Given :
A volume of 80.0 mL of a 0.690 M [tex]HNO_3[/tex] solution is titrated with 0.790 M KOH.
To Find :
The volume of KOH required to reach the equivalence point.
Solution :
We know, at equivalent point :
moles of [tex]HNO_3[/tex] = moles of KOH
[tex]M_{HNO_3}V_{HNO_3}=M_{KOH}V_{KOH}\\\\0.690\times 80 = 0.790\times V_{KOH}\\\\V_{KOH}=\dfrac{0.690\times 80 }{ 0.790}\ ml\\\\V_{KOH}=69.87\ ml[/tex]
Therefore, volume of KOH required is 69.87 ml.
Hence, this is the required solution.
Choose all the answers that apply.
Fluorine (F) has seven electrons in its outermost shell. Fluorine _____.
-is a metal
-fills its shell by giving up seven electrons
-fills its shell by gaining one electron
-becomes a positively charged ion
-becomes a negatively charged ion
-is a nonmetal
Answer:
Fluorine is a non-metal, fills its shell by gaining one electron and becomes a negatively charged ion.
Explanation:
Fluorine have seven electrons in its outermost shell. This means that fluorine is located in Group 17(Halogens) in the Periodic Table. Note that halogens are non-metal elements. So fluorine is a non-metal.
Fluorine fills its shell by gaining one electron because it only needs one electron to achieve stable octet electron arrangement. ( it's easier to gain one electron than to lose all seven electrons in the outermost shell)
As fluorine atom gain one electron to achieve stable octet electron arrangement, its number of electrons becomes greater than its number of protons. So it becomes a negatively charged ion.
What is the heat gjoules transferred by a chemical reaction to the reservoir of a calorimeter containing 135g of dilute aqueous solution (c=4.184 J/g^ C) the reaction causes the temperature of the reservoir to rise from 23.0 27.0 degrees * C
Answer:
Required heat = 2,259.36 N (approx)
Explanation:
Given:
Mass = 135 g
Specific heat (c) =4.184 J/gC
Change in temperature ΔT = 27-23 = 4 c
Find:
Required heat
Computation:
Q = mcΔT
Q = (135)(4.184)(4)
Required heat = 2,259.36 N (approx)
The heat transferred by the chemical reaction to the reservoir of a calorimeter containing 135 g of dilute aqueous solution is 2259.36 J
To solve this question, we'll begin by calculating the change in the temperature of the reservoir. This can be obtained as follow:
Initial temperature (T₁) = 23 °C
Final temperature (T₂) = 27 °C
Change in temperature (ΔT) =?ΔT = T₂ – T₁
ΔT = 27 – 23
ΔT = 4 °CFinally, we shall determine the heat transferred to the reservoir.
Change in temperature (ΔT) = 4 °C
Mass (M) = 135 g
Specific heat capacity (C) = 4.184 J/gºC
Heat (Q) =?Q = MCΔT
Q = 135 × 4.184 × 4
Q = 2259.36 JTherefore, the heat transferred by the chemical reaction to the reservoir of a calorimeter containing 135 g of dilute aqueous solution is 2259.36 J
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Calculate the sublimation pressure of the solid at the melting point of 400.00 K assuming that the enthalpy of sublimation is not a function of temperature.
This question is incomplete, the complete question is;
Tonksite is a solid at 300.00K. At 300.00 K its enthalpy of sublimation is 66.00 kJ/mol. The sublimation pressure at 300.00 K is 5.00 × 10⁻⁴ atm
Calculate the sublimation pressure of the solid at the melting point of 400.00 K assuming that the enthalpy of sublimation is not a function of temperature.
Answer: the sublimation pressure of the solid at the melting point is 0.3727 atm
Explanation:
Given that;
T1 = 300 K
T2 = 400 K
H_sub = 66 kJ/mol = 66000 J/mol
P1 = 5.00 × 10⁻⁴ atm
p2 = ?
now using the expression
log( p2 / 5.00 × 10⁻⁴ ) = (H_sub / R × 2.303 ) (( T2 - T1) / T1T2)
now we substitute of given values into the expression
log(p2/p1) = (66000 / 8.314 × 2.303 ) (( 400 - 300) / 300 × 400 )
p2 = 0.3727 atm
therefore the sublimation pressure of the solid at the melting point is 0.3727 atm
HELPPPPP
Identify whether each of the following changes is a physical change or a chemical change. Write “P” on the line for a physical change and a “C” for a chemical change.
