radiation
O B. Visible light
O C. Gamma rays
D. X-rays

Answers

Answer:

A. infrared

Explanation:

Heat lamps used to keep foods warm are infrared on the light spectrum

Which type of wave displaces the particles of the medium parallel to the direction on which the wave travels?

Answers

Longitudinal waves

In a longitudinal wave the particles are displaced parallel to the direction the wave travels.

A sprinter accelerates at 8mps, he weights 850 grams. What
force is he exerting?

Answers

You do mass times weight, 8 times 850= 6,800. So the answer is 6,800.


How much energy must the brakes absorb to bring a 1200kg car from 30m/s to 15 m/s?

Answers

34 credits from karma make more answer

How long will it take you to drive, at 80km/h a distance of 275km?

Answers

Answer:

3.44 s

Explanation:

speed=distance/time

=>t = s/v

=> t = 275/80

= 3.437.. s

a student throws a 140 g snowball at 8.5 m/s at the side of a schoolhouse, where it hits and sticks. what is the magnitude of the average force on the wall if the duration of the collision is .16 s?​

Answers

Answer:

7.4375N

Explanation:

According to Newtons second law

F = ma

m is the mass = 140g = 0.14kg

Get the acceleration

v = u + at

8.5 = 0+0.1a

a = 8.5/0.16

a = 53.125m/s²

Get the required force

F = 0.14 * 53.125

F = 7.4375N

Hence the magnitude of the average force on the wall is 7.4375N

19. What is shape of BF3​

Answers

Explanation:

The geometry of the BF 3 molecule is called trigonal planar (see Figure 5). The fluorine atoms are positioned at the vertices of an equilateral triangle. The F-B-F angle is 120° and all four atoms lie in the same plane.

On Apollo Moon missions, the lunar module would blast off from the Moon's surface and dock with the command module in lunar orbit. After docking, the lunar module would be jettisoned and allowed to crash back onto the lunar surface. Seismometers placed on the Moon's surface by the astronauts would then pick up the resulting seismic waves.
Find the impact speed of the lunar module, given that it is jettisoned from an orbit 110 km above the lunar surface moving with a speed of 1600 m/s .
My Approach:
Ei = Ef
1/2*m*vi2 - (G*m*ME)/(radius of moon + orbital distance) = 1/2*m*vf2 ​- (G*m*ME)/r
=> (0.5 * m * 16002) - (6.67 * 10-11 * 7.35*1022 * m/(1737.4*103 +180*103) = (0.5*m*v^2) - (6.67*10-11 * 7.35*1022 * m/(1737.4*103 )

Answers

Answer:

Following are the solution to the given question:

Explanation:

For crashing speed, we can use energy conservation:

kinetic energy [tex]= \frac{1}{2}\times m \times v^2[/tex]  

potential energy [tex]= -\frac{GMm}{r}[/tex]

moon mass[tex]= 7.36\times 10^{22} \ kg[/tex]

Radius[tex]= 1738\ km[/tex]  

[tex]\to (K + U) \ orbit = (K + U)\ crash\\\\\to \frac{1}{2}\times m \times v_o^2 - \frac{GMm}{(1738000 + 110000)} \\\\ \to \frac{1}{2}\times m \times vc^2 - \frac{GMm}{1738000}[/tex]

Calculating the mass drop for the leave:

[tex]\to \frac{vo^2}{2} - \frac{GM}{1848000}\\\\ \to \frac{vc^2}{2} - \frac{GM}{1738000}[/tex]

Solve the value for

[tex]vc = \sqrt{(vo^2 +2\times GM \times(\frac{1}{1738000} - \frac{1}{1848000}))}\\\\vc = \sqrt{(1600^2 +2\times 6.67\times 10^{-11} \times 7.36 \times 10^{22}\times (\frac{1}{1738000} - \frac{1}{1848000}))}\\\\vc = 1701 \ \frac{m}{s}\\\\[/tex]  

The approach is correct but misrepresented in replacing 180 km instead of 110 km.

