A sonar emits a sound signal of frequency 40000Hz, towards the bottom of the sea.
This signal is reflected on the body of a submarine after a delay of 0.3 seconds.
Given: Speed of sound in water is 1500 m/s.

Calculate the period of this wave.

Answers

Answer 1

Answer:

0.000025s

Explanation:

Period it’s. : T(s)= 1/f(Hz)=1/40000Hz=0.000025s


Related Questions

CAN SOMEONE HELP ME WITH THIS

Answers

Answer:

D

Explanation:

Answer is D, you are welcome

What sort of force is magnetism?
pls help ASAP :)
no links pls​

Answers

Answer:

Magnetism is one aspect of the combined electromagnetic force. It refers to physical phenomena arising from the force caused by magnets, objects that produce fields that attract or repel other objects.

Calcular la densidad absoluta de un fluido cuya masa es de 12.8 kg y que ocupa un volumen de 16.3 cm

Answers

Answer:

[tex]d=785.27\ g/cm^3[/tex]

Explanation:

The question says that, "Calculate the absolute density of a fluid whose mass is 12.8 kg and which occupies a volume of 16.3 cm³".

Mass, m = 12.8 kg = 12800 g

Volume, V = 16.3 cm³

The density of an object is defined as the mass per unit volume i.e.

[tex]d=\dfrac{m}{V}\\\\d=\dfrac{12800}{16.3}\\\\d=785.27\ g/cm^3[/tex]

So, the absolute density of the fluid is equal to [tex]785.27\ g/cm^3[/tex].

GIVING BRAINLIEST IF YOU ANSWER CORRECTLY!! (20 pts!!)

Answers

Answer:

c 1386J

Explanation:

You use the formula MCΔT where m is mass, C is specific heat, and delta t is change in temperature

Jake appears to have several personalities. One is his dead cousin Bob, who
apparently bought a car Jake didn't know about. Jake said he had no memory
of buying the car. Jake also has a personality of a 12-year-old child. Jake
appears to be suffering from:
A. schizophrenia.
B. generalized anxiety disorder.
C. dissociative identity disorder.
D. major depression.
SUBMIT

Answers

The answer is C. Dissociative identity disorder

-

This should be easy to spot

Answer: DISSOCIATIVE IDENTITY DISORDER

Explanation:

Select the correct location on the image.
Which color in the visible spectrum has the highest frequency?

Answers

Answer:

Violet I took the test and it was right

Answer:

Violet the dude above was correct i took the test and got it right

Explanation:

Which part of and organism is preserved in cast and mold fossils

Answers

Answer:

bones

Explanation:

Bones are is preserved in cast and mold fossils.

Normally the other 'parts of the body' like muscles, ligaments, blood and organs are soft.

Answer:

bones

Explanation:

Astronomers build optical telescopes on tops of mountains because a. there is less air to dim the light. b. the seeing is better. c. CCDs work better with a beautiful mountain view. Astronomers build optical telescopes on tops of mountains because a. there is less air to dim the light. b. the seeing is better. c. CCDs work better with a beautiful mountain view. all choices, a, b and c choice c only choice a only choice b only choices a and b

Answers

Answer: choices a and b

Explanation:

Telescope can be defined as am optical instrument which is designed to observe the distant objects clear and nearer. It comprises of arrangement of lenses which allow the rays of light to be collected. The collected light is focused and the image so produced is magnified in the form of an image. The telescopes are prepared and manufactured on mountains top as this will help in preventing the distortion of light obtain from the star due to the fluctuation of air mass in the atmosphere. The atmospheric distortion affects the resolution, and affects the vision. The atmospheric pressure is low at the mountain tops so it will help in better observation of the sky.

