A triangle has vertices at A(-2,3,) B(2,1) and C(1,0) after a transformation the image of the triangle has vertices at A(-2,-3) B(2,-5) and C(1,-6) identify the transformation

Answer:

Step-by-step explanation:

f(0) = 4

f(x)=0   when x = 0.75

f(x) =5  when x =3

A{ x ∈ R ║ 3≤x}

Functions that are symmetric with respect to the x-axis are those with even degree of y, i.e y², y⁴ etc.

Correct choices are:

Answer:

[tex]x=\dfrac{1}{8}y^2[/tex]

[tex]x=-y^2+9[/tex]

Step-by-step explanation:

Functions are symmetric with respect to the x-axis if for every point (a, b) on the graph, there is also a point (a, −b) on the graph:

To determine if a graph is symmetric with respect to the x-axis, replace all the y's with (−y).  If the resultant expression is equivalent to the original expression, the graph is symmetric with respect to the x-axis.

Therefore, any function that includes the term y² will be symmetric with respect to the x-axis since (-y)² = y².

[tex]\begin{aligned}&\textsf{Given}: \quad& x&=\dfrac{1}{8}y^2\\&\textsf{Replace $y$ for $(-y)$}: \quad& x&=\dfrac{1}{8}(-y)^2\\&\textsf{Simplify}: \quad &x&=\dfrac{1}{8}y^2\\\end{aligned}[/tex]

Therefore, since the resultant expression is equivalent to the original expression, it is symmetric with respect to the x-axis.

[tex]\begin{aligned}&\textsf{Given}: \quad& x&=-y^2+9\\&\textsf{Replace $y$ for $(-y)$}: \quad& x&=-(-y)^2+9\\&\textsf{Simplify}: \quad &x&=-y^2+9\\\end{aligned}[/tex]

Therefore, since the resultant expression is equivalent to the original expression, it is symmetric with respect to the x-axis.

Answer: (-12,-1)

Step-by-step explanation: Point A=-1 and Point B=-12

:)

Answer:

[tex] \binom{?}{?} [/tex]

Step-by-step explanation:

$40 Pam use type diagram

$45. bro

Answer:

70

Step-by-step explanation:

Had this question too ;)

Answer:

30%

Step-by-step explanation:

130980-91686=39294

39294/130908=0.3

Answer: 168,609 ton

Hi, to answer this question, first we have to calculate the amount of the weight decrease by multiplying the original weight of the goods (240,870) by the percentage decrease in decimal form ( divided by 100)

Mathematically speaking:

240,870 (30/100) =72,261 ton

Finally we have to subtract that value to the original weight:

240,870-72,261 = 168,609 ton

Feel free to ask for more if needed or if you did not understand something.  

Step-by-step explanation:

The amount of money that must be deposited today is $749   .

In the question ,

it is given that ,

the amount that is need to be made (A) = $2250

time (t) = 20 years

rate percent (r) = 5.5%  = 0.055

let the amount that must be deposited today be P .

The amount that is needed to be deposited today at 5.5% compounded continuously can be calculated using the formula .

A = P×[tex]e^{r\times t}[/tex]

Substituting the values , we get
2250 = P × [tex]e^{0.055\times 20}[/tex]

2250 = P × [tex]e^{1.1}[/tex]

P = 2250/ [tex]e^{1.1}[/tex]

P = 748.9599

P ≈ 749

Therefore , The amount of money that must be deposited today is $749   .

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Answer:

Let the girls be x

then, 5:4 = 5x and 4x

,

total stud.=36 so,

5x+4x=36

9x=36

x=36÷9

hence

x=4

now, boys = 5x=5×4=20

girls= 4x=4×4=16

so there are 16 girls

Step-by-step explanation:

x + y = 42

5x + 9y = 190

x = 42 - y

5(42 - y) + 9y = 190

210 - 5y + 9y = 190

210 + 4y = 190

4y = -20

y = -5

x = 42 - y = 42 - -5 = 42 + 5 = 47

Answer:40%

Step-by-step explanation:

Answer:

67

Step-by-step explanation:

33,500/500 = 67

To check our work:

67 x 500 = 33,500

Answer:

67 percentStep-by-step explanation:

The annual rainfall in 2016 is 336 mm.

