A net force of 60 N north acts on an object with a mass of 30 kg. Use Newton's second law of
motion to calculate the amount of acceleration the object will experience. Then explain how the
amount of acceleration will change if the net force or the mass of the object increases.

Answers

Answer 1

Answer:

Explanation:

F = ma. For us, this looks like

60 = 30a and

a = 2 m/s/s

If the force goes up to, say, 90, then

90 = 30a and

a = 3...if the force goes up, the acceleration also goes up.

If the mass goes up to say, 60, and the force stays the same, then

60 = 60a and

a = 1...if the mass goes up, the acceleration goes down.


Related Questions

Who's Madame Marie curie?​

Answers

Explanation:

In 1911, Marie was awarded a second Nobel Prize in Chemistry for her discovery of the elements polonium and radium. In honor of the 100-year anniversary of her Nobel award, 2011 was declared the "International Year of Chemistry."

What are the si units

Answers

Answer:

The uniy which is accepted all over the world is called SI unit.

Explanation:

The system of measurement that is agreed by the international convention if scientists that is held in paris of France to adopt an international unit is called SI unit unit.

ACELLUS PHYSICS HELP!!

A 6.93*10-4 C charge has a potential energy U = -3.09 J at a point in space. What is the electric potential V at that point? Include the sign, + or - . (Unit = V)​

Answers

Answer:

Potential difference, V = -0.000224 Volts

Explanation:

Given the following data;

Quantity of charge = 6.93*10-4 C

Energy = -3.09 J

To find the electric potential V at that point?

Mathematically, the energy transferred per unit of charge is given by the formula;

E = QV

Where:

E is the energy

Q is the quantity of charge

V is the potential difference.

Substituting into the formula, we have;

[tex] -3.09 = 6.93*10^{-4} * V [/tex]

[tex] V = \frac {6.93*10^{-4}}{-3.09} [/tex]

Potential difference, V = -0.000224 Volts

How high can a body vertically thrown with a speed of 40m/s raise after 3 sec (neglecting air
resistance)​

Answers

y = 75.9 m

Explanation:

y = -(1/2)gt^2 + v0yt + y0

If we put the origin of our coordinate system at the point where a body is launched, then y0 = 0.

y = -(1/2)(9.8 m/s^2)(3 s)^2 + (40 m/s)(3 s)

= -44.1 m + 120 m

= 75.9

what is average velocity??​

Answers

Answer:

The average velocity of an object is its total displacement divided by the total time taken. In other words, it is the rate at which an object changes its position from one place to another. Average velocity is a vector quantity.

the arithematic mean of initial velocity and final velocity of a moving body is called average velocity

Explanation:

Hope it helps

To help the plant photosynthesize more, leaves and stems
grow
the light.

Answers

what’s the question?

what is a product made from no renewable resources

Answers

Answer:

a nail

Explanation:

Answer:

crude oil, natural gas, coal, and uranium. These are all resources that are processed into products that can be used commercially.

Explanation:

Define emf of a battery? ​

Answers

Answer:

Electromotive force or EMF is equal to the terminal potential difference when no current flows. EMF (ϵ) is the amount of energy (E) provided by the battery to each coulomb of charge (Q) passing through.

How is the annostructure on the chocolate related to the nanostructure of the grating?

help me plss:(

Answers

Answer:

From butter in croissants to cocoa solids in chocolate, edible fats pack a flavor punch that delights like no other macronutrient we consume. Fats are the most energy dense macronutrients, providing more than twice as many kilocalories per gram as proteins or carbohydrates, which may be the reason we've developed a taste for them.

Explanation:

Is the crust uniform (the same) in thickness around the world? Explain

Answers

The thickness of the crust isn't uniform around the world. It varies through different tectonic areas. The continental crust would be thicker than the oceanic crust.

Two arrows are shot vertically upward. The second arrow is shot after the first one, but while the first is still on its way up. the initial speeds are such that both arrows reach their maximum heights at the same instant, although these heights are different. Suppose the that initial speed of the first arrow is 34 m/s and that the second arrow is fired 0.204081632653061 seconds after the first. Determine the initial speed of the second arrow.

Answers

Answer:

The initial speed of the second arrow is 33.8 m/s.

Explanation:

initial speed of first arrow, u = 34 m/s

Let the initial height of the second arrow is h.

Let they both reaches at maximum height H.

Let the time taken by the first arrow is t and the second arrow is t - 0.0204

Let the initial speed of the second arrow is u'.

Use first equation of motion for the first arrow.

v = u - gt

0 = u - gt

34 = gt ..... (1)

For the second arrow

v =u' - g (t - 0.0204)

0 = u' - gt + 9.8 x 0.0204

u' = 34 - 0.1999 = 33.8 m/s

Determine the small gravitational force F which the copper sphere exerts on the steel sphere. Both spheres are homogeneous, and the value of r is 50 mm. Express your result as a vector.