What will be the change in velocity of a 850 kg car if a force of 50,000N is
applied for 0.5 s? (Round to one decimal)

Answers

Answer:

i'm not quite sure

Explanation:

just grive me a sec

Answer:

29.4 m/s

Explanation:

f = ma

a = [tex]\frac{f}{m}[/tex]

a = [tex]\frac{50000}{850}[/tex]

a = 58.8 [tex]m/s^{2}[/tex]

a = [tex]\frac{change in velocity}{t}[/tex]

change in velocity= at

change in velocity = 58.8 × 0.5

change in velocity = 29.4 m/s

Potential Energy: A cat which weighs 10 kg walks up a ladder. The ladder has a height of 15 m. How many joules of gravitational
potential energy does the cat have?

Answers

20 espero que esto te ayude por que yo ya lo hice jsjsjs

number of atoms of each element ammonium hydroxide?​

Answers

Answer:

Explanation:

Ammonium Hydroxide has the chemical formula of

NH4OH

There is 1 Nitrogen (N) = 1

There are 5 Hydrogens (H) = 5

There is 1 Oxygen  (O) = 1

In total, there are 7 atoms in 1 molecule of NH4OH


Explain how air exerts a pressure​

Answers

air exert a pressure take a glass and put the water on it and small piece a paper and glass take downword and observe it so tha air exert pressure

A 4kg object has a momentum of 12 kg*m/s, what is the objects velocity?

Answers

Momentum = mass x velocity
12 = 4 x v | ÷ both sides by 4
12 ÷ 4 =v
v= 3 m/s

Using the image, which area of the ocean floor would have the largest amount of pressure? Explain

Answers

Answer: the area were the most pressure is at the deep sea trench (the deepest part)

Explanation: because the more on top of you is the more pressure.

A plane travels 4.0 km at an angle of 25◦ to the ground, then changes direction and travels 10 km at an angle of 16◦ to the ground. What is the magnitude of the plane's total displacement? Answer in units of km.

Answers

Answer:

6.1 km

Explanation:

Given that a plane travels 4.0 km at an angle of 25◦ to the ground, then changes direction and travels 10 km at an angle of 16◦ to the ground. What is the magnitude of the plane's total displacement? Answer in units of km

The magnitude of the total displacement D can be calculated by using cosine formula

Ø = 25 - 16 = 9 degree

D^2 = 4^2 + 10^2 - 2 × 4 × 10 × cos 9

D^2 = 16 + 100 - 80cos9

D^2 = 116 - 79.02

D = sqrt( 36.98)

D = 6.1 m

Therefore, the magnitude of the plane's total displacement is 6.1 km

Please help!!!! It's due today!!!

Answers

p=300kg x 4m/s^2= 1200kg m/s?

A car moving 20 m/s accelerates to pass
a truck. Five seconds later the car is
moving 30 m/s. What is the acceleration
of the car?
A. 5 m/s
B. -5 m/s
C. -2 m/s
D. 2 m/s
Gooooo

Answers

The answer is 2m/s.
The equation is a=(vf-vi)/2

Marcus tries to move a refrigerator but can't. Has he done work?

A) Yes, because he used energy.
B) Yes, because he exerted a force.
C) No, because he did not move the object.
D) No, because he did not use energy.

Answers

Answer:

A

Explanation:

Even if the refrigerator did not move he still used energy to try to push it it's just his energy wasnt stronger than the refrigerator's energy

To Calculate Velocity and Average Velocity you can use the same formula as both.

True Or False?

Answers

Answer:

I believe it's True!    Brainliest??

Explanation: Hope you have a great day :)

Giving brainliest!! if you answer correctly :) (30pts)

Answers

Answer:

32000joule.

Explanation:

given

mass. (m)=160kg

speed (v)=20m/s

now

kinetic energy =1/2 (mv²)=1/2 ×{160×20²}=32000joule.

Answer:

Explanation:

Ke = 1/2 mv2

Ke = 1/2(160)(20)2

= 1/2(160)(400)

= 32000J

Option B is the correct answer

What method is used when you try several different solutions to see what
works?
A. Trial and error
B. Stages
C. Heuristic
D. Rational

Answers

Answer:

A

Explanation:

Trial and error is basically trying something, if it works, great. If it does not work, try another way.

Answer:

A. Trial and error

Explanation:

The other user is correct.

