Answer:
The student squeezed the clothespin less the second time because the muscles in his hand began to fatigue
Explanation:
The image shows landforms in Monument Valley, Utah.
Which correctly lists the three features shown in the photo?
folds, strike-slip faults, and anticlines
anticlines, synclines, and folds
synclines, normal faults, and strike-slip faults
normal faults, folds, and anticlines
The correctly lists the three features shown in the photo is folds, strike-slip faults, and anticlines.
What is the difference between folds and failures?Modern folds are those that emerged recently (on the scale of geological periods), that is, in the Tertiary Period (between 65 million and 2.5 million years ago). Faults are geological structures that originate from vertical (top-down) or inclined internal forces.
The transcurrent fault – also called horizontal fault – occurs when there is displacement in the horizontal plane between the two blocks, being more common in zones where two tectonic plates meet, when these also move horizontally.
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Answer: folds, strike-slip faults, and anticlines. (A)
Explanation: Got it right on my exam on Edge.
Puck 1 is moving 10 m/s to the left and puck 2 is moving 8 m/s to the right. They have the same mass, m.
a. What is the total momentum of the system before the collision? (Answer in terms of the mass, m.) (0.5 points)
b. What is the total momentum of the system after the collision? (Answer in terms of the mass, m.) (0.5 points)
c. Write puck 1's velocity after the collision in component form. (1 point)
d. What is the y-component of puck 2's velocity after the collision? (1 point)
e. What is the x-component of puck 2's velocity after the collision? (1 point)
f. At what angle does puck 2 move after the collision? Determine the angle and draw it on the diagram. (1 point)
g. What is the magnitude of puck 2's velocity after the collision? (1 point)
Answer:
(a) the total momentum of the system before the collision = -2m kg.m/s.
(b) the total momentum of the system after the collision = -2m kg.m/s.
(c) puck 1's velocity after the collision in component form = (5.44 i, 2.54 j)
Explanation:
Given;
mass of Puck 1 , = m
mass of Puck 2, = m (since they have the same mass m)
initial velocity of Puck 1, u₁ = 10 m/s to the left
initial velocity of Puck 2, u₂ = 8 m/s to the right
Let the rightward direction be positive direction
Let the leftward direction be negative direction
(a) the total momentum of the system before the collision;
P₁ = (initial momentum of Pluck 1) + (initial momentum of Pluck 2)
P₁ = (-mu₁) + mu₂
P₁ = mu₂ - mu₁
P₁ = m(u₂ - u₁)
P₁ = m(8 - 10)
P₁ = -2m kg.m/s
(b) the total momentum of the system after the collision;
Based on the principle of conservation of linear momentum, the total momentum before collision is equal to the total momentum after collision.
Thus, the total momentum of the system after the collision is -2m kg.m/s.
(c) puck 1's velocity after the collision in component form
[tex]v = (v_x, v_y)\\\\v = (vcos \theta , vsin \theta)\\\\v = (6cos 25^0 , 6sin25^0)\\\\v = (5.44i, 2.54j)m/s[/tex]
Where did all the golden carals go?
Answer:
Thanos went *snap*
Explanation:
When balancing a chemical equation, can a coefficient within a chemical equation be adjusted to
balance the chemical equation?
The answer to a multiplication problem is called the?
Answer:
product
Explanation:
Answer:
product
Explanation:
You find the product when you multiply two or any number of factors.
ANSWER QUICK 30 POINTS
What force controls the movement of the planets around the sun, holds together stars grouped in galaxies, and galaxies grouped in clusters? Thoroughly explain your answer, making sure to include an example and describe how this force keeps planets in orbit. Make sure to write at least 3-5 sentences and proper conventions (spelling, grammar, punctuation, etc.) to respond. Put all answers in your own words
Answer:
Gravity controls the movement of the planets around the sun, holds together stars grouped in galaxies, and galaxies grouped in clusters. The Universal Law of Gravitation depends on two things. First it depends on mass of each object and the second factor is the distance between two objects. If the mass of one object is Larger, the gravitational pull towards it will be larger and the smaller distance, the larger the gravitational pull will be between the objects. Therefore the Larger planets have more moon and the inner planets have less.
Explanation:
Calculate speed...
D=40 m
T=10 s
a
40 m/s
b
400 m/s
c
4 m/s
Answer:
c
Explanation:
speed=distance÷time
40÷10=4
The eagles suck, so do the giants and the jets and jaguars are irrelevant
anyone wanna argue
Naw ur pretty accurate, heck collage is the only football worth watching most the time. Hook'um horns!
