Alang and his children went into a grocery store that sells apples for $2 each and peaches for $0.50 each. Alang has $20 to spend and must buy a minimum of 16 apples and peaches altogether. If xx represents the number of apples purchased and yy represents the number of peaches purchased, write and solve a system of inequalities graphically and determine one possible solution.

Answers

Answer 1

The system of inequalities has been solved graphically and one possible solution is buying 4 apples and 12 peaches.

How to write and solve the system of inequalities graphically?

In order to write a system of linear inequalities to describe this situation, we would assign variables to the number of apples purchased and number of peaches purchased by Alang and his children, and then translate the word problem into algebraic equation as follows:

Let the variable x represent the number of apples purchased.Let the variable y represent the number of peaches purchased.

Since apples for $2 each and peaches for $0.50 each, the cost of fruits is given by:

2x + 0.5y ≤ 20

Also, they must buy a minimum of 16 apples and peaches altogether:

x + y ≥ 16

Therefore, a possible solution when x = 4 is given by:

x + y ≥ 16

4 + y ≥ 16

y ≥ 16 - 4

y ≥ 12

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Alang And His Children Went Into A Grocery Store That Sells Apples For $2 Each And Peaches For $0.50

Related Questions

A & B = (A + B) x A + (A - B) divided by B. find the value of 4 & - 2.

Answers

Answer:

-7

Step-by-step explanation:

A= 4

B= -2

((4-2) × 4 + (4+2))/-2

14/-2

-7

There are two more quarters than dimes and as many nickles as quarters and dimes together. The total amount of money is 3.75. How many quarters, dimes and nickles are there?

Answers

Answer: 9 quarters, 7 dimes, & 16 nickels

Step-by-step explanation:

We set number of dimes as d:

Number of quarters: d + 2Number of nickels: d + 2 + d = 2d + 2

So, set up the equation to solve:

[tex]0.10d+0.25(d+2)+0.05(2d+2)=3.75\\\\0.10d+0.25d+0.5+0.1d+0.1=3.75\\\\0.45d=3.75-0.5-0.1=3.15\\\\d=7[/tex]

So now that we know there're seven dimes, we can plug them in our initial equations to find the number of quarters and nickels:

Number of quarters: d + 2 = 7 + 2 = 9Number of nickels: d + 2 + d = 2d + 2 = 2(7) + 2 = 16

Special right triangles

Answers

In the special right triangle, x has a value of √3/2

Special Right Triangle

A special right triangle is a right triangle with some regular feature that makes calculations on the triangle easier, or for which simple formulas exist. For example, a right triangle may have angles that form simple relationships, such as 45°–45°–90°. This is called an "angle-based" right triangle.

To find the value of x, we should take into consideration that two of the sides of the triangle are equal to each other.

Using Pythagoras theorem;

[tex](\sqrt{3}) ^2 = x^2 + x^2\\3 = 2x^2\\x^2 = \frac{3}{2} \\x = \sqrt{\frac{3}{2} }[/tex]

The value of x in the triangle is √3/2

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I need help please please

Answers

In the given triangle LMN, measure of side LM = 18in. and measure of angle MLN is 28° then the measure of side LN = 18in. , m ∠M = 76° and

m ∠N = 76°.

As given in the question,

In the given triangle LMN,

Measure of side LM = 18in.

Measure of angle MLN is equal to 28°

It is given that side LM ≅ LN

LM = 18 in.

LN = 18in.

In a triangle  LMN ,

In a triangle opposite sides are congruent to each other then angle opposite to them also congruent to each other.

LM ≅LN

⇒m ∠N = m ∠M

In a ΔLMN,

Let x° be the measure of angle M and N each.

m ∠M + m ∠N + m ∠L = 180°

⇒ x° + x° + 28° = 180°

⇒ 2x° = 180° -28°

⇒2x° = 152°

⇒ x = 76°

Therefore, in the given triangle LMN, measure of side LM = 18in. and measure of angle MLN is 28° then the measure of side LN = 18in. , m ∠M = 76° and m ∠N = 76°.

