A student must analyze data collected from an experiment in which a block of mass 2M traveling with a speed v0 collides with a block of mass M that is initially at rest. After the collision, the two blocks stick together. What applications of the equation for the conservation of momentum represent the initial and final momentum of the system for a completely inelastic collision between the blocks?

Answer: Kinetic Energy

Explanation:Kinetic energy is the energy of motion. All moving objects have kinetic energy.

Answer:

Kinetic energy

Explanation:

Kinetic energy is energy produced when the object is in motion.

Answer:

[tex]154.44\ \text{m/s}[/tex]

Explanation:

L = Length of guitar string = 0.66 m

Difference of fourth and first harmonic = 351 Hz

v = Wave propagation speed on the guitar strings

So,

[tex]\dfrac{4v}{2L}-\dfrac{v}{2L}=351\\\Rightarrow \dfrac{3v}{2L}=351\\\Rightarrow v=\dfrac{351\times 2\times 0.66}{3}\\\Rightarrow v=154.44\ \text{m/s}[/tex]

The wave propagation speed on the guitar strings is [tex]154.44\ \text{m/s}[/tex].

Answer: hetero i think i dont know

Explanation:

Answer:

When two substances that cannot dissolve each other are mixed, a mixture is formed.

i hope this helps a little bit.

Answer:

please find your answer in the attached picture, along with explanation.

Answer:

i guess it is D because,

y = A sin(wt)

w = [tex]\frac{2\pi }{T}[/tex] and t = 3T/ 2

now, Y = A sin ( [tex]\frac{2\pi }{T} X \frac{3T}{2}[/tex])

so, Y = 0radian

Explanation:

The magnitude of the particle's displacement a time 3T/2 is zero. The correct option is D.

Magnitude is simply "distance or quantity" in the context of physics.

A = amplitude of SHM

T = time period of SHM

At t = 0 s, the position of a particle is, x = A

At t = 3T/2, find the magnitude of the particle's displacement

d = magnitude of displacement of particle at time

t = 3T/2

t = ?

t= t1 + t2 = T + T/2

where

t1 = T

t2 = T/2

Now, in time t1 = T, the particle will return to its initial position as the particle completes one full cycle of motion in time T.

Therefore, after time t1 = T, the position of the particle is given by x = A, and the total displacement by the particle is 0.

Now in time

t2=T/2

The particle will go to another extreme position, given by x = -A.

Therefore, the net displacement of particles in time

3/T2

is given by:

d=0+(−A)=−A

d=−A

Therefore, the correct option is D. 0.

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Answer:

The distance between the helicopter and the man is increasing at a rate of 50.622 feet per second.

Explanation:

First, we create a geometric diagram representing the situation between man (point O),  helicopter (point P) and helipad (point H). The distance between man and helicopter is represented by Pythagorean Theorem:

[tex]x^{2}+y^{2} = r^{2}[/tex] (1)

Where:

[tex]x[/tex] - Distance between man and helipad, in feet.

[tex]y[/tex] - Distance between helipad and helicopter, in feet.

[tex]r[/tex] - Distance between man and helicopter, in feet.

By Differential Calculus, we derive an expression for the rate of change of the distance between man and helicopter ([tex]\dot r[/tex]), in feet per second:

[tex]2\cdot x\cdot \dot x + 2\cdot y\cdot \dot y = 2\cdot r\cdot \dot r[/tex]

[tex]\dot r = \frac{x\cdot \dot x + y\cdot \dot y}{r}[/tex]

[tex]\dot r = \frac{x\cdot \dot x + y\cdot \dot y}{\sqrt{x^{2}+y^{2}}}[/tex] (2)

Where:

[tex]\dot x[/tex] - Rate of change of the distance between man and helipad, in feet per second.

[tex]\dot y[/tex] - Rate of change of the distance between helicopter and helipad, in feet per second.

If we know that [tex]x = 40\,ft[/tex], [tex]y = 129\,ft[/tex], [tex]\dot x = 0\,\frac{ft}{s}[/tex] and [tex]\dot y = 53\,\frac{ft}{s}[/tex], then the rate of change of the distance between man and helicopter is:

[tex]\dot r = \frac{x\cdot \dot x + y\cdot \dot y}{\sqrt{x^{2}+y^{2}}}[/tex]

[tex]\dot r = 50.622\,\frac{ft}{s}[/tex]

The distance between the helicopter and the man is increasing at a rate of 50.622 feet per second.

Answer: A. It gives off a range of wavelengths of electromagnetic radiation that depends on its temperature.

