A wave has frequency of 50 Hz and a wavelength of 10 m. What is the speed of the wave? Group of answer choices

Answer:

1.0125 x 10^19

Explanation:

current flowing through conductive wire= 9mA = 9 x 10^ -3 A

charge passing per 3 min

Q = It

= 9 x 10^ -3 x (3 x 60)

= 1.620 C

no of electrons in charge

Q = ne

1.620 = n x 1.6 x 10 ^ -19

n. = 1.0125 x 10 ^19

Answer:

2.5m/s²

Explanation:

Given parameters:

Mass of car  = 1400kg

Resultant force  = 3500N

Speed  = 30m/s

Unknown:

Average acceleration = ?

Solution:

According to the Newton's second law of motion:

     Force  = mass x acceleration

Now;

       3500 = 1400 x acceleration

      Acceleration  = [tex]\frac{3500}{1400}[/tex]   = 2.5m/s²

Answer:

elements

not really an explanation

Answer:

Approximately [tex]5.5\; \rm N[/tex], assuming that the volume of these two charged objects is negligible.

Explanation:

Assume that the dimensions of these two charged objects is much smaller than the distance between them. Hence, Coulomb's Law would give a good estimate of the electrostatic force between these two objects regardless of their exact shapes.

Let [tex]q_1[/tex] and [tex]q_2[/tex] denote the magnitude of two point charges (where the volume of both charged object is negligible.) In this question, [tex]q_1 = 20 \times 10^{-6}\; \rm C[/tex]  and [tex]q_2 = 15 \times 10^{-6}\; \rm C[/tex].

Let [tex]r[/tex] denote the distance between these two point charges. In this question, [tex]r = 0.7\; \rm m[/tex].

Let [tex]k[/tex] denote the Coulomb constant. In standard units, [tex]k \approx 8.98755\times 10^{9}\; \rm kg \cdot m^{3}\cdot s^{-2}\cdot C^{-2}[/tex].

By Coulomb's Law, the magnitude of electrostatic force (electric force) between these two point charges would be:

[tex]\begin{aligned}F &= \frac{k \cdot q_1 \cdot q_2}{r^{2}}\end{aligned}[/tex].

Substitute in the values and evaluate:

[tex]\begin{aligned}F &= \frac{k \cdot q_1 \cdot q_2}{r^{2}}\\ &\approx 8.98755 \times 10^{9}\; \rm kg \cdot m^{3}\cdot s^{-2}\cdot C^{-2} \\ &\quad \times 20\times 10^{-6}\; \rm C\\ &\quad \times 15\times 10^{-6}\; \rm C \\ &\quad \times \frac{1}{{(0.7\; \rm m)}^{2}}\\ &\approx 5.5\; \rm N \end{aligned}[/tex].

Answer:

B is the difference قصدي لا انا اعرف بشير بس ما اعرف اخوه يعني *قصدي لا انا اعرف بشير بس ما اعرف اخوه يعني *قصدي لا انا اعرف بشير بس ما اعرف اخوه يعني *قصدي لا انا اعرف بشير بس ما اعرف اخوه يعني *قصدي لا انا اعرف بشير بس ما اعرف اخوه يعني *

Answer:

The change in velocity is 5.5 km/h

Explanation:

The initial velocity with which the sailboat is travelling, v₁ = 10 km/h

The final velocity with which the sailboat is travelling, v₂ = 15.5 km/h

The change in velocity, Δv, is the difference between final velocity, v₂ and the initial velocity, v₁, as follows;

Mathematically, Δv = v₂ - v₁

By substituting the given values, we have;

Δv = 15.5 km/h - 10 km/h = 5.5 km/h

The change in velocity, of the sailboat Δv = 5.5 km/h.

Answer:

299,792,458 m/s = speed of light

Explanation:

Explanation:

W=f×d

=20×6

w=120 joule

Answer:

The true statements are;

The median of A is the same as the median of B

The interquartile range of B is greater than the interquartile range of A

Explanation:

The given parameters are;

The set of the number of runs, A = {1, 4, 2, 2, 3, 1, 1, 2, 1}

The number of runs the pitcher allows in the tenth game = 9 runs

The set of the number of runs allowed in 10 games B = {1, 4, 2, 2, 3, 1, 1, 2, 1, 9}

Rearranging the data, we get  

A = 1, 1, 1, 1, 2, 2, 2, 3, 4

B = 1, 1, 1, 1, 2, 2, 2, 3, 4, 9

For the set A, we have;

Q₁ = 1, Q₂ = 2, Q₃ = 2

Therefore, the interquartile range of A = Q₃ - Q₁ = 2.5 - 1 = 1.5

For the set B, we have;

Q₁ = 1, Q₂ = 2, Q₃ = 2

Therefore, the interquartile range of A = Q₃ - Q₁ = 3.25 - 1 = 2.25

Therefore, the correct answers with regards to the two data are;

The median of A is the same as the median of B

The interquartile range of B is greater than the interquartile range of A

Answer:

blood picks up waste products such as carbon dioxide

returns to right atrium

moves to right ventricle and to lungs

blood travels from the lungs to the left atrium

carries oxygen and nutrients to the body cells

Explanation:

In the circulatory system, the blood carries the carbon dioxide to the right atrium of the heart through superior vena cava, then it move to right ventricle through tricuspid valve. The blood move to lungs following pulmonary artery and from lungs blood travels to the left atrium. From left atrium blood moves to the rest of the body through aorta and carries oxygen and nutrients to the whole body cells through.

Hence, the correct order is as follows:

blood picks up waste products such as carbon dioxide

returns to right atrium

moves to right ventricle and to lungs

blood travels from the lungs to the left atrium

carries oxygen and nutrients to the body cells

Answer:

1.  -0.863 kgm/s 2. -1.438 kgm/s

Explanation:

1. What is the change in momentum of the bullet if it embeds in the block?

Since the block does not move, the velocity of the bullet after hitting the block , v is zero. That is v = 0 m/s

Now, the momentum change of the bullet ΔP = m(v - u) where m = mass of block = 5.75 g = 5.75 × 10⁻³ kg, u = initial velocity of bullet = 1.50 × 10² m/s and v = final velocity of bullet after hitting the block = 0 m/s (since it embeds in the block and the block does not move).

So, ΔP = m(v - u)

= 5.75 × 10⁻³ kg(0 m/s - 1.50 × 10² m/s)

= 5.75 × 10⁻³ kg(- 1.50 × 10² m/s)

= -8.625 × 10⁻¹ kgm/s

= -0.8625 kgm/s

≅ -0.863 kgm/s

2. What is the change in momentum of the bullet if it bounces off the block in the opposite direction with a speed of 100 m/s?

If it bounces off the block in the opposite direction with a speed of 100 m/s, then its final velocity is v = -100 m/s.

So, our momentum change ΔP' = m(v - u) where m = mass of block = 5.75 g = 5.75 × 10⁻³ kg, u = initial velocity of bullet = 1.50 × 10² m/s and v = final velocity of bullet after hitting the block = -100 m/s = -1 × 10² m/s

So, ΔP = m(v - u)

= 5.75 × 10⁻³ kg(-1 × 10² m/s - 1.50 × 10² m/s)

= 5.75 × 10⁻³ kg(-2.50 × 10² m/s)

= -14.375 × 10⁻¹ kgm/s

= -1.4375 kgm/s

≅ -1.438 kgm/s

Answer:

b

Explanation:

element z are isotopes because number of netron are different and number of protons are same

Answer:

B

Explanation:

I can't explain right now, mabe later.

Answer:

The index of refraction varies with frequency or color. Frequency does not change as light travels from one medium to another.

Explanation:

Green light has a higher refractive index than orange light for the same material because orange color has a higher wavelength than green light and if the wavelength of light increases the refractive index decreases.

The distance between two identical locations (adjacent crests) in successive cycles is known as the wavelength, and it is used to describe waveform signals that are transmitted over wires or into space. Typically, in wireless systems, this length is specified in meters (m), centimeters (cm), or millimeters (mm). The wavelength is more frequently described in nanometers (nm), which are units of 10-9 m, or angstroms, which are units of 10-10 m, for infrared (IR), visible light (UV), and gamma radiation.

Frequency, which is defined as the number of wave cycles per second, and wavelength have an inverse relationship. The wavelength of a signal decreases with increasing frequency, or we can say that wavelength and refractive index are inversely proportional to each other.

To get more information about Wavelength :

https://brainly.com/question/13533093

#SPJ5

Answer:

The new force is 2.8125 N

Explanation:

Newton’s Law of Universal Gravitation

Objects attract each other with a force that is proportional to their masses and inversely proportional to the square of the distance.  

[tex]\displaystyle F=G{\frac {m_{1}m_{2}}{r^{2}}}[/tex]

Where:

m1 = mass of object 1

m2 = mass of object 2

r     = distance between the objects' center of masses

G   = gravitational constant: 6.67\cdot 10^{-11}~Nw*m^2/Kg^2

Suppose two spheres have a gravitational force between them of F = 45 N. Now increase the distance to r'=4r. The new force F' is:

[tex]\displaystyle F'=G{\frac {m_{1}m_{2}}{(4r)^{2}}}[/tex]

[tex]\displaystyle F'=G{\frac {m_{1}m_{2}}{16r^{2}}}[/tex]

[tex]\displaystyle F'=\frac{1}{16}\ G{\frac {m_{1}m_{2}}{r^{2}}}[/tex]

Substituting the original value of the force:

[tex]\displaystyle F'=\frac{1}{16}\ 45 N[/tex]

F' = 2.8125 N

The new force is 2.8125 N

Answer:

A. The expected electricity bill for this month is Rs 18,896.2

B. The item which consumed the most energy during the month is the electric cooker with a total consumption of 1,110Kw/Month

Explanation:

Step 1 - Identify electrical appliances

I only have 8 electrical appliances in my home.

