Answer:
a) the rate of heat transfer from the pipe to the air is 23.866 watts
b) YES, the rate of heat transfer changes to 3518.61 watt
Explanation:
Given that:
steam is saturated at 17.90 bar.
the pipe is stainless steel and has an outside diameter of 6.75 cm
length = 34.7 m
Air flows over the pipe at 7.6 m/s
Bulk fluid temperature of 27°C
we know that
hD/k = 0.028 (Re)^0.8 (Pr)^0.33
Outside diameter of pipe = 6.75 cm
length of the pipe = 34.7 m
velocity of air = 7.6 m/s
Cp of air = 1.005 kJ/Kgk
viscosity of air = 1.81 × 10⁻⁵ kg/(m.sec)
thermal conductivity of air = 2.624 × 10⁻⁵ kw/m.k
so as
hD/k = 0.028 (Re)^0.8 (Pr)^0.33
hD/k = 0.028 (Dvp / u)^0.8 (Cpu / k)^0.33
(h × 0.0675 / 2.624 × 10⁻⁵) = (0.028 ([0.0675 × 7.6 × 1.225] / [1.81 ×10⁻⁵])^0.8) (((1.005 × 1.81 × 10⁻⁵) / (2.624 × 10⁻⁵))^0.33))
h = 0.0414 w/m².k
a)
Now to find the rate of heat transfer Q
Q = hAΔT
Q = 0.0414 × (2π × 0.03375 × 34.7) × (105.383 - 27)
Q = 23.866 watts
therefore the rate of heat transfer from the pipe to the air is 23.866 watts
b)
Now the flow direction changes to parallel flow, then
(h × 0.0675 / 2.624 × 10⁻⁵) = (0.028 ([34.7 × 7.6 × 1.225] / [1.81 ×10⁻⁵])^0.8) (((1.005 × 1.81 × 10⁻⁵) / (2.624 × 10⁻⁵))^0.33))
h = 6.1036 w/m².k
so from the steam table, saturated steam at 17.70 bar, temperature of steam will be 105.383°C
so to find the rate of heat transfer Q
Q = hAΔT
Q = 6.1036 × (2π × 0.03375 × 34.7) × (105.383 - 27)
Q = 3518.61 watt
Therefore the rate of heat transfer changes to 3518.61 watt
Whats wrong with the wind turbine?
Answer:
The wind turbine has little impact on the environment compared to conventional power plants. Meanwhile the Wind turbine can affect the wildlife meaning birds are being harmed by the blades.
Explanation: Hope that helps:)
A transmitter has an output power of 0.1mW while the fiber has coupling loss of 12dB, attenuation of
6dB/km for the length of 500m. The link contains two connectors of 2dB average loss. The receiver has a
minimum acceptable power ( sensitivity) of -35dBm. The designer has allowed a 4dB margin. Based on
the given information,
a) Calculate total link loss
b) Determine the receiver's sensitivity
c) Identify this system is good practice or not
Determine the greatest pressure drop allowed over the 10-m-long pipe caused by viscous friction, so the flow remains laminar.
This question is incomplete, the complete question is;
Determine the greatest pressure drop allowed over the 10-m-long pipe caused by viscous friction, so the flow remains laminar.
The 125-mm-diameter smooth pipe is transporting SAE 10W-30 oil with ρ=920 kg/m3 and µ=0.2 N.s/m2 .
Answer: the greatest pressure drop allowed is 14247 Pascals
Explanation:
LAMINAR FLOW INF PIPE
greatest pressure drop
(P1 - P2) = pressure drop
(P1 - P2) = 32uvl / D²
so (P1 - P2) ∝ V
greatest pressure drop is only at very high velocity
now Re (Reynold Number = svd / u
Re ∝ V
so velocity is high when Re is high
Re = 2000 ( Highest for LAMINAR)
Re = 2000 = svd / u
now in the question we were given that
s = 920 kg/m³, u = 0.2 NS/m², d = 125mm = 0.125m, l = 10m
so we substitute;
2000 = (920 × v × 0.125) / 0.2
v = 3.48 m/s
now pressure drop = (P1 - P2) = 32UVL / d²
we substitute
(P1 - P2) = (32(0.2) (3.48)(10)) / (0.125)²
(P1 - P2) = 14247 Pascals
therefore the greatest pressure drop allowed is 14247 Pascals
Bars A and B have cross-sectional areas of 400 m2 and a modulus of elasticity of 200 GPa. A gap exists between bar A and the rigid vertical bar before the force F (10 kN) is applied. Determine the axial stress in bar B, and the deformation of bar A.
