A poorly-built machine has three components that can independently fail with a
probability of 1/3. The machine will fail if any component fails. What is the probability
that the machine fails?

Answer:The area A of a rectangle is represented by the formula A=lw where l is the length and w is the width. The length of the rectangle is 5.

Write an equation that makes it easy to find the width of the rectangle if we know the area and the length.

Step-by-step explanation:

Answer: 44

Step-by-step explanation:

since OPN and RPQ are similar triangles, you can use ratios to find their sides

[tex]\frac{24}{15} =\frac{x}{15+12.5}[/tex]  or  [tex]\frac{24}{15} =\frac{x}{27.5}[/tex]

cross multiply to get: 24*27.5 = 15x

660/15 = x

x = 44

Answer:

the value of x is 135 i believe

Step-by-step explanation:

sorry if im wrong

Answer: y=-2x

Step-by-step explanation: Use the slope formula

-8-2/4-(-1)

-10/5=-2

y=-2

Answer:

y = - 2x

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c  ( m is the slope and c the y- intercept )

calculate m using the slope formula

m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]

with (x₁, y₁ ) = (- 1, 2 ) and (x₂, y₂ ) = (4, - 8 )

m = [tex]\frac{-8-2}{4-(-1)}[/tex] = [tex]\frac{-10}{4+1}[/tex] = [tex]\frac{-10}{5}[/tex] = - 2 , then

y = - 2x + c ← is the partial equation

to find c substitute either of the 2 points into the partial equation

using (- 1, 2 )

2 = 2 + c ⇒ c = 2 - 2 = 0

y = - 2x + 0 , that is

y = - 2x ← equation of line

The amount of chocolate left is three and seven-twelfths pounds

The amount of chocolate left is found by addition and subtraction of fraction

The fraction required are:

Eva bought seven and one-half pounds of chocolate chips = 7 1/2

She used three and three-fourths pounds = 3 3/4

two and five-sixths pounds in some muffins = 2 5/6

total amount used = addition of amount used

3 3/4 + 2 5/6

= 3 11/12

the amount left is gotten by subtraction of amount used from amount Eva bought

= 7 1/2 - 3 11/12

= 3 7/12

this is three seven-twelfths

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Approximately Carlo takes 2 minutes time to sing the song.

Given that, Ariel sings a song in 5.92 minutes. Carlos sings the same song in 7.73 minutes.

Rounding a number means the process of making a number simpler such that its value remains close to what it was. The result obtained after rounding off a number is less accurate, but easier to use. While rounding a number, we consider the place value of digits in a number.

Now,

Difference of singing time = 7.73-5.92

= 1.81 minutes

≈ 2 minutes

Hence, approximately Carlo takes 2 minutes time to sing the song.

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Answer:

100°

Step-by-step explanation:

The sum of any polygon angles add to  ( n-2)(180)   where n is the number of sides ......for a quadrlateral    ( 4-2)(180 ) = 360

60 + 90 + 110 +  x = 360    shows    x = 100 °

Answer:

sin75^°-sin15^°=1/√2

Answer:

4

Step-by-step explanation:

you can use the formula y=mx+b where b is 4

The values of the variables "a", "b", and "c" are 3.06, 169.74, and 0, respectively. The total amount Gary will pay is $769.74.

Gary purchased a S750 TV on a credit card with a 22% annual percentage rate, and he wants to pay it off in payments of $200 per month. The table shows the information for the first four months after Gary used his credit card. We need to calculate the values of the missing variables and the total amount he will pay.

The variable "a" is the interest charged on the left amount in the third month.

a = (366.68 - 200)*0.018333 = 3.06

The variable "b" is the monthly amount paid by Gary. It is less than or equal to $200, depending on the payment amount. Since the amount to be paid is $169.74, which is less than $200, he will pay the whole amount in one go.

b = 169.74

The variable "c" is the interest charged on the left amount in the fourth month. Since then, the entire amount has been paid.

c = 0

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The number of solutions in the system is 1

From the question, the system of equations is given as

Also, we understand that the linear equation is a vertical straight line.