Sam goes to a friend's house by bike. His friend's house is 350m away. The journey takes 50s. What is Sam's average speed?

Answers

V=d/t
V=350m/50s
V=7m/s

Answer:

Sam's average speed was 7ms-1

Explanation:

speed= distance / time

speed= 350 / 50

speed= 7 metres per second.

8.
2
AI
6
HCI
AICI:
+
H



Answers

Answer:

I'm sorry I can't help you...

can someone help me with this please what are the two correct answers??​

Answers

Answer:

The answers should be B and D

Explanation:

I hope this helps!

The answers are B and D

A television that requires an average of 0.40 ampere of current is operated on a
120-volt service for 5.0 hours. How much energy is used?
a. 1.5 kWh
b. 0.15 kWh
C. 0.24 kWh
d. 0.67 kWh

Answers

The energy that has been used is 0.24 kWh

You pull straight up on the string of a yo-yo with a force 0.19 N, and while your hand is moving up a distance 0.12 m, the yo-yo moves down a distance 0.30 m. The mass of the yo-yo is 0.058 kg, and it was initially moving downward with speed 3.4 m/s. (b) What is the new speed of the yo-yo

Answers

Answer:

2.54 m/s

Explanation:

By conservation of energy,

work done by force due to hand = mechanical energy gained by yo-yo

So Fd = mgh + 1/2m(v₂² - v₁²)

where F = force on string = 0.19 N, d = distance moved by hand = 0.12 m, m = mass of yo-yo = 0.058 kg, g = acceleration due to gravity = 9.8 m/s², h = distance moved by yo-yo = 0.30 m, v₁ = initial speed of yo-yo = 3.4 m/s and v₂ = final speed of yo-yo = unknown

So,  Fd = mgh + 1/2m(v₂² - v₁²)

Fd/m = gh + 1/2(v₂² - v₁²)

Fd/m - gh = 1/2(v₂² - v₁²)

2(Fd/m - gh) = (v₂² - v₁²)

(v₂² - v₁²) = 2(Fd/m - gh)

v₂²  = v₁² + 2(Fd/m - gh)

taking square-root of both sides, we have

v₂  = √[v₁² + 2(Fd/m - gh)]

Substituting the values of the variables into the equation, we have

v₂  = √[(3.4 m/s)² + 2(0.19 N × 0.12 m/0.058 kg - 9.8 m/s² × 0.30 m)]

v₂  = √[(3.4 m/s)² + 2(0.19 N × 0.12 m/0.058 kg - 9.8 m/s² × 0.30 m)]

v₂  = √[(3.4 m/s)² + 2(0.0228 Nm/0.058 kg - 9.8 m/s² × 0.30 m)]

v₂  = √[(3.4 m/s)² + 2(0.393 Nm/kg - 2.94 m²/s²)]

v₂  = √[(3.4 m/s)² + 2(-2.547 m²/s²)]

v₂  = √[11.56 m²/s² - 5.094 m²/s²)]

v₂  = √[6.466 m²/s²]

v₂ = 2.54 m/s

(True/False) The normal force is always opposite in direction to weight.

Answers

Answer:

True

Explanation:

What work is the person doing doing to the box if the box is just being held and it is not moving?

Answers

Allowing for a platform in which the box holds potential energy

A 90° elbow in a horizontal pipe is used to direct water flow upward at a rate of 40 kg/s. The diameter of the entire elbow is 10 cm. The elbow discharges water into the atmosphere, and thus the pressure at the exit is the local atmospheric pressure. The elevation difference between the centers of the exit and the inlet of the elbow is 50 cm. The weight of the elbow and the water in it is considered to be negligible. Determine (a) the gage pressure at the center of the inlet of the elbow and (b) the anchoring force needed to hold the elbow in place. Take the momentum-flux correction factor to be 1.03 at both the inlet and the outlet.

