A student states that a triangle can be formed with side lengths 3 in, 5 in, and 9 in. Is the student correct? why, or why not? yes, because 3 + 5 < 9 yes, because 3 + 9 > 5 no, because 3 + 9 > 5 no, because 3 + 5 < 9.

The simplified expression to represent the number of members this year is 1.15m

An expression simply refers to the mathematical statements which have at least two terms which are related by an operator and contain either numbers, variables, or both.

From the information, the membership in the volunteers Club increased by 15% from last year. If the number of members last year was m.

The number of members will be:

= Old members+ Increase in members

= m + (15% × m)

= m + 0.15m

= 1.15m

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Answer:

below

Step-by-step explanation:

Rate =  4/5 mi / 2/5 hr =  2 mi /hr

3/4 hr for lunch

20 miles / 2 miles/hr   + 3/4 hr =  10 3/4 hr to hike 20 miles with a lunch

Answer: 6x(-x+3)

Step-by-step explanation:

You can factor out the 6 and x. -6x^2 divided by 6x = -x, and 18x divided by 6x = 3. So the answer is 1. 6x(-x+3)

Answer:

-6x^2+18x

-6x^2-18x

6x^2+18x

-6x^2+108x

Step-by-step explanation:

1.

6x(-x+3)

6x(-x)+6x(3)

-6x^2+18x

2.

-6x(X+3)

-6x(X)+-6x(3)

-6x^2-18x

3.

x(6x+18)

x(6x)+x(18)

6x^2+18x

4.

6(-x^2+18x)

6(-x^2)+6(18x)

-6x^2+108x

Hopes this helps please mark brainliest

Answer:

Step-by-step explanation:

3y+6-4x=0

3y-4x=0-6

3y-4x=-6

y-4x=6/3

y-4x=2

y-x=2/4

y-x=0.5

The equation of the required perpendicular line is y = (-5/4)x - 30.

We are given an equation. The equation is linear in nature. The equation represents a straight line. The equation of the given straight line is y = (4/5)x + 23. We need to find the equation of the straight line that is perpendicular to the given line and passes through the point that has coordinates (-40, 20).

The slope of the given line is 45. Let the slope of the required perpendicular line be represented by the variable "m". The slope of the perpendicular line must be the negative reciprocal of the slope of the given line.

m = -1/(4/5)

m = -5/4

The equation of the required line is of the form y = mx + c.

y = (-5/4)x + c

We know that this line passes the point (-40, 20).

20 = (-5/4)(-40) + c

20 = 50 + c

c = -30

Hence, the equation of the required line is y = (-5/4)x - 30.

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Hey there! I explained and wrote everything on paper since it's hard to type so you can view the pic uploaded! Hope it helps, if you have any doubts, please feel free to ask :)

The numbers are inserted into the tree and shown in the below diagrams.

Given that,

Put these numbers into a 2-3-4 tree: 10, 15, 20, 40, 60, 80, 90, 100, 30, 70, and 50.

Binary Tree Data Structure: What is it?

A Binary Tree is a Tree data structure with two children or less. We typically refer to them as the left and right child since each element in a binary tree can only have two children.

Representation of a Binary Tree

A pointer to the topmost node of a binary tree serves as its representation. The root's value is NULL if the tree is empty.

The following components are found in a binary tree node:

Data

Pointer to left child in data

Pointer to the right-hand child

Thereforer, The numbers are inserted into the tree

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The question was incomplete. Check below the complete question.

insert 10, 15, 20, 40, 60, 80, 90, 100, 30, 70, and 50 into a 2-3-4 tree and select the correct answer

Correlation is a bi-variate analysis that measures the strength of association between two variables and the direction of the relationship.

What is bi-variate analysis?

Bivariate analysis is one in every of the only kinds of quantitative (statistical) analysis. It involves the analysis of 2 variables (often denoted as X, Y), for the aim of deciding the empirical relationship between them.

Main Body:

The correlation coefficient's value ranges from +1 to -1. the entire degree of correlation between the 2 variables is indicated by a worth of one. The association between the 2 variables are weaker because the parametric statistic price approaches zero.

Hence correlation investigate linear association between two variables.