Answer:
axial stress in bar B = 25Mpa.
Deformation of bar A = 0.4mm.
Explanation:
PS: Kindly check the attached picture for the diagram showing the two bars that is to say the bar A and the bar B.
So, we are given the following data or information or parameters which we are going to use in solving this particular question or problem. Here they are;
The cross-sectional areas of Bars A and B = 400 mm2, the modulus of elasticity of bar A and bar B = 200 GPa, applied force = 10kN.
STEP ONE: The first step is to determine or calculate the axial stress in bar B. Therefore,
Axial stress in bar B = 10 × 10³ ÷ 400 × 10⁻⁶ = 25 Mpa.
STEP TWO: The second step here is to determine or calculate the deformation of bar A. Therefore,
The deformation of bar A = 20 × 10³ ×1.5 ÷ 400 × 10⁻⁶ × 200 × 10³ = 0.375 mm.
four working ladies a,b c,d are sitting around a table
1) a sits opposite to cook
2.b sits on the right side of the beautician
3.teacher is on the left side of an accountant
4.d sits opposite to c
5.c is to the right of the accountant
Answer:
A accountant
D teacher
B cook
C beautician
Explanation:
C is on the right of the accountant, so D (opposite C) is the teacher. The accountant is to the right of the teacher, so cannot be B, and must be A. Then B (opposite A) is the cook, and C (left of B) is the beautician.
__
Clockwise from A:
A accountant
D teacher
B cook
C beautician
WILL MAKE AS BRAINLEST
I answered some of them can anyone help with the rest?
1. What document granted permission to found and established the boundaries of the Georgia Colony?
The charter
2. Why was Georgia founded as a “buffer colony”?
defend the southern British colonies from Spanish Florida.
3. Why did Oglethorpe originally want to start a new colony in the New World?
He wanted to give debtors another chance at life instead of prison
4. According to the Charter of 1732, what are the three reasons for starting the colony of Georgia?
Charity Economics Defense
5. How did the relationship between Oglethorpe and Tomochichi impact the founding and establishment of the colony of Georgia?
6. Who founded the city of Savannah?
James Oglethorpe
7. Describe, in detail, how the following individuals contributed to the founding of Georgia:
Tomochichi:
Mary Musgrove:
8. What were the Salzburgers able to produce that the colonists of Savannah had trouble producing?
9. Who was the interpreter /ambassador between Oglethorpe and Tomochichi?
10. Who was the leader of the Yamacraw Indians?
11. What did the Malcontents want to happen in Georgia? (Think rules)
12. Who is credited with saving the lives of many colonists from disease (cholera) after he and his people were allowed into the colony of Georgia?
13. What type of colony was Georgia at first? Who would oversee the colony of Georgia?
14. After the Trustee Colony fell, what type of colony would Georgia become?
15. Who “ran” the colony of Georgia once it became a Royal Colony?
16. What rule did the Malcontents want to change the most?
Land
17. When the slavery ban was lifted, Georgia saw a rapid increase in what between 1750-1775?
Agraculture
18. What did the Royal Governors do that help prove they were trying to keep the settlers satisfied? (Think change in rules/laws)
19. What were the five main goods that were sold in the Georgia Colony? Remember WRIST
20. What increased dramatically after the Royal period began?
What type of shading techniques requires using the side of the pencil to add value.
Answer:
YES
Explanation:
NO
;-;
Match each titration term with its definition.
Process of slowly adding a solution to react with another solution and determine the Choose... concentration of one of the solutions tased on the reaction between them
Solution of an unknown concentration that has another solution slowly added to it Choose...