22. Water boiling ______23. Iron rusting ______24. Butter melting _____25. Wood rotting ______
26.Alcohol evaporating _____27.Glass breaking ______28.Mowing the lawn ______29.Baking a cake ______
Answer:
22 is P
23 is C
24 is P
25 is C
26 is P
27 is P
28 is P
29 is C because youre using thermal heat and you cannot return to raw batter
What is the temperature of o3 gas if the average speed(actually the root mean square speed of the molecules is 750 m/s
Answer:
1.08 × 103 K
hope this helps :)
Explanation:
What is magma?
solid rock with a fine texture
cooled rock with large crystals
molten rock below Earth’s surface
flowing rock above Earth’s surface
Answer:
C. molten rock below Earth’s surface
Explanation:
hello I am working on naming compounds and wondering if you could help me figure out the name
Al2(SO4)3 aluminium sulfate
Element
Molar mass (g/mol)
1.008
H
С
12.01
16.00
Using the information in the table, calculate the number of moles in a 2.03 kg sample of citric acid
(C6H8O7)
Write your answer using three significant figures.
mol C6H8O7-
Answer:
Number of moles = 10.6 mol
Explanation:
Given data:
Molar mass of H = 1.008 g/mol
Molar mass of C = 12.01 g/mol
Molar mass of O = 16.00 g/mol
Mass of citric acid = 2.03 kg (2.03×1000 = 2030 g)
Number of moles of citric acid = ?
Solution:
Formula:
Number of moles = mass/molar mass
Now we will calculate the molar mass of citric acid:
C₆H₈O₇ = (12.01× 6) + (1.008×8) + (16.00×7)
C₆H₈O₇ = 72.06 + 8.064+112
C₆H₈O₇ = 192.124g/mol
Number of moles = 2030 g/ 192.124g/mol
Number of moles = 10.6 mol
The number of moles in a 2.03 kg sample of citric acid is :
- 10.6 mol
Molar MassGiven:
Molar mass of H = 1.008 g/mol
Molar mass of C = 12.01 g/mol
Molar mass of O = 16.00 g/mol
Mass of citric acid = 2.03 kg (2.03×1000 = 2030 g)
Number of moles of citric acid = ?
Formula:
Number of moles = mass/molar mass
The molar mass of citric acid:
C₆H₈O₇ = (12.01× 6) + (1.008×8) + (16.00×7)
C₆H₈O₇ = 72.06 + 8.064+112
C₆H₈O₇ = 192.124g/mol
Number of moles = 2030 g/ 192.124g/mol
Number of moles = 10.6 mol
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what is the chimestry
Which of the three crowns was made of gold? Explain:
Answer:
I need more context. Maybe add a picture.
Explanation:
Answer:
Crown B
Explanation:
because the density of gold is 19.3 and the density of the crown is 19.29.
If an object has a density of 6.05 g/cm3 and a volume of 36.5 cm3, what is its mass?
Answer:
0.42 g/cm3
Explanation:
Answer:
20/40=0.5 g/cm^3 becuase, mass/volume=density
Explanation:
3 letters start from X
Answer:
xanthophyll
xenobiotic
xenon
X group
x-rays
x-ray tube
the coefficient of 02 is needed to balance the equation C3h8+O2+3co2+4H20
Answer:The anwser is 5
Explanation:
C. Where is sugar removed from the blood?
and how can you tell
Answer:During absorption and digestion, the carbohydrates in the food you eat are reduced to their simplest form, glucose. Excess glucose is then removed from the blood, with the majority of it being converted into glycoge, the storage form of glucose, by the liver's hepatic cells via a process called glycogenesis
Explanation:
What is the pH of a bleach solution that has a [OH−]=1.3×10−4 M?
Answer:
pH = 10.113
Explanation:
Here, we can find pOH first:
pOH = [tex]-log([OH^-])[/tex] = 3.886.
Then, we can find pH which is 14 - pOH. We then get the answer above.
Then, we can find pH which is 14 - pOH. We then get the answer above.
The pH of acid is between 0-7 on pH scale while for base pH range is from 7-14. Thus the pH of 1.3×10⁻⁴ M bleach solution is 10.62.
What is pH?pH is a measurement of amount of hydronium ion H₃O⁺ in a given sample. More the value of hydronium ion concentration, more will be the solution acidic.