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Kirk will drive 15 kilometer east  to get back to his home

The problem will be solved using basic addition operator and subtraction

Let the given information be represented as follows

he drives 15 kilometers west = 15 W

45 kilometers east = 45 E

75 kilometers west = 75 W

Kirk will drive East to get home = ?

since the distances are all in the horizontal direction we add up the west directions and subtract the east direction

15 W + 75 W = 45 E + ?

90 W = 45 E + ?

? = 90 - 45

? = 45 E

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The number nickel is 12, and the number dimes are 8 if Jill has 20 coins, consisting of nickels and dimes totaling $1.40.

It is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.

If in the linear equation, one variable is present, then the equation is known as the linear equation in one variable.

It is given that:

Jill has 20 coins, consisting of nickels and dimes totaling $1.40.

Let the number of nickels be n, and the number of dimes is 20 - n.

$1 = 10 dimes

$1 = 20 nickels

(1/20)n + (1/10)(20 - n) = 1.40

After solving:

n = 12

The number nickel = 12

The number dimes = 20 - 12 = 8

Thus, the number nickel is 12, and the number dimes are 8 if Jill has 20 coins, consisting of nickels and dimes totalling $1.40.

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x=14/3 and y=-28 when  x = -6. and  y = 20 for equation y = 6x +8

x=30 and y=-4 for when  x = -6. and  y = 20 for equation  y = 2/3x

x=-15 and y=11,  when  x = -6. and  y = 20 for equation   y = -x + 5

x=2 and y=-2 ,  when  x = -6. and  y = 20 for equation  y = 6.5x + 7

Two or more expressions with an Equal sign is called as Equation.

For equation y = 6x +8

When x=-6

y=6(-6)+8=-36+8=-28

when y =20

20=6x+8

28=6x

x=28/6=14/3

x=14/3 and y=-28 when  x = -6. and  y = 20 for equation y = 6x +8

For equation y = 2/3x

When x=-6, y=2/3(-6)=-4

y=20, 20=2/3x

60=2x

x=30

x=30 and y=-4 for when  x = -6. and  y = 20 for equation  y = 2/3x

For equation y = -x + 5

When x=-6, y=6+5=11

When y=20,

20=-x+5

15=-x

x=-15

x=-15 and y=11,  when  x = -6. and  y = 20 for equation   y = -x + 5

For equation y = 6.5x + 7

When x=-6

y=6.5(-6)+7

y=-39+7=-2

When y=20

20=6.5x+7

13=6.5x

2=x

x=2 and y=-2 ,  when  x = -6. and  y = 20 for equation  y = 6.5x + 7

Hence,

x=14/3 and y=-28 when  x = -6. and  y = 20 for equation y = 6x +8

x=30 and y=-4 for when  x = -6. and  y = 20 for equation  y = 2/3x

x=-15 and y=11,  when  x = -6. and  y = 20 for equation   y = -x + 5

x=2 and y=-2 ,  when  x = -6. and  y = 20 for equation  y = 6.5x + 7

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Answer: 8

Step-by-step explanation:

= (-100) ÷ (200 - (14 + 16) x 5) + 10

= (-100) ÷ (200 - 30 x 5) + 10

= (-100) ÷ (200 - 150) +10

= (-100) ÷ 50 + 10

= -2 + 10

=8

Answer:   8

Step-by-step explanation:    Remember BIDMAS, order of operations (brackets, indices, division, multiplication, addition, subtraction), since we have multiple brackets inside one another we'll start with the most inner brackets and then work from there.

14-(-16) = 30

30 x 5 = 150

200 - 150 = 50

(-100) ÷ 50 = -2

-2 + 10 = 8

The graph of the system of inequalities can be seen in the image at the end.

Here we have the following system of inequalities:

y < 2x - 5

y > -3x + 1

So first we need to graph the two lines:

y = 2x - 5

y = -3x + 1

With dashed lines (because the symbols < and > are used).

And then we shade all the region below the line:

y = 2x - 5

And we shade the region above the line:

y = -3x + 1

So we will get the graph below:

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Answer:

equilateral acute

Step-by-step explanation:

equilateral-- all the sides have the same length

acute-- all the angles are below 90 degree

Answer:

Step-by-step explanation:

You'r answer should be an equilateral acute.

The ratio that can be used to find x is sin 21 = x/22.

The trigonometric ratios are the ratios that we can use to obtain the sides and the angles that are in a right angled triangle. The term right angled triangle has to do with a triangle that has one of its angles as 90 degrees.

Now;

Given that;

Sin θ = opposite/hypotenuse

opposite = x

hypotenuse = 22

θ  = 21 degrees

It now follows that to obtain the side x we have to use;

sin 21 = x/22

Hence, in looking for the side x, we have to use sin 21 = x/22

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8 AM to 3 PM is 7 hours = 420 mins

Find how many rotations:
420 / 36 = 11.66666 rotations

Using ratio

1 rotation : 360 degrees

11.66666 : x degrees

x = 11.66666 / 1 * 360 = 4200 degrees

Using combination formula , total 987 ways or outcomes are possible /involve atleast 8 heads.

We have given that, a coin is tossed 10 times .

total possble outcomes = 2¹⁰ = 1024

here, the chances of occurrence of tail and heads and equal so, this is independent event .

we want to calculate total numbers of possble wats atleast 8 heads occurs .

At least 8 heads means exactly two toss gives Tail as a result.

here we count sequences with exactly 8 heads, and also count sequences with more than three heads. We could compute this by equivalent, by subtracting from 1025 the number of sequences with no head, only one head, and only 2 heads

= 1024 - ⁸C₀ ( + ⁸C₁ + ⁸C₂ )

= 1024 - ( 1+8+28) = 1024 - 37

= 987

Hence , 987 outcomes involve atleast 8 heads.

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Answer:

x y

-2 -9

0 1

2 -9

4 -19

explanation:

you simply replace the x with the figure given in the x table or columns or rows

Answer:

so -2024y0000 division is s

You invest $892 at the end of each year in an investment with annual rate of return 6%. Then  the investment worth after 15 year will be 14182.8 dollar

we know that

SI = prt

where

SI= simple interest

A= amount

P= principal

r= rate

t= number of year

according to the question

SI= 892* 0.06*1

 = 53.52

 A =  892+53.52

    = 945.52

after 15 years amount will be

A= 945.52*15

  = 14182.8

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The standard error of the mean is 11.99

Given,

In the question :

No. of observation is  100

The sample mean is = 1234

Standard Deviation is = 120

To find the standard error of the mean.

Noe, According to the question:

No. of observation:

N = [tex](C_{v}[/tex] / ∈[tex])[/tex] ^2

Where,

∈ = allowance % error of mean

[tex]C_{v}[/tex] = coefficient of variation

[tex]C_{v} =[/tex] σ / x bar × 100

σ = standard deviation and x bar = mean

x bar = 1234 , σ = 120 and N = 100

[tex]C_{v} = \frac{120}{1234}[/tex]  × 100

[tex]C_{v}[/tex] = 9.72%

N = [tex](C_{v}[/tex] / ∈[tex])[/tex] ^2

100 = (9.72/∈)^2

100∈^2 = (9.72)^2

∈^2  = 0.944784

∈ = 0.972%

The standard error of mean = mean x percentage of absolute mean error

= 1234 x 0.972/100

= 11.99

Hence, The standard error of the mean is 11.99

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With deceleration of 6 ft/s² and initial speed of 66 ft/s, the airplane will stop after travelling 363 ft.

Use the equation of motion:

v² = u² + 2 · a · s

Where:

v = final velocity

a = acceleration

u = initial velocity

s = distance

Deceleration is a negative acceleration.

Parameters given from the problem:

u = 66 ft/s

a = - 6 ft/s²

v = 0  since the airplane stops.

Plug these parameters into the formula:

v² = u² + 2 · a · s

0 = 66² + 2 · (-6)· s

s = 66² / 12

s = 363 ft.

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The equation of the parabola, in vertex form, that represents the ball's distance, y, from the hole, x seconds after the ball is hit is

y = (-2m/s^2)t^2 + (-2m/s)t + 6m

ax² + bx + c = 0 is a quadratic equation, which is a second-order polynomial equation in a single variable. a 0. It has at least one solution because it is a second-order polynomial equation, which is guaranteed by the algebraic fundamental theorem. The answer could be simple or complicated.

Given,

Assume for the moment that the hole is located at y = 0m, where x represents the time variable.

We are aware of:

The vertices are (-1s, 8m).

x in seconds and y in meters, I presume

The ball enters the hole at time x = 1s, hence we also have the following point:

(1s, 0m).

The vertex of the quadratic equation y = ax2 + bx + c is located at:

x = -b/2a,

Next, we have:

-1 = -b/2a.

Next, we have equations for trees:

8m = a(-1s)2, b(-1s), and c

0m = (a(1s)2) + (b(1s)2) + (c)

-1s = -b/2a.

The third equation should have one variable isolated first, and then it should be substituted in one of the other two:

1s2a = b.

Therefore, we can change b to bi 1s2a in the first two equations.

8m = 1s×2a×1s - a×1s2a1s + c

0m = 1s×2a×1s + a×1s×2a + c

We can combine the two equations to get:

8m is equal to a(1s2 - 2s2) + c, or a×1s2 - c.

0m is equal to a(1s2 + 2s2) + c, or a×3s2 + c.

We may quickly remove c from the second equation and then substitute it in the first equation:

c = -a3s^2

The initial equation is now:

8m is equal to -a×1s2 - a×3s2 - a×4s2.

a = 8m/-4s^2 = -2m/s^2.

We can now determine the values of c and b using a.

c = -(-(-2m/s2)*3s2)*3s2 = 6m.

B is equal to 1s*2a = 1s*(-2m/s2) = -2m/s.

The equation is then:

y = (-2m/s^2)t^2 + (-2m/s)t + 6m

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Answer:

(-5,-4)

as 90 degree rotation counter clockwise would land in the third quaderant where both x and y are negative

The equation of line passing through the point (-3, -1) and is perpendicular to the line y = -x/2 - 5 is y = 2x + 5

perpendicular lines are defined as two lines that meet or intersect each other at right angles (90°).

In such lines the product of their gradients is -1.

if y = -x/2 - 5

then comparing the equation with y = mx + c

it means slope(m) = -1/2

so the slope(p) of the second line perpendicular to the above line will be

p x m = -1

p = -1/m

p = -1 ÷ -1/2

p = 2

so if x = -3, y = -1 and substituting these values into the equation of line , y = mx + c becomes

-1 = 2 x (-3) + c

-1 = -6 + c

collect like terms

c= 6 - 1

c = 5

Equation of the second line becomes,

y = 2x + 5

In conclusion, the equation of the lines passing through point(-3, -1) is y = 2x + 5

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The average speed of the train is 18m/sec and the length of the train is 72 m.

let  x represent the length of the train.

and 'S' be the speed of the train.

Given, that the train passes through 360 m long tunnel  completely in 24 sec.

⇒ 360+x/24 = s

⇒ 24s = 360+x ...eq(1)

And also given that it passes through another tunnel 216 m long completely in 16 sec.

⇒ 216+x/24 = s

⇒ 16s = 216 + x .... eq(2)

⇒ subtract eq(1) from eq(2)

⇒ 24s = 360 + x

   16s = 216 + x

8s = 144

s = 18 m/sec

length of the train: 24s = 360+x

24(18) = 360+x

432 = 360+x

x = 432-360

x = 72m

Hence the length of the train is 72 m.

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Answer and Explanation:

m∠1 = 43° because opposite angles are congruent

m∠2 = 137° because ∠2 and 43° are supplementary, so m∠2 + 43° = 180°

m∠3 = 137° because opposite angles are congruent, so m∠3 = m∠2

m∠5 = 43° because alternate angles are congruent

m∠6 = 137° because ∠5 and ∠6 are supplementary, so 43° + m∠6 = 180°

m∠7 = 137° because alternate exterior angles are congruent, so m∠7 = m∠2

m∠8 = 43° because alternate exterior angles are congruent, so m∠8 = m∠1

Answer:

angle 1: 43

angle 2: 137

Step-by-step explanation:

Lets find angle 1 first :)

Since oposite diagonal angles are the same, this will make angle 1 43 degrees :)

Now lets find angle 2!

Since 1 was 43 degrees, and a flat line is 180 degrees we must subtract!

Lets do that now!

180 - 43 = 137

Angle 2 will be 137 degrees!

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Answer:

D

Step-by-step explanation:

The slope if before the x so in this case it's -3.

The y-intercept is at the end so it's -2.

Answer:

D. slope = -3 and y-intercept = -2

Step-by-step explanation:

Slope Intercept Form:

The variables:

y = -3x -2

Answer:it depends on how many sides their are

Step-by-step explanation:

just factual