When the required amount of one solution has been added to the second solution to Choose... complete the reaction
Solution of known concentration that is slowly added to a solution of unknown Choose... concentration
Glassware that allows a solution to be precisely and slowly added to another solution Choose...
A reagent added to the analyte solution that changes color when the reaction is Choose... complete
Answer:
1) titration
2) titrand
3) equivalence point
4) titrant
5) Burette
6) Indicator
Explanation:
The process of adding a known volume a standard solution to another solution to react with it in order to determine the concentration of the unknown solution is known as titration.
The solution to which another solution of known concentration is added is called the titrand while the solution of known concentration is called the titrant.
A burette is a glassware used to slowly add a known volume of the titrant to the titrand. An indicator shows the point when the reaction is complete by a color change. This is the point when the required amount of one solution has been added to the second solution. It is also called the equivalence point.
I. The process of slowly adding a solution to react with another solution and determine the concentration of one of the solutions based on the reaction between them: Titration.
II. A solution of an unknown concentration that has another solution slowly added to it: Analyte.
III. When the required amount of one solution has been added to the second solution to complete the reaction: Endpoint.
IV. A solution of known concentration that is slowly added to a solution of unknown concentration: Titrant.
V. A glassware that allows a solution to be precisely and slowly added to another solution: Burette.
VI. A reagent added to the analyte solution that changes color when the reaction is complete: Indicator.
Titration is also referred to as titrimetry or volumetric analysis and it can be defined as a chemical process in which a solution of known concentration is slowly added to a solution of unknown concentration, in order to determine the concentration or quantity of the analyte (solution of an unknown concentration)
For example, titration can be used to determine the concentration of a basic solution by titrating it with an acid solution of known concentration that is required to neutralize the basic solution.
In Chemistry, the following terms and apparatus are used for the titration of solutions:
Analyte.Indicator.Burette.Ring stand.Endpoint.Titrant.Conical flask.Read more: https://brainly.com/question/23307058
Use the Intermediate Value Theorem to show that there is a root of the given equation in the specified interval. Ex = 6 − 5x, (0, 1) The equation ex = 6 − 5x is equivalent to the equation f(x) = ex − 6 + 5x = 0. F(x) is continuous on the interval [0
Answer:
some part of your question is incomplete
attached below is the complete question
Answer :
F(0) = -5 < 0
F(1) = e - 1 > 0
since the functions : f(0) and f(1) have opposite signs then there is a 'c' whereby F(c) = 0 ( intermediate value theorem fulfilled )
Hence there is a root in the given equation : [tex]e^x = 6 - 5x[/tex]
Explanation:
using Intermediate value Theorem
If F(x) is continuous and f(a) and f(b) have opposite signs then there will be a'c'E (a,b) whereby F(c) = 0
given equation : [tex]e^x = 6 - 5x[/tex] on (0,1)
and F(x) = [tex]e^x - 6 + 5x = 0[/tex]
This shows that the F(x) is continuous on (0,1)
F(0) = [tex]e^0 - 6 + 5(0)[/tex] = -5 which is < 0
F(1) = [tex]e^1 -6 + 5(1)[/tex] = e -1 > 0 and e = 2.7182
since the functions : f(0) and f(1) have opposite signs then there is a 'c' whereby F(c) = 0 ( intermediate value theorem fulfilled )
Hence there is a root in the given equation : [tex]e^x = 6 - 5x[/tex]
Experimental Design Application Production engineers wish to find the optimal process for etching circuit boards quickly. They create a single replicate 24experiment to test the effect of the following factors on time to etch a circuit board: (A) Concentration of nitric acid in the etchant, (B) temperature of the etchant, (C) stirring rate in the etching tank, (D) surface area of the board. Running this experiment, they obtain the data in HW_EDA_137.csv.Preview the document Which factors effects and interaction effects are significant?