On subtracting pH from 14, we get pOH which measures the concentration of hydroxide ion in a given solution. pH depend on the temperature. At room temperature pH scale is between 0 to 14. pH of neutral solution is 7
The concentration of bleach solution is 1.3×10⁻⁴ M
Concentration of OH⁻=1.3×10⁻⁴ M
Mathematically,
pOH=-log[OH⁻]
Substituting the values
pH=-log[1.3×10⁻⁴]
= 3.886.
pH+ POH=14
pH=14-3.886.=10.62
Therefore, the pH of 1.3×10⁻⁴ M bleach solution is 10.62.
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Electrolysis of water produces its constituent elements, hydrogen and oxygen. This process is represented by the following balanced chemical equation:
2 H2O(l) → 2 H2(g) + O2(g).
If 8.05 grams of oxygen gas was produced in the reaction, how many molecules of water were decomposed?
Do enter the coefficient of the answer only. Do NOT include the unit in final answer.
_______________________________ × 1023 H2O molecules.
Answer:
3.011 × 10²³
Explanation:
Given data:
Mass of oxygen produced = 8.05 g
Molecules of water decomposed = ?
Solution:
Balance chemical equation:
2H₂O → 2H₂ + O₂
Number of moles of oxygen produced:
Number of moles = mass/molar mass
Number of moles = 8.05 g/ 32 g/mol
Number of moles = 0.25 mol
Now we will compare the moles of water with oxygen.
O₂ : H₂O
1 : 2
0.25 : 2×0.25 =0.5 mol
0.5 moles of water were decomposed.
Molecules of water decomposed:
1 mole = 6.022× 10²³ molecules of water
0.5 mol ×6.022× 10²³ molecules of water/ 1mol
3.011 × 10²³ molecules of water
Answer each of the following questions with increases, decreases, or does not change.
a) If the intermolecular forces in a liquid increase, the normal boiling point of the liquid increases .
b) If the intermolecular forces in a liquid increase, the vapor pressure of the liquid does not change .
c) If the surface area of a liquid increases, the vapor pressure increases .
d) If the temperature of a liquid decreases, the equilibrium vapor pressure increases .
Drag and drop your selection from the following list to complete the answer:
does not change decreases increases
Answer:
a) increases
b) decreases
c) does not change
d) increases
Explanation:
The vapour pressure of a liquid is dependent on;
I) the magnitude of intermolecular forces
II) the temperature of the liquid
Hence, when any of these increases, the vapour pressure increases likewise.
Similarly, the boiling point of a liquid depends on the magnitude of intermolecular forces present because as intermolecular forces increases, more energy is required to break intermolecular bonds.
Lastly, increase in surface area of a liquid does not really affect it's vapour pressure.
Write the letter of the correct term for each definition in the blank. Use each term only once.
a. filtration
b. distillation
c. decantation
d. evaporation
e. centrifugation
f. chromatography
1. Separates substances on the basis of the boiling points of the substances:__________
2. Separates solutions based on boiling points when one substance remains a solid:__________
3. Separates pure substances from a mixture based upon different rates of flow:__________
4. Separates solids from liquids by pouring the liquid off the top of the solid:__________
5. Separates solids from liquids by using a porous barrier:__________
6. Separates heterogeneous substances based upon different densities:__________
Answer:
1.b. distillation
2.d. evaporation
3.f. chromatography
4.c. decantation
5.a. filtration
6.e. centrifugation
Explanation:
1. Distillation is the process in which a homogenous mixture of liquid is separated on the basis of difference in boiling points of the substances.
2. Evaporation is the process in which water is converted into gas or vapor based on the boiling point of water or solid.
3. Chromatography is defined as the process used to pure substances from a mixture based on the flow rate of the fluid. The fluid mixture to be separated is called the mobile phase that flows on a stationary phase.
4. Decantation is defined as the process that separates mixtures in which water is poured off the substance to be separated or over solid.
5. Filtration is a separation process in which solids can be separated from liquids by pouring the mixture over a porous barrier.
6. Centrifugation is defined as the separation process that separates heterogeneous substances on the basis of densities in which centripetal acceleration allows substance with high density to move outward in the radial direction.
Which of the following correctly lists the five atoms in order of increasing size (smallest to
largest)?
O, F, Mg, S, Ba
Answer:
F - O - S - Mg - Ba
Explanation:
as you move left to right on the periodic table the number of electrons increase.
