A population of beetles are growing according to a linear growth model. The initial population (week 0) is Po 4, and the population after 7 weeks is Pr = 67. Find an explicit formula for the beetle population after n weeks. Pn = After how many weeks will the beetle population reach 256? ___ weeks

Answers

Answer 1

The explicit formula for the beetle population after n weeks can be determined using the given data. The formula is Pn = 4 + (n - 0) * ((67 - 4) / (7 - 0)), where Pn represents the population after n weeks. It will take 28 weeks for the beetle population to reach 256.

The linear growth model assumes that the beetle population increases by a fixed amount each week. To find the explicit formula, we start by calculating the growth rate per week. We know that in 7 weeks, the population increased from 4 to 67. The change in population is 67 - 4 = 63, and the change in weeks is 7 - 0 = 7. Therefore, the growth rate per week is (67 - 4) / (7 - 0) = 9.

Using this growth rate, we can express the population after n weeks using the formula Pn = 4 + (n - 0) * 9. This simplifies to Pn = 4 + 9n. Now, to determine how many weeks it takes for the population to reach 256, we substitute Pn = 256 into the formula. Solving for n, we get 256 = 4 + 9n. By rearranging the equation, we find 9n = 252, and dividing both sides by 9 yields n = 28. Therefore, it will take 28 weeks for the beetle population to reach 256.

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Related Questions

There are 180 trees in gardner grove orchard, and 18 of them are pears. What percent of the trees are pear trees?

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the answer is 32.4%

I need this answer as soon as possible

Answers

The perimeter is the distance all the way around. So it's the sum of the lengths of all 4 sides.

From the picture, you can clearly see the lengths of all 4 sides.

Writum down and adum up !

if a, b, and c are n n invertible matrices, does the equation c 1 .a c x /b 1 d i n have a solution, x? if so, find it.

Answers

The equation c₁ · a · c · x / b₁ · d · iₙ can have a solution for x if and only if the matrices a, b, and c are compatible and satisfy certain conditions.

Further information about the matrices and their properties is required to determine the specific solution.

To determine if the equation c₁ · a · c · x / b₁ · d · iₙ has a solution, we need to consider the compatibility and properties of the matrices involved.

Let's break down the equation:

c₁: The first column of matrix c.

a: Matrix a.

c: Matrix c.

x: The solution vector.

b₁: The first row of matrix b.

d: Matrix d.

iₙ: The identity matrix of size n.

For the equation to have a solution, the matrices a, b, and c need to be compatible, meaning their dimensions align appropriately for matrix multiplication. Specifically, the number of columns in matrix a should match the number of rows in matrix c.

Additionally, certain conditions or properties of the matrices may be required to ensure a solution exists. Without additional information about the specific matrices a, b, c, and d, it is not possible to determine the solution for x.

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Find the inverse Laplace transform of

a) F(s)= 10/s(s+2)(s+3)²

b) F(s)= s/s²+4s+5

c) F(s)=e^-3s s/(s-2)^2 +81

Answers

a) The solution to the given problem isL(F) = f(t) = 0 + (-(10 + 7C)/6)[tex]e^{-2t}[/tex]) + C[tex]e^{-3t}[/tex]+ D[tex]e^{-3t}[/tex]

b) The solution to the given problem isL(F) = [tex]e^{-2t}[/tex] [sin t + cos t](c)

c) The solution to the given problem is L(F) = 1/9 [[tex]e^{2t}[/tex] sin 9t - 3[tex]e^{2t}[/tex]) cos 9t]

(a)The inverse Laplace transform of F(s) = 10/s(s + 2)(s + 3)² can be found as follows:

L(F) = L{10/[s(s + 2)(s + 3)²]}

= 10 ∫∞₀[tex]e^{-st}[/tex]) /[s(s + 2)(s + 3)²] dt

L{F} = L⁻¹{10/[s(s + 2)(s + 3)²]}

By using partial fractions, we can simplify the equation and get it in a form that can be integrated easily.