Answer:
Hello your question is incomplete attached below is the missing part and answer
options :
Effect A
Effect B
Effect C
Effect D
Effect AB
Effect AC
Effect AD
Effect BC
Effect BD
Effect CD
Answer :
A = significant
B = significant
C = Non-significant
D = Non-significant
AB = Non-significant
AC = significant
AD = Non-significant
BC = Non-significant
BD = Non-significant
CD = Non-significant
Explanation:
The dependent variable here is Time
Effect of A = significant
Effect of B = significant
Effect of C = Non-significant
Effect of D = Non-significant
Effect of AB = Non-significant
Effect of AC = significant
Effect of AD = Non-significant
Effect of BC = Non-significant
Effect of BD = Non-significant
Effect of CD = Non-significant
g At this party, is the fact that a person is from South America independent of that person being majoring in biomedical engineering?
Answer:
Yes, this is completely independent.
Explanation:
Yes, this is completely independent. Even though there are no South American individuals that are majoring in biomedical engineering in this party it is still a completely independent factor. The origin of birth of an individual does not tie them to a specific degree or field of expertise, therefore a South American individual can study anything they want including mechanical engineering, electrical engineering, or biomedical engineering.
A closed system of mass 20 kg undergoes a process in which there is a heat transfer of 1000 Q6: ki from the system to the surroundings. The work done on the system is 200 kl. If the initial 5 specific internal energy of the system is (250+R:) kl/kg, what is the final specific internal energy, in kj/kg? Neglect changes in kinetic and potential energy:
The final specific internal energy : 190 kJ/kg
Further explanationThe laws of thermodynamics 1 state that: energy can be changed but cannot be destroyed or created
The equation is:
[tex]\tt E_{in}-E_{out}=\Delta E~system\\\\\Delta E=\Delta U+\Delta KE+\Delta PE\\\\\Delta U=m(U_2-U_1)\\\\Q-W=\Delta U+\Delta KE+\Delta PE[/tex]
Energy owned by the system is expressed as internal energy (U)
This internal energy can change if it absorbs heat Q (U> 0), or releases heat (U <0). Or the internal energy can change if the system does work or accepts work (W)
The sign rules for heat and work are set as follows:
• The system receives heat, Q +
• The system releases heat, Q -
• The system does work, W -
• the system accepts work, W +
A closed system of mass 20 kg⇒m=20 kg
Heat transfer of 1000 kJ from the system to the surroundings⇒Q=-1000 kJ
The work done on the system is 200 kJ⇒W=+200 kJ
The initial specific internal energy of the system is 250 kJ /kg⇒U₁ = 250 kj/kg
Neglect changes in kinetic and potential energy⇒ΔKE+ΔPE=0, so
Q-W = ΔU
Input in equation
[tex]\tt -1000-200=20(U_2-250)\\\\-1200=20U_2-5000\\\\3800=20U_2\\\\U_2=190~kJ/kg[/tex]
Type the correct answer in the box. Spell all words correctly.
Anne works for NASA. She was responsible for developing an aerodynamic design of a space shuttle. What type of engineer is she?
Anne is a(n)
engineer.
Answer:
Anne is a mechanical engineer.
Explanation:
There are many different types of engineers (mechanical, industrial, electrical, chemical and civil) around the world. When a job involves designing machines, it falls under mechanical engineering. Such job requires a person to be as creative as possible, so he/she can come up with an innovative design that will be reasonable when used.
Designing machines includes spacecrafts. Therefore, Anne is a mechanical engineer working for NASA.
What is technology and what are the four features of technology?
Answer: Technology is the application of scientific knowledge for practical purposes, especially in industry.
Mechanical.
Electronic.
Industrial and manufacturing.
Medical.
Communications.
Explanation:
Answer:
Technology is something like a phone or like a tablet or like an electrace car
Explanation:
In the feature i belive that there is going to be more and higher andanved technology or like people say flying cars a robots. But i feel more advanced stuff like phones and computers or labtops or like tablets.
in a vehicle you're servicing the fuel pressure drops rapidly when the engine is says that one or more turned off. Technician a says that one or more could be leaking technician b says that a defective check valve in the fuel pump could be the cause who is correct
Answer:
Both Technicians A and B are correct
Explanation:
If the fluid pressure will decrease quickly in a car when the ignition says that one or more has been switched off. One or two could be leaking or the source could be a faulty check mechanism in the catalytic converter.