The correct lists of the five atoms in order of increasing size smallest to
largest is :
D) F - O - S - Mg - Ba
Atomic RadiusThe correct lists of the five atoms in order of increasing size smallest to
largest is F - O - S - Mg - Ba.
The atomic radius of a chemical element may be a degree of the measure of its molecule, as a rule the mean or commonplace remove from the center of the core to the furthest isolated electron.
The arrange will be:
Fluorine(F) (50 pm)Sulfur(S) (100 pm) Magnesium(Mg) (150 pm) Barium(Ba) (215 pm)As you move cleared out to right on the periodic table the number of electrons increment.
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Naphthalene is soluble in diethyl ether, but it is insoluble in water regardless of the solution pH. Explain why this compound cannot be readily ionized in aqueous solution.
Answer:
Naphthalene is a non polar substance
Explanation:
In chemistry, the principle of like dissolves like is the over aching principle that controls the dissolution of one substance in another.
Naphthalene dissolves in diethyl ether because diethyl ether is a non polar solvent just as naphthalene is a nonpolar substance.
Since water is a polar solvent, it can not dissolves naphthalene at any pH because naphthalene is a nonpolar substance.
noble gas notation for titanium
Answer:
Titanium [Ar] 3d2 4s2
Explanation:
Which statement gives an advantage of multicellular organisms?
A. Cells are able to provide support
B. They can reproduce quickly
C. Their size allows them to maintain structure easily
D. They need small amounts of energy
Answer:
A. Cells are able to provide support
32. A chemical reaction in which calcium carbonate CaCO3 is decomposed, results in the
production of two simpler compounds.
CaCO3
>CaO
+
CO2
? 9
28.00 g
21.97 g
What mass of calcium carbonate, to the nearest hundredth of a gram, is
decomposed in this reaction?
Answer:
Mass of calcium carbonate decompose 49g.
Explanation:
Given data:
Mass of CaO = 28.00 g
Mass of CO₂ = 21.97 g
Mass of calcium carbonate decompose = ?
Solution:
Chemical equation:
CaCO₃ → CO₂ + CaO
Number of moles of CO₂:
Number of moles = mass/molar mass
Number of moles = 21.97 g / 44 g/mol
Number of moles = 0.49 mol
Number of moles of CaO:
Number of moles = mass/molar mass
Number of moles = 28.00 g / 56.1 g/mol
Number of moles = 0.49 mol
Now we will compare the moles of CaCO₃ with CaO and CO₂ .
CO₂ : CaCO₃
1 : 1
0.49 : 0.49
CaO : CaCO₃
1 : 1
0.49 : 0.49
Mass of CaCO₃ decompose:
Mass = number of moles × molaer mass
Mass = 0.49 mol × 100.1 g/mol
Mass = 49 g
Answer:
CaO
Explanation:
A compound containing only carbon, hydrogen, and oxygen is analyzed using combustion analysis. When 50.1 g of the compound is burned, 91.8 g of carbon dioxide and 25.1 g of water are collected. In order to determine the moles of carbon in the compound, first determine the moles of carbon dioxide that were produced from the combustion.
Answer:
[tex]C_{3}H_4O_2[/tex]
Explanation:
Hello,
In this case, since the carbon of the initial compound is present in the carbon dioxide product, we can compute the mass and moles of carbon in the compound:
[tex]n_C=91.8g CO_2*\frac{1molCO_2}{44gCO_2} *\frac{1molC}{1molCO_2} =2.09molC\\\\m_C=91.8g CO_2*\frac{1molCO_2}{44gCO_2} *\frac{1molC}{1molCO_2}*\frac{12gC}{1molC} =25.0gC[/tex]
Next, the mass and moles of hydrogen in the compound, is contained in the yielded amount of water, thus, we compute the mass and moles of hydrogen in the compound:
[tex]n_H=25.1gH_2O*\frac{1molH_2O}{18gH_2O} *\frac{2molH}{1molH_2O} =2.79molH\\\\m_H=25.1gH_2O*\frac{1molH_2O}{18gH_2O} *\frac{2molH}{1molH_2O} *\frac{1gH}{1molH} =2.79gH[/tex]
In such a way, the mass of oxygen comes from the mass of the compound minus the mass of carbon and oxygen:
[tex]m_O=50.1g-25.0g-2.79g=22.31gO[/tex]
And the moles:
[tex]n_O=22.31gO*\frac{1molO}{16gO}=1.39molO[/tex]
Then, we compute the subscripts by diving the moles of C, H and O by the moles of oxygen as the smallest moles:
[tex]C:\frac{2.09}{1.39}=1.5 \\\\H:\frac{2.79}{1.39}=2\\ \\O:\frac{1.39}{1.39} =1[/tex]
After that, we write:
[tex]C_{1.5}H_2O[/tex]
Which must be shown in whole number only, thereby we multiply the subscripts by 2, so the empirical formula turns out:
[tex]C_{3}H_4O_2[/tex]
Best regards.