L(F) = 10 ∫∞₀ {1/s - 2/(s + 2) + 3/(s + 3) - 2/(s + 3)² + 1/(s + 2)(s + 3)} [tex]e^{-st}[/tex]dt

L{F} = L⁻¹{1/s} - 2L⁻¹{1/(s + 2)} + 3L⁻¹{1/(s + 3)} - 2L⁻¹{d/ds[1/(s + 3)]} + L⁻¹{1/(s + 2)}

As the inverse Laplace transform of L{F} is given by L(F)

= L⁻¹{1/s} - 2L⁻¹{1/(s + 2)} + 3L⁻¹{1/(s + 3)} - 2L⁻¹{d/ds[1/(s + 3)]} + L⁻¹{1/(s + 2)}

Thus, the solution to the given problem isL(F) = f(t) = 0 + (-(10 + 7C)/6)[tex]e^{-2t}[/tex]) + C[tex]e^{-3t}[/tex]+ D[tex]e^{-3t}[/tex]

(b)

The inverse Laplace transform of F(s) = s/[s² + 4s + 5] can be found as follows:

L(F) = L{s/[s² + 4s + 5]}

= ∫∞₀ s e^(–st) / (s² + 4s + 5) dt

L{F} = L⁻¹{s/[s² + 4s + 5]}

By using partial fractions, we can simplify the equation and get it in a form that can be integrated easily. L(F) = ∫∞₀ [s/(s² + 4s + 5)] [tex]e^{-st}[/tex]) dt

L{F} = L⁻¹{s/(s² + 4s + 5)}

The solution to the given problem isL(F) = [tex]e^{-2t}[/tex] [sin t + cos t](c)

c) The inverse Laplace transform of F(s) = ([tex]e^{-3s}[/tex]) s/[(s - 2)² + 81] can be found as follows:

L(F) = L{([tex]e^{-3s}[/tex]) s/[(s - 2)² + 81]}= ∫∞₀ ([tex]e^{-st}[/tex]) s/[(s - 2)² + 81] dt

L{F} = L⁻¹{([tex]e^{-3s}[/tex])) s/[(s - 2)² + 81]}

So, The solution to the given problem is L(F) = 1/9 [([tex]e^{2t}[/tex]) sin 9t - 3([tex]e^{2t}[/tex]) cos 9t]

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Joey made strawberry jam and raspberry jam. He made enough strawberry jam to fill 1/2 of a jar. If he made 2/5 as much raspberry jam as strawberry jam, how many jars will the raspberry jam fill?

Answers

Answer:  1/5 of a jar

Step-by-step explanation:

1/2 times 2/5= .2 = 1/5.

Answer:

1/5 of a jar

Step-by-step explanation:

The width of a rectangular frame is 6 in. shorter than its length. The area of the frame is 216 in?
What is the frame's length?

Answers

Answer:

18 in

Step-by-step explanation:

len = y

width= y - 6

the area of rectangle is len x width

(Y) x (Y-6) = 216

Y^2 - 6Y = 216, Y^2 - 6y -216 = 0

y = (36 /2) or (-24 /2)

len couldn't be negative so 18

Find the length of the third side if necessary write in simplest radical form

Answers

Answer:

hi

Step-by-step explanation:

Find the range of the function

Answers

Answer:

y€ R : y greater than or equal to 1

Cheryl's making trail mix for a friend she always uses three cups of almonds for every four cups of cashews if Cheryl wants to make a larger batch of trail mix which of the following has the same ratio of almonds cashews
A. 9 cups of almonds for every 20 cups of cashews
B. 6 cups of almonds for every 12 cups of cashews
C. 9 cup of almonds for every 12 cups of cashews
D. 12 cups of almonds for every 20 cups of cashews

Answers

Answer:

c

Step-by-step explanation:

3x3=9

4x3=12

Answer:

C

Step-by-step explanation:

3 cups of almonds / 4 cups of cashews

So to get 9 cups of almonds, we need to multiply almonds and cashews by 3

3*3 = 9 cups of almonds

4*3 = 12 cups of cashews

So the correct answer is C

Use the binomial series to find a Taylor polynomial of degree 3 for 1 91 +32 T3(0) X + c? + 23

Answers

The Taylor polynomial of degree 3 for the function 1/(1-2x) centered at x=0 is (1+2x+4x²+8x³).