So, we have the system to be

A vertical line can only intersect with a quadratic line at one point

Hence, there is only one solution in the system

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Answer:

9(x+4)= 6

Step-by-step explanation:

I could be wrong but im not sure

The equation of the trend line in the scatter plot is y = - 4x + 24

What is the slope-intercept form?

Writing the equation of a line in the slope-intercept form simply makes the slope (steepness) and y-intercept (where the line crosses the vertical y-axis) obvious.

Here, we have

The yellow points are located at points (6, 0) and (4, 8)

For a linear equation that passes through the points (x₁, y₁) and (x₂, y₂), the slope is:

s = (y₂ - y₁)/(x₂ - x₁)

Then, for the equation, the slope is

s = (8-0)/(4-6) = -4

Then the linear equation become

y = -4x + b

where b is the y-axis intercept.

To find b, we use that when x = 6, y = 0

0 = 6×(-4) + b

b = 24

Then equation become y = - 4x + 24

Hence, the equation of the trend line in the scatter plot is y = - 4x + 24

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Using the Law of Cosines, the value of x is 40.9°.

Cosine formula, cos A [tex]=\frac{b^{2}+c^{2}-a^{2} }{2bc}[/tex].

Here, A = x

          a = 16

          b = 15

          c = 24

cos x [tex]=\frac{15^{2}+24^{2}-16^{2}}{2*15*24}[/tex]

         [tex]=\frac{225+576-256}{720}[/tex]

         [tex]=\frac{801-256}{720}[/tex]

         [tex]=\frac{545}{720}[/tex]

         = 0.756

x [tex]= cos^{-1}0.756[/tex]

 = 40.9

Hence, value of x is 40.9°.

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Answer:

[tex]a_1=3[/tex]

[tex]a_n=a_n_-_1+2[/tex]

Step-by-step explanation:

Recursive formula : an = a(n-1) + d

where d = common difference , an = nth term, and n = number of terms

Because we are just writing the recursive formula rather than the explicit formula, the only defined term will be "d" or the common difference.

Here, the common difference is +2. This is evident as you must add 2 to get to 5 and then add 2 to get to 7 etc.

So d = 2

Plugging this into the recursive formula we get an = a(n-1) + 2

Also it's very important to state the first term which is 3 so a1 = 3

Step-by-step explanation:

The drawing has the side dimension of 7.6 cm

  since each cm represents 90 m   the ACTUAL park is

        7.6 x 90 = 684 meters

  similarly, the bottom of the drawing has the dimension 9.1 cm which represents    9.1 x 90 = 819 m

the area of the park is then

Area =  height x width =     684 m x 819 m = 560 196 m^2

OR  in one step:

Area of the actual park is then

(7.6 cm * 90 m / cm )   X  ( 9.1 cm * 90 m/cm ) = 560 196 m^2

Answer:

1

3

6

are all the correct answers because they made the most sense and looked the most proportional

the 4.3 represents The number of apples in 1 pound

The 4.3 in the equation represents the number of apples in 1 pound

The solution of an equation refers usually to the values of the variables involved in that equation which if substituted in place of those variable would give a true mathematical statement.

We are given equation y = 4.3x can be used to determine the total cost, y, in dollars, of x pounds of apples.

Here we can see that y = 4.3x

4.3 = y/x

then we can say that 4.3 is slope of striaght line in term os linear equation.

4.3 in the equation represents the number of apples y, in dollars, of x pounds.

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Answer: based on the information that you gave me, I think the answer is :

A. sex is an explanatory variable; starting salary is the response variable ;area of specialization is a possible confounding variable

hope this helps

Step-by-step explanation:

Answer:

Angle BAC =50

Step-by-step explanation:

Since O is the circumcenter and angle BOC is the angle subtended by the arc BC at the center and angle BAC is the angle subtended by arc BC

The range of the given function is represented as {y | -5 ≤ y ≤ 5 , y ∈ R} .

Range of a function is defined as the possible values of y or the dependent variable in relation to the values of x.

Here from the graph we can see that the greatest value y achieves is 5.

The lowest value of y from the graph is -5 for all the values of x.