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find the common difference d to make 5 comma space x comma space y comma space 32 as a part of an arithmetic sequence.

Answers

The common difference 9 will make 5, x, y, 32 an arithmetic sequence of 5, 14, 23, 32.

It is given that the arithmetic sequence is

5, x, y, 32

We know that for any arithmetic sequence the term aₙ is

aₙ = a + (n - 1)d

where,

a = first term

n = order of the value in the sequence

Since x is the second term

x = 5 + (2 - 1)d

or, x = 5 + d

Similarly,

y = 5 + 2d

32 = 5 + 3d

or, 3d = 27

or, d = 9

Hence, x = 14

y = 5 + 18

= 23

Hence, the common difference is 9

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Lucy owes three of her friends 5.60 each how much money does Lucy owe in total

Answers

Answer:

16.80

Step-by-step explanation:

The ratio is 1:5.60. Where 1 is the amount of friends and 5.60 is the amount owed. Since there are 3 friends, multiply 5.60 by 3.

Answer: 16.8

Step-by-step explanation: basically multiply 5.60 by 3 (5.60 x 3 = 16.8) or add 5.60 3 times (5.60 + 5.60 + 5.60 = 16.8)

inside a square with side length $10$, two congruent equilateral triangles are drawn such that they share one side and each has one vertex on a vertex of the square. what is the side length of the largest square that can be inscribed in the space inside the square and outside of the triangles?

Answers

Using the concepts of equilateral triangle, we got that  2.113 is the side length of the largest square that can be inscribed in the space inside the square and outside of the triangles.

Firstly we find the side length of equilateral triangle , G is the midpoint of side FE.

Let GE=x, since G is the midpoint due to that DE=GB.

So, using basic trigonometry=DG^GB=x√3.

Thus DB=2x√3.

Since DB is the diagonal of ABCD, it has length 10√2 Then we can set up the equation 2x√3=10√2. So the side length of the triangle is

2x=(10√2)/√3.

Now look at the diagonal AC it is made up of twice the diagonal of the small square plus the side length of the triangle. Let the side length of the small square be y:

Let the side length of the small square be y:

AC=y√2 + [(10√2)/√3]+y√2=10√2.

Solving  for y:

=>y√2+y√2 + (10√2√3)/3=10√2

=>y√2+y√2 + (10√6)/3=10√2

=> [3y√2+3y√2 + (10√6)] /3=10√2

=>6y√2+10√6=30√2

=>6y√2 = 30√2-10√6

=>y√2 = (30√2-10√6)/6

=>y = (30√2-10√6)/6√2

=>y = (60-20√3)/12

=>y= 5(3−√3)3  or 2.113

Hence, inside a square with side length 10, two congruent equilateral triangles are drawn such that they share one side and each has one vertex on a vertex of the square. the side length of the largest square that can be inscribed in the space inside the square and outside of the triangles is to be 2.113.

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If x is 60% of y and y is 30% of z, x is what percent of z?

Answers

Answer:

18%

Step-by-step explanation:

x is 60% of y

[tex]x = y*\frac{60}{100} =y*0.6=0.6y\\x=0.6y[/tex]

y is 30% of z

[tex]y = z*\frac{30}{100} =z*0.3=0.3z\\y=0.3z[/tex]

x is what percent of z?