Explanation: Given, 1/(1-2x) = ∑n=0 to infinity of 2^n * x^n The above series is the binomial series for (1+x)^n where n=-1Using the binomial series for n=-1, we have1/(1-2x) = ∑n=0 to infinity of 2^n * x^n= ∑n=1 to infinity of 2^(n-1) * x^(n-1)= 1 + ∑n=1 to infinity of 2^n * x^nTaking up to degree 3, we get1/(1-2x) = 1 + 2x + 4x² + 8x³ + ...Therefore, the Taylor polynomial of degree 3 for 1/(1-2x) is 1 + 2x + 4x² + 8x³.

An infinite sum of words that are expressed in terms of a function's derivatives at a single point is known as the Taylor series or Taylor expansion of a function in mathematics. Near this point, the function and the sum of its Taylor series are equivalent for the majority of common functions. for Brook Taylor, who introduced the Taylor series in 1715, they are named for him. In honour of Colin Maclaurin, who made great use of this unique example of Taylor series in the middle of the 18th century, a Taylor series is sometimes known as a Maclaurin series where 0 is the point at which the derivatives are taken into account.

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How many zeros appear at the end of 115!? Do not compute 115!.
Your argument must come from prime factorizations to receive
credit.

Answers

there will be 27 zeros at the end of 115!.

To determine the number of zeros at the end of 115!, we need to consider the prime factorization of the number and examine how many factors of 5 are present.

A zero at the end of a factorial occurs when there is a factor of 10 present, which is equivalent to having both factors of 2 and 5. Since the number of factors of 2 is usually abundant, the crucial factor is the number of factors of 5.

In the prime factorization of 115!, the factors of 5 arise from the multiples of 5 (5, 10, 15, 20, ...) as well as higher powers of 5 (25, 50, 75, ...). We need to determine how many multiples of 5, multiples of 25, multiples of 125, and so on are present.

1. Multiples of 5: The number of multiples of 5 in 115! is given by ⌊115/5⌋ = 23.

2. Multiples of 25: The number of multiples of 25 in 115! is given by ⌊115/25⌋ = 4.

3. Multiples of 125: The number of multiples of 125 in 115! is given by ⌊115/125⌋ = 0 since there are no numbers in the range 1 to 115 that are multiples of 125.

Adding up these counts, we have 23 + 4 = 27 factors of 5.

Therefore, there will be 27 zeros at the end of 115!.

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the quotient of 17 and z

Answers

Answer:

17÷z = quotient

Step-by-step explanation:

quotient = ÷

Find the value of x. I WILL MARK YOU BRAINLIEST!!!

Answers

Answer:

4x+3x+2x=180

9x=180

x=20

A population of values has a normal distribution with u = 42.3 and o = 44.6. You intend to draw a random sample of size n = 20. Find the probability that a single randomly selected value is greater than 19.4. P(X> 19.4) = Find the probability that a sample of size n = 20 is randomly selected with a mean greater than 19.4. P(M> 19.4) =
Previous question

Answers

(a) The probability that a single randomly selected value is greater than 19.4. P(X> 19.4) = 0.6965.

(b) The probability that a sample of size n = 20 is randomly selected with a mean greater than 19.4. P(M> 19.4) =  0.9883.

To solve these probability questions, we can utilize the properties of the standard normal distribution since we know the mean and standard deviation of the population.

(a) Find the probability that a single randomly selected value is greater than 19.4.