Explanation: Quizzed

Answer:

velocity ratio

mechanical advantage

Relative density

Answer:

1-1=0

Explanation:

ahriqqwertyuioo

Answer:

the maximum voltage induced in the coil is 2.574 × 10⁻⁵ V

Explanation:

Given the data in the question;

Number of turns N = 10

major axis Ma = 13 cm = 0.13 m

a = 0.13/2 = 0.065 m

Minor axis Mi = 6 cm = 0.06 m

b = 0.06/2 = 0.03 m

we know that; 1 RPM = 0.10472 rad/s

rate of rotation R = 73rpm = 7.64 rad/s

Magnetic field = 55 uT

we know that, Area of ellipse = π × a × b

we substitute

A = π × 0.065 m × 0.03 m

A = 0.006126 m²

so

Maximum Voltage = N × Area × Magnetic field × rate of reaction

we substitute

Maximum Voltage = 10 × 0.006126 × ( 55 × 10⁻⁶ ) × 7.64

Maximum Voltage = 2.574 × 10⁻⁵ V

Therefore, the maximum voltage induced in the coil is 2.574 × 10⁻⁵ V

Answer:

How much power is required to pull a sled if you use 60J of work in 5 seconds? ... Misfortune occurs and Renatta and her friends find themselves getting a workout. They apply a cumulative force of 1080 N to push their car 218 m to the ... Calculate the amount of work done when moving a 567N crate a distance of 20 meters.

Explanation:

Misfortune occurs and Renatta and her friends find themselves getting a ... They apply a cumulative force of 1080 N to push the car 218 m to the nearest fuel ... Write down what they give you. ... Determine the work done by Lamar in deadlifting 300 kg to a height of 0.90 m ... Work = Force x Distance = Joules (force = weight).

Answer:

love is a feeling that you get for people that you care about.

Explanation:

Answer:

Love is a feeling of affection for someone, when you adore somebody.

I wish true love and soul mates were real ( •_•)

Answer:

Acceleration of the car = 5.51 m/s²

Explanation:

Given:

Initial speed of car = 0 m/s

Final speed of car = 27 m/s

Time taken by car = 4.9 seconds

Find:

Acceleration of the car

Computation:

Using first equation of motion

v = u + at

Where

v = Final velocity

u = Initial velocity

t = Time taken

a = Acceleration

So,

v = u + at

27 = 0 + a(4.9)

a(4.9) = 27

a = 5.51 m/s²

Acceleration of the car = 5.51 m/s²

Answer:

Hello! Your answer would be, O False

Explanation:

Hope I helped! Brainiest plz!♥ Have a nice morning! Hope you make a 100%! -Abby

Answer:

False is the correct answer.

Explanation:

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Answer:

dasd

Explanation:

dsdas

[tex]\mathfrak{\huge{\orange{\underline{\underline{AnSwEr:-}}}}}[/tex]

Actually Welcome to the concept of resistors,

The equivalent circuit is given as,

1/Rp = 1/3 + 1/6 + 1/9

1/Rp = 6+3+2/18

1/Rp = 11/18

Rp = 18/11 ==> 1.63 ==> 1.6 ohms

hence the equivalent resistance of the circuit is 1.6 ohms

The equivalent resistance of the circuit is 1.6Ω. The correct option is B.

Ohm’s law state that ” At constant temperature, the current (I) flowing through a conductor is directly proportional to the potential difference(V) across the two endpoints of the given conductor.”

I.e V ∝ I

V=IR

Where V= potential difference across the conductor.

I = current flowing through the conductor.

R= constant pf proportionality i.e resistance which unit is ohm(Ω).

There are two ways we can connect the resistors.

(i) series connection

If a number of resistors are said to be connected in series When the same current (I) flows through them.

Let R1, R2, and R3 be the resistors connected in series.

Then the R equivalent is

Req=R1+R2+R3

(ii) parallel connection

A number of resistors are said to be connected in parallel when the same potential difference(V) exists across each of them.

Let R1, R2, and R3 be the resistors connected in parallel.

Then the R equivalent is

1/Req=1/R1+1/R2+1/R3

In this question,

The three resistance connected in parallel by applying the above formula we get,

1/Req=1/R1+1/R2+1/R3

1/Req = 1/3 + 1/6 + 1/9      .................  (∵R1=3Ω,R2=6Ω AND R3=9Ω)

1/Req =11/18

Req=18/11

Req=1.6363Ω

Req≈1.6Ω

Therefore, The equivalent resistance of the circuit is 1.6Ω.

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Answer:

The amount of time needed to stop the marble is much less than the amount of time needed to stop the basketball.

Explanation:

To explain this question we can use the equation:

Change in momentum = Force x Time

Where momentum = mass x Velocity

In the case of the basketball, it has a much larger mass than the marble, meaning it has much more momentum than the marble. This means that with the same amount of force, it will need much more time to stop.

Likewise, the marble has less mass than the basketball meaning it will have less momentum. This means that with the same amount of force, it will require less time to stop.

Logically this also makes sense if we think about it in a real life scenario. If we try to stop a marble with our finger, we can stop it much faster then if we try to stop a basketball with our finger because of the difference in mass between the two objects, therefore the marble will require much less time to be stopped than the basketball.