A block and tackle of 6 pulleys is used to raise a load of 300 newton steadily through a height of 30 meters. If the work done against friction is 2000j calculate the work done by effort?

Answers

Answer:

W = F * S = 300 N * 30 m = 9000 Joules

This is the work out of the system regardless of how the pulleys are arranged

Conservation of energy tells that

Work Out = Work In - Work done by friction

So Work In = 9000 J + 2000 J = 11000 J      The work input to the system

8. Which element will most likely form an ionic bond with chlorine?
A. O
B.N
C.S
D.K

Answers

the answer to this is A. O

A ray diagram is shown. A tree acts as the object further than 2 F away from a biconvex lens. The distance between 2 F and the object is labeled W. The distance between F and 2 F is labeled X. There I a light ray parallel to the principal axis is bent through F on the image side of the lens. There is a ray straight through the center of the lens. The rays intersect a point below the principle axis between F and 2 F on the image side of the lens and is closer to the principal axis than the object is tall. The intersect point is labeled Z and the distance between F and 2 F on the image side of the lens is labeled Y. Which letter represents the location of the image produced by the lens? W X Y Z

Answers

Answer:

Z

Explanation:

correct on edge

Answer: Z

good luck!

an object is moving at 60m/s and has a mass of 5 kg what is its momentum​

Answers

Answer:

300

Explanation:

the momentum is 300

p=mv

p=5×60

5×60 =300

The fictional rocket ship Adventure is measured to be 65 m long by the ship's captain inside the rocket.When the rocket moves past a space dock at 0.5c. As rocket ship Adventure passes by the space dock, the ship's captain flashes a flashlight at 1.20-s intervals as measured by space-dock personnel.

Required:
How often does the flashlight flash relative to the captain?

Answers

Answer:

1.04 s

Explanation:

The computation is shown below:

As we know that

t = t' × 1 ÷ (√(1 - (v/c)^2)

here

v = 0.5c

t = 1.20 -s

So,

1.20 = t' × 1 ÷ (√(1 - (0.5/c)^2)

1.20 = t' × 1 ÷ (√(1 - (0.5)^2)

1.20 = t' ÷ √0.75

1.20 = t' ÷ 0.866

t' = 0.866 × 1.20

= 1.04 s

The above formula should be applied

The owner of a van installs a rear-window lens that has a focal length of -0.304 m. When the owner looks out through the lens at a person standing directly behind the van, the person appears to be just 0.237 m from the back of the van, and appears to be 0.343 m tall. (a) How far from the van is the person actually standing

Answers

Answer:

[tex]p =-1.03[/tex]

Explanation:

From the question we are told that:

Focal length of lens [tex]f=-0.304 m[/tex]

Image distance [tex]q=0.237 m[/tex]

Height of image [tex]H_i=0.343[/tex]  

Generally the lens equation is mathematically given by

[tex]\frac{1}{f} = \frac{1}{q} - \frac{1}{p}[/tex]

Where [tex]p[/tex] is Subject

[tex]p = \frac{(qf) }{(f - q)}[/tex]

[tex]p = \frac{(-0.237)(-0.304)) }{((-0.304) - (0.237))}[/tex]

[tex]p =-1.03[/tex]

Therefore the distance between  the person and the car is

[tex]p =-1.03[/tex]

A 700-gram grinding wheel 22.0 cm in diameter is in the shape of a uniform solid disk. (We can ignore the small hole at the center.) When it is in use, it turns at a constant 215 rpm about an axle perpendicular to its face through its center. When the power switch is turned off, you observe that the wheel stops in 50.0 s with constant angular acceleration due to friction at the axle.
What torque does friction exert while this wheel is slowing down?