Let the annual rainfall in 2016 be 100x mm.

Now it is given that rainfall in 2017 is 25% more than rainfall in 2016.

So. rainfall in 2017 is = 100x + 100x*(25/100) = 100x+25x = 125x mm

Also given that the amount of rainfall in 2017 = 420 mm.

According to question the suitable equation is,

125x = 420

x = 420/125

x = 3.36

Hence the rainfall in 2016 is = 100x = 100*3.36 = 336 mm.

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Answer: It is positive and increasing

Step-by-step explanation:

From point e to f it is clearly going up, and is part of the positive side of the graph.

The value of derivative of d/dx[5f(x)-4x] at x=2 = 16.

From the table:

At x=2,

f'(x) = 4

f(x) = 4x

= d/dx(5*4x - 4x)

= d/dx(20x - 4x)

= d/dx(16x)

= 16

Therefore the value of derivative of d/dx[5f(x)-4x] at x=2 = 16.

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The image of the end points X(-3 , 1) and Y(4 , -5) is

X'' = (-1 , 3) and Y'' = (5 , -4).

Given, a line segment with end points X(-3 , 1) and Y(4 , -5)

We have to find the image of the points after the given composition,

Reflection in the line y = x.

Rotation 180° about the origin.

After the reflection the image of the points X and Y be,

X' = (1 , -3) and Y' = (-5 , 4)

Now, after the rotation of the points of 180° about the origin be,

X'' = (-1 , 3) and Y'' = (5 , -4)

Hence, the image of the end points X(-3 , 1) and Y(4 , -5) is

X'' = (-1 , 3) and Y'' = (5 , -4).

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The expression 3x+11y cannot be factorized.

What is factorization?

To factorise an algebraic statement, we first identify the terms' highest common factors before organising the words in the appropriate way. An algebraic expression's factorization is, to put it simply, the process of expansion in reverse. The same way, as the product of their factors, are the algebraic expressions written in algebra. The only difference is that in an algebraic expression, variables and integers are combined to perform mathematical operations like addition or subtraction.

Here the given expression 3x+11y didn't have any common factors.

The given expression has two variables 3x and 11y and they didn"t have any common terms.

Hence the expression 3x+11y cannot be factored.

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Answer:meh

Step-by-step explanation:good enough

The time that would be taken for the money to double is 9 years.

Given that a compound interest has to do with the type of interest that is charged both on the principal and on the interest. We know that the principal is the money that was invested.

Let the principal be P and let the time taken be t. Let us now apply the formula;

A = P(1 + r)^n

Where A = 2P and r = 0.08

2P = P(1 + 0.08)^n

2P/P = (1.08)^n

2 = (1.08)^n

ln2 = nln1.08

n = ln2/ln1.08

n = 0.693/0.077

n = 9

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Answer:

315

Step-by-step explanation:

2/180=3.5/x

2x=630

x=315

The number of ways to split the integers, given the condition and using the Fundamental Counting Theorem, is of:

144.

It is a theorem that states that if there are n independent trials, each with [tex]n_1, n_2, \cdots, n_n[/tex] possible results, the total number of outcomes considering all trials is calculated by the multiplication of the factorials as presented as follows:

[tex]N = n_1 \times n_2 \times \cdots \times n_n[/tex]

Given the condition that the greater number is at least 2 times the lesser number we have that the pairs are composed by one number between 1 and 7 and another number between 8 and 14.

Hence the pairs of each number are built as follows:

Hence the number of ways to split the numbers is:

2 x 3 x 4 x 3 x 2 = 144.

(the numbers were multiplied because of the Fundamental Counting Theorem).

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Answer: All Are correct

Step-by-step explanation:

Look at graph, the vertex hits the origin, the parent function is on the top half of the graph (quads 1 and 2), both the left and right side have a slope of 1, and it is v shaped!

Answer: The answer is 5.

Step-by-step explanation:

4.5  ÷  0.9 = 450/90.
Convert decimal 4.5 to fraction 45/10

Convert decimal 0.9 to fraction 9/10

Divide 450/90

Simply 450/90 = 5

Answer:

5

Step-by-step explanation:

The value for the side of rectangle XZ is equal 14, using the trigonometric ratios of cosine and sine of angles.

The trigonometric ratios concerns the relationship of an angle of a right-angled triangle to ratios of two side lengths. The basic trigonometric ratios includes;

sine, cosine and tangent.

Considering the triangle WYZ, the cosine of angle Y;

cos(Y) = 21/YZ {adjacent/hypotenuse}

YZ = [21/cos(Y)] {cross multiply}

Considering the triangle XYZ, the cosine of angle Y;

cos(Y) = YZ/28

YZ = 28 × cos(Y)

Therefore,

28cos(Y) = [21/cos(Y)]

cos²(Y) = 21/28 {cross multiply}

cos(Y) = √(21/28) {take the square root of both sides}

cos(Y) = 0.8660

Y = cos^(-1)(0.8660) {cross multiply}

Y = 30°

To get the side XZ, considering the triangle XYZ the sine of 30°;

sin30° = XZ/28 {opposite/hypotenuse}

by cross multiplication

XZ = 28 × sin30°

XZ = 14

Therefore, by proper application of the trigonometric ratios of cosine and sine of the angle for the given triangle, the side XZ = 14.

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Answer:

x=10

y=5

Step-by-step explanation:

you have to find the length

The equation of the line d that is parallel to line c is y = -5x + 4.

The equation of a line in slope intercept form can be represented as follows:

y = mx + b

where

Therefore, c has an equation y = -5x + 3. Line d is parallel to line c. Therefore, they have the same slopes. Parallel lines have the same slope.

Hence, let's find the equation of line d passing through (2, -6)

Let's find the y-intercept

-6 = -5(2) + b

-6  = -10 + b

b = -6 + 10

b = 4

Therefore, the equation of the line d is y = -5x + 4

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Answer: Yes

Step-by-step explanation:

Yes, it is because if you multiply 2 and 5, you get 10. 2 and 5 LCM is also 10. If you check 2 and five multiples you see this is also proved true.

2 - 2, 4, 6, 8, 10, 12, 14, 16, 18, 20 ...

5 - 5, 10, 15, 20 ...

a) The decay formula for the mass of Strontium-90 is m(t) = 75 · [tex]e^{-t /40.395}[/tex].

b) The sample of Strontium-90 has a mass of approximately 13.258 miligrams after 70 days.

c) The sample of Strontium-90 takes a time of approximately 146.405 days.

The mass of Strontium-90 decays exponentially in time, whose model is described below:

m(t) = m' · [tex]e^{- t /\tau}[/tex]

Where:

And the time constant can be estimated by the following formula:

τ = t' / ㏑ 2

Where t' is the half-life of the isotope.

a) If we know that m' = 75 mg and t' = 28 d, then the expression for the mass of the sample is:

τ = 28 / ㏑ 2

τ ≈ 40.395 d

m(t) = 75 · [tex]e^{-t /40.395}[/tex]

b) And the mass of the isotope after 70 days is:

m(70) = 75 · [tex]e^{- 70 / 40.395}[/tex]

m(70) ≈ 13.258 mg

The current mass is approximately 13.258 miligrams.

c) If we know that m(t) = 75 · [tex]e^{-t /40.395}[/tex] and m(t) = 2 mg, then the time needed for the decay is:

75 · [tex]e^{-t /40.395}[/tex] = 2

[tex]e^{-t /40.395}[/tex] = 2 / 75

- t / 40.395 = ㏑ (2 / 75)

t = - 40.395 · ㏑ (2 / 75)

t ≈ 146.405 d

The needed time is approximately 146.405 days.

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Answer:r

Step-by-step explanation:r

Answer: you prob fininshed 5,3

Step-by-step explanation:

also this is easy im srry for doing this