Answer:
2.7
Explanation:
The following data were obtained from the question:
Mass (m) of box = 100 Kg
Length (L) of ramp = 4 m
Height (H) of ramp = 1.5 m
Mechanical advantage (MA) of ramp =?
Mechanical advantage of a ramp is simply defined as the ratio of the length of the ramp to the height of the ramp. Mathematically, it is given by:
Mechanical Advantage = Lenght / height
MA= L/H
With the above formula, we can obtain the mechanical advantage of the ramp as follow:
Length (L) of ramp = 4 m
Height (H) of ramp = 1.5 m
Mechanical advantage (MA) of ramp =?
MA = 4/1.5
MA = 2.7
Therefore, the mechanical advantage of the ramp is 2.7
Write a message to Mr. Chang explaining why the groundwater heating system will warm the school more than the water heater system. Use evidence to support your claim. For each piece of evidence you use, explain how the evidence supports your claim.
Answer:
For, heating purposes more the quantity of water more will be the heating. Clearly, underground heating would have more water and hence, it will have edge over the water heater system.
Moreover, for things at the same temperature, the thing with more molecules has more total kinetic energy (thermal energy) than the thing with fewer molecules. The groundwater heating system uses heat from the heat stored naturally in groundwater or aquifers. Thus, saving the cost of power required to heat in normal water heater.
Explanation:
The groundwater heating system will warm the school more than the water heater system due to the fact that it uses more water more than the other system.
Based on the complete question, it should be noted that the addition of energy leads to an increase in motion which results in the rise in temperature.
The groundwater heating system will warm the school more than the water heater system due to the fact that it uses more water more than the other system even though its water isn't as warm as in the other system.
Read related link on:
https://brainly.com/question/20116115
Intensitatea curentului electric a unui circuit este de 123A iar sarcina electrica este de 1,7C sa se afle intervalul de timp in care este transportata sarcina electrica
The intensity of the electric current of a circuit is 123A and the electric charge is 1.7C to find the time interval in which the electric charge is transported.
Given that,
Current, I = 123 A
Electric charge, q = 1.7 C
To find,
The time interval in which the charge is transported.
Solution,
The electric current is given by electric charge per unit time. So,
[tex]I=\dfrac{q}{t}\\\\t=\dfrac{q}{I}\\\\t=\dfrac{1.7}{123}\\\\t=0.0138\ s[/tex]
So, the required time is 0.0138 seconds.
Appliances connected so that they form a single pathway for
charges to flow are connected in a(n)
A. series circuit.
B. parallel circuit.
C. off circuit.
D. open circuit
Appliances connected so that they form a single pathway for charges to flow are connected in a(n)
Answer:A. Series circuit
#CARRYONLEARNING #STUDYWELLAppliances connected so that they create a single pathway for charges to flow are connected in a series circuit. Therefore, option (A) is correct.
What is the resistance of resistors connected in series?In a series combination of appliances, they are connected end-to-end. Consider two resistors, R₁ and R₂ which are connected in a series combination then their effective resistance can be given by:
Total Resistance of the series circuit, R = R₁ + R₂
In a series combination, the current flows through one appliance and then through another appliance. The same current flows through each appliance in one direction. The total voltage of the series circuit is equal to the sum of all the voltage drops across all appliances.
A potential difference of the series circuit, V = V₁ + V₂
Therefore, when appliances are connected in a series circuit they form a single pathway for charges to flow.
Learn more about resistors in series, here:
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A friend tells you that objects with more mass fall faster because they
have a stronger gravitational pull to Earth. How can you show your friend
that this is not true?
Answer:
by throwing heavy mass and less mass in vacuum simultaneously.
IS IT B!! if not pls helpp!
Answer:
I believe you are correct but we just started this unit
Explanation:
ANSWER QUICK 30 POINTS
What force controls the movement of the planets around the sun, holds together stars grouped in galaxies, and galaxies grouped in clusters? Thoroughly explain your answer, making sure to include an example and describe how this force keeps planets in orbit. Make sure to write at least 3-5 sentences and proper conventions (spelling, grammar, punctuation, etc.) to respond. Put all answers in your own words
Answer:
Gravity controls the movement of the planets around the sun, holds together stars grouped in galaxies, and galaxies grouped in clusters. The Universal Law of Gravitation depends on two things. First it depends on mass of each object and the second factor is the distance between two objects. If the mass of one object is Larger, the gravitational pull towards it will be larger and the smaller distance, the larger the gravitational pull will be between the objects. Therefore the Larger planets have more moon and the inner planets have less.
