A soccer player practices kicking the ball into the goal from halfway down the soccer field, which is 45 meters away. The time it takes for the ball to get to the goal from the time it is kicked is 3 seconds. The player wants to know the velocity of the ball.

Is there enough information to calculate this?


Yes, displacement is 45 meters, elapsed time is three seconds, and the direction is toward the goal. Velocity is 135 m/s toward the goal.


No, only speed can be calculated from the distance of 45 meters and the time of 3 seconds.


Yes, displacement is 45 meters, time is three seconds, and the direction is toward the goal. Velocity is 15 m/s towards the goal.

Answer:All six of the ions contain 10 electrons in the 1s, 2s, and 2p orbitals, but the nuclear charge varies from +7 (N) to +13 (Al)

Explanation:

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Answer:

1.000 atm

Explanation:

Step 1: Write the reversible reaction

A(g) ⇌ 2 B(g)

Step 2: Calculate the reaction quotient

Q = [B]²/[A]

Q = 0.030²/0.50

Q = 0.0018

since Q < Kp, the reaction will proceed to the right

Step 3: Make an ICE chart

       A(g) ⇌ 2 B(g)

I      0.50      0.030

C       -x          +2x

E    0.50-x    0.030+2x

Step 4: Find the value of "x"

We will use the definition of the pressure equilibrium constant.

Kp = 67.2 = [B]²/[A] = (0.030+2x)²/0.50-x

33.6 - 67.2x = 0.0009 + 0.12x + 4x²

4x² + 67.32x -33.5991 = 0

We solve this quadratic equation and we get x=0.485112  and x=−17.3151 (neglected).

Step 5: Find the partial pressure of B at equilibrium

pB = 0.030+2x = 0.030+2(0.485112) = 1.000 atm

The equilibrium partial pressure of B would be:

[tex]1.000 atm[/tex]

Reversible Reaction

Given that,

Reaction

[tex]A(g)[/tex] ⇄ [tex]2 B(g)[/tex]

Charge on the reaction vessel [tex]= 0.50 atm[/tex] of A

[tex]0.030 atm[/tex] of B

To find,

Reaction quotient first

[tex]= B^2/A\\= (0.030)^2/0.50\\= 0.0018[/tex]

This shows that the reaction quotient is greater than Kp.

Through the reaction [tex]A(g)[/tex] ⇄ [tex]2 B(g)[/tex], ICE can be drawn

I      [tex]0.50[/tex]      [tex]0.030[/tex]

C    [tex]-x[/tex]        [tex]+2x[/tex]

E    [tex]0.50-x[/tex]   [tex]0.030+2x[/tex]

Now,

We will determine the value of [tex]x[/tex],

Kp [tex]= 67.2[/tex]

[tex]= [B]^2/[A][/tex]

[tex]= (0.030+2x)^2/0.50-x[/tex]

⇒ [tex]33.6 - 67.2x[/tex] [tex]= 0.0009 + 0.12x + 4x^2[/tex]

⇒ [tex]4x^2 + 67.32x -33.5991 = 0[/tex]

∵ [tex]x = -17.3151[/tex]

Therefore, Equilibrium Partial Pressure

[tex]= 0.030+2x[/tex]

[tex]= 0.030+2(0.485112)[/tex]

= [tex]1.000[/tex] atm

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Answer:

45.78 g NaClO

Explanation:

The reaction that takes place is:

In order to react completely, 1.36 moles of chlorine would require (2*1.36) 2.72 moles of NaOH. There are more moles than that, so NaOH is the limiting reactant.

We calculate the moles of NaClO formed, from the limiting reactant:

Finally we convert NaClO moles to grams, using its molecular weight:

Answer:

B. LZAQD

A. Younger than A but older than Q

Explanation:

To solve this problem, we simply apply the stratigraphic laws which are the law of superposition and principle of cross cutting.

According to the principle of cross-cutting "features that cuts through a rock are younger than the layers they cut through". In this problem, the fault cuts through layers LZ and A which suggests that these layers are older than the faulting event. Layer Q is unaffected by the faulting so, the fault is older than the layer.

