A rare Pokemon trading card deck you have been wanting to buy costs 4500. You have earned 2485 from helping your mom in her online selling business. If you can save 155 weekly from your allowance, how many weeks would it take for your funds to reach 4500

Answer:

Step-by-step explanation:

4/56\8

The rate of recycling 200 pounds of cans based on the mentioned information is $110.

Firstly calculating the cost of cans per pounds. Then we will proceed to actual calculation about rate of recycling 200 pounds.

Cost of recycling one pound of can = total cost ÷ number of recycled cans

Keep the values in formula

Cost of recycling one pound of can = 23.65/43

Performing division

Cost of recycling one pound of can = 0.55

Cost of recycling 200 pounds of cans = 0.55 × 200

Performing multiplication

Cost of recycling 200 pounds of cans = 110

Therefore, the required rate is $110.

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Answer:

8 + 56d

Step-by-step explanation:

We will open the parentheses, multiplying the stuff outside by the stuff inside. So, we get:

8*1 + 8*7d

Then, we can simplify by giving us:

8 + 56d

Hope this helped!

The reason to choose problem B over A is simple -  it is more relatable to them.

Problem A involves dinosaurs, which may be more interesting to students than the abstract concept of creating an area with rope. Additionally, the use of feet as a unit of measurement in Problem A may be more familiar to students than inches.

Finding a number that represents the quantity of anything is called measurement. An accepted quantity that is used to represent a physical quantity is called a measurement unit. Let's learn about some of the standard units used to measure physical quantities.

The inch, foot, yard, and mile are the fundamental units of length and distance measurement in the English system. The rod, furlong, and chain are additional length units.

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The longest side of a triangle is opposite the largest interior angle, and the shortest side is opposite the smallest angle.

Triangle

A triangle is a three-sided polygon, which has three vertices. The three sides are connected with each other end to end at a point, which forms the angles of the triangle. The sum of all three angles of the triangle is equal to 180 degrees.

Angle

A figure which is formed by two rays or lines that shares a common endpoint is called an angle. The word “angle” is derived from the Latin word “angulus”, which means “corner”. The two rays are called the sides of an angle, and the common endpoint is called the vertex.

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The polynomial in intercept form so that P(x)=0 has the given roots is, x^2 - √3x - 2x + 2√3 = 0.

What is polynomial?

A polynomial is an expression in mathematics that only uses the operations of addition, subtraction, multiplication, and powers of positive-integer variables. It consists of indeterminates and coefficients. The polynomial x^2 4x + 7 is an illustration of one with a single indeterminate x.

We have to find the polynomial in intercept form so that P(x)=0 has the roots 2 and √3.

Let 2 and √3 are the roots of the polynomial so,

x = 2,  x = √3

⇒ x - 2 = 0,  x - √3 = 0

⇒ (x - 2)(x - √3) = 0

x^2 - √3x - 2x + 2√3 = 0

Hence, the polynomial in intercept form so that P(x)=0 has the given roots is, x^2 - √3x - 2x + 2√3 = 0.

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this question is related to numbers and the solution is as follows,

Rover eats 3/4 can of cat food in a day.

given

in 60 days it will consume 60 x 3/4 cans = 45 cans of cat food

3 cans cost = $5 and a pack contains 3 cans

45 cans is equivalent to= 45/3

= 15 packs

15 packs cost = 15 x $5 = $75

So it will cost $ 75 to feed Rover for 60 days

Bobo eats 1/2 of a can of cat food per day

in 60 days it will consume 60 x 1/2 cans = 30 cans of cat food

3 cans cost $5 and a pack contains 3 cans

30 cans are equivalent to 30/3 = 10 packs

10 packs will cost = 10 x $5 = $50

So it will cost $50 to feed Bobo for 60 days

In total, in 60 days it will cost $75 +$ 50 = $125 to feed both cats in 60 days.

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As calculated from the data we get the result as that $ 125 is required for the cat food of both the cats in a month.

We are given that in 60 days he will consume  ,

60 x 3/4 cans

= 45 cans of cat food

The cost of 3 cans cost = $5

and one pack has 3 cans in it.

Therefore, 45 cans is equivalent to

= 45/3

= 15 packs

So , the cost of 15 cans will be ,

15 packs cost = 15 x $5 = $75

Therefore ,$75 is used for 60 days of cat food for Rover.

