A parking lot has 117 spaces total. If 36 of the spaces have cars in them, what is the ratio of empty spaces to filled spaces?

Answer: I'll give you formula

Step-by-step explanation: circumference = 2 x π x radius

radius = diameter÷2      area = π × radius²

Answer:

c

brainlest

Step-by-step explanation:

Answer: y= 1/2x + 7

Step-by-step explanation:

Answer:

35 degrees celsius

Answer:

a = 3

Step-by-step explanation:

ok so first you do the reciprocal of division which is multiplication. So its gonna be 3/4 x 1/a = 1/4

you multiply the fractions 3/4 x 1/a and get 3/4a = 1/4

then you cross multiply and you get 12=4a

swap sides so its going to be 4a = 12

divide both sides by 4 and you get a = 3

Step-by-step explanation:

subject arts and architecture what primary

Answer:

Step-by-step explanation:

Yes, but like they say in Vegas, you're trying to make your point the hard way.

8 * (8 - 4)              So the distributive property is means remove the brackets.

8*8 - 4*8               What you have done is multiply the numbers on either side of the - sign by 8. It is a good practice NOT to destroy the minus sign just yet.

64 - 32

32                          The answer is 32. That's how the distributive property works

With this question only It might be easier to do what is inside the brackets first. That's making your point the easy way.

8*(8-4) = 8* 4 = 32

Using conditional probability, it is found that there is a 0.7873 = 78.73% probability that Mona was justifiably dropped.

Conditional Probability

[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]

In which

In this problem:

The probability of failing the test is composed by:

Hence:

[tex]P(A) = 0.46(0.37) + 0.63 = 0.8002[/tex]

The probability of both failing the test and being unfit is:

[tex]P(A \cap B) = 0.63[/tex]

Hence, the conditional probability is:

[tex]P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.63}{0.8002} = 0.7873[/tex]

0.7873 = 78.73% probability that Mona was justifiably dropped.

A similar problem is given at https://brainly.com/question/14398287

Answer:

Step-by-step explanation:

From the question, I couldn't really tell what the chart looks like, so I am guessing it looks like this:

Sidewalk 1:

x  |  y

2  |  17

0  | 5

Sidewalk 2:

x  |  y

1  |  20

3  | 26

Part a.

Now, we have to write the equation for sidewalk 1 in slope-intercept form.

Slope-intercept form is represented as this: [tex]y=mx+b[/tex], where m is the slope and b is the y-intercept. Because this is true for all values on the line, we can plug in values of the chart for Sidewalk 1.

[tex]17=2m+b\\5=0m+b[/tex]

Subtracting the second equation from the first, we have

[tex]12=2m[/tex], and [tex]m = 6[/tex].

Now, we can just plug 6 back into the first equation to get:

[tex]17=2(6)+b[/tex]  to get [tex]17 = 12 + b[/tex], and then [tex]b = 5[/tex].

Now, we can just rewrite slope intercept form for Sidewalk 1 to have

[tex]y=6x+5[/tex].

Part b.

Point-slope form is represented as [tex]y-y_1=m(x-x_1)[/tex], where x and y are the coordinates of one point, and x1 and y1 are the coordinates of another point on the line. Because the chart represented for Sidewalk 2 includes a point, namely [tex](1, 20)[/tex] and [tex](3, 26)[/tex], we can plug this in and solve for the slope:

[tex]26-20=m(3-1)[/tex]

This is it in point-slope form. Because the second part of the question asks us to convert to slope-intercept form, we must solve for the slope, or m.

Expanding, we have [tex]26-20=3m-m[/tex]

Combining like terms, we have [tex]6 = 2m[/tex], and then [tex]3 = m[/tex]. Now, we need to plug a point and the slope back into point-slope form, not needing another point. We choose [tex](1, 20)[/tex], even though [tex](3, 26)[/tex] works just as well.

[tex]y-20=3(x-1)[/tex]

Expanding, we have [tex]y-20=3x-3[/tex]

Adding 20 to both sides, we have [tex]y=3x+17[/tex]

Part c. and d.

We see that both equations do not have the same slope, so then they are not parallel, meaning they don't have no solutions. If they have a solution, we can set them equal to each other.

[tex]3x+17=6x+5[/tex]

Subtracting 3x, we have [tex]17=3x+5[/tex]

Subtracting 5, we have [tex]12 = 3x[/tex]

Dividing by 3, we have [tex]x = 4[/tex].