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Mass of Iron produced : 1.5 kg

Reaction

a) CaCO3→CaO + CO2

b) CO2 + C → 2CO

c) Fe2O3 + 3CO → 2Fe + 3CO2

From the reaction above : 1 mol CaCO₃ = 2 mol Fe

mol CaCO₃ :

1340 : 100 g/mol = 13.4

mol Fe :

2 x 13.4 = 26.8

mass Fe :

26.8 x 56 g/mol=1500.8 g⇒1.5 kg

Answer:

51.53 grams .

Explanation:

Na₃PO₄    ⇄  3Na⁺¹   +    PO₄⁻³ .

1 mole           3 mole

725 mL of 1.3 M Na⁺  ions

= .725 x 1.3 moles of Na⁺ ions

= .9425 moles

3 mole of Na⁺  is formed by 1 mole of Na₃PO₄

.9425 mole of Na⁺  is formed by .9425/3  mole of Na₃PO₄

Na₃PO₄ needed =  .9425/3  moles = .3142 moles

Molecular weight of Na₃PO₄ = 164

grams of Na₃PO₄ needed = .3142 x 164 = 51.53 grams .

Answer:

100Jkg/°C

Explanation:

Given parameters:

Mass of metal  = 2kg

Amount of heat energy  = 1600J

Initial temperature  = 5°C

Final temperature = 13°C

Unknown:

Specific heat capacity of the metal  = ?

Solution:

Specific heat capacity of a body is the amount of heat needed to raise the temperature of unit mass of a body by 1°C.

  H  = m x C x (T₂ - T₁ )

H is the amount of heat

m is the mass

C is the unknown specific heat capacity

T is the temperature

     Insert the parameters and solve;

  1600 = 2 x C x (13 - 5)

   1600  = 16C

        C = 100Jkg/°C

Answer:

m = 0.00659 kg = 6.59 g

Explanation:

From Faraday's Law of Electrolysis, we know that:

m = ZQ

where,

m = mass of silver deposited = ?

Q = charge supplied = (1.65 A-hr)(3600 s/1 hr) = 5940 C

Z = electrochemical equivalent of silver = 1.18 x 10⁻⁶ kg/C

Therefore,

m = (1.11 x 10⁻⁶ kg/C)(5940 C)

m = 0.00659 kg = 6.59 g

The mass of silver that would be deposited by a battery is 6.65 grams

The precipitation of Ag requires the removal of one electron. The reduction process for silver electrode at the cathode is as follows:

[tex]\mathbf{Ag^+ + e^- \to Ag(s)}[/tex]

∴

In one mole of an electron, the charge carried = 96500 C

Recall that:

The atomic mass of silver (Ag) = 108 g

∴

The mass of silver that would be deposited in a 5940 C can be computed as:

[tex]\mathbf{=5940\ C \times \dfrac{108 \ g }{96500 \ C}}[/tex]

= 6.65 grams

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Answer:

0.0166

Explanation:

This conversion of 100 seconds to minutes has been calculated by multiplying 100 seconds by 0.0166 and the result is 1.6666 minutes.

I hope this helps,

even a little bit

Answer:

If I remember correctly it should be 10^7 meters.

Explanation:

The power of ten are we able to view the entire Earth in space is 10^8. This is further explained below.

Generally, A telescope is simply defined as a device that magnifies views of faraway things

In conclusion, The power of the telescope will be at 10^8.

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#SPJ2

Answer:

pue like ad

Explanation:

For the two pure substance that you cannot identified , The steps taken in the right sequence are:

Pure substance are regarded as substance that does not have impurities. one common way of finding out the purity of a substance is by its melting and boiling point determination.

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Answer:

b  

Explanation:

Answer:

5.2 mol

Explanation:

Step 1: Given data

Step 2: Calculate the mole fraction of oxygen

We will use the following expression.

pO₂ = P × X(O₂)

X(O₂) = pO₂ / P

X(O₂) = 140 kPa / 530 kPa

X(O₂) = 0.264

Step 3: Calculate the moles of oxygen

We will use the definition of mole fraction of oxygen.