Now , we know that Bobo eats 1/2 of a can food in a day.

Therefore, in 60 days he will  eat,

60 x 1/2 cans

= 30 cans of food

As we know, 3 cans cost $5 and a pack contains 3 cans

Therefore, 30 cans = 30/3 = 10 packs

10 packs will cost = 10 x $5 = $50

So , $50 is spend to feed Bobo , in a month.

Therefore , if will combine their cost we will get that ,

$75 +$ 50 = $125 is required to feed both the cats in one month.

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On solving the provided question we can say that - the prime factors of 32 are 2 × 2 x 2 x 2 x 2 and of 64 are - 2 x 2 × 2 x 2 x 2 x 2

Any natural number other than 1 with just itself and the number 1 as its divisors is considered a prime factor. Actually, 2, 3, 5, 7, 11, and so on are some of the first prime numbers. an amount that has been multiplied to produce another amount. By dividing 15 by 3 and 5, for instance, we get 3 5 = 15. main elements: Prime factors include all factors that are prime but are not composite. A few prime factors of 30 are 2, 3, and 5. Only 2 and 3 are prime factors of 12, so listing 2 twice as 2 2 3 (or 22 3) is necessary to factorize 12. The sum of 2 + 3 is not 12.

the prime factors of

32 are 2 × 2 x 2 x 2 x 2

64 are - 2 x 2 × 2 x 2 x 2 x 2

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The number of times the diameter of Uranus is larger than the diameter of Mars is 7.5 times

From the question, we have the following parameters that can be used in our computation:

The diameters of Uranus and Mars

These diameters are given as

Diameter of Uranus: 5.11×10^4 kilometers

Diameter of Mars: 6.79×10^3 kilometers

Express the diameters properly

So, we have the following representation

Diameter of Uranus: 5.11 × 10⁴ kilometers

Diameter of Mars: 6.79 × 10³ kilometers

This means that

Number of times larger = Diameter of Uranus/Diameter of Mars

Substitute the known values in the above equation, so, we have the following representation

Number of times larger = 5.11 × 10⁴ kilometers/6.79 × 10³ kilometers

Evaluate the quotient

So, we have the following representation

Number of times larger = 7.5

Hence, the number of times is 7.5

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If his plants are indoors, he must water them at least once a week or they will die.

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Answer:

[tex]w^{2}[/tex]

Step-by-step explanation:

Explanation:

When solving a function, you plug in the given [tex]x[/tex]-value (what's inside the parentheses next to the [tex]g[/tex] or [tex]f[/tex]) into the corresponding equation (what [tex]f(x)[/tex] and [tex]g(x)[/tex] are set equal to).

Before starting the worksheet, take a simpler example:

Given the function [tex]h(x) = x + 2[/tex],

the following work solves for [tex]h(3)[/tex].

[tex]h(3) = 3 + 2[/tex]

[tex]h(3) = 5[/tex]

Essentially, to solve for the value of a function for a given [tex]x[/tex]-value, simply plug in that value in for [tex]x[/tex] and simplify the resulting expression.

Onto problem 14 from the given worksheet:

We are given [tex]f(x) = 3x + 2[/tex] and are asked to solve for [tex]f(4)[/tex].

Hence, all we have to do is plug [tex]4[/tex] in for [tex]x[/tex]:

[tex]f(4) = 3(4) + 2[/tex]

[tex]f(4) = 12 + 2[/tex]

[tex]f(4) = 14[/tex]

You can apply this concept to the rest of the problems.

The number of children that swam in the public pool that day is 194

and the number of adult that swam in the public pool that day is 117

Let x represent the number of children that swam in the public pool that day.

Let y represent the number of adult that swam in the public pool that day.

On a certain hot summer day, 311 people used the public swimming pool. This means that

x + y = 311

The daily prices are 1.50 for children and 2.00 for adults. The receipts for admission totaled to $525. This means that

$1.50x + $2.00y = $525 - - - - - - - -1

Substituting x = 311 - y into equation 1, it becomes

1.50(311 - y) + 2.00y = 525

466.5 - 1.50y + 2.00y = 525

0.5 y = 58.5

y = 117

Substituting y = 117 into x = 311 - y, it becomes

x = 311 - 117

x = 194

Hence , the number of children that swam in the public pool that day is 194 and the number of adult that swam in the public pool that day is 117.