Because there is no x = x, or anything like that, the solution does not have infinite solutions and therefore has one solution, meaning it is consistent independent.

Step-by-step explanation:

If you like my answer than please mark me brainliest thanks

Answer:

Step-by-step explanation:

Initial class size = 30 students

Class size now is 40% larger:

First let's find larged amount

[tex]\\ \sf\longmapsto 40\%\:of\:30[/tex]

[tex]\\ \sf\longmapsto 0.4(30)[/tex]

[tex]\\ \sf\longmapsto 12[/tex]

Class size=30+12=42students

Answer:

xd

Step-by-step explanation:

3X+4y=8

this is the graph that represents the solution

Answer:

$9.61 per shirt

Step-by-step explanation:

You take the total cost of $48.05 and divide it by the number of t-shirts which is 5.

48.05/5 = 9.61

[tex]6x^2-x=2\implies 6x^2-1x-2=0 \\\\[-0.35em] ~\dotfill\\\\ ~~~~~~~~~~~~\textit{quadratic formula} \\\\ \stackrel{\stackrel{a}{\downarrow }}{6}x^2\stackrel{\stackrel{b}{\downarrow }}{-1}x\stackrel{\stackrel{c}{\downarrow }}{-2}=0 \qquad \qquad x= \cfrac{ - b \pm \sqrt { b^2 -4 a c}}{2 a}[/tex]

[tex]x = \cfrac{ -(-1) \pm \sqrt { (-1)^2 -4(6)(-2)}}{2(6)}\implies x = \cfrac{1\pm\sqrt{1+48}}{12} \\\\\\ x = \cfrac{1\pm\sqrt{49}}{12}\implies x = \cfrac{1\pm 7}{12}\implies x = \begin{cases} \frac{8}{12}\to &\frac{2}{3}\\[1em] -\frac{6}{12}\to &-\frac{1}{2} \end{cases}[/tex]

Answer:

OOO

OOO

OO

Step-by-step explanation:

Where OOO is == 1.

OO is 2/3 of OOO.

Answer:

Jill plz tell if i am right

Step-by-step explanation:

give me schoology website

Answer:

5.62790697674

Step-by-step explanation:

there you go

Answer:

the annswer is 5

Step-by-step explanation: you just have to divide the highlighted numbers, which are 20 ÷ 5

Answer:

$2 each

Step-by-step explanation:

$14.50-$4.50=$10.00

10.00/5 games =$2 each

Answer:

[tex]\huge\colorbox{blue}{A}\huge\colorbox{orange}{N}\huge\colorbox{gray}{S}\huge\colorbox{red}{W}\huge\colorbox{yellow}{E}\huge\colorbox{purple}{R}[/tex]

hitsss

Take the first partial derivatives of f(x, y):

∂f/∂x = -2 (x - 5) = 10 - 2x

∂f/∂y = -2y

The critical points occur where both derivatives are zero:

10 - 2x = 0   ===>   x = 5

-2y = 0   ===>   y = 0

So there is only critical point at (5, 0), which takes on a value of f(5, 0) = 25.

Compute the Hessian matrix for f :

[tex]H(x, y) = \begin{bmatrix}\frac{\partial^2f}{\partial x^2} & \frac{\partial^2f}{\partial x\partial y} \\ \frac{\partial^2f}{\partial y\partial x} & \frac{\partial^2f}{\partial y^2}\end{bmatrix} = \begin{bmatrix}-2&0\\0&-2\end{bmatrix}[/tex]

Since det(H(x, y)) = 4 > 0 for all x, y, the critical point (5, 0) is a relative minimum.

f has no saddle points.

Using the t-distribution, it is found that the 99% confidence interval for the difference is (0.058, 3.462).

We are given the standard deviation for the samples, hence, the t-distribution is used to solve this question.

The standard errors are given by:

[tex]s_A = \frac{1.79}{\sqrt{18}} = 0.4219[/tex]

[tex]s_B = \frac{1.95}{\sqrt{18}} = 0.4596[/tex]

For the distribution of differences, the mean and the standard error are given by:

[tex]\overline{x} = \mu_A - \mu_B = 23.95 - 22.19 = 1.76[/tex]

[tex]s = \sqrt{0.4219^2 + 0.4596^2} = 0.6239[/tex]

The interval is given by:

[tex]\overline{x} \pm ts[/tex]

The critical value for a two-tailed 99% confidence interval with 18 + 18 - 2 = 34 df is t = 2.7284.