Answers

Solution :

We know that the volume of sphere is given by :

[tex]$V=\frac{4}{3}\pi r ^3$[/tex]

Given r = 50 mm

The density of copper is :

[tex]$\rho_c = 8910 \ kg/m^3$[/tex]

The density of steel is :

[tex]$\rho_s = 7830\ kg/m^3$[/tex]

Therefore, mass of copper is :

[tex]$m_c= V . \rho$[/tex]

[tex]$m_c= \frac{4}{3} \pi (0.05)^3 \times 8910$[/tex]

     = 4.665 kg

     = 4665 g

Similarly, mass of steel is :

[tex]$m_s= V . \rho$[/tex]

[tex]$m_s= \frac{4}{3} \pi (0.025)^3 \times 7830$[/tex]

     = 0.512 kg

     = 512 g

Now the distance between the centers of the particles is by Pythagoras theorem,

[tex]$l^2=(4r)^2+(2r)^2$[/tex]

l = 4.472 x r

 = 4.472 x 50

 = 224 mm

 = 0.224 m

From the law of gravitation,

We know,  [tex]G = 6673 \times 10^{-11} \ m^3 / kg-s^2[/tex]

∴  [tex]$F=G\times \frac{m_c \times m_s}{l^2}$[/tex]

[tex]$F=6.673 \times 10^{-11}\times \frac{4.665 \times 0.512}{(0.224)^2}$[/tex]

[tex]$F = 3.176 \times 10^{-9} \ N$[/tex]

Now,

[tex]$\alpha = \tan^{-1} \left( \frac{2r}{4r}\right)$[/tex]

   =  [tex]$26.56^\circ$[/tex]

Therefore, we can write it in the vector form as

[tex]$\text{F}=F(-i . \cos \alpha - j. \sin \alpha)$[/tex]

[tex]$\text{F}=3.176 \times 10^{-9}(-i . \cos 26.56 - j. \sin 26.56)$[/tex]

[tex]$\text{F}=(-2.840\ i- 1.420 \ j) \times 10^{-9} \ N$[/tex]

One twin sets off on a long space voyage traveling at 0.9 c, while the other stays on Earth. When she returns 60 years later, the traveling sister has hardly aged at all, while her twin has aged 60 years. Which aspect of relativity is demonstrated in this situation

Answers

Answer:

This is the twin paradox.

pls help will mark brainliest, pls

Answers

Answer:

The answer is true. This is correct.

Which of the following changes occurs during nuclear fission?
A. Energy is absorbed from the surroundings.
B. Atomic nuclei combine to form a larger nucleus.
C. Energy is converted into mass.
D.
The parent nucleus splits into lighter daughter elements.
Reset

Answers

Answer:

The parent nucleus splits into lighter daughter elements

Explanation:

Nuclear fission involves the splitting of nucleus of a lighter element with smaller particles

On what factors does critical velocity depend on

Answers

Explanation:

The critical velocity is that velocity of liquid flow, up to which its flow is streamlined (laminar)& above which its flow becomes turbulent. It's denoted by Vc & it depends upon: Coefficient of viscosity of liquid (η) Density of liquid. Radius of the tube.

4. A girl is sitting on a tire swing that is attached with a rope that is 2.1 m in length. Her dad pushes her with a speed of 3.0 m/s. If the centripetal force is 88 N, what is the mass of the girl? ​

Answers

The centripetal acceleration is given by
a
=
v
2
r
and Newton's Second Law says
F
=
m
a
, so
F
=
m
v
2
r
. Rearranging,
m
=
F
r
v
2
=
88

2.1
2.5
2

29.6

k
g
.

While traveling along a highway a driver slows from 24 m/s to 15 m/s in 12 seconds. What is the automobile's acceleration? (Remember that a negative value indicates a slowing down or deceleration.) don't forget to write the formula(1pt.) and the unit (1pt.)

Answers

Answer:

Acceleration = -0.75 m/s²

Explanation:

Given the following data;

Initial velocity = 24 m/s

Final velocity = 15 m/s

Time = 12 seconds

To find the acceleration of the automobile;

Acceleration can be defined as the rate of change of the velocity of an object with respect to time.

This simply means that, acceleration is given by the subtraction of initial velocity from the final velocity all over time.

Hence, if we subtract the initial velocity from the final velocity and divide that by the time, we can calculate an object’s acceleration.

Mathematically, acceleration is given by the equation;

[tex]Acceleration (a) = \frac {final \; velocity - initial \; velocity}{time}[/tex]

Substituting into the formula, we have;

[tex] Acceleration = \frac{15 - 24}{12}[/tex]

[tex] Acceleration = \frac{-9}{12}[/tex]

Acceleration = -0.75 m/s²

Therefore, the automobile is decelerating because its final velocity is lesser than its initial velocity, leading to a negative value.

particles that are found in the sun's plasma​

Answers

Answer:

This plasma mostly consists of electrons

The answer is electrons

A ball is dropped from rest out of a high window in a tall building for 5 seconds. Assuming we ignore air resistance and assume upwards to be positive. A) What will be the final velocity of the ball B) What is the height of the building if it hits the ground after those 5 seconds.

Answers

Answer:

what is the upwards force?