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There are 5/12 strawberries were left. This can be solved using the concept of fraction addition.

A fraction is a piece of the entire. The number is stated in arithmetic as a quotient, which signifies the numerator divided by the denominator. Both are integers in a straightforward fraction. The numerator or denominator of a complex fraction is a fraction. A suitable fraction has a numerator that is smaller than its denominator.

Three main fractional kinds exist. They come in three varieties: appropriate fractions, incorrect fractions, and mixed fractions. The numerator and denominator words are known as fractions. We define its kinds in light of these two words.

Given that,

A farmer took 2/3 of the strawberry that he harvested to a market.

At the market, the farmer sold 1/4th of the strawberry.

Now, the farmer has left no of strawberries were:

= (2/3) - (1/4)

= (8 - 3) / 12

= 5 / 12

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A linear, negative relationship is the type of relationship which is shown in graph of Time vs. Position of Battery Operated Car .

A linear equation is an algebraic expression such as y=mx+b. The slope is m, and the y-intercept is B. A "linear equation in two variables" is the term used to describe the previous sentence, which has variables named y and x. Two different variables can be found in bivariate linear equations. Examples of linear equations include 2x - 3 = 0, 2y = 8, m + 1 = 0, x/2 = 3, x + y = 2, and 3x - y + z = 3. The term "linear" refers to an equation having the form y=mx+b, where m stands for the slope and b for the y-intercept.

given

The area's 46-16 opposed to 14 is different from the area's 18 and T in a different way. The place is there. It isn't linearly getting farther apart. The lee is actually growing as a result.

Option B, the slanting upwards, is what we're going to go with. Since it will be linear, it isn't option C. It is untrue that the speaking has not been constant over the distance. Because it is a D-option, this increase-decrease is untrue. Option B is the best choice. Absolutely.

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On solving the provided question, we can say that coordinates of the point in the unit circle  S = ( cos [tex]3\pi /2[/tex] , sin [tex]3\pi /2[/tex] ) => S= ( 0 , -1 )

Every point in the plane that is a certain distance away from a certain point forms a circle (center). It is, thus, a curve formed by points moving in the plane at a fixed distance from a point. At every angle, it is also rotationally symmetric about the center. A circle is a closed two-dimensional object where every pair of points in the plane are equally spaced out from the "center." A line that goes through the circle creates a specular symmetry line. At every angle, it is also rotationally symmetric about the center.

S = (0, -1 )

coordinates of the point in the unit circle

S = ( cos [tex]3\pi /2[/tex] , sin [tex]3\pi /2[/tex] )

S= ( 0 , -1 )

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To tell if a log graph is a growth or decaying, look at the slope of the line. If the slope is positive, then it is growth; if the slope is negative, then it is decay.

A positive slope indicates that the value is increasing over time, while a negative slope indicates that the value is decreasing over time. To find the slope, take two points on the line and calculate the change in the y-value divided by the change in the x-value.

If the answer is positive, the graph is growth; if the answer is negative, the graph is decay. Additionally, you can look at the y-intercept of the graph, which is the value where the line meets the y-axis. If the y-intercept is positive, the graph is growth; if the y-intercept is negative, the graph is decay.

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Check the picture below.

[tex]\stackrel{\textit{\LARGE Areas}}{\stackrel{rectangle}{(4)(20)}~~ + ~~\stackrel{triangle}{\cfrac{1}{2}(\underset{b}{5})(\underset{h}{20})}}\implies 80+50\implies \text{\LARGE 130}~m^2[/tex]

Answer:

To enclose the rectangular garden, Owen will need to put fencing along the length of the garden, which is 25 feet, and along the width of the garden. He wants to use less than 8 feet of fencing, so the width of the garden must be less than 8 feet.

The total amount of fencing needed will be equal to the length of the garden plus the width of the garden, multiplied by 2 (since there are two sides to the garden for each of the length and width).

For example, if the width of the garden is 5 feet, the total amount of fencing needed will be 25 + 5 + 25 + 5 = 60 feet, which is less than 8 feet.

So, the width of the garden can be any value less than 8 feet.