Answers

Answer:

(a) The gauge pressure is 4,885.3 Pa

(b) The anchoring force needed to hold the elbow in place is approximately 296.5 N

The direction of the anchoring force is approximately ≈ 134.8

Explanation:

The given parameters in the fluid dynamics question are;

Pipe elbow angle, θ = 90°

The mass flowrate of the water, [tex]\dot m[/tex] = 40 kg/s

The diameter of the elbow, D = 10 cm

The pressure at the point of discharge of the fluid = Atmospheric pressure

The elevation between the inlet and exit of the elbow, z = 50 cm

The weight of the elbow and the water = Negligible

(a) The velocity of the fluid, v₁ = v₂ = v is given as follows;

ρ·v·A = [tex]\dot m[/tex]

v = [tex]\dot m[/tex]/(ρ·A)

Where;

ρ = The density of the fluid (water) = 997 kg/m³

A = The cross-sectional area of the of the elbow = π·D²/4 = π×0.1²/4 ≈ 0.00785398163

A = 0.00785398163 m²

v = 40 kg/s/(0.00785398163 m² × 997 kg/m³) ≈ 5.1083 m/s

Bernoulli's equation for the flow of fluid is presented as follows;

[tex]\dfrac{P_1}{\rho \cdot g} +\dfrac{v_1}{2 \cdot g} + z_1 = \dfrac{P_2}{\rho \cdot g} +\dfrac{v_2}{2 \cdot g} + z_2[/tex]

v₁ = v₂ for the elbow of uniform cross section

P₁ - P₂ = ρ·g·(z₂ - z₁)

P₁ - P₂ = The gauge pressure = [tex]P_{gauge}[/tex]

z₂ - z₁ = z = 50 cm = 0.5 m

∴ [tex]P_{gauge}[/tex] = 997 kg/m³ × 9.8 m/s² × 0.5 m = 4,885.3 Pa

The gauge pressure, [tex]P_{gauge}[/tex] = 4,885.3 Pa

(b) The forces acting on the elbow are;

[tex]F_{Rx}[/tex] + [tex]P_{gauge}[/tex]·A = -β·[tex]\dot m[/tex]·v

[tex]F_{Ry}[/tex]  = β·[tex]\dot m[/tex]·v

∴ [tex]F_{Rx}[/tex]  = -β·[tex]\dot m[/tex]·v -  [tex]P_{gauge}[/tex]·A

[tex]F_{Rx}[/tex]  = -1.03 × 40 kg/s × 5.1083 m/s -  4,885.3 Pa × 0.00785398163 m² ≈ -208.83 N

[tex]F_{Ry}[/tex]  = 1.03 × 40 kg/s × 5.1083 m/s = 210.46196 N

The resultant force, [tex]F_R[/tex], is given as follows;

[tex]F_R[/tex] = √([tex]F_{Rx}[/tex]² + [tex]F_{Rz}[/tex]²)

∴ [tex]F_R[/tex] = √((-208.83)² + (210.46196)²) ≈ 296.486433934

Therefore;

The anchoring force needed to hold the elbow in place, [tex]F_R[/tex] ≈ 296.5 N

The direction of the anchoring force, θ

[tex]\theta = tan^{-1}\left( \dfrac{F_{Ry}}{F_{Rx}} \right)[/tex]

∴ θ = arctan(210.46196/(-208.83)) = -45..2230044°

θ = 180° + -45.2230044° = 134.7769956°

∴ The direction of the anchoring force is approximately, θ ≈ 134.8°

An old woman is worried about time. She walks at a rate of 2 meters per second and travels a
distance of 454 meters. How long does it take her to complete the motion?


Please help ASAP!! BRAINLIST please explain thankyou!!!

Answers

Answer:

227 seconds.

Explanation:

Speed is equal to distance divided by time. s = d/t

We can rearrange this algebraically to solve for the time it will take to cover a certain distance at a certain speed. Time is equal to distance divided by speed.  t = d/s

Then we substiture our known values for the variables and solve for our unknown.

t = 454m / 2m/s = 227s

Answer:

If the lady is traveling 2 meters per second and she travels 454 meters then you will have to divide 454 by 2 to get the amount of time she walked.

454 divided by 2 = 227

This means that the lady traveled for 227 seconds or about 3.78 minutes.

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