To calculate this probability, we need to standardize the value 19.4 using the formula: z = (x - μ) / σ, where x is the value, μ is the mean, and σ is the standard deviation.

z = (19.4 - 42.3) / 44.6 = -22.9 / 44.6 ≈ -0.51498

Using the standard normal distribution table or a calculator, we can find the corresponding probability for z > -0.51498, which is approximately 0.6965.

Therefore, P(X > 19.4) ≈ 0.6965.

(b) Find the probability that a sample of size n = 20 is randomly selected with a mean greater than 19.4.

For this question, we need to consider the sampling distribution of the sample mean. The mean of the sampling distribution is equal to the population mean (μ = 42.3), and the standard deviation of the sampling distribution, also known as the standard error, is equal to σ / √n, where σ is the population standard deviation and n is the sample size.

Standard error = 44.6 / √20 ≈ 9.9766

To find the probability that the sample mean is greater than 19.4, we need to standardize the sample mean using the formula: z = (x - μ) / (σ / √n), where x is the value (19.4 in this case), μ is the mean, σ is the standard deviation, and n is the sample size.

z = (19.4 - 42.3) / (44.6 / √20) ≈ -22.9 / 9.9766 ≈ -2.2972

Using the standard normal distribution table or a calculator, we can find the corresponding probability for z > -2.2972, which is approximately 0.9883.

Therefore, P(M > 19.4) ≈ 0.9883.

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What is the probability of spinning a number greater than 4?

Answers

Answer:

Please upload the full question.....here the total number of outcomes is not mentioned and hence it can't be solved.

Answer:

Hence, the required probability of getting a number greater than 4, P(E) = 1/3.

Step-by-step explanation:

A 28 ft tall house casts a shadow that is 35 ft long. A umbrella outside the house casts a shadow that is 16 7/8 long. How tall is the umbrella?

Answers

Answer:

The unbrella is 13.5 feet tall.

Step-by-step explanation:

35 / 28 = 1.25

1.25x = 16 7/8

x = (16 7/8) / 1.25

x = 13.5 ft

Write a survey question for which you would expect to collect numerical data.

Answers

Answer:

How many siblings do you have?

The linear approximation at z = 0 to sin(42) is A + Bz where A is:

Answers

the linear approximation at z = 0 to sin(42) is A + Bz, where A = sin(42) and B is the coefficient of z, which is cos(42).

The linear approximation of a function f(x) at a point x = a is given by the equation f(x) ≈ f(a) + f'(a)(x - a). In this case, we want to approximate sin(42) at z = 0.

The derivative of the sine function is cos(x), so the derivative of sin(42) with respect to z is cos(42). Evaluating the derivative at z = 0, we have cos(42).

To find A in the linear approximation A + Bz, we substitute z = 0 into the original function sin(42) and obtain A = sin(42).

Therefore, the linear approximation at z = 0 to sin(42) is A + Bz, where A = sin(42) and B is the coefficient of z, which is cos(42).

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I'll give brainliest please help​

Answers

Answer:

∠R = 38°

Step-by-step explanation:

∠R = 1/2(arc PE - arc SQ)

∠R = 1/2(140 - 64) = 1/2(76) = 38°

Renee is a sales associate at a store. She earns $80 a week plus a 15% commission on her sales. Last week, she sold $200 worth of items. What is the total amount Renee earned for the week? How much did she earn from commission?
Renee earned a total of $
for the week. The amount she earned from commission was $
.

Answers

Answer:

The amount earned for the week=$110

Amount earned from commission =$30

Step-by-step explanation:

commission earned on sales = $200×15%= $30

total amount for the week=$80 +$30= $110

A part manufactured at a factory is known to be 12.05 cm long on average, with a standard deviation of 0.350. One day you suspect that that the part is coming out a little longer than usual, but with the same deviation. You sample 14 at random and find an average length of 12.20. What is the z-score which would be used to test the hypothesis that the part is coming out longer than usual?