Step-by-step explanation:

The required perimeter of the new rectangle is 66 inches.

A quadrilateral with all of its angles equal, or right angles, is a rectangle.

In addition to having all equal angles, a square also has all equal sides.

Therefore, a particular case of a square is a rectangle.

To put it another way, a rectangle can also be a square (when all sides to are equal).

Because every square is a quadrilateral with all four angles at right angles, every square is also a rectangle.

To be a square, a rectangle's sides must all be the same length, hence not all rectangles are squares.

So, a perimeter equals 2(l+b).

50 is the circumference and 17 is the length here.

Suppose the breadth is x.

50 = 2(17+x)

50 = (2*17)+(2*x)

50 = 34 + 2x

50 - 34 = 2x

16 = 2x

16/2 = x

8 = x

The first triangle's width is eight inches.

We know that the length of the other rectangle is 17.

And that the width is two times that of the first triangle.

Length = 17, width = 2*8 = 16, etc.

For the border:

p = 2(l+b)

p =  2(17+16)

p =  (2*17)+(2*16)

p =   34+32

p  =   66

Therefore, the required perimeter of the new rectangle is 66 inches.

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Complete question:

Najib cuts out a rectangle that has a perimeter of 50 inches and a length of 17 inches. He cuts out another rectangle that is the same length and twice as wide. What is the perimeter of the new rectangle?

C) The whole hundredths of 2347 is 234700 hundredths.  Zero-tenths are in 2,347. The whole tenth of 2347 is 2470tenth.

D) The tenth in 234. 7 are 7. The whole tenth of 234. 7 is 2347.

What is the tenth?

The tenth place is represented by the first digit following the decimal. The hundredth place is represented by the digit that follows the decimal.

Given number is 2347.

To find the whole hundredth, multiply the number by 100.

The whole hundredth in 2347 is 2347 × 100 = 234700.

The given number can be written as 2347.0.

Thus tenth of 2347 is 0.

To find the whole tenth, multiply the number by 10.

The whole tenth in 2347 is 2347 × 10 = 23470.

Thousand     Hundred       Ten      decimal point     Tenth

     2                      3              4                   .                    7

The tenth of in 234. 7 is 7.

The whole tenth in 234. 7 is 234.7 × 10 = 2347.

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The length of the rectangle is 3l/4, and the breadth of the rectangle is s = 3l/4

Let's call the original breadth of the rectangle "b" and the original length of the rectangle "l". From the information given, we know that:

4b = 3l

We also know that when the breadth is increased by 1m and the length is reduced by 1m, the rectangle becomes a square. Therefore, the new breadth and new length are equal. Let's call the new breadth and length "s".

s = b + 1 = l - 1

We can substitute the first equation into the second equation to get:

s = b + 1 = (3l/4) - 1

Now we can solve for s:

s = b + 1m = (3l/4) - 1m

s = (3l/4) - 1m + 1m = (3l/4) = l - 1m

Now we can substitute this back into the first equation:

4b = 3(l - 1m)

We can now solve for b:

4b = 3l - 3m

b = (3l/4) - (3m/4)

Therefore, the original breadth of the rectangle was (3l/4) - (3m/4) and the original length was 3l/4.

We can find the value of length and breadth by substituting the value of s in the first equation

4s = 3l

s = 3l/4

So, the length of the rectangle is 3l/4, and the breadth of the rectangle is s = 3l/4

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The density of the wood is between 0.35 g/cm^3

The density of a substance can be calculated using the formula:

density = mass / volume

To calculate the volume of the cuboid, we can use the formula:

volume = length x width x height

So, using the measurements provided:

volume = 13.2 cm x 16.0 cm x 21.7 cm = 5541.44 cm^3

To calculate the density of the wood, we divide the mass by the volume:

density = 1970 g / 5541.44 cm^3

We can convert cm^3 to g/cm^3 by converting the volume to g

1cm^3 = 1g/cm^3

density = 1970 g / 5541.44 g/cm^3

density = 0.3555 g/cm^3

However, as the measurements provided have a degree of uncertainty, we should consider bounds to find the range of possible densities.