Since x = 0.6y and y = 0.3z:

[tex]\%=\frac{x}{z} *100\\\\\%=\frac{0.6y}{z}*100\\ \\\%=\frac{0.6(0.3z)}{z} *100\\\\\%=\frac{0.18z}{z} *100\\\\\%=0.18*100\\\\\%=18[/tex]

Shivani won the raffle at the zoo and gets to feed the dolphins! The dolphin trainer gives
Shivani a bucket of fish to divide evenly among 3 dolphins. Each dolphin gets 6 fish.
Which equation can you use to find the number of fish f in the bucket before Shivani feeds
the dolphins?
Pls help ASAP

Answers

Answer:

Step-by-step explanation:

f/4 = 3

3/8 x 4/3 please help me I’ve been stuck at this

Answers

Answer:

1/2

Step-by-step explanation:

Answer:

1/2

Step-by-step explanation:

3/8*4/3

The 3 can be cancel out

you can also cancel out 8 and 4

leaving you with 1/2

Find a polynomial function with real coefficients that has the given zeros
-1, 8,3 - 21,

Answers

A polynomial function with real coefficients that has the given zeros -1, 8, 3, -21 is x^4−11x^3−197x^2−297x+504.

In the given question we have to find a polynomial function with real coefficient that has the given zeros -1, 8,3, -21.

The given zeros are -1, 8,3 - 21.

Let the variable is x.

So the factor from the given zeros are

(x-1), (x+8), (x+3), (x-21)

To find the polynomial we multiply the factors to each other.

=(x-1)(x+8)(x+3)(x-21)

We firstly multiply the factor with the pair of two using the distributive property.

={x(x-1)+8(x-1)}{x(x+3)-21(x+3)}

=(x^2-x+8x-8)(x^2+3x-21x+63)

Simplifying

=(x^2+7x-8)(x^2-18x+63)

=x^2(x^2+7x-8)-18x(x^2+7x-8)+63(x^2+7x-8)

=(x^4+7x^3-8x^2)-(18x^3+126x^2-144x)+(63x^2+441x-504)

=x^4+7x^3-8x^2-18x^3-126x^2+144x+63x^2+441x-504

=x^4−11x^3−197x^2−297x+504

Hence, a polynomial function with real coefficients that has the given zeros -1, 8, 3, -21 is x^4−11x^3−197x^2−297x+504.

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Darnelle has a $10,000, three-year loan with an APR of 5%. She uses the table below to compute information on the loan.

a. What is her monthly payment?

b. What is the total of all her monthly payments?

c. What is the total finance charge?

Answers

Given data
Principal = $10.000
Rate= 5 %= 0.05
Time = 6years (Assume)
A = p(1+rt)
A = 10.000/1+0.05×6)
A = 10,000(1+0.30)
A = 10.000/1.30)
A = 13.000
So the final amount for simple interest is $13,000
To determine her monthly payment
Given that it is spread over 6 years
There are 12×6 months= 72months
So monthly pay = 10000/72 = $180.56
The total of all her monthly payments would be $13,000 which is equal to the
final amount.

So the final amount for simple interest is $13,000
To determine her monthly payment
Given that it is spread over 6 years
There are 12×6 months= 72months
So monthly pay = 10000/72 = $180.56
The total of all her monthly payments would be $13,000 which is equal to the
final amount.
The finance charge is equal to the interest.
- $13.000 - $10.000 = $3000
So the finance charge would be $3000.
Therefore, her monthly payment would be $180.56, the total of all her
monthly payments would be $13,000 and the total finance charge is $3000

Q5.
Heres a formula
r = √(w² − h² )
Work out the value of r when w=9√2 and h=5root6.
Give your answer in the form
a√b
where a and b are integers greater than 1.

Answers

Answer:

r = 2[tex]\sqrt{3}[/tex]

Step-by-step explanation:

using the rules of radicals

[tex]\sqrt{a}[/tex] × [tex]\sqrt{b}[/tex] ⇔ [tex]\sqrt{ab}[/tex]

([tex]\sqrt{x}[/tex] )² = x

substitute the given values of w and h into the equation

r = [tex]\sqrt{w^2-h^2}[/tex]

  = [tex]\sqrt{(9\sqrt{2})^2-(5\sqrt{6})^2 }[/tex]

  = [tex]\sqrt{162-150}[/tex]

  = [tex]\sqrt{12}[/tex]

  = [tex]\sqrt{4(3)}[/tex]

  = [tex]\sqrt{4}[/tex] × [tex]\sqrt{3}[/tex]

  = 2[tex]\sqrt{3}[/tex]

marley's bank charges a $3 service fee each time money is whithdrawn from another bank's atm. Marley is traveling and must withdraw money from another bank's atm 4 times. Which expressions model the charge in the balance of her account due to service fees?