Answers

The z-score to test the hypothesis that the part is coming out longer than usual is approximately 1.61.

Sample mean = x = 12.20 cm

Population mean = μ = 12.05 cm

Standard deviation = σ = 0.350 cm

Sample size = n = 14

A hypothesis is an informed prediction regarding the solution to a scientific topic that is supported by sound reasoning. there is the expected result of the experimentation even if there is not proved in an experiment.

Calculating the z-score -

[tex]z = (x - u) / (\alpha / \sqrt n)[/tex]

Substituting the values -

[tex]z = (12.20 - 12.05) / (0.350 / \sqrt{14)[/tex]

= z = 0.15 / (0.350 / √14)

= 0.093

Substituting the value again into the formula:

z = 0.15 / 0.093

= 1.61

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The diameter of a circle is 20 centimeters. What is the circumference?

Answers

C ≈ 62.83cm is the answer!

Hope this helps!

What he said great! Wow

How would I find the arc of WTV

Answers

To find the arc of circle WTV, you need the arc length or central angle. Use formulas: Arc Length = (Arc Angle / 360) × (2πr) or Arc Length = (Central Angle / 360) × (2πr).

To find the arc of a circle, WTV, you would need to know either the length of the arc or the measure of the central angle subtended by the arc. If you have the length of the arc, you can use the formula:

Arc Length = (Arc Angle / 360 degrees) × (2πr),

where r is the radius of the circle. Rearranging the formula, you can solve for the Arc Angle:

Arc Angle = (Arc Length / (2πr)) × 360 degrees.

If you know the measure of the central angle, you can calculate the arc length using a similar formula:

Arc Length = (Central Angle / 360 degrees) × (2πr).

To find the radius, you would need additional information such as the diameter or circumference of the circle. Once you have the radius, you can substitute the values into the appropriate formula to find either the arc length or the central angle of the circle.

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The data set below represents a sample of scores on a 10-point quiz. 7, 4, 9, 6, 10, 9, 5, 4 Find the sum of the mean and the median

Answers

The sum of the mean and the median of the given dataset, which consists of the scores 7, 4, 9, 6, 10, 9, 5, and 4, is 13.25.

To find the sum of the mean and the median, we first need to calculate the mean and median of the given dataset.

The dataset is: 7, 4, 9, 6, 10, 9, 5, 4

To find the mean, we sum up all the numbers in the dataset and divide by the total number of data points:

Mean = (7 + 4 + 9 + 6 + 10 + 9 + 5 + 4) / 8 = 54 / 8 = 6.75

To find the median, we arrange the numbers in ascending order:

4, 4, 5, 6, 7, 9, 9, 10

Since we have 8 data points, the median will be the average of the two middle numbers:

Median = (6 + 7) / 2 = 6.5

Now we can find the sum of the mean and the median:

Sum of mean and median = 6.75 + 6.5 = 13.25

Therefore, the sum of the mean and the median of the given dataset is 13.25.

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find vertex of this function ​

Answers

Answer:

Step-by-step explanation:

(-1,-9)

Q1
The sum of the first 68 positive odd integers is ?

Q2
The degree of recurrence relation an = 2an-2 + 5an-49 is ??

Q3
In how many ways can an organization containing 19 members elect a president, treasurer and secretary (assuming no person is elected to more than one position)?

Q4
The Greatest Common Divisor (GCD) of 28 × 37 × 58 and 23 × 33 × 54 is ??

Answers

Q1: Sum of first 68 positive odd integers.

Let's represent the first 68 positive odd integers by: 1, 3, 5, 7, ..., 135, 137. The first term, a = 1. The last term, l = 137And, the number of terms, n = 68We need to find the sum of these terms. To find the sum of an arithmetic series, we use the following formula: Sn = n/2[2a + (n-1)d]. Here, d = common difference. Since the given sequence is of odd numbers, the difference between any two consecutive terms is 2. So, d = 2. Put these values in the formula to get: Sn = 68/2[2(1) + (68-1)2], Sn = 34[2 + 135], Sn = 68 × 67Sum of first 68 positive odd integers = 4546.