The lower bound for the length is 13.2 cm - 0.1 cm = 13.1 cm

The upper bound for the length is 13.2 cm + 0.1 cm = 13.3 cm

The lower bound for the width is 16.0 cm - 0.1 cm = 15.9 cm

The upper bound for the width is 16.0 cm + 0.1 cm = 16.1 cm

The lower bound for the height is 21.7 cm - 0.1 cm = 21.6 cm

The upper bound for the height is 21.7 cm + 0.1 cm = 21.8 cm

The lower bound for the mass is 1970 g - 5 g = 1965 g

The upper bound for the mass is 1970 g + 5 g = 1975 g

We can now use these bounds to calculate the range of possible densities:

Density lower bound = 1965 g / (13.3 cm x 16.1 cm x 21.8 cm) = 0.350 g/cm^3

Density upper bound = 1975 g / (13.1 cm x 15.9 cm x 21.6 cm) = 0.360 g/cm^3

So the density of the wood is between 0.35 and 0.36 g/cm^3 to one decimal place.

So the density is 0.35 g/cm^3 with an uncertainty of 0.01 g/cm^3

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So on solving the provided question, here  we can say that by is a simultaneous equations the value of x = - 3/5 and y = 9/10

Multiple algebraic equations that have the same unknowna as the give in the  variables and the same answer are referred to as simultaneous equations. This suggests that there is a single solution to the simultaneous equations. Examples of simultaneous equations include: 2x - 4y = 4, 5x + 8y = 3, and others. This implies that the simultaneous equations have a single solution. The simultaneous equations 2x - 4y = 4, 5x + 8y = 3, and others are examples.

y = -x + 1.5

y = 1.5x + 2.5

x = -3/5

y = 9/10

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As a result, using the values provided, we can turn these data into a bar graph.

A graph is a type of non-linear data structure that consists of nodes, also called vertices, and edges. Any two edges can connect the nodes, which are also known as vertices in a graph. This graph's vertices are 1, 2, 3, and 5, while its edges are 1, 2, 1, 3, 2, 5, and 4, 50.

Here,

The gene contributes to the development of pigment.

Yes, factors such as temperature, light cycle, and the presence of mutagens can affect the color of the fur.

In the evolution chart, Mcl provided has ullets that it runs. In mature solutions, the dominating truit moderate is thus always present.

Therefore, using the supplied numbers, we may convert these data into a bar graph.

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The mirror image of (2,5) in y-axis is (-2,5)

The term mirror image of the point is a reflected duplication that appears identical but in reverse.

Here we have given point is (2, 5).

And we have to find the mirror image of this point with respect to the y-axis that is the mirror image is a point whose distance is same from the origin O (0, 0) and same from both axes as of the point (2, 5) is.

As we all know that (2, 5) lies on the first quadrant, then the mirror image with respect to the y-axis must lie on the second quadrant.

And we all also know that In second quadrant, here the x-coordinate of any point (x, y) is negative.

Therefore, while we looking into the given graph we have identified that the mirror image is (- 2, 5).

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Answer:

  ∠LOP = 96°

Step-by-step explanation:

Given an inscribed angle of 48°, you want to know the measure of the central angle that subtends the same arc.

The measure of an inscribed angle is half the measure of the arc it subtends.

  ∠LMP = 1/2(arc LP)

  48° = 1/2(arc LP) . . . . . . use the given value

  96° = arc LP . . . . . . . . . multiply by 2

The measure of an arc of a circle is the same as the measure of the central angle it subtends: the arc measure and its central angle measure are identical.

  arc LP = ∠LOP

  96° = ∠LOP

__

Additional comment

That's a long way of saying the central angle is twice the inscribed angle that subtends the same arc. ∠LOP = 2×∠LMP.

The perimeter of the rectangle, given the area and the segment from R ( 6, -16) to S (14, - 1 ) is 88 units

To find the perimeter, first find the distance between  R ( 6, -16) to S (14, - 1 ) which will allow you to find the length of one side. This distance can be found by the formula :
= √((x2 – x1)² + (y2 – y1)²)

= √((14 – 6)² + (-1 – (-16))²)

= 17 units

This means that one side of the rectangle measures 17 units so the other side would be:

Area = Length x Width

459 = 17 x Width

Width = 459 / 17

Width = 27 units

The perimeter of the rectangle is:

= Length + Width + Length + Width

= 17 + 27 + 17 + 27

= 88 units

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