Explanation:
Puck 1 is moving 10 m/s to the left and puck 2 is moving 8 m/s to the right. They have the same mass, m.
a. What is the total momentum of the system before the collision? (Answer in terms of the mass, m.) (0.5 points)
b. What is the total momentum of the system after the collision? (Answer in terms of the mass, m.) (0.5 points)
c. Write puck 1's velocity after the collision in component form. (1 point)
d. What is the y-component of puck 2's velocity after the collision? (1 point)
e. What is the x-component of puck 2's velocity after the collision? (1 point)
f. At what angle does puck 2 move after the collision? Determine the angle and draw it on the diagram. (1 point)
g. What is the magnitude of puck 2's velocity after the collision? (1 point)
Answer:
(a) the total momentum of the system before the collision = -2m kg.m/s.
(b) the total momentum of the system after the collision = -2m kg.m/s.
(c) puck 1's velocity after the collision in component form = (5.44 i, 2.54 j)
Explanation:
Given;
mass of Puck 1 , = m
mass of Puck 2, = m (since they have the same mass m)
initial velocity of Puck 1, u₁ = 10 m/s to the left
initial velocity of Puck 2, u₂ = 8 m/s to the right
Let the rightward direction be positive direction
Let the leftward direction be negative direction
(a) the total momentum of the system before the collision;
P₁ = (initial momentum of Pluck 1) + (initial momentum of Pluck 2)
P₁ = (-mu₁) + mu₂
P₁ = mu₂ - mu₁
P₁ = m(u₂ - u₁)
P₁ = m(8 - 10)
P₁ = -2m kg.m/s
(b) the total momentum of the system after the collision;
Based on the principle of conservation of linear momentum, the total momentum before collision is equal to the total momentum after collision.
Thus, the total momentum of the system after the collision is -2m kg.m/s.
(c) puck 1's velocity after the collision in component form
[tex]v = (v_x, v_y)\\\\v = (vcos \theta , vsin \theta)\\\\v = (6cos 25^0 , 6sin25^0)\\\\v = (5.44i, 2.54j)m/s[/tex]
In the diagram shown above, the circles represent small balls that have
electric charges. Ball 1 has a negative charge, and ball 2 is repelled by ball 1
Next, you see that ball 2 repels ball 3 and that ball 3 attracts ball 4. What is
the electric charge on ball 4?
Ball 4 may have either a positive or negative charge,
Ball 4 has a negative charge.
Ball 4 has a positive charge.
Answer:
ball 4 has a positve charge
Explanation:
-Ball 2: is negative because it is repelled by ball one (like signs repel)
- ball 3: is also negative because it is repelled by ball one (like signs repel)
- Ball 4: is positive because it is attracted by ball 3 (opposite signes attract)
How does attachment affect exploration? Be sure to include findings from both Harlow and Ainsworth in your response.
Answer:
Attachment can affect many things. When you go back to the experiment, you see that they are testing 4 monkeys. They want to see if they would go to the cloth mother or the wire mother. But that is just the base of the experiment. Once the monkeys pick the mother, they have attached themselves to the mother, because animals will pick what is mother, because once you are born, the "hunger games" begin in the wild. They will stay by their mother's side until they are grown and ready to go on their own. When you think about this whole experiment, you know that this experiment was designed as a test of the relative importance of contact comfort. They could have picked any animal for this, and the outcome would have been very similar because as a baby you need to find things that you trust and that is your mother.
Explanation:
A body with mass 2 kg absorbs heat 418.4J when its temperature raises from 293K to 343K . What is the specific heat of the body?
Answer:
C M (change in T) = heat absorbed thermal equation for heat gained
C = 418.4 J / (2 kg * 50 deg K) = 4.184 J / kg * deg K specific heat
Note: 1 gm =.001 kg
So C = .004184J / gm * deg K
Also, 1 J = .239 cal so in conventional terms
C = .001 cal / gm deg K (very low, water would be 1 cal / gm deg C
On Earth, a spring stretches by 5.0 cm when a mass of 3.0 kg is suspended from one end.
The gravitational field strength on the Moon is
1/6 of that on Earth.
Which mass, on the Moon, would stretch the spring by the same extension?
Reasons too :(
igcse physics
Answer:
Mass = 18.0 kg
Explanation:
From Hooke's law,
F = ke
where: F is the force, k is the spring constant and e is the extension.
But, F = mg
So that,
mg = ke
On the Earth, let the gravitational force be 10 m/[tex]s^{2}[/tex].