A 57.07 g sample of a substance is initially at 24.3°C. After absorbing of 2911 J of heat, the temperature of the substance is 116.9 CWhat is the specific heat (SH) of the substance?
Answer:
Approximately [tex]0.551\; \rm J\cdot kg^{-1} \cdot \left(^\circ\! C \right)^{-1}[/tex].
Explanation:
The specific heat of a material is the amount of energy required to increase unit mass (one gram) of this material by unit temperature (one degree Celsius.)
Calculate the increase in the temperature of this sample:
[tex]\Delta T = (116.9 - 24.3)\; \rm ^\circ\! C= 92.6\; \rm ^\circ\! C[/tex].
The energy that this sample absorbed should be proportional the increase in its temperature (assuming that no phase change is involved.)
It took [tex]2911\; \rm J[/tex] of energy to raise the temperature of this sample by [tex]\Delta T = 92.6\; \rm ^\circ\! C[/tex]. Therefore, raising the temperature of this sample by [tex]1\; \rm ^\circ\! C[/tex] (unit temperature) would take only [tex]\displaystyle \frac{1}{92.6}[/tex] as much energy. That corresponds to approximately [tex]31.436\; \rm J[/tex] of energy.
On the other hand, the energy required to raise the temperature of this material by [tex]1\; \rm ^\circ\! C[/tex] is proportional to the mass of the sample (also assuming no phase change.)
It took approximately [tex]31.436\; \rm J[/tex] of energy to raise the temperature of [tex]57.07\; \rm g[/tex] of this material by [tex]1\; \rm ^\circ C[/tex]. Therefore, it would take only [tex]\displaystyle \frac{1}{57.07}[/tex] as much energy to raise the temperature of [tex]1\; \rm g[/tex] (unit mass) of this material by [tex]1\; \rm ^\circ \! C\![/tex]. That corresponds to approximately [tex]0.551\; \rm J[/tex] of energy.
In other words, it takes approximately [tex]0.551\; \rm J[/tex] to raise [tex]1\; \rm g[/tex] (unit mass) of this material by [tex]1\; \rm ^\circ \! C[/tex]. Therefore, by definition, the specific heat of this material would be approximately [tex]0.551\; \rm J\cdot kg^{-1} \cdot \left(^\circ\! C \right)^{-1}[/tex].
Explain How does its structure affect its function
Answer:
What are we talking about here?
Explanation:
Vocabulary Terms: Please copy down the definitions for words below from the Smart Screen.
Length is defined as
Height is defined as
Circumference is defined as
Perimeter is defined as
Diagonal is defined as
Diameter is defined as
Answer:
Explanation:
Length: Length is a measure of distance
Height:The measurement from base to top or (of a standing person) from head to foot.
Circumference:The enclosing boundary of a curved geometric figure, especially a circle
Perimeter: Length of the outline of a shape.
Diagonal:A line segment that goes from one corner to another, but is not an edge. So when we directly join any two corners (called "vertices") which are not already joined by an edge, we get a diagonal. Diagonals of Polygons.
Diameter: A straight line passing from side to side of any figure or body, through its center.
Use the drop-down menu to complete the statement.
Atoms of elements in the same group have the same number of
. This is why they have similar chemical properties.
Answer:
valence electrons
Explanation:
other guy was close enough
Atoms of elements in the same group have the equal number of valence electrons. That is why they have similar chemical properties.
Why does the element in the same group have similar chemical behavior?The chemical properties of elements depend on the number of valence electrons in their outermost shell. Those elements which are placed in the same group in the periodic table have the same number of valence electrons.
Therefore, elements present in the same group of the modern periodic table have similar chemical behavior.
The elements having a similar valence shell electronic configuration in their atoms are arranged in the same group of the periodic table. These valence electrons decide the chemical properties and reactivities of the chemical elements.