Answers

The expressions represent the service fee charge on her account balance is 4x+3.

Given that,

Every time money is withdrawn from an ATM run by a different bank, Marley's Bank levies a $3 service fee. Marley needs to make four ATM withdrawals from a different bank while she is abroad.

We have to find which expressions represent the service fee charge on her account balance.

The expression we can write as,

4x+3

Because 4 times he has taken from ATM money and adding the service fee $3.

Therefore, The expressions represent the service fee charge on her account balance is 4x+3.

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If f(x) = 4x5 - x - 3, then what is the remainder when f(x) is divided by x - 3?​

Answers

The remainder of the division of the given polynomial by (x - 3) is 966.

From the question, we have

f(x) = 4x^5 - x - 3

The remainder of the division is the f(x) at x= 3

f(3) = 4*3^5 - 3 - 3

=972-6

=966

Multiplication:

Finding the product of two or more numbers in mathematics is done by multiplying the numbers. It is one of the fundamental operations in mathematics that we perform on a daily basis. Multiplication tables are the main use that is obvious. In mathematics, the repeated addition of one number in relation to another is represented by the multiplication of two numbers. These figures can be fractions, integers, whole numbers, natural numbers, etc. When m is multiplied by n, either m is added to itself 'n' times or the other way around.

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Lourdes is reading a biography for her history class. She reads 30 pages each day. After 9 days, Lourdes has read (3)/(5) of the biography. Write a linear equation to represent the number of pages Lourdes still has to read after x days.

Answers

The linear equation is z = 450 - 30 x, where z is the number of pages Lourdes has left to read after x days

We need to write a linear equation to represent the number of pages

Lourdes has left the number of pages to read after x days

Lourdes reads 30 pages each day

Lourdes will read for x days

The number of pages Lourdes will read in x day = 30 x

The left pages will be the difference between the total pages of the

book and the pages Lourdes read.

After 9 days Lourdes completes 3/5 of the total number of pages.

So the  number of pages Lourdes reads after 9 days = 30×9 = 270 pages.

Let The total number of pages in the book = y

Therefore 3/5 × y = 270.

So y = 270 × (5/3) = 450 pages.

The total number of pages in the book = 450 pages.

Lourdes will read 30 x in x days

The number of pages left = 450 - 30 x

Assume that z represents the number of pages Lourdes has left to read after x days

z = 450 - 30 x

The linear equation is z = 450 - 30 x, where z is the number of pages Lourdes has left to read after x days

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A group of friends wants to go to the amusement park. They have $89.50 to spend on parking and admission. Parking is $7.75, and tickets cost $27.25 per person, including tax. Write and solve an equation which can be used to determine p, the number of people who can go to the amusement park.

I had trusted a VERIFIED answer and got it wrong, so for everyone in the future, here is the correct answer.


Answers:

Equation: 27.25p + 7.75 = 89.5

Answer: p = 3

Answers

The equation which can be used to determine p is 7.75 + 27.25p = 89.50, then the number of people who can go to the amusement park is 3

The total amount that they have to spend on parking and admission = $89.50

The parking cost = $7.75

The ticket cost including tax = $27.25

Consider the number of people who can go to amusement park as p

Then the equation will be

7.75 + 27.25p = 89.50

Subtract both side of the equation by 7.75

27.25p + 7.75 - 7.75 = 89.50 - 7.75

27.25p = 81.75

Divide both side of the equation by 27.25

27.25p / 27.25 = 81.75 / 27.25

p = 3

Hence, the equation which can be used to determine p is 7.75 + 27.25p = 89.50, then the number of people who can go to the amusement park is 3