3.0 x 10 = k x 5.0
30 = 5k
⇒ k = [tex]\frac{30}{5}[/tex] ................ 1
On the Moon, the gravitational force is [tex]\frac{1}{6}[/tex] of that on the Earth.
m x [tex]\frac{10}{6}[/tex] = k x 5.0
[tex]\frac{10m}{6}[/tex] = 5k
⇒ k = [tex]\frac{10m}{30}[/tex] ............. 2
Equating 1 and 2, we have;
[tex]\frac{30}{5}[/tex] = [tex]\frac{10m}{30}[/tex]
m = [tex]\frac{900}{50}[/tex]
= 18.0
m = 18.0 kg
The mass required to produce the same extension on the Moon is 18 kg.
Answer:
18 kg
Explanation:
weight (N) = mass (kg) × gravitational acceleration (m/s²)force (N) = k (spring constant) × extension (m)On Earth, acceleration of gravity is 10 m/s²
weight = 3.0 (kg) × 10 (m/s²)weight = 30 (N)Since weight is a force, the force is 30 N. The value of spring constant is unknown
30 (N) = k × 5 (m)k = 6 (m/N)Spring constant is 6. Now let's find the mass on the Moon
mass (kg) × gravitational acceleration (m/s²) = k (spring constant) × extension (m)Gravitational acceleration of the moon is 1/6 of that on Earth. Earth's g = 10, so Moon's g = 10/6
m × 10/6 = 6 × 5m = 30/(10/6)m = 18The mass is 18 kg
What 2 factors impact gravitational pull?
mass and distance
matter and energy
size and shape
speed and direction
Answer:
When dealing with the force of gravity between two objects, there are only two things that are important – mass, and distance. The force of gravity depends directly upon the masses of the two objects, and inversely on the square of the distance between them
The eagles suck, so do the giants and the jets and jaguars are irrelevant
anyone wanna argue
Naw ur pretty accurate, heck collage is the only football worth watching most the time. Hook'um horns!
The answer to a multiplication problem is called the?
Answer:
product
Explanation:
Answer:
product
Explanation:
You find the product when you multiply two or any number of factors.
A 10.0kg box sits at rest on ramp that has an incline of 20.0° from the horizontal. What is the force of gravity acting on the box?
A. -98.0N
B. 98.0N
C. -92.1N
D. -33.5N
Answer:
98.0N
Explanation:
What does ionic bond mean
Answer:
The acception and donation of elections within two elements is called as ionic bond.MARK ME AS A BRAINLIST AND FOLLOW ME :)PLEASE HELP ASAP!!!!!
Carrie pulls a 41.5 kg bin across the floor of her garage using a rope that is attached to the bin. She pulls with a force of 138 N, at an angle of 28.0° above horizontal. The coefficient of kinetic friction between the floor and the box is 0.290 . What is the acceleration of the box?
Answer: 0.81N
Explanation: Fwx = .165x 9.81 Silicon 30 = 0.81N
If the mass of an object increases, then its kinetic energy will ____________ because __________________________
Answer:
when mass will increase then kinetic energy will also increase because both have positive relationship
Explanation:
when volume increase then molecule come closer then more movement will occurs and kinetic energy increase
Which of the following quantities are vectors?
charges
electric fields
energy
potentials
Answer:
electric fields
Explanation:
Calculate speed...
D=40 m
T=10 s
a
40 m/s
b
400 m/s
c
4 m/s
Answer:
c
Explanation:
speed=distance÷time
40÷10=4
If you put something like a piece of cardboard between a magnet and an iron nail, the magnet still holds the nail in place, even though the magnet is not touching the nail. Explain how that happens. Use the word induce in your response.
Answer:
A magnet has a field having lines of force around it that moves through the air which is a nonpermeable medium that allows the passage of magnetic field lines of force. The cardboard is a similar nonpermeable medium and the magnetic lines of force pass through to induce magnetism in the iron nail which is a ferromagnetic material that becomes magnetized by the magnetic field from the magnet
The induced magnetism in the iron nails causes the reverse poles to form in the iron with the iron domain's induced north pole pointing in the direction of the south pole of the magnet and vice versa
The iron nail is then attracted to the magnet as like poles attract, thereby holding the iron nail in place with the cardboard in between, without direct contact between the nail and the magnet as the cardboard prevents the magnet from touching the iron nail held in place
Explanation:
What is the speed of a person travelling 30 meters in 5 seconds?
Answer:
[tex]6\:\mathrm{m/s}[/tex]
Explanation:
Denote average speed by [tex]S=\frac{d}{t}[/tex] where [tex]d[/tex] is total distance travelled and [tex]t[/tex] is time.