Hence the range will be {-5 ≤ y ≤ 5}

Now the graph is continuous, so we accept all values of y, hence y ∈ R .

Therefore the range will be: {y | -5 ≤ y ≤ 5 , y ∈ R} .

The set of all possible values for the results of the dependent variable, or the entire set of all possible values when the domain is substituted, is the range of a function.

The steps to find the range is:

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[tex](\stackrel{x_1}{10}~,~\stackrel{y_1}{4})\hspace{10em} \stackrel{slope}{m} ~=~ - \cfrac{3}{5} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{4}=\stackrel{m}{- \cfrac{3}{5}}(x-\stackrel{x_1}{10}) \\\\\\ y-4=- \cfrac{3}{5}x+6\implies {\Large \begin{array}{llll} y=- \cfrac{3}{5}x+10 \end{array}}[/tex]

The sequence converges and its limit is zero

A sequence is an ordered set of numbers governed by a rule.

The limit of a sequence is the value the sequence approaches

The convergence of a sequence is when the sequence approached a definite value

The divergence of a sequence is when the sequence does not approach a  definite value.

Since we have the sequence (√3 - √1), (√4 - √2), (√5 - √3), (√6 - √2), We need to find the general term of the sequence.

Observing this, we find that the general term Uₙ = √(n + 2) - √n

To determine if the limit converges or diverges, we take the limit of the sequence as n → ∞.

So,

[tex]\lim_{n \to \infty} U_n = \lim_{n \to \infty} \sqrt{n + 2} - \sqrt{n} \\= \lim_{n \to \infty} \sqrt{n + 2} - \lim_{n \to \infty} \sqrt{n} \\= \sqrt{\infty - 2} - \sqrt{\infty} \\= \sqrt{\infty} - \sqrt{\infty} \\= \infty -\infty[/tex]

Since this is an indeterminate form, we use L'hopital's rule to find the limit.

Uₙ = √(n + 2) - √n

= √n{√[(n + 2)/n] - 1}

= √n÷ 1/{√[(1 + 2/n] - 1}

Differentiating, we have

lim n → ∞ Uₙ = lim n → ∞ d√n/dn ÷ d(1/{√[(1 + 2/n] - 1})/dn

= 1/(2√n)/-√[(1 + 2/n] - 1})⁻² × 1/2√(1 + 2/n] × (-2/n²)

= n²[√(1 + 2/n] - 1})²/(2√n)√(1 + 2/n]

= n²[√(1 + 2/n] - 1})²/(2√n)√(1 + 2/n)]

Dividing through by n², we have

= n²[√(1 + 2/n] - 1})²/n² ÷ (2√n)√(1 + 2/n)]/n²

= [√(1 + 2/n] - 1})² ÷ (2(√n)³√(1 + 2/n³)]

Dividing both the numerator and denominator by (√n)³, we have

= [√(1 + 2/n] - 1})²/(√n)³ ÷ (2(√n)³√(1 + 2/n³)]/(√n)³

= (1 + 2/n] - √(1 + 2/n] + 1)/(√n)³ ÷ [2√(1 + 2/n³)]

= (1(√n)³ + 2/n²] - √{(1 + 2/n]/n)³} + 1/(√n)³) ÷ [2√(1 + 2/n³)]

= (1(√n)³ + 2/n²] - √{(1/n³ + 2/n⁴} + 1/√n)³) ÷ [2√(1 + 2/n³)]

So, lim n → ∞ Uₙ = lim n → ∞  (1(√n)³ + 2/n²] - √{(1/n³ + 2/n⁴} + 1/√n)³) ÷ [2√(1 + 2/n³)]

=  (1(√∞)³ + 2/∞²] - √{(1/∞³ + 2/∞⁴} + 1/√∞)³) ÷ [2√(1 + 2/∞³)]

=  (0 + 0] - √{(0 + 0} + 0) ÷ [2√(1 + 0)]

= (0 - 0 + 0)/2

= 0/2

= 0

The sequence converges and its limit is zero

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The volume of a trunk of a regular quadrangular pyramid is 2754 cubic centimeters.