Q2: Degree of recurrence relation. To find the degree of a recurrence relation, we find the largest value of n in the relation. Here, an = 2an-2 + 5an-49The largest value of n in the relation is n = 49. So, the degree of the recurrence relation is 49.

Q3: Number of ways to elect office bearers in an organization. Let's assume that the 19 members of the organization are named M1, M2, M3, ..., M19. The president can be elected in 19 ways. After the president is elected, the treasurer can be elected in 18 ways. After the treasurer is elected, the secretary can be elected in 17 ways. Therefore, the total number of ways in which the president, treasurer, and secretary can be elected is:19 × 18 × 17 = 5,814.

Q4: Greatest Common Divisor (GCD)To find the GCD of two numbers, we need to find their prime factors.28 × 37 × 58 = 2² × 7 × 37 × 2 × 29 = 2³ × 7 × 29 × 37Similarly, 23 × 33 × 54 = 23 × 3² × 2 × 3 × 3 × 2 × 3 = 2³ × 3⁵ × 23.

The common prime factors are 2³ and 23. So, the GCD is: 2³ × 23 = 184. The GCD is 184.

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Find the first three terms of x[n] using power series expansion if X(z) 2z3 + 13z2 + 7 73 + 722 + 2z + 1 =

Answers

The first three terms of x[n] using the power series expansion are x[0] = 73, x[1] = 2, and x[2] = 13.

We can select the first three terms of x[n] using the power series development by expressing the given articulation X(z) as a polynomial in z. We should modify the articulation as follows to obtain the power series development: By comparing the given expression to the power series form, the coefficients can be identified: X(z) equals 2z3, 13z2, 7z, 73, 722/z, 2/z, and 1: a0 rises to 73, a1 approaches 2, a2 approaches 13, and a3 approaches 7. X(z) = a0, a1z, a2z2, a3*z3, and... Consequently, the following are the first three terms of x[n]:

The initial three terms of x[n] are provided by the power series development: x[0] = a0; x[1] = a1; x[2] = a2; x[0] = a0; The values of x[0] and x[1] are 73, 2, and 13.

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Clarence has $90 in a savings account that earns 10% annually. The interest is not
compounded. How much will he have in 5 years?

Answers

Answer:

132 dollars I think

Step-by-step explanation:

a 18 The number 21 has no composite factors. What is another number that has no composite factors? A. 27- B. 52- C. 77- D. 81-​

Answers

The number that has no composite factors is (c) 77

How to determine another number that has no composite factors

From the question, we have the following parameters that can be used in our computation:

Number = 21

The factors of 21 are 3 and 7

These factors are composite numbers because they are prime numbers

using the above as a guide, we have the following:

The number 77 has no composite factors

This is so because

77 = 7 * 11

These factors are composite numbers because they are prime numbers

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At the state fair, admission at the gate is $9. In addition, the cost of each ride is $2. Suppose that Reuben will go on x rides.
Reuben wants the total number of dollars he spends on admission and rides to be fewer than . Using the values and variables given, write an inequality describing this.

Answers

Answer:

i think you forgot to add how little he wants to spend

Step-by-step explanation:

Reuben wants the total number of dollars he spends on admission and rides to be fewer than ??? whats the number that he wants to spend