X(O₂) = n(O₂) / n

n(O₂) = X(O₂) × n

n(O₂) = 0.264 × 7.0 mol

n(O₂) = 1.8 mol

Step 4: Calculate the moles of nitrogen

The total number of moles is equal to the sum of moles of the individual gases.

n(O₂) + n(N₂) = n

n(N₂) = n - n(O₂)

n(N₂) = 7.0 mol - 1.8 mol

n(N₂) = 5.2 mol

The Nobel gases, Group 8 elements  have the  smallest atomic radIi in the periodic table.

Atomic radius decreases as you move across a period. This is because Within  a period, a new electron is being added to the same shell , and at the same time a new proton is added , This causes an attraction and causes the electron to pull nearer to the nucleus causing the radius to shrink and reduce in size.

In decreasing order of atomic radius, we have alkali metals>halogens> transition metal  > Nobel gases

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Explanation:

C3H8+5O2----->3CO2+4H2O

Answer:

C3H8+5O2----->3CO2+4H2O

Explanation:

Answer:

Explanation:

The number of S atoms can be found by using the formula

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

N = 0.67 × 6.02 × 10²³

We have the final answer as

Hope this helps you

Answer:

1.9 L

Explanation:

Step 1: Given data

Step 2: Calculate the final volume of the balloon

According to Avogadro's law, the volume of an ideal gas is directly proportional to the number of moles. We can calculate the final volume of the balloon using the following expression.

V₁ / n₁ = V₂ / n₂

V₂ = V₁ × n₂ / n₁

V₂ = 2.5 L × 3.0 mol / 4.0 mol

V₂ = 1.9 L

Answer:

See explanation

Explanation:

According to the Journal of Chemical Education, Volume 80, No.8 (2003); "The first ionization energy of bismuth appears to be  anomalous......It has been claimed that spin– orbit coupling by the Russell–Saunders scheme would lower  the ground state of Bi+ ..."

However, the involvement of  d and f orbitals in Bi and Po implies that the outermost orbitals are poorly screened hence the drop between nitrogen and oxygen is not observed between Bi and Po.

The same argument could be extended to explain the reason why  there not a corresponding drop between Ba and Tl is the sixth period even though they are in the same group as Be and B.

Electrons - 7

Atomic mass - 14

For future reference, you can find the number of Electrons by subtracting the number of protons (7) from the element's mass number (14

We know, Atomic Number = Number of Electrons (In a neutral atom).

& Atomic mass = Number of protons + Number of Neutrons

The atomic number of nitrogen is 7. The number of electrons a neutral nitrogen atom has is "Seven (7)", and its atomic mass is approximately "Fourteen(14)" amu

Hope this helps!

Answer:

The phases of the Moon depend on the moon's position compared to the Earth and the Sun. Remember that the moon revolves around the Earth. As the moon goes around the Earth, half of the moon is always illuminated by the Sun.

Answer:

solubility

Explanation:

Her cells use oxygen, in the oxidation of sugar(glucose) to provide energy in the body's admissible form (i.e ATP).

Her cells, like that of every animal depend on the oxidation of sugars particularly glucose by Oxygen, O2 to provide energy in a process termed Cellular respiration.

The process of cellular respiration in her cell occurs in the mitochondria although the first part of cellular respiration occurs in the cytoplasm.

Essentially, the process of cellular respiration is made of 3 metabolic pathways as follows;

Ultimately, the admissible form of energy, the Adenosine Tri Phosphate-ATP is the end result of this glucose metabolism.

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Answer: The mole percent of 1-methylcyclohexene was 80.21% and the mole percent of 3-methylcyclohexene was 19.79%. This is because 1-methylcyclohexene is the major product with the more stable carbocation intermediate and 3-methylcyclohexene is the minor product with the less stable carbocation intermediate.

Explanation: The mole percent of 1-methylcyclohexene was 80.21% and the mole percent of 3-methylcyclohexene was 19.79%

Answer:

Image result for Where do karst regions occur?

Karsts are found in widely scattered sections of the world, including the Causses of France; the Kwangsi area of China; the Yucatán Peninsula; and the Middle West, Kentucky, and Florida in the United States.

Explanation:

Answer:

Middle West Kentucky.

Explanation:

Karst are found in widely scatter sections of the world.

Answer:

b

Explanation: