A swimming pool and deck are built in a rectangle with length 40 ft and width 18 ft. If the pool itself is
320 square feet, what is the area of the deck itself?
A. 320 square feet
B. 400 square feet
C. 480 square feet
D. 560 square feet

Answer:

I am not sure but sold of the say 2,334

Answer:

58 child tickets

Step-by-step explanation:

5.7(x)+9.8(149-x)=1222.40

5.7x+1460.2-9.8x=1222.40

1460.2-4.1x=1222.40

-4.1x=-237.8

x=58

Answer:

13x+23.5

Step-by-step explanation: I dont know how to explain

Answer:

1.9059 x 10 -12

Step-by-step explanation:

Answer:

I am not sure about that

Answer:

okay so look

Step-by-step explanation:

you calculate the area of the whole square then the area of the triangle , then you subtract the area of the square with the area of the triangle so you'll get the area of the blue region

Answer:

i can't not understand sorry

Answer:

[tex]Mean = 7[/tex]

Step-by-step explanation:

Given

[tex]Data: 2, 4, 6, 12, 8, 10.[/tex]

Required

Determine the mean

The mean of a data is calculated as thus:

[tex]Mean = \frac{\sum x}{n}[/tex]

In this case:

[tex]n = 6[/tex]

So, the formula becomes:

[tex]Mean = \frac{2+4+6+12+8+10}{6}[/tex]

[tex]Mean = \frac{42}{6}[/tex]

[tex]Mean = 7[/tex]

True.

Hope this helped!

Answer:

I would say true

Step-by-step explanation:

Answer:

[tex](a)[/tex] [tex]C(x)=500+20x-5x^{\frac{3}{4}}+0.01x^2[/tex]

    [tex]p(x)=320-7.7p[/tex]

    [tex]R(x)=(320-7.7p)p=320p-7.7p^2[/tex]

[tex](b)[/tex] [tex]x=82 \text{planes}[/tex]

[tex](c)[/tex] [tex]p=\$30.91 M\;\; \text{per plane}[/tex]

[tex](d)[/tex] maximum profit [tex]=\$ 15.90M[/tex]

Step-by-step explanation:

Given that,

The company estimates that the initial cost of designing the aeroplane and setting up the factories in which to build it will be 500 million dollars.

The additional cost of manufacturing each plane can be modelled by the function.

[tex]m(x)=20x-5x^{\frac{3}{4}}+0.01x^2[/tex]

[tex](a)[/tex]  Find the cost, demand (or price), and revenue functions.

   [tex]C(x)=500+20x-5x^{\frac{3}{4}}+0.01x^2[/tex]

   [tex]p(x)=320-7.7p[/tex]

   [tex]R(x)=(320-7.7p)p=320p-7.7p^2[/tex]

[tex](b)[/tex]  Find the production level that maximizes profit.

    [tex]f=R(x)-C(x)[/tex]

 [tex]\Rightarrow f=320p-7.7p^2-(500+20x-5x^{\frac{3}{4}}+0.01x^2)[/tex]

[tex]\Rightarrow df=320dp-15.4pdp-20dx+5(\frac{3}{4} )x^{\frac{-1}{4} }dx-0.02xdx[/tex]

     [tex]x=320-7.7p[/tex]

     [tex]p=\frac{320-x}{7.7}[/tex]

    [tex]\frac{dp}{dx} = \frac{-1}{7.7}[/tex]

[tex]\frac{df}{dx}=\frac{320}{-7.7} -\frac{15.4(320-x) }{7.7(\frac{-1}{7.7} )}-20+5\frac{3}{4} x^{\frac{-1}{4}} -0.02x=0[/tex]

    [tex]\Rightarrow -41.5584+83.1169-0.2597x-20+3.75x^{\frac{-1}{4} }-0.02x=0[/tex]

   [tex]\Rightarrow 21.5585+3.75x^{\frac{-1}{4} }-0.279x=0[/tex]

   [tex]\Rightarrow x=82 \text{planes}[/tex]

[tex](c)[/tex]  Find the associated selling price of the aircraft that maximizes profit.

  [tex]p=\frac{320-82}{7.7}[/tex]

[tex]\Rightarrow p=\$30.91 M\;\; \text{per plane}[/tex]

[tex](d)[/tex]  Find the maximum profit.

Manufacturing cost of one plane is:

[tex]m(1)=20-5+0.01[/tex]

         [tex]=\$15.01 M[/tex]

maximum profit [tex]=\$(30.91-15.01)M[/tex]

                           [tex]=\$15.90M[/tex]

Answer: D. The equation has infinitely many solutions.

Step-by-step explanation:

Given equation: [tex]-9(x + 3) + 12 = -3(2x + 5) - 3x[/tex]

[tex]\Rightarrow -9(x)+(-9)(3)+12=(-3)(2x)+(-3)(5)-3x\\\\\Rightarrow\ -9x-27+12=-6x-15-3x\\\\\Rightarrow\ -9x-15=-9x-15\\\\\Rightarrow\ -9x+9x=-15+15\\\\\Rightarrow\ 0=0[/tex]

which is true.

This happens when all numbers are solutions.

i.e. The equation has infinitely many solutions.

Correct option : D.

Answer: she has 15 dimes and 45 pennies.

Step-by-step explanation:

01p+1d=1.95

p=3d

01(3d)+.1d=1.95

p=3.15

03d+.1d=1.95

p=45

.13d=1.95

d=15

Step-by-step explanation:

Ratio

= Difference between Prediction and Actual / Prediction

= (99 - 88)/99 = 11/99.

Percentage Error

= Difference between Prediction and Actual * 100%

= (99 - 88) * 100% = 11.1%. (1)

The ratio (a) & percent error (b) will be option A which is a=11/99 and b= 11.11% respectively

Approximate value = 99 frames

Exact value = 88 frames

∴ Ratio (a) = (99-88)/99

∴ a = 11/99

∴ Percent error (b) = (11/99) x 100

∴ b = 11.11%

So, the answer of ratio (a) & percent error (b) will be 11/99 and 11.11% respectively

Learn more about Ratio and percent error here:

https://brainly.com/question/5493941

#SPJ2

Answer:

17》6

18》12

19》8

20》3

21》2

the bar with age 18 this is because as you minus from both sides the middle number will be in age 18

Hey there!

I believe the answer to your question is 47.21 ml of oxygen are in the 55 ml sample of sea water.

To get this, you can do 0.8584 x 55 = 47.212, because you want to find 85.84% of 55, to know how much oxygen is in the sample. Then, you round it to the nearest hundreth.

Hope it helps! Have a great day! Do tell me if I'm mistaken.

Answer:

Please check the explanation.

Step-by-step explanation:

Given the quadratic equation

5x²−2x−9 = 0

To factor the quadratic function 5x²−2x−9, we should solve the corresponding quadratic equation 5x²−2x−9 = 0.

Indeed, if x₁ and x₂ are the roots of the quadratic equation ax²+bx+c=0, then

ax²+bx+c = a(x-x₁)(x-x₂)

Now,

solving the quadratic function 5x²−2x−9 = 0

[tex]-5x^2+2x+9=0[/tex]

subtract 9 from both sides

[tex]-5x^2+2x+9-9=0-9[/tex]

Simplify

[tex]-5x^2+2x=-9[/tex]

Divide both sides by -5

[tex]\frac{-5x^2+2x}{-5}=\frac{-9}{-5}[/tex]

[tex]x^2-\frac{2x}{5}=\frac{9}{5}[/tex]

Add (-1/5)² to both sides

[tex]x^2-\frac{2x}{5}+\left(-\frac{1}{5}\right)^2=\frac{9}{5}+\left(-\frac{1}{5}\right)^2[/tex]

[tex]x^2-\frac{2x}{5}+\left(-\frac{1}{5}\right)^2=\frac{46}{25}[/tex]

[tex]\left(x-\frac{1}{5}\right)^2=\frac{46}{25} \\[/tex]

[tex]\mathrm{For\:}f^2\left(x\right)=a\mathrm{\:the\:solutions\:are\:}f\left(x\right)=\sqrt{a},\:-\sqrt{a}[/tex]

so solving

[tex]x-\frac{1}{5}=\sqrt{\frac{46}{25}}[/tex]

[tex]x-\frac{1}{5}=\frac{\sqrt{46}}{\sqrt{25}}[/tex]

Add 1/5 to both sides

[tex]x-\frac{1}{5}+\frac{1}{5}=\frac{\sqrt{46}}{5}+\frac{1}{5}[/tex]

[tex]x=\frac{\sqrt{46}+1}{5}[/tex]

similarly solving

[tex]x-\frac{1}{5}=-\sqrt{\frac{46}{25}}[/tex]

[tex]x-\frac{1}{5}=-\frac{\sqrt{46}}{5}[/tex]

Add 1/5 to both sides

[tex]x-\frac{1}{5}+\frac{1}{5}=-\frac{\sqrt{46}}{5}+\frac{1}{5}[/tex]

[tex]x=\frac{-\sqrt{46}+1}{5}[/tex]

Thus, the roots are:

[tex]x_{1} =\frac{\sqrt{46}+1}{5},\:x_{2}=\frac{-\sqrt{46}+1}{5}[/tex]

Conclusion:

Since the roots are irrational, we do not factor further.

Therefore, we leave 5x²−2x−9 as it is.