Picking up a puppy is easy, but picking up a large horse is difficult. *
1st law
2nd law
3rd law
Answer:
1st
Explanation:
It is because the horse is heavier
Does the planet exert a torque on the meteoroid with respect to the center of mass of the planet? Why or why not?
Answer:
yes
Explanation:
because the planet exerts a centripetal force on the meteorold
No, the planet doesn't exert a torque on the meteoroid with respect to the center of mass of the planet.
What is a Torque?
This is defined as a form of twisting force which is responsible for rotation of objects.
The planet doesn't exert a torque on the meteoroid with respect to the center of mass of the planet because it exerts a force on the meteoroid parallel to its position vector relative to the center of mass of the planet.
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What happens to
light when it is
transmitted?
When light is transmitted through an object things can happen. The light could be reflected by the thing. Or it could be absorbed by the object. Saying this based on what I know.
7. Mac and Tosh are arguing about the track design. Mac claims that the car is moving fastest at point F because it is furthest along the track Tosh disagrees, claiming that the car moves fastest at point F because point F is at the lowest height Who do you agree with? Make a modification of the track design for point F and gather some evidence to support one claim or the other. Then discuss what changes you made, what observations were made, and the reasoning that supports one of the claim of either Mac or Tosh.
Answer:
Tosh is correct.Swap the locations of points B and F on the track and gather speed data. If Mac is correct, the speed at F (closer to the start) should be lower. (It will not be, confirming Tosh's claim.)Explanation:
The total energy of the car is continuously being exchanged between potential energy and kinetic energy as the car moves along the track. Neglecting energy loss due to friction, the kinetic energy will be greatest when the potential energy is least, at the lowest point on the track. As a consequence we agree with Tosh that the speed will be greatest at F because it is the lowest point.
__
If the track were modified to move the lowest point nearer the start, say by interchanging points B and F, then data could be gathered to show whose theory is supported. The evidence needed is the speed of the car at the new location of point F. Tosh's argument is supported if the speed at the new point F is substantially the same.
A 30.0 kg box is placed on a 3.00 m tall shelf. What how much work was done on the box?
Answer:
W = 882.9[J]
Explanation:
In order to be able to calculate the work, we must first calculate the force necessary to lift the box. Since the necessary force is equivalent to the weight of the box, we can determine the weight of the box by means of the product of mass by gravitational acceleration.
[tex]w = m*g\\[/tex]
where:
w = weight [N]
m = mass = 30 [kg]
g = gravity acceleration = 9.81 [m/s²]
[tex]w = 30*9.81\\w = 294.3 [N][/tex]
Now, the work can be calculated multiplying the force (weight) by the distance [m]
[tex]W = w*d\\W = 294.3*3\\W=882.9[J][/tex]
A body with mass 2 kg absorbs heat 418.4J when its temperature raises from 293K to 343K . What is the specific heat of the body?
Answer:
C M (change in T) = heat absorbed thermal equation for heat gained
C = 418.4 J / (2 kg * 50 deg K) = 4.184 J / kg * deg K specific heat
Note: 1 gm =.001 kg
So C = .004184J / gm * deg K
Also, 1 J = .239 cal so in conventional terms
C = .001 cal / gm deg K (very low, water would be 1 cal / gm deg C
Use the equation below to answer questions (14-21). C12H22O11(s) → 12C(s) + 11H2O(g) 14)The left side of the chemical equations is the _______________________. 15)List the coefficients of the reactants ____________________ What type of chemical reaction is this equation? ________________________________ 16)The number 11 is called a ________________ 17)How many atoms in oxygen of the reactants ______________ 18)The right side is called the ________________ 20)List the four states of matter: ________________________________________________ 21)What are the number of atoms on the product side?
Answer:
14) Reactant
15) 1 .Precipitation reaction equation
16) The coefficient
17) 6.6242 × 10²⁴ atoms of oxygen
18) The product
20) The four states of matter are;
a) Solids
b) Liquids
3) Gas
4) Plasma
21) The total number of atoms in the product is 2.7099 × 10²⁵ atoms.