Why do the changes to the mass of the planet NOT AFFECT the orbital path of the Planet?
Answer:
changes of Mass affect the planet because... I'm sorry If this didn't help.
Stack memory is implemented as a stack data structure. Provide the sequence of push and pop operations on stack memory when the collatz method (provided below) is called with n = 5. Note that an enqueue and dequeue is associated with a method call. For example, the first and last operations in the sequence should be push(collatz(4)) and pop(collatz(4)) respectively. public void collatz(int n) { if (n == 1) return; else if (n % 2 == 0) collatz(n / 2); else collatz(3*n + 1); }
Answer:
attached below is the solution
Explanation:
hello attached below is the sequence of push and pop operations on stack memory
For The collatz method below
public void collatz(int n) {
if (n == 1) return;
else if (n % 2 == 0)
collatz(n / 2);
else collatz(3*n + 1); }
The insulator is the connection between the grounded circuit conductor and the equipment grounding conductor at the service.
Describe the blade design for a wind turbine that you would choose. Why did you choose this design?
Answer: aerofoil type blades
Explanation: they are more difficult to make but offer better performance and higher rotational speeds making them ideal for electrical energy generation.
Consider a W21x93. Determine the moment capacity of the beam. Assume the compression flange is not laterally braced and that the unbraced length is 15 feet. Assume Cb
Answer:
The answer is "828.75"
Explanation:
Please find the correct question:
For W21x93 BEAM,
[tex]Z_x = 221.00 in^3 \\\\\to \frac{b_t}{2t_f} =4.53\\\\\to \frac{h}{t_w}=32.3[/tex]
For A992 STREL,
[tex]F_y= 50\ ks[/tex]
Check for complete section:
[tex]\to \frac{b_t}{2t_f} =4.53 < \frac{65}{\sqrt{f_y = 9.19}}\\\\\to \frac{h}{t_w} =32.3 < \frac{640}{\sqrt{f_y = 90.5}}[/tex]
Design the strength of beam =[tex]\phi_b Z_x F_y\\\\[/tex]
[tex]=0.9 \times 221 \times 50\\\\=9945 \ in \ \ kips\\\\=\frac{9945}{12}\\\\= 828.75 \ft \ kips \\[/tex]
Due within next 5 minutes... Should scientists be allowed to research human cloning? Explain and defend your answer.
Answer:
science is hard but human cloning this is legendary but still its up to the government but me i would allow this because its something that science can upgrade to
Explanation:
Help please all of the numbers b4 the equal sign are wrong
Answer:
3/5" = 12'1 3/4" = 35'1 1/4" = 25'9/10" = 18'2 13/20" = 53'Explanation:
One number is wrong; they all lack units.
The basic ratio is 1" = 20', so you can divide feet by 20 to find inches.
3/5" = 12'1 3/4" = 35'1 1/4" = 25'9/10" = 18'2 13/20" = 53'Perhaps you want decimal inches:
0.60" = 12'1.75" = 35'1.25" = 25'0.90" = 18'2.65" = 53'Been struggling with this for last 2 hours. Need help, please.
A local government is considering a change to its building code, requiring that all new driveways and parking lots use green technology, such as crushed stone, rather than asphalt. Discuss the benefits and liabilities of each technology, taking into account environmental impacts.
Your answer must have at least two paragraph and be between ½ page and one page in length
Timken rates its bearings for 3000 hours at 500 rev/min. Determine the catalog rating for a ball bearing running for 10000 hours at 1800 rev/min with a load of 2.75 kN with a reliability of 90 percent.
Answer:
C₁₀ = 6.3 KN
Explanation:
The catalog rating of a bearing can be found by using the following formula:
C₁₀ = F [Ln/L₀n₀]^1/3
where,
C₁₀ = Catalog Rating = ?