Answer:

final velocity=-49m/s and height=122.5

Explanation:

u=0,t=5s,v=?

v=u+gt

v=0+(-9.8)5

v=-49m/s

h=ut+1/2gt*2

h=0(5)±1/2(-9.8)5*2

h=-122.5 or 122.5

but height=122.5 because height cannot be negative

An elephant pushes with 2000 N on a load of trees. It then pushes these trees for 150 m. How much work did the elephant d

Answers

Answer:

300000

Explanation:

2000×150= 300000

Can somebody please answer this correctly I will give brainliest

Answers

I think what’s wrong is that the paper clip isn’t connecting to the other thing on the bottom

(answer it or get reported) Please answer it w the steps​

Answers

Answer;

The mass value for the above kinetic energy equation is 400.0000 kg. This is equal to:

■ 400,000.0000 g.

■ 14,109.6000 ounces.

■ 881.8480 pounds.

5. Alex worked out for 4 hours and lost 3 lbs. during that time. What is the range of water that he should drink in ounces after his workout?

Answers

9 ounces bc if he does then he wont be so like ugh I'm out of wonder land yeah 9 ounces deffo

As shown in the diagram below, a 1 kg rock tied to a rope is
swung by a boy. This rock has a constant speed of 5 m/s,
and the length of the rope is 1 m. The rock's angular
momentum is

Answers

Answer:

Explanation:

Angular momentum has a formula of L = mvr. Fillingin:

L = (1.0)(5.0)(1.0)

L = 5.0 kg*m/s

Choices:
A. Most kinetic energy and least potential energy
B. Most potential energy and least kinetic energy
C. Potential energy is equal to kinetic energy
D. Potential energy is increasing
E. Potential energy is decreasing
F. Kinetic energy is increasing
G. Kinetic energy is decreasing
Directions: Write one letter from the choices above in each of the spaces.
1. When the minion hits the ball at position one, what choices best describe the energy present. (choose 3)
___________, ___________, _____________

2. Position 2 (choose 2) ____________, ___________

3. Position 3 (choose 3) _____________, ____________, ______________

4. Position 4 (choose 2) ______________, _____________

5. Position 5 (choose 2) ______________, _____________

6. Positions 6 (right when the ball is about to touch the ground ___________, ____________, _____________

Answers

Answer:

I think there's a pdf for the questions you need

WorksheetKineticVsPotentialEnergy.pdf

Explanation:

28. The mass of a steel building frame is 5500 kg. What power is used to raise it to a helght of 5.0 m If the work is done in 12.0 seconds?
Remember to include your data, equation, and work when solving this problem.

Answers

Answer:

2292W

Explanation:

Use the formula for energy first:

[tex]E=D*M[/tex]

Where E = Energy || D = Distance || M = Mass.

Solve that equation:

E = 5 * 5500    ==>     27500J

To find power, divide energy per time:

27500J / 12s =~  2292W

Did it in a rush, any problems message me

Given the following reactants, what are the most likely products?

Answers

The answer is B

CO2+H2O

Cart A with a mass equal to 24 kg is moving to the right at 3.2 m/s. It collides with Cart B that
has a mass of 32 kg and is moving to the left with a velocity of 12.8 m/s. After the collision,
Cart A has a velocity of 2.9 meters per second to the left. What is the speed of the Cart B after
the collision?

Answers

Answer:

Explanation:

According to the Law of Momentum Conservation, what happens after the collision has to equal what happened before the collision because momentum cannot be created nor destroyed; it has to go somewhere else. Like energy eventually dissipates into heat. The equation for this is:

[tex][m_Av_A+m_Bv_B)]_b=[(m_Av_A+m_Bv_B)]_a[/tex] and filling in our info, calling right positive and left negative:

[(24(3.2) + 32(-12.8)] = [(24(-2.9) + 32(vB)] and

[(77 - 410)] = [(-7.0 × 10¹ + 32vB)] and

-330 = -7.0 × 10¹ + 32vB and

-260 = 32vB so

vB = -8.1 m/s Thus, cart B is moving to the left at a velocity of 8.1 m/s

(I used the rules for sig dig very intentionally and correctly; I'm not sure how strict your teacher is about them. I require my students to use the rules to perfection, as I did here.)

Find the temperature of a mixture obtained by mixing 32 grams of water at a temperature of 22 degrees Celsius with 88 grams of water at a temperature of 75 degrees Celsius.

Answers

Answer:

60.87 °C

Explanation:

Applying,

Heat lost = heat gain

cm'(t₂-t₃) = cm(t₃-t₁).............. Equation 1

Equation 1 can futher be simplified to

m'(t₂-t₃) = m(t₃-t₁)................Equation 2

Where m' = mass of the hot water, m = mass of the cold water, t₁ = initial temperature of the cold water, t₂ = initial temperature of the hot water, t₃ = temperature of the mixture.

From the question,

Given: m' = 88 g, m = 32 g, t₁ = 22°C, t₂ = 75°C

Substitute these values into equation 2

88(75-t₃) = 32(t₃-22)

6600-88t₃ = 32t₃-704

32t₃+88t₃ = 6600+704

120t₃ = 7304

t₃ = 60.87 °C

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