Explanation:
14) The left side of the chemical equation is the reactant
15) The coefficient is the number in font of the formula, here, the coefficient of the reactant C₁₂H₂₂O₁₁ is 1 .This is a precipitation reaction equation
16) The number 11 in front of the formula, H₂O, is called a coefficient
17) On mole of a substance is defined as containing one Avogadro's number, [tex]N_A[/tex] of molecules
[tex]N_A[/tex] ≈ 6.022 × 10²³ mol⁻¹
In the reactant, C₁₂H₂₂O₁₁, there are 11 elements of oxygen in one mole of the reactants, which gives 11 × 6.022 × 10²³ = 6.6242 × 10²⁴ atoms of oxygen in one mole of the reactants
18) The right side of the chemical equation is called the product
20) The four states of matter are;
a) Solids
b) Liquids
3) Gas
4) Plasma
21) The number of elements on the product side are;
12 Carbon + 22 Hydrogen + 11 Oxygen = 45 Elements total
However, given that there are 12 moles of carbon, we have;
12 × 6.02 × 10²³ = 7.2264 × 10²⁴ atoms of carbon
For hydrogen, we have;
22 × 6.02 × 10²³ = 1.32484 × 10²⁵ atoms of hydrogen
For oxygen, we have;
11 × 6.02 × 10²³ = 6.6242 × 10²⁴ atoms of oxygen
The total number of atoms in the product is 7.2264 × 10²⁴ + 1.32484 × 10²⁵ + 6.6242 × 10²⁴ = 2.7099 × 10²⁵ atoms.
A ball is thrown with 50J of kinetic energy, it hits a target which moves with 30J of kinetic energy, how much energy goes to the thermal store of the surroundings?
Answer:
The energy that will go will for thermal store of the surroundings is 20 J.
Explanation:
Given;
kinetic of the thrown ball, K.E₁ = 50 J
kinetic energy used to move the target, K.E₂ = 30 J
The excess energy that will go will for thermal store of the surroundings;
ΔK.E = K.E₁ - K.E₂
ΔK.E = 50J - 30J
ΔK.E = 20 J
Therefore, the energy that will go will for thermal store of the surroundings is 20 J.
Appliances connected so that they form a single pathway for
charges to flow are connected in a(n)
A. series circuit.
B. parallel circuit.
C. off circuit.
D. open circuit
Appliances connected so that they form a single pathway for charges to flow are connected in a(n)
Answer:A. Series circuit
#CARRYONLEARNING #STUDYWELLAppliances connected so that they create a single pathway for charges to flow are connected in a series circuit. Therefore, option (A) is correct.
What is the resistance of resistors connected in series?In a series combination of appliances, they are connected end-to-end. Consider two resistors, R₁ and R₂ which are connected in a series combination then their effective resistance can be given by:
Total Resistance of the series circuit, R = R₁ + R₂
In a series combination, the current flows through one appliance and then through another appliance. The same current flows through each appliance in one direction. The total voltage of the series circuit is equal to the sum of all the voltage drops across all appliances.
A potential difference of the series circuit, V = V₁ + V₂
Therefore, when appliances are connected in a series circuit they form a single pathway for charges to flow.
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How does attachment affect exploration? Be sure to include findings from both Harlow and Ainsworth in your response.
Answer:
Attachment can affect many things. When you go back to the experiment, you see that they are testing 4 monkeys. They want to see if they would go to the cloth mother or the wire mother. But that is just the base of the experiment. Once the monkeys pick the mother, they have attached themselves to the mother, because animals will pick what is mother, because once you are born, the "hunger games" begin in the wild. They will stay by their mother's side until they are grown and ready to go on their own. When you think about this whole experiment, you know that this experiment was designed as a test of the relative importance of contact comfort. They could have picked any animal for this, and the outcome would have been very similar because as a baby you need to find things that you trust and that is your mother.
Explanation:
A 10.0kg box sits at rest on ramp that has an incline of 20.0° from the horizontal. What is the force of gravity acting on the box?
A. -98.0N
B. 98.0N
C. -92.1N
D. -33.5N
Answer:
98.0N
Explanation:
a.) Determine the work done by Zach on the bull.
Explanation:
Work done is a physical quantity that is defined as the force applied to move a body through a particular distance.
Work is only done when the force applied moves a body through a distance.
Work done = Force x distance
The maximum work is done when the force is parallel to the distance direction.
The minimum work is done when the force is at an angle of 90° to the distance direction.
So to solve this problem;
multiply the force applied by Zack and distance through which the bull was pulled.