Plugging in given values, we get:
[tex]S=\frac{30}{5}=\fbox{$6\:\mathrm{m/s}$}[/tex].
Answer:
s
Explanation:
Picking up a puppy is easy, but picking up a large horse is difficult. *
1st law
2nd law
3rd law
Answer:
1st
Explanation:
It is because the horse is heavier
Who is the father of Nuclear Physics?
Answer:
Ernest Rutherford, 1st Baron Rutherford of Nelson
A ball is thrown with 50J of kinetic energy, it hits a target which moves with 30J of kinetic energy, how much energy goes to the thermal store of the surroundings?
Answer:
The energy that will go will for thermal store of the surroundings is 20 J.
Explanation:
Given;
kinetic of the thrown ball, K.E₁ = 50 J
kinetic energy used to move the target, K.E₂ = 30 J
The excess energy that will go will for thermal store of the surroundings;
ΔK.E = K.E₁ - K.E₂
ΔK.E = 50J - 30J
ΔK.E = 20 J
Therefore, the energy that will go will for thermal store of the surroundings is 20 J.
Select the correct answer.
A stone is dropped from a tower 100 meters above the ground. The stone falls past ground level and into a well. It hits the water at the bottom
of the well 5.00 seconds after being dropped from the tower. Calculate the depth of the well. Glven: g=-9.81 meters/second?
A.22.5 meters
B.50.7 meters
C.100 meters
D.110 meters
E.152.45 meters
Answer:
A
Explanation:
Givens
d = 100 meters plus the depth of the well
d = 100 + x where x is the depth of the well.
vi = 0 m/s The object is dropped. It was not thrown.
t = 5 seconds
a = 9.81 m/s^2
formula
d = vi*t + 1/2 a t^2
solution
100 + x = 0 + 1/2 * 9.81 * 5^2
100 + x = 122.625 Subtract 100 from both sides
x = 122.625 - 100
x = 22.6 m
The well is 22.6 meters deep.
A 30.0 kg box is placed on a 3.00 m tall shelf. What how much work was done on the box?
Answer:
W = 882.9[J]
Explanation:
In order to be able to calculate the work, we must first calculate the force necessary to lift the box. Since the necessary force is equivalent to the weight of the box, we can determine the weight of the box by means of the product of mass by gravitational acceleration.
[tex]w = m*g\\[/tex]
where:
w = weight [N]
m = mass = 30 [kg]
g = gravity acceleration = 9.81 [m/s²]
[tex]w = 30*9.81\\w = 294.3 [N][/tex]
Now, the work can be calculated multiplying the force (weight) by the distance [m]
[tex]W = w*d\\W = 294.3*3\\W=882.9[J][/tex]
When a cyclist is decelerating uphill the forces on him are balanced or unbalanced
Answer:
Unbalanced
Explanation:
A cyclist decelerating uphill has unbalanced forces acting on him. An unbalanced force acting on a body has a net force which is greater than zero. When a body is accelerating or decelerating, the forces are not balanced.
A body with a net force of zero has balanced forces acting on it. Such body is moving with constant acceleration. According to newton's first law of motion" a body will remain in state of rest or of uniform motion unless an external force acts on it". The external force causes acceleration to change drastically.what are the three laws of motion and examples
Explanation:
In Newton's 1 law, an object will not change its motion unless a force acts on it.
The motion of a ball falling down through the atmosphere, or a model rocket being launched up into the atmosphere are both examples of Newton's first law.
In Newton's 2 law, the force on an object is equal to its mass times its acceleration.
Riding your bicycle is a good example of this law of motion at work. ... Your leg muscles pushing pushing on the pedals of your bicycle is the force. When you push on the pedals, your bicycle accelerates.
In Newton's 3 law, when two objects interact, they apply forces to each other of equal magnitude and opposite direction.
For example, when you jump, your legs apply a force to the ground, and the ground applies and equal and opposite reaction force that propels you into the air.
This is very hard, I don't understand.
Answer:
[tex]4x - 6 = 90 \\ 4x = 96 \\ \boxed{x = 24}[/tex]
Now, AD is an altitude of∆ABC
Therefore, D is the midpoint of BC
[tex]x + 7 = 2x - 15 \\ \boxed{x = 22}[/tex]
CD is (22+7) = 29 & DB is (2×22-15) = 29
[tex] \huge \boxed{\: x = 24 }\\ \huge \boxed{CD \: and \:DB= 29}[/tex]