F = Design Load = 2.75 KN
L = Design Life = 1800 rev/min
n = No. of Hours Desired = 10000 h
L₀ = Rating Life = 500 rev/min
n₀ = No. of Hours Rated = 3000 h
Therefore,
C₁₀ = [2.75 KN][(1800 rev/min)(10000 h)/(500 rev/min)(3000 h)]^1/3
C₁₀ = (2.75 KN)(2.289)
C₁₀ = 6.3 KN
Suppose an underground storage tank has been leaking for many years, contaminating a groundwater and causing a contaminant concentration directly beneath the site of 0.30 mg/L. The contamination is flowing at the rate of 0.5 ft/day toward a public drinking water well 1 mile away. The contaminant degrades with a rate constant of 1.94 x 10^-4 1/day. Draw a picture of the system. Estimate the steady-state pollutant concentration expected at the well. If the slope factor is 0.02 (mg/kg-day)^-1.
Required:
Estimate the cancer risk for an adult male drinking the water for 10 years.
Answer: the cancer risk for an adult male drinking the water for 10 years is 2.88 × 10⁻⁶
Explanation:
firstly, we find the time t required to travel for the contaminant to the well;
Given that, contamination flowing rate = 0.5 ft/day
Distance of well from the site = 1 mile = 5280 ft
so t = 5280 / 0.5 = 10560 days
k is given as 1.94 x 10⁻⁴ 1/day
next we find the Pollutant concentration Ct in the well
Ct = C₀ × e^-( 1.94 x 10⁻⁴ × 10560)
Ct = 0.3 x e^-(kt)
Ct= 0.0386 mg/L
next we determine the chronic daily intake, CDI
CDI = (C x CR x EF x ED) / (BW x AT)
where C is average concentration of the contaminant(0.0368mg/L), CR is contact rate (2L/day), EF is exposure frequency (350days/Year), ED is exposure duration (10 years), BW is average body weight (70kg).
now we substitute
CDI = (0.0368 x 2 x 350 x 10) / ((70x 365) x 70)
= 257.7 / 1788500
= 0.000144 mg/Kg.day
CDI = 1.44 x 10⁻⁴ mg/kg.day
Finally we calculate the cancer risk, R
Slope factor SF is given as 0.02 Kg.day/mg
Risk, R = I x SF
= 1.44 x 10⁻⁴ mg/kg.day x 0.02Kg.day/mg
R = 2.88 × 10⁻⁶
therefore the cancer risk for an adult male drinking the water for 10 years is 2.88 × 10⁻⁶
Construct a Mohr circle for the stress element at A in problem 2. Using ruler and compass, draw the Mohr circle to the scale. Draw the stress element for principal normal stresses correctly oriented and show the stresses acting on it. Do the same for the element of maximum shear stress
Answer:
hello your question is incomplete attached below is the missing diagram to the question and the detailed solution
Answer : principal stresses : 0.82 MPa, -33.492 MPa
shear stress = 17.157 MPa
∅ = 9.09 ≈ 10°
Explanation:
The principal stress ( б1 ) = 0.82 MPa
( б2 ) = -33.492 MPa
The shear stress = 17.157 MPa
∅ = 9.09 ≈ 10°
attached below is the detailed solution and the Mohr's circle
What motivated software engineers to move from the waterfall model to the incremental or spiral model
Answer:
1. They needed to develop multiple components in software programs.
2. The ability to overlap the development to be more evolutionary in nature.
3. The need to be more risk-averse or the unwillingness to take risks led to the use of a spiral model.
Explanation:
Software development life cycle (SDLC) can be defined as a strategic process or methodology that defines the key steps or stages for creating and implementing high quality software applications.
In SDLC, a waterfall model can be defined as a process which involves sequentially breaking the software development into linear phases. Thus, the development phase takes a downward flow like a waterfall and as such each phase must be completed before starting another without any overlap in the process.
An incremental model refers to the process in which the requirements or criteria of the software development is divided into many standalone modules until the program is completed.
Also, a spiral model can be defined as an evolutionary SDLC that is risk-driven in nature and typically comprises of both an iterative and a waterfall model. Spiral model of SDLC consist of these phases; planning, risk analysis, engineering and evaluation.