A north magnetic pole is facing another north magnetic pole with a distance x
. If the distance between the poles becomes 1/2x
, what happens to the magnitude of the field energy between them?(1 point)
The field energy will gradually dissipate until it reaches zero.
The field energy will remain unchanged.
The field energy will decrease.
The field energy will increase.
Answer:
Option 4 (The field energy will increase) is the right response.
Explanation:
Whereas the power kept secure in either an attribute has been collected, the artifact would be decided to push throughout the straight line that induces the electrostatic repulsion to greatly reduce. This same power generated will indeed be significantly decreased as well as supplanted by the power generation of the motion. Sometimes when magnetic poles figure together including poles, this same energy rendered inaccessible would then greatly reduce if those who keep moving off from each other. So our policy requires that perhaps the magnets would be tried to push throughout a position that reduces the energy consumed. That is, they're being allowed to force apart.All those other alternative solutions aren't closely linked to the example in question. Therefore the choice above is the right one.
On Earth, a spring stretches by 5.0 cm when a mass of 3.0 kg is suspended from one end.
The gravitational field strength on the Moon is
1/6 of that on Earth.
Which mass, on the Moon, would stretch the spring by the same extension?
Reasons too :(
igcse physics
Answer:
Mass = 18.0 kg
Explanation:
From Hooke's law,
F = ke
where: F is the force, k is the spring constant and e is the extension.
But, F = mg
So that,
mg = ke
On the Earth, let the gravitational force be 10 m/[tex]s^{2}[/tex].
3.0 x 10 = k x 5.0
30 = 5k
⇒ k = [tex]\frac{30}{5}[/tex] ................ 1
On the Moon, the gravitational force is [tex]\frac{1}{6}[/tex] of that on the Earth.
m x [tex]\frac{10}{6}[/tex] = k x 5.0
[tex]\frac{10m}{6}[/tex] = 5k
⇒ k = [tex]\frac{10m}{30}[/tex] ............. 2
Equating 1 and 2, we have;
[tex]\frac{30}{5}[/tex] = [tex]\frac{10m}{30}[/tex]
m = [tex]\frac{900}{50}[/tex]
= 18.0
m = 18.0 kg
The mass required to produce the same extension on the Moon is 18 kg.
Answer:
18 kg
Explanation:
weight (N) = mass (kg) × gravitational acceleration (m/s²)force (N) = k (spring constant) × extension (m)On Earth, acceleration of gravity is 10 m/s²
weight = 3.0 (kg) × 10 (m/s²)weight = 30 (N)Since weight is a force, the force is 30 N. The value of spring constant is unknown
30 (N) = k × 5 (m)k = 6 (m/N)Spring constant is 6. Now let's find the mass on the Moon
mass (kg) × gravitational acceleration (m/s²) = k (spring constant) × extension (m)Gravitational acceleration of the moon is 1/6 of that on Earth. Earth's g = 10, so Moon's g = 10/6
m × 10/6 = 6 × 5m = 30/(10/6)m = 18The mass is 18 kg
what are the three laws of motion and examples
Explanation:
In Newton's 1 law, an object will not change its motion unless a force acts on it.
The motion of a ball falling down through the atmosphere, or a model rocket being launched up into the atmosphere are both examples of Newton's first law.
In Newton's 2 law, the force on an object is equal to its mass times its acceleration.
Riding your bicycle is a good example of this law of motion at work. ... Your leg muscles pushing pushing on the pedals of your bicycle is the force. When you push on the pedals, your bicycle accelerates.
In Newton's 3 law, when two objects interact, they apply forces to each other of equal magnitude and opposite direction.
For example, when you jump, your legs apply a force to the ground, and the ground applies and equal and opposite reaction force that propels you into the air.
PLEASE HELP ASAP!!!!!
Carrie pulls a 41.5 kg bin across the floor of her garage using a rope that is attached to the bin. She pulls with a force of 138 N, at an angle of 28.0° above horizontal. The coefficient of kinetic friction between the floor and the box is 0.290 . What is the acceleration of the box?
Answer: 0.81N
Explanation: Fwx = .165x 9.81 Silicon 30 = 0.81N
3 conditions that may be
required for a chemical reaction to occur.
a) Las siglas M. RU significan
Answer:
Ver la explicación a continuación.
Explanation:
En física estas siglas significan movimiento rectilíneo uniforme, es decir es el tipo de movimiento donde la velocidad es constante. La velocidad no cambia con el tiempo.