Then:

[tex]\overline{x} - ts = 1.76 - 2.7284(0.6239) = 0.058[/tex]

[tex]\overline{x} + ts = 1.76 + 2.7284(0.6239) = 3.462[/tex]

The 99% confidence interval for the difference is (0.058, 3.462).

For more on the t-distribution, you can check https://brainly.com/question/16162795

Check the picture below.

notice, we have three pair of sides, let's add them all up to get the area

[tex]\stackrel{\textit{left and right}}{2(8\cdot 14)}+\stackrel{\textit{front and back}}{2(3.5\cdot 8)}+\stackrel{\textit{top and bottom}}{2(3.5\cdot 14)}\implies 378~in^2[/tex]

Answer: 12% of people responded as City D

Answer:

B

Step-by-step explanation:

If you go to -4, 0 the line intersects that point

There are 100 numbers in the range 100-199. Find the smallest and largest multiple of 13 in this range. We have

104 = 8•13

195 = 15•13

so there are 15 - 8 + 1 = 8 multiples of 13 between 100 and 199.

Then the sum we want is

[tex]\displaystyle \sum_{k=100}^{199} k - \sum_{\ell=8}^{15}13\ell[/tex]

or equivalently,

(100 + 101 + 102 + … + 199) - 13 (8 + 9 + … + 15)

To compute these sums, recall the following formula:

[tex]\displaystyle \sum_{i=1}^n i = 1 + 2 + 3 + \cdots + n = \frac{n(n+1)}2[/tex]

Then

[tex]\displaystyle \sum_{k=100}^{199} k = \sum_{k=1}^{199} k - \sum_{k=1}^{99} k = \frac{199\cdot200}2 - \frac{99\cdot100}2 = 14,950[/tex]

and

[tex]\displaystyle \sum_{\ell=8}^{15} 13\ell = 13 \left(\sum_{\ell=1}^{15} \ell - \sum_{\ell=1}^7 \ell\right) = 13 \left(\frac{15\cdot16}2 - \frac{7\cdot8}2\right) = 1,196[/tex]

which means the sum we want is 14,950 - 1,196 = 13,754.

Answer:

A.1 B.2 E.5 F.6

Step-by-step explanation:

Hope it helps brainliest awnser pls

Answer:

5/8

Step-by-step explanation:

1/4÷2/5=1/4×5/2=5/8 barrel/Hour

Answer:

(1+y)^(3/2)-3(1+y)^(1/2)=(1+x)^(3/2)-3(1+x)^(1/2)+c

Step-by-step explanation:

This is separable.

Multiply x dx on both sides and divide both sides by (1+y)^(1/2) to obtain:

y/(1+y)^(1/2)=(1+x)^(-1/2) x dx

Using law of exponents to get rid of negative exponent by finding reciprocal:

y/(1+y)^(1/2)=x/(1+x)^(1/2) dx

Let u=(1+y)^(1/2).

Then u^2=1+y.

Differentiate: 2 u du=dy

[Let v=(1+x)^(1/2).]

Plug in our substitution:

(u^2-1) 2u du/u=(v^2-1) 2v dv/v

Simplify:

(u^2-1) 2 du=(v^2-1) 2 dv

Integrate both sides:

(u^3/3-u) 2+L=(v^3/3-v) 2+K

Divide both sides by 2:

u^3/3-u +L/2=v^3/3-v+K/2

K/2-L/2 is just a constant value C:

u^3/3-u=v^3/3-v+C

Use substitution again to put back in terms of x and y:

((1+y)^(1/2))^3/3-(1+y)^(1/2)=((1+x)^(1/2))^3/3-(1+x)^(1/2)+C

Simplify the exponent part a bit:

(1+y)^(3/2)/3-(1+y)^(1/2)=(1+x)^(3/2)/3-(1+x)^(1/2)+C

I don't like the division by 3 so multiply both sides by 3:

(1+y)^(3/2)-3(1+y)^(1/2)=(1+x)^(3/2)-3(1+x)^(1/2)+3C

3C is still just an unknown constant, c.

(1+y)^(3/2)-3(1+y)^(1/2)=(1+x)^(3/2)-3(1+x)^(1/2)+c

gak bisa bahasa inggris.

Step-by-step explanation:

maap.