What motivated software engineers to move from the waterfall model to the incremental or spiral model is actually due to the following fact;
They needed to develop multiple components in software programs. The ability to overlap the development to be more evolutionary in nature. The need to be more risk-averse or the unwillingness to take risks led to the use of a spiral model.(a) At a simple interest rate of 12% per year, determine how long it will take $5000 to increase to twice as much. (b) Compare the time it will take to double if the rate is 20% per year simple interest.
Explanation:
10000=5000(1.12^x)
2=1.12^x
(log_1.12)(2)=x
x= about 6.1163
10000=5000(1.2^x)
2=1.2^x
(log_1.2)(2)=x
x= about 3.8019
compare them by saying like 20% will be 6.12/3.8 times faster
First Order Logic
Translate into First Order Logic (FOL) the following statements. Then write the negations of the FOL propositions found.
1. All tigers are fast. Domain: animals.
2. Some tigers are fierce and dangerous. Domain: animals.
3. Every prime number is odd. Domain: positive integers.
4. All prime numbers except two are odd. Domain: positive integers.
5. All fruits are either yellow or red. Domain: produce.
6. For every integer number, there exist a bigger integer. Domain: integers.
Answer:
1) ∀x [ Tiger(x) → Fast(x) ]
2) эx [ Tiger (x) ∧ Fierce (x) ∧ Dangerous(x) ]
3) ∀x [ Prime(x) → Odd(x) ]
4) ∀x [ prime (x) ∧ ~Two(x) → Odd (x) ]
5) ∀x [ Fruits(x) → ( yellow(x) ∨ Red(x) ]
6) ∀xэy [ I(x) → greater (y, x) ]
Explanation:
Translating the statements into first Order Logic and their negations
1) All tigers are fast. Domain: animals.
∀x [ Tiger(x) → Fast(x) ]
2) Some tigers are fierce and dangerous. Domain: animals
эx [ Tiger (x) ∧ Fierce (x) ∧ Dangerous(x) ]
3) Every prime number is odd. Domain: positive integers
∀x [ Prime(x) → Odd(x) ]
4) All prime numbers except two are odd. Domain: positive integers
∀x [ prime (x) ∧ ~Two(x) → Odd (x) ]
5) All fruits are either yellow or red. Domain: produce.
∀x [ Fruits(x) → ( yellow(x) ∨ Red(x) ]
6) For every integer number, there exist a bigger integer. Domain: integers.
∀xэy [ I(x) → greater (y, x) ]
Answer:
Answer:
1) ∀x [ Tiger(x) → Fast(x) ]
2) эx [ Tiger (x) ∧ Fierce (x) ∧ Dangerous(x) ]
3) ∀x [ Prime(x) → Odd(x) ]
4) ∀x [ prime (x) ∧ ~Two(x) → Odd (x) ]
5) ∀x [ Fruits(x) → ( yellow(x) ∨ Red(x) ]
6) ∀xэy [ I(x) → greater (y, x) ]
Explanation:
Translating the statements into first Order Logic and their negations
1) All tigers are fast. Domain: animals.
∀x [ Tiger(x) → Fast(x) ]
2) Some tigers are fierce and dangerous. Domain: animals
эx [ Tiger (x) ∧ Fierce (x) ∧ Dangerous(x) ]
3) Every prime number is odd. Domain: positive integers
∀x [ Prime(x) → Odd(x) ]
4) All prime numbers except two are odd. Domain: positive integers
∀x [ prime (x) ∧ ~Two(x) → Odd (x) ]
5) All fruits are either yellow or red. Domain: produce.
∀x [ Fruits(x) → ( yellow(x) ∨ Red(x) ]
6) For every integer number, there exist a bigger integer. Domain: integers.
∀xэy [ I(x) → greater (y, x) ]
Explanation:
10.06 kg of R-134 a at 300 kPa fills a rigid container whose volume is 14 L. Determine the temperature and total enthalpy in the container.The container is now heated until the pressure at 600 kPa. Determine the temperature and total enthalpy when the heating is completed. Use data from the steam tables.
The temperature in the container is what C.
The total energy in the container is what kJ.