According to the question,

We have the following information:

The side of the base is 18cm, the length of the upper side is 7.5cm and the height of the trunk is 20.4cm.

Now, we know that the trunk of a regular quadrangular pyramid is in the shape of a cuboid.

And the following formula is used to find the volume of cuboid:

Length*breadth*height

​ Volume of a trunk of a regular quadrangular pyramid = 7.5*18*20.4

Volume of a trunk of a regular quadrangular pyramid = 2754 cubic centimeters

Hence, the volume of a trunk of a regular quadrangular pyramid is 2754 cubic centimeters.

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Answer:

Step-by-step explanation:

You want the equation of the line with slope 3/5 that passes through point (5, 3).

The point-slope form of the equation of a line with slope m through point (h, k) is ...

  y -k = m(x -h)

You have m=3/5, (h, k) = (5, 3), so your equation is ...

  y -3 = 3/5(x -5) . . . . point-slope form of desired equation

This can be simplified to ...

  y -3 = 3/5x -3

  y = 3/5x . . . . . . . add 3

Answer:6400 multiplied  by 13% (0.13)  then multiply that answer by 52 , for weeks in the year.  

Step-by-step explanation:

6400*.013= $832.00

832*52= $43264.00

Answer:

[tex]f(x) = (x+1)(x-2)(x+4)[/tex]

        [tex]= (x^{2} +x-2x-2)(x+4)\\\\= (x^{2} -x-2)(x+4)\\\\= x^{3}-x^{2}-2x+4x^{2} -4x-8\\\\= x^{3} +3x^{2} -6x-8[/tex]

the dimensions of the dumpster that will minimize its surface area

length l = 6.32

width w =  1.58

height h = 0.39

Length = l

width = w

height = h

given that length is four times its width

l = 4w

Now, the formula for the surface area of a cube is;

S = 2lh + 2lw + 2wh

substitute l = 4w in the above equation

S = 2(4w)h+2(4w)w+2wh

S = 8wh+8[tex]w^{2}[/tex]+2wh

S = 10wh + 8[tex]w^{2}[/tex]

formula for the volume of a cube is;

V = lwh

now substitute l=4w in the above equation

V = (4w)wh

V = 4[tex]w^{2}[/tex]h

h = 4[tex]w^{2}[/tex]/V

Put V/2w² for h in the surface area equation to get;

S= 8w² + 10w(V/4w²)

 = 8w² + 5V/2w

given that volume V = 25.6 substitute that in the above equation

S = 8w² + 5(25.6)/2w

  = 8w² + 128/2w

Since we want to minimize the surface area, let us find the first derivative of S to get;

S' = 16w - 128/2w²

At S' = 0

0 = 16w-  128/2w²

16w =  128/2w²

32w³ = 128

w³ = 128/32

w³ = 4

w = [tex]\sqrt[3]{4}[/tex]

w = 1.58 yds

since l = 4w substitute the value of w in that

l = 4(1.58) = 6.32

h = 4[tex]w^{2}[/tex]/V = 4([tex]1.58^{2}[/tex])/25.6

h = 0.39

the dimensions are

length l = 6.32

width w =  1.58

height h = 0.39

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The image of the polygon after rotation of 90° about the origin is  A'(-1, 3) , B'(2 , -2) , C'(-3 , -3) , the graph of the polygon and its image is shown below .

In the question ,

it is given that ,

the vertices of the polygon is A(-3,-1), B(2, 2), C(3,-3) .

the graph of the polygon ABC is shown below .

We know when the point (x , y) is rotated 90° in clockwise direction , it s coordinate change to (y , -x) .

So , image of coordinate A(-3,-1) is

A'(-1,-(-3)) = A'(-1, 3)

image of coordinate B(2, 2) is

B'(2 , -2)

image of coordinate C(3,-3) is

C'(-3 , -3)

So , the graph of the image with coordinates A'(-1, 3) , B'(2 , -2) , C'(-3 , -3) is shown below .

Therefore , The image of the polygon after rotation of 90° about the origin is  A'(-1, 3) , B'(2 , -2) , C'(-3 , -3) , the graph of the polygon and its image is shown below .

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