Step 2 - Assign usage per hour and calculate wattage used /month

Step 3 - Add up all the Kw used per month and multiply by the cost of 1 Kw

Total Kilowatt Consumed/Month = 1110 +108+120+10+84.6+421.2+29.7+6.12

= 1,889.62Kw/Month

Total cost of energy consumed per month = 1889.62 * Rs 10

= Rs 18,896.2

Cheers!

Answer:

The force of Gravity on the ball

Explanation:

Gravity of earth pulls the ball back down to the ground.

Answer:

a) 1.55 m/s

b) 2.3 m/s

Explanation:

We know that the boat travels across the river, if we define the river as the x-axis, then the velocity of the boat is only on the y-axis.

Then we can write the velocity of the boat in still water as:

S = (0, B)

Now, when the boat is on the river, the velocity of the boat will be equal to the velocity of the boat in still water plus the velocity of the river.

The velocity of the river is:

v = (R, 0).

Then the velocity of the boat in that river is:

V' = (0, B) + (R, 0) = (R, B)

Now, we know that the velocity of the boat is 10km/h, and it travels at an angle of 34° with respect to the shore.

We can use the Pythagoreans theorem to write the components of this velocity as:

x-axis component = 10km/h*cos(34°) = 8.29 km/h

y-axis component = 10km/h*sin(34°) =  5.59 km/h

Then the velocity of the boat can be written in components as:

velocity = ( 8.29 km/h,  5.59 km/h)

And we knew that the velocity of the boat was written as  (R, B)

Then we must have:

R = 8.29 km/h

B = 5.59 km/h

a) The speed of the boat in m/s:

We know that the speed of the boat is 5.59 km/h.

First, we know that:

1km = 1000m, then:

5.59 km/h = 5.59*(1000m)h = 5,590 m/h

And we know that:

1h = 3600s

Then we can write:

5,590 m/h = 5,590 m/(3600s) = 1.55 m/s

b) The speed of the river in m/s:

We know that the speed of the river is 8.29 km/h

Using the same reasoning as above, we can do the change of units as follows:

8.29 km/h = 8.29 (1000m)/(3600s) = 2.3 m/s

Answer:

52.802

Explanation:

"Significant figures" in Mathematics refer to the digits that give accuracy to the value of a measurement. There are specific rules when it comes to determining the significant figures. For example, all non-zero digits are considered significant and zeroes located in-between non-zero numbers are significant. In the number given above, the digit "0" is located between "8" and "1," therefore, it is significant. All the digits above are significant.

The problem is only asking for "five" significant figures. We can do this by counting from the left to the right. By this means, we know that the number will be rounded off to the nearest thousandths, which is "1." The number after 1 is 5, which means that 1 digit will be added to number 1, thus, making the digit into "2." The last digit (5) will then be removed.

Explanation:

five significant of 52.8015=52.801 ..

Answer:

28.1 m/s

Explanation:

[tex]u_x[/tex] = Initial velocity of the fish = 1.52 m/s

y = Height of the bird = 40 m

[tex]a_y[/tex] = Acceleration in y axis = [tex]9.81\ \text{m/s}^2[/tex]

[tex]u_y[/tex] = Initial velocity in y axis = 0

[tex]y=u_yt+\dfrac{1}{2}a_yt^2\\\Rightarrow 40=0+\dfrac{1}{2}\times 9.81t^2\\\Rightarrow t=\sqrt{\dfrac{40\times 2}{9.81}}\\\Rightarrow t=2.86\ \text{s}[/tex]

[tex]v_y=u_y+a_yt\\\Rightarrow v_y=0+9.81\times 2.86\\\Rightarrow v_y=28.057\ \text{m/s}[/tex]

The final velocity in x direction will remain the same as the initial velocity as there is no acceleration in the x direction [tex]u_x=v_x=1.52\ \text{m/s}[/tex]

Resultant velocity is given by

[tex]v=\sqrt{v_x^2+v_y^2}\\\Rightarrow v=\sqrt{1.52^2+28.057^2}\\\Rightarrow v=28.1\ \text{m/s}[/tex]

The fish is moving at a velocity of 28.1 m/s when it hits the water.

Answer:

W= F × d

W= 2kn × 3.6

W= 7.2 J

Work is measured in Joules!

Answer: It is a transverse wave ^^

Explanation:

Answer

given :

m=1.4 kg

r/q = N

N = m(9.8)

= 1.4 kg(9.8)

= 13.72 Newton

Answer:

9.8066500286389 N

Explanation:

Answer:

See the answer below

Explanation:

The time Laura took to reach the post office would depend on the speed of cycling.

We know that;

 speed = [tex]\frac{distance}{time}[/tex]

hence,

time = [tex]\frac{distance}{speed}[/tex]

Since the distance from Laura's house to the post office is 4 km, the equation becomes;

time = [tex]\frac{4}{speed}[/tex]

Just ensure that the speed is in km per hour, minute, or seconds in order to obtain the time in hours, minutes, or seconds respectively.

Answer:

25 km/h

Explanation:

speed=distance÷time

125÷5=speed

125÷5=25 (then add units)