Answer:

R=√a/3

now put square on both side to remove square root

(√A/3)²=R²

A/3=R²

so we get

A=3(R²)

plz mark me brainest

Answer:

$15.02

Step-by-step explanation:

Let's write out some equations.

Company A:

60.50+0.12x=A

Company b:

45.50+0.10x=B

Now let's compare. If x=1, Company A charges

60.50+0.12=60.62=A

On the other hand, Company B charges

45.50+0.10=45.60=B

A-B=60.62-45.60=15.02

Since these are linear we can safely assume that this is constant :)

Solve for x and y :

x + y = 1   →   y = 1 - x

x ² + y ² = -1

x ² + (1 - x)² = -1

x ² + (1 - 2x + x ²) = -1

2x ² - 2x + 1 = -1

2x ² - 2x + 2 = 0

x ² - x + 1 = 0

x ² - x + 1/4 = -3/4

(x - 1/2)² = -3/4

x - 1/2 = ±√(-3/4)

x - 1/2 = ±√3/2 i

x = 1/2 ± √3/2 i   →   x = exp(± iπ/3)

y = 1 - (1/2 ± √3/2 i )   →   y = -1/2 ± √3/2 i   →   y = exp(± 2iπ/3)

Then

x ⁷ + y ¹³ = exp(± 7iπ/3) + exp(± 26iπ/3)

… = exp(± iπ/3) + exp(± 2iπ/3)

since 7π/3 is equivalent to π/3, and 26π/3 is equivalent to 2π/3 (both modulo 2π).

In either case, we get

x ⁷ + y ¹³ = x + y = 1

so the answer is (2) 1.

Answer:

z = 25

Step-by-step explanation:

adjacent angles in a rhombus are supplementary

3z - 15 + 7z - 55 = 180

10z - 70 = 180

10z = 250

z = 25

Answer:

-2 - 24i

Step-by-step explanation:

a + bi + (7 - 3i) + (5 + 9i) + 13i = 10 - 5i

a + bi + 7 + 5  - 3i + 9i + 13i = 10 - 5i

                a + bi  + 12  + 19i = 10 - 5i

                         a + bi          = 10 - 5i - 12 - 9i

                                 a + bi = 10 - 12 - 5i - 9i

                                 a + bi = -2 - 24i

Answer:

x= -2

Step-by-step explanation:

Use Euler’s Formula to find the missing number.

18

Answer:

Use Euler’s Formula to find the missing number.

Faces: __8__

Edges: 15

Vertices: 9

Answer is 8

Step-by-step explanation:

Note: this answer assumes that the equation of the line must be in slope-intercept form.

Answer:

[tex]y= -3x + 5[/tex]

Explanation:

When you need to write an equation and know its slope and a point it intersects, you can use the point slope formula [tex]y-y_1 = m (x-x_1)[/tex] first. In order to write an equation using this formula, the [tex]m[/tex], [tex]x_1[/tex], and [tex]y_1[/tex] must be substituted in for real values.

The [tex]m[/tex] represents the slope, so write the slope of this equation, -3, in its place. The [tex]x_1[/tex] and [tex]y_1[/tex] represent the x and y values of a point the line intersects. We know that the line must intersect the point (2, -1). Write 2 in the place of

[tex]y-(-1) = -3(x-(2))[/tex]

[tex]y+1 = -3(x-2)[/tex]

Now, to put it in slope-intercept or [tex]y = mx + b[/tex] form, just expand the right side and isolate [tex]y[/tex]:

[tex]y+1 = -3(x-2)\\y + 1 = -3x + 6 \\y = -3x + 5[/tex]

Therefore, [tex]y= -3x + 5[/tex] is the answer.

Answer:

Rewriting [tex]6^{-2}[/tex] without an exponent we get [tex]\mathbf{\frac{1}{36}}[/tex]

Step-by-step explanation:

We need to rewrite the following without an exponent. [tex]6^{-2}[/tex]

We need to solve the exponent to find the result.

We know the exponent rule: [tex]a^{-b}=\frac{1}{a^b}[/tex]

Now using this rule to solve the equation:

[tex]6^{-2}\\=\frac{1}{6^2}\\We \:know \:that\:6^2 = 6\times 6=36\\=\frac{1}{36}[/tex]

So, Rewriting [tex]6^{-2}[/tex] without an exponent we get [tex]\mathbf{\frac{1}{36}}[/tex]

Answer:

$43680

Step-by-step explanation:

Given data

Tuition was ​$. 42,000 last year

The tuition increased by​ 4%

Hence the current year tuition is given as

Current tuition= 42,000 + 4/100*42,000

Current tuition= 42,000 + 0.04*42,000

Current tuition= 42,000 +1680

Current tuition= $43680

Hence the current tuition is $43680