Answers

Solution :

Given :

Mass of grinding wheel, m = 700 g

                                             = 0.7 kg

Diameter of the grinding wheel, d = 22 cm

                                                         = 0.22 m

Radius of the grinding wheel, r = 0.11 m

Initial angular velocity of grinding wheel, [tex]$\omega_0$[/tex] = 215 rpm

                                                                               [tex]$=215 \ rpm \times \frac{2 \pi \ rad}{1 \ rev}\times \frac{1 \ min}{60 \ s}$[/tex]

where, [tex]$\pi = \frac{22}{7}$[/tex]

Time taken to stop, t = 50 s

Final angular velocity is [tex]$\omega$[/tex] = 0

Angular acceleration of the grinding wheel is given by :

[tex]$\alpha = \frac{\omega-\omega_0}{t}$[/tex]

   [tex]$=\frac{0-215 \ rpm \times \frac{2 \pi \ rad}{1 \ rev}\times \frac{1 \ min}{60 \ s}}{50 \ s}$[/tex]

   [tex]$=-0.45 \ rad/s^2$[/tex]

Magnitude of the angular acceleration of grinding wheel [tex]$\alpha$[/tex] [tex]$=-0.45 \ rad/s^2$[/tex]

Moment of inertia of the grinding wheel (solid disk),

[tex]$I=\frac{1}{2}mR^2$[/tex]

   [tex]$=\frac{1}{2} \times 0.7 \times 0.11^2$[/tex]

  [tex]$=4.235 \times 10^{-3} \ kgm^2$[/tex]

Torque exerted by friction while the wheel is slowing down is

[tex]$\tau = I \alpha$[/tex]

  [tex]$=4.235 \times 10^{-3} \times 0.45$[/tex]

 [tex]$=1.90 \times 10^{-3} \ Nm$[/tex]

is being a plat 2 in rainbow 6 siege a good rank?

Answers

Answer:

In a way it does, but overall, there are many factors that affect your rank. In general, and talking about the average Platinum II, they are pretty decent according to casual player standards.

Explanation:

HELP ME PLEASEE I NEED HELP CLICK HERE

Answers

Answer:

Bacteria: Unicellular organisms that can cause disease in living things

Plant: A multicellular organism that makes it's own food

Animal: A multicellular organism that does not make it's own food

what term is used to describe the block of organs (heart, lungs, liver, kidneys and spleen) that are removed during the autopsy?

Answers

The term used to describe the block of organs that are removed during the autopsy is Thoracic organs.

The organs that are removed during autopsy include:

Thoracic organs;Cervical organs, and Abdominal organs

The thoracic cavity contains organs and tissues that function in the respirator, cardiovascular, nervous and digestive system.

These thoracic organs include the following;

heart, lungs, liver, kidneys and spleen.

Thus, we can conclude that the term used to describe the block of organs that are removed during the autopsy is Thoracic organs.

Learn more here:https://brainly.com/question/25087653

A heating coil operates on 220 V if it draws 15.0 A. Find it's resistance

Answers

Answer:

R ≈ 15 ohms

Explanation:

Using ohm's law equation,

I = V/R, to solve for the resistance of the heating coil.

R = V/I

Known:

V = 220 v = 220 kgm^2s^-3A^-1

I = 15 A

Unknown:

R =?

Solution:

R = (220 kgm^2s^-3A^-1)/ 15.0 A

R = 14.6 kgm^2s^-3A^-2

R ≈ 15 kgm^2s^-3A^-2

R ≈ 15 ohms

3. An object has 90,000 J Kinetic energy and is moving at 12m/s. What is the objects mass?

Answers

1250 KG is your answer :)

11.Electricity is made at a power plant by huge
(C). Coil
(D). Wire
(A). Motor
(B). Generator​

Answers

i think it’s b. generators


PLEASE HELP

Which of the following are examples of gravity in action? Select all that apply.
A. an earthquake
B. a planet orbiting the sun
C. a ball flying through the air
D. precipitation falling to Earth

Answers

B and C because an earthquake does not directly affect gravity, and precipitation doesn’t fall, it is water surfacing

What are applications of zeroth law of thermodynamics?​

Answers

Answer:

Applications of zeroth law of thermodynamics:

1. When we get very hot food, we wait to make it normal. In this case, hot food exchanges heat with surrounding and brings equilibrium.