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It has one counter staffed with one teller who provides customer service on a variety of needs as required by the clients. Requ Radio Shack supplied 450 laptops at the price of $4,500. When, it decided to increase the price to S5,500, the supply of the laptops is increased to 600. Calculate the price elasticity of supply using the mid-point formula. 3 marks A company is conducting a cost-benefit analysis for its information system (is) department. in this, the salary of an employee is an example of a(n) ________ cost. help please! predict whether each substance will dissolve in water. A constant friction force of 23 N acts on a 55- kg skier for 22 s on level snow. What is the skier's change in velocity? Express your answer to two significant figures and include the appropriate units. A loan is granted at 18,6 % p.a. compounded daily. It is repaid by means of regular, equal monthly payments of R2300 per month where the first payment is made one year after the loan is granted. If the last payment is made exactly five years after the loan is granted, then the value of the loan, to the nearest cent, is R FILL IN THE BLANK in the short run, movement along the sras curve____ corresponds to ______ in the unemployment rate, all else being equal. A bird is flying along the straight line 2y - 6x = 6. In the same plane, an aeroplane starts to fly in a straight line and passes through the point (4, 12). Consider the point where aeroplane starts to fly as origin. If the bird and plane collides then enter the answer as 1 and if not then 0. Note: Bird and aeroplane can be considered to be of negligible size. Quick ratio Adieu Company reported the following current assets and current liabilities for two recent years: . Dec. 31, 20Y4 Dec. 31, 20Y3 Cash $800 $770 Temporary investments. 1,200 1,500 Accounts receivable 850 950 Inventory 2,300 2,700 Accounts payable 1,900 2,300 a. Compute the quick ratio on December 31 for each year. Round to one decimal place. . 20Y4 20Y3 Quick Ratio ____ ____ b. Is the quick ratio improving or declining? Improving For Brazil region/country explain the meaning for each of the values below and provide 1 example of practice/tradition/myth/legend that support each of the following values { The Globe project for definitions and ch 2 in the textbook)(no duplications of examples accepted Make sure you don't repeat the same examples posted by your peers that selected your same country): Please review the exemplar under the Course Requirements tab for more details.AssertivnessGenderEgalitarianismFuture orientationPerformance Orientation. Prove each of the following statements using mathematical inductions. (a) Show that + - + + 2 = 1 - 22 23 for all integer n 1. 27 272 (b) Show that 89 | (5n 6n) for all integer n 0. + Here interest rate is 7.2% not any value don't copywrong data chegg answers solve clearly according to my data only ifnot just skipasap for 3 upvotes tq8.28 You are buying a new home for $416 000. You have an agreement with the savings and loan company to borrow the needed money if you pay 20 percent in cash and monthly payments for 30 years at an in Ethnic Studies mostly focuses on the following:- absence of Native American history- identity, struggle, resilience, and contributions of Indigenous, Black and People of Color communities- conflict between different racial ethnic groups- traditions of people of color being erased A population has a standard deviation of 29. We take a random sample of size 24 from this population. Let Xbar be the sample mean and let Xtot be the sample sum of our sample. These are random variables. a) What is the variance of this population? _______b) What is the variance of Xtot? (to three decimal places) ______c) What is the standard deviation of Xtot? (to three decimal places) ______d) What is the variance of Xbar? (to three decimal places) ________ e) What is the standard deviation of Xbar? (to three decimal places) ______f) What is the smallest sample size, n, which will make the standard deviation of Xtot at least 250?______g) What is the smallest size sample, n, which will make the variance of Xtot at least 40000?________ Radiology Associates is considering an investment, which will cost $259,000. The investment produces no cash flows for the first year. In the second year, the cash inflow is $58,000. This inflow will increase to $150,000 and then $200,000 for the following two years before ceasing permanently. The firm requires a 14 percent rate of return and has a required discounted payback period of 3.5 years. Accept or reject this project? Why? In year 0, Javens Inc. sold machinery with a fair market value of $620,000 to Chris. The machinerys original basis was $484,840 and Javenss accumulated depreciation on the machinery was $72,000, so its adjusted basis to Javens was $412,840. Chris paid Javens $62,000 immediately (in year 0) and provided a note to Javens indicating that Chris would pay Javens $93,000 a year for six years beginning in year 1.What is the amount and character of the gain that Javens will recognize in year 0?What amount and character of the gain will Javens recognize in years 1 through 6?