Este tipo de movimiento se puede describir con la siguiente ecuación.
[tex]x=x_{0}+v*t[/tex]
Donde:
x = posición final [m]
xo = posición inicial [m]
v = velocidad [m/s]
t = tiempo [s]
A friend tells you that objects with more mass fall faster because they
have a stronger gravitational pull to Earth. How can you show your friend
that this is not true?
Answer:
by throwing heavy mass and less mass in vacuum simultaneously.
If you put something like a piece of cardboard between a magnet and an iron nail, the magnet still holds the nail in place, even though the magnet is not touching the nail. Explain how that happens. Use the word induce in your response.
Answer:
A magnet has a field having lines of force around it that moves through the air which is a nonpermeable medium that allows the passage of magnetic field lines of force. The cardboard is a similar nonpermeable medium and the magnetic lines of force pass through to induce magnetism in the iron nail which is a ferromagnetic material that becomes magnetized by the magnetic field from the magnet
The induced magnetism in the iron nails causes the reverse poles to form in the iron with the iron domain's induced north pole pointing in the direction of the south pole of the magnet and vice versa
The iron nail is then attracted to the magnet as like poles attract, thereby holding the iron nail in place with the cardboard in between, without direct contact between the nail and the magnet as the cardboard prevents the magnet from touching the iron nail held in place
Explanation:
Space questions
Please help
Answer:
(1) The relationship between the altitude height, 'h', and the orbital speed, [tex]v_{orbit}[/tex], of the satellite is an inverse relationship
[tex]v_{orbit}[/tex] = 1/(h + R)
(2) The height of the satellite, is approximately 24,442 meters
(3) Please find attached the drawing showing the two lines that indicate the direction of the gravitational force on the satellites created with Microsoft Visio
Explanation:
(1) From the given data table, as the altitude increases, the orbital velocity decreases, therefore, the relationship between altitude, 'h', and orbital velocity, '[tex]v_{orbit}[/tex]', is an inverse relationship which can be expressed as follows;
[tex]v_{orbit} = \sqrt{\dfrac{G \cdot M}{r} }[/tex]
Where;
G = The universal gravitational constant
M = The mass of the Earth, or planet about which the satellite orbits
r = The distance between the center of the planet and the satellite = h + R
R = The radius of the planet
When [tex]v_{orbit}[/tex] = 27,500, h = r - R = 1000
We have;
[tex]v_{orbit}[/tex]² ∝ 1/r
[tex]v_{orbit}[/tex]² = k/r = k/(R+ h)
When, [tex]v_{orbit}[/tex]² = 27,500² = 756,250,000
r = h + R = 1000 + R
∴ 756,250,000 = k/(1000 + R)
(1,000 + R) × 756,250,000 = k
When, [tex]v_{orbit}[/tex]² = 18,000² = 324,000,000
r = h + R = 10,000 + R
∴ 324,000,000 = k/(10,000 + R)
324,000,000 = ((1,000 + R) × 756,250,000)/(10,000 + R)
∴ 324,000,000×(10,000 + R) = (1,000 + R) × 756,250,000
R × (756,250,000 - 324,000,000) = 324,000,000×10,000 - 1,000 × 756,250,000
R = (324,000,000×10,000 - 1,000 × 756,250,000)/(756,250,000 - 324,000,000) = 5746.09600925
R = 5,746.09600925
k = (1,000 + R) × 756,250,000 = (1,000 + 5,746.09600925) × 756,250,000 = 5.1017351 × 10¹²
k = 5.1017351 × 10¹²
(2) When, [tex]v_{orbit}[/tex] = 13,000 m/s, we have;
13,000² = 5.1017351 × 10¹²/(5,746.09600925 + h)
∴ 5,746.09600925 + h = 5.1017351 × 10^(12)/(13,000²) = 30187.7816568
h = 30187.7816568 - 5,746.09600925 = 24,441.6856476
The height of the satellite, h ≈ 24,442 meters
(3) Please find attached the drawing showing the two lines indicating the direction of the force of gravity exerts on the satellites created with Microsoft Visio.
16. If a car starts from rest and reaches a velocity of 50 m/s in 8 seconds, what was the
acceleration?
Answer:
The answer is (60 mph - 0 mph) / 8s = (26.8224 m/s - 0 m/s) / 8s = 3.3528 m/s 2 (meters per second squared) average acceleration. That would be 27,000 miles per hour squared.