2. We keep things in the fridge and those things come equilibrium with fridge temperature.

3. Temperature measurement with a thermometer or another device.

4. In the HVAC system, sensors or thermostats are used to indicate temperature. It always comes in a thermal equilibrium with room temperature.

5. If you and the swimming pool you’re in are at the same temperature, no heat is flowing from you to it or from it to you (although the possibility is there). You’re in thermal equilibrium.

0)
A-B-C-D-E
Describe the mass of the reactants and products given the balanced chemical reaction
A)
The mass of the products is 2/3 that of the reactants.
B)
The mass of the reactants equals the mass of the products.
C)
The mass of the reactants is less than the mass of the products.
D)
The mass of the reactants is greater than the mass of the products.

Answers

Answer:

D)

The mass of the reactants is greater than the mass of the products.

What kind of story would a Romantic audience find MOST appealing?

A. science fiction or futuristic worlds
B. a comedy or something light-hearted
C. one based on Christian morals and piety
D. something where a person disappears in nature

Answers

b i think or d but i’m pretty sure b

government as an academic field of study ​

Answers

Government as an academic field of study is a vast subject, encompassing political institutions and political theories. ... Government allows for civil order by creating laws and protecting its citizens. In order to ensure enforcement of laws, government also creates punishments for those who break the law.

Answer: True

Explanation:

Government as an academic field of study refers to the study of political institutions, processes and theories taught in schools, colleges and higher institution of learning. It is called Political Science in higher institution.

⦁ Determining the magnetic flux, A rectangular piece of stiff paper measures 10 cm x 5 cm. You hold the piece of paper in a uniform magnetic field that has a magnitude of 4.0 x10-3 T For each situation below, - sketch a diagram showing the magnetic field and the paper, - determine the magnitude of the magnetic flux through the paper, when the magnitude of the flux is (a) maximized (b) minimized (c) halfway between its maximum and minimum value, when the angle between the magnetic field lines and the area normal vector is 300

Answers

Answer:

jguewjdofe

Explanation:

A body starts from rest and travels ‘s’ m in 2nd second, than acceleration is.
1) 2s m / s2 2) 3 s m / s2 3) 23 s m / s2 4) 32 s m / s2

Answers

Answer:

3m

Explanation:

what is the relationship between Force, area and mass​

Answers

Answer:

F=ma

Explanation:

Force is equal to mass multiplied by area

Force= mass × area

In turn the formula can be twisted so

Force/mass= area

Force/area= mass

Answer:

It states that the rate of change of velocity of an object is directly proportional to the force applied and takes place in the direction of the force. It is summarized by the equation: Force (N) = mass (kg) × acceleration (m/s²). Thus, an object of constant mass accelerates in proportion to the force applied.

Consider the situation in which three identical spheres of clay are launched simultaneously, one along each possible path. All three spheres of clay are launched with the same initial linear speed and collide with the rod at the same time. The time of collision with the rod for each sphere is time t0. Which of the following predictions is correct about the motion of the system containing the rod and all three spheres of clay immediately after the collision?

a. The system will rotate in the clockwise direction with a constant angular speed.
b. The system will rotate in the counterclockwise direction with a constant angular speed.
c. The system will rotate in the clockwise direction with a changing angular speed.
d. The system will rotate in the counterclockwise direction with a changing angular speed.

Answers

Answer:

a. The system will rotate in the clockwise direction with a constant angular speed.

Explanation:

As all the clay is identical sphere and there will be hence same mass 'm' for all three clay spheres. Now their identical speed 'v' and collision time [tex]$'t_0'$[/tex] are also same. So all the spheres will exert same force F on the rod.

[tex]$f=\frac{mv}{t_0}$[/tex]

Force exerted by the clay Z on rod is passing through pivot, so no torque will be produced.

Now clay X will collide at near distance from pivot than that of clay Y.

So clay Y will produce more torque than clay X. So clay Y will give more clockwise torque. So rod will rotate clockwise.

Now in any impact because net force and net torque are zero (because in impact torque and force occurs in equal and opposite pairs). So net angular momentum will be conserved and hence angular speed will be constant.

Therefore it is clear that option (a) is correct.

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