The temperature in the container when the heating is completed is what C.
The total energy in the container when the heating is completed is what kJ.
Answer:
fggffgethjbdxvgrsbjb you are my world I see the attached resume
Set up the following characteristic equations in the form suited to Evanss root-locus method. Give L(s), a(s), and b(s) and the parameter, K, in terms of the original parameters in each case. Be sure to select K so that a(s) and b(s) are monic in each case and the degree of b(s) is not greater than that of a(s).
a) s + (1/τ) = 0 versus parameter τ
b) s2 + cs + c + 1 = 0 versus parameter c
c) (s + c)3 + A(Ts + 1) = 0
i. versus parameter A
ii. versus parameter T
iii. versus the parameter c, if possible. Say why you can or can not. Can a plot of the roots be drawn versus c for given constant values of A and T by any means at all.
d) 1 + (kp + k1/s + kDs/Ts + 1)G(s) = 0. Assume that G(s) = A c(s)/d(s), where c(s) and d(s) are monic polynomials with the degree of d(s) greater than that of c(s).
i. versus kp
ii. versus kI
iii. versus kD
iv. versus τ
Answer:
attached below is the detailed solution and answers
Explanation:
Attached below is the detailed solution
C(iii) : versus the parameter C
The parameter C is centered in a nonlinear equation, therefore the standard locus will not apply hence when you use a polynomial solver the roots gotten would be plotted against C
Answer: a(s) is of degree n and b(s) is of degree n-1.
a)Characteristic equation in form suitable for Evans's root-locus method is given by a(s) + b(s)K = 0, where a(s) and b(s) are polynomials of s with real coefficients. Now, given equation can be represented as: s + (1/τ) = 0 => s + (1/τ) = 0s + (1/τ)K = 0=> K = -τs/τ + 0Thus, L(s) = s, a(s) = 1, b(s) = 1 and K = -τ.
b)The characteristic equation is given by:s^2 + cs + c + 1 = 0For the root-locus method, we have to write the characteristic equation in the form a(s) + b(s)K = 0. Since the degree of a(s) is 2, we select K such that the degree of b(s) is also 2, and so b(s) will be monic.s^2 + cs + c + 1 = 0=> (s + c/2)^2 + 1/4 - c^2/4 + c = 0=> s^2 + (2c)s + (1 + c - c^2/4) = 0Now, taking a(s) = s^2 + (2c)s + (1 + c - c^2/4) and b(s) = 1 with K = -1/c^2, we have:a(s) + b(s)K = s^2 + (2c)s + (1 + c - c^2/4) - 1/c^2 = 0
c) The characteristic equation is given by:(s + c)3 + A(Ts + 1) = 0
i. versus parameter A:s = -c is a repeated root of multiplicity 3 when A = 0For s = -c, the characteristic equation becomes:-A(Tc + 1) = 0If A = 0, the characteristic equation will be (s + c)^3 = 0 and will have a repeated root at s = -c with a multiplicity of 3.
ii. versus parameter T:s = -c is a repeated root of multiplicity 3 when T = 0.For s = -c, the characteristic equation becomes:3c^2s + A = 0If A = 0, the characteristic equation will be (s + c)^3 = 0 and will have a repeated root at s = -c with a multiplicity of 3.
iii. versus the parameter c:We cannot draw the root locus of (s + c)3 + A(Ts + 1) = 0 with respect to the parameter c because there is no c term in the characteristic equation; it only contains c cubed.
d) The characteristic equation is given by:1 + (kp + k1/s + kDs/Ts + 1)G(s) = 0Assuming G(s) = Ac(s)/d(s), where c(s) and d(s) are monic polynomials with the degree of d(s) greater than that of c(s), the characteristic equation becomes:
d(s) + kp d(s) + k1 d(s)/s + kDs c(s)/T = 0.
Thus, a(s) = d(s) + k1 d(s)/s and b(s) = kDc(s)/T + kp d(s) with K = -1.
Therefore, a(s) is of degree n and b(s) is of degree n-1.
Learn more about root-locus : https://brainly.com/question/18406313
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