For example, all the elements in group 1 of the periodic table have one electron in their valence shell and all the elements present in group 17 have seven electrons in their valence shell.
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The heat of fusion for naphthalene is 0.148 kJ/g. Calculate the heat energy in joules required to melt 52.95 g of naphthalene.
Answer:
7836.6 J
Explanation:
The following data were obtained from the question:
Heat of fusion (Hf) = 0.148 KJ/g
Mass (m) = 52.95 g
Heat (Q) required =..?
The heat (Q) required to melt the sample of nephthalene can be obtained as follow:
Q = m·Hf
Q = 52.95 × 0.148
Q = 7.8366 KJ
Finally, we shall convert 7.8366 KJ to Joule (J) in order to obtain the desired result. This can be obtained as follow:
1 kJ = 1000 J
Therefore,
7.8366 KJ = 7.8366 KJ × 1000 J / 1 KJ
7.8366 KJ = 7836.6 J
Therefore, 7.8366 KJ is equivalent to 7836.6 J
Thus, 7836.6 J of heat energy is required to melt the sample of nephthalene.
The heat required for melting of 52.95 g of naphthalene has been 7.8366 kJ.
The heat of fusion has been the energy required by 1g for the change in the substance.
The heat required to melt naphthalene can be given as:
Heat = mass × Heat of fusion
The given mass = 52.95 g
The heat of fusion = 0.148 kJ/g
The heat required can be given as:
Heat = 0.148 × 52.95 kJ
Heat = 7.8366 kJ.
The heat required for melting of 52.95 g of naphthalene has been 7.8366 kJ.
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1.547 grams of hydrated MgSO4 is heated in a crucible. After heating, 0.7554 grams of anhydrous MgSO4 remains in the crucible. How many waters of hydration were attached to the MgSO4
Answer:
7
Explanation:
Let x represent the number of moles of water in the hydrated salt i.e MgSO₄.xH₂O
The following data were obtained from the question:
Mass of MgSO₄.xH₂O = 1.547 g
Mass of anhydrous MgSO₄ = 0.7554 g
Mole of H₂O = x =?
Next, we shall determine the mass of water, H₂O in the hydrated salt, MgSO₄.xH₂O. This can be obtained as follow:
Mass of MgSO₄.xH₂O = 1.547 g
Mass of anhydrous MgSO₄ = 0.7554 g
Mass of H₂O =?
Mass of H₂O = (Mass of MgSO₄.xH₂O) – (Mass of anhydrous MgSO₄)
Mass of H₂O = 1.547 – 0.7554
Mass of H₂O = 0.7916 g
Finally, we shall determine the value of the x as illustrated below:
Mass of MgSO₄.xH₂O = 1.547 g
Molar mass of MgSO₄.xH₂O = 24 + 32 + (16×4) + x[(2×1) + 16]
= 24 + 32 + 64 + x(2 + 16)
= 120 + 18x
Mass of H₂O = 0.7916 g
Molar mass of xH₂O = 18x
Molar Mass of xH₂O/ Molar mass of MgSO₄.xH₂O = mass of xH₂O /Mass of MgSO₄.xH₂O
18x/ 120 + 18x = 0.7916/1.547
Cross multiply
0.7916 (120 + 18x) = 18x × 1.547
94.992 + 14.2488x = 27.846x
Collect like terms
94.992 = 27.846x – 14.2488x
94.992 = 13.5972x
Divide both side by 13.5972
x = 94.992 / 13.5972
x = 7
Thus, the formula for the hydrated salt, MgSO₄.xH₂O is MgSO₄.7H₂O
Number of moles of water, H₂O in the hydrated salt MgSO₄.7H₂O is 7.
The number of moles of attached water molecules is 7.
Mass of hydrated MgSO4 = 1.547 grams
Mass of anhydrous MgSO4 = 0.7554 grams
Number of moles of hydrated MgSO4 = 1.547 grams/120 + 18x
Number of moles of anhydrous MgSO4 = 0.7554 grams /120
Number of moles of anhydrous salt = Number of moles of hydrated salt
0.7554 grams /120 = 1.547 grams/120 + 18x
0.7554(120 + 18x) = 1.547 × 120
90.6 + 13.6x = 185.6
185.6 - 90.6 /13.6 = x
x = 7
The number of moles of attached water molecules is 7.
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