Hope this helped!

I dont know you could start by asking your teacher, parent, and or siblings.

Ps the last part was a joke they never help.

Answer:

I think that perihelion is the point of the Earth's course that is close to the Sun. And i'm sure that aphelion in short is astronomy or otherwise the point in the orbit of a planet.

Explanation:

Hope this helps :)

Answer:

Explained below.

Explanation:

For a boat or any object to float on water, it's density must be less than that of water.

Now, when the maximum capacity of people to be carried by the boat is exceeded, it's possible that the maximum mass of people will also be exceeded depending on the mass of the people in the boat.

Now, we know that; density = mass/volume.

Thus, the higher the mass of the people, the higher the density and the higher the density, the more likely it is to be above that of water and the more likely it is to sink.

Explanation:

The speed of light in vacuum is the same by all observers (2nd Principle). You would find that the starlight passes you at c. This is more than a thousand times faster than existing space craft.

According to all observers, the velocity of light in a vacuum will be the same (2nd Principle). You'd discover that the starlight is passing you at c. Compared to current spacecraft, this really is a thousand times faster.

The amount of the shift in approach per unit of time or the size of the displacement over time for an object can be used to describe speed, which would be a scalar quantity in everyday language and kinematics.

The maximum speed that can be maintained when a time period grows closer to zero is the starting speed.

By dividing the object's distance traveled by the duration of the interval, the mean pace of the object for the given period of time is calculated. Speed and velocity are not always the same thing.

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Answer:

the flux through the plane is zero.

Explanation:

Answer:

The small intestine absorbs most of the nutrients in your food, and your circulatory system passes them on to other parts of your body to store or use. Special cells help absorbed nutrients cross the intestinal lining into your bloodstream.

Explanation:

Answer:

W' = 1.66 x 10¹⁴ N

Explanation:

First, we will calculate the mass:

[tex]W = mg[/tex]

where,

W = weight on earth = 690 N

m = mass = ?

g = acceleration due to gravity on earth = 9.8 m/s²

Therefore,

[tex]m = \frac{W}{g} = \frac{690\ N}{9.8\ m/s^2}\\\\m = 70.4\ kg[/tex]

Now, we will calculate the value of g on the neutron star:

[tex]g' = \frac{GM}{R^2}[/tex]

where,

g' = acceleration due to gravity on the surface of the neutron star = ?

G = Gravitational Constant = 6.67 x 10⁻¹¹ N.m²/kg²

M = Mass of the Neutron Star = 1.99 x 10³⁰ kg

R = Radius of the Neutron Star = 15 km/2 = 7.5 km = 7500 m

Therefore,

[tex]g' = \frac{(6.67\ x\ 10^{-11}\ N.m^2/kg^2)(1.99\ x\ 10^{30}\ kg)}{(7500\ m)^2}\\\\g' = 2.36\ x\ 10^{12}\ m/s^2[/tex]

Therefore, the weight on the surface of the neutron star will be:

[tex]W' = mg'\\W' = (70.4\ kg)(2.36\ x\ 10^{12}\ m/s^2)[/tex]

W' = 1.66 x 10¹⁴ N

Answer:

The car must be moving away from the person.

Explanation:

From Doppler's Effect, we know that when a sound source moves towards a stationary observer, the apparent frequency of that sound increases. While the apparent frequency decreases if the source moves away from the stationary observer.

The audible range of frequencies for a human ear is 20 Hz to 20000 Hz. Therefore, in order for the sound of a loud speaker to be audible for the person, the frequency must decrease below 20000 Hz.

Due to this reason, the car must be moving away from the person.

Answer:

Explanation:

The magnitude of the net force acting on an object is equal to the mass of the object multiplied by the acceleration of the object, as shown in this formula. We find its magnitude using the Pythagorean Theorem or the distance formula, and we find its direction using the inverse tangent function. Given a position vector →v=⟨a,b⟩, the magnitude is found by |v|=√a2+b2. The direction is equal to the angle formed with the x-axis, or with the y-axis, depending on the application.

Answer:

Distance is 300 and displacement is 100

Explanation:

Distance= 100+100+100=300

Displacement=100

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Answer:

4.8 m/s

Explanation:

Given: angular velocity of wheel ω = 2.5 rev/sec

radius r = 30 cm

length of arrow = 24 cm

For arrow to pass through spinning ring it has to pass between any two spokes of the wheel.

angle between two spokes = π/4

time taken by a spook to reach the position of adjacent spoke t =θ/ω

=  π/4/(2.5×2π) = 1/20 sec

for the arrow to pass through the spokes of the wheel it should take time t <1/20 sec to pass through the wheel

a) therefore, minimum speed = (24/100)/(1/20) = 4.8 m/s