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5.03 exam Solve three and two fifths plus three and four sixths

Answers

Answer:

seven and two thirtieths

Step-by-step explanation:

3 2/5 + 3 4/6 find an equal value between 5 and 6

3 12/30 + 3 20/30

12+20=32

32/30=1 2/30

3+3+1=7

7 2/30

select all of the following statements that are true
1. if 6 > 10, then 8 x 3 = 24
2. 6 + 3 = 9 and 4 x 4 = 16
3. if 6 x 3 = 18 then 4+8=20
4. 5x3=15 or 7+5 = 20

Answers

The statements that is true are "6 + 3 = 9 and 4 x 4 = 16" , the true statement is (2) .

In the question ,

four statements are given ,

we need to find which statement is true ,

Option(1) ,

if 6 > 10, then 8 x 3 = 24

we know , that 10 > 6 , but it is given that 6 > 10 ,

hence the statement is false  .

Option(2)

6 + 3 = 9 and 4 x 4 = 16

we know , that 6+3=9 and 4×4=16

so , the statement is true .

Option(3)

if 6 x 3 = 18 then 4+8=20

we know , that 4+8 = 12 , but it is given that 4+8=20

So , the statement is false ,

Option(4)

5x3=15 or 7+5 = 20

we know , that 7+5 = 12 , but it is given that 7+5=20

So , the statement is false .

Therefore , The statements that is true are "6 + 3 = 9 and 4 x 4 = 16" , the true statement is (2) .

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a fair 6-sided die is repeatedly rolled until an odd number appears. what is the probability that every even number appears at least once before the first occurrence of an odd number?

Answers

The probability that every even number appears at least once before the first occurrence of an odd number is  [tex]\frac{1}{20}[/tex]

Take  [tex]A_{k}[/tex]  - the event that odd number appeared on the k-th throw,  B  - every even number appeared at least once.

Let’s find  P(B|[tex]A_{k}[/tex]) . Note that this probability is 0 for  k∈{1,2,3}  as you need  k≥4  to place all distinct even numbers before the odd one.

Now for  k≥4  we need to use the formula of inclusions and exclusions:  P(B¯|[tex]A_{k}[/tex])=P(C2+C4+C6|[tex]A_{k}[/tex])=

=P(C2|[tex]A_{k}[/tex])+P(C4|[tex]A_{k}[/tex])+P(C6|[tex]A_{k}[/tex])−P(C2C4|[tex]A_{k}[/tex])−P(C2C6|[tex]A_{k}[/tex])−P(C4C6|[tex]A_{k}[/tex])  where  Ci  is the event that the dice i is missing.

These probabilities are:

P(Ci/[tex]A_{k}[/tex])=[tex](\frac{2}{3} )^{k-1}[/tex]

P(CiCj|[tex]A_{k}[/tex])=[tex](\frac{1}{3} )^{k-1}[/tex]

So

P(B|[tex]A_{k}[/tex])=1–P(B¯|[tex]A_{k}[/tex])=1−3⋅[tex](\frac{2}{3} )^{k-1}[/tex]+3[tex](\frac{2}{3} )^{k-1}[/tex].= 1 − [tex]\frac{9}{2}[/tex].[tex](\frac{2}{3} )^{k}[/tex]+9[tex](\frac{1}{3} )^{k}[/tex]

Now as  P([tex]A_{k}[/tex])= [tex]\frac{1}{2^{k} }[/tex]we conclude that

P(B) = ∞∑k=4P(B/[tex]A_{k}[/tex])P([tex]A_{k}[/tex])=  ∞∑k=4([tex](\frac{1}{2} )^{k}[/tex]−[tex]\frac{9}{2}[/tex][tex](\frac{1}{3} )^{k}[/tex]+9.[tex](\frac{1}{6} )^{k}[/tex])=

=[tex]\frac{\frac{1}{16} }{\frac{1}{2} }[/tex]−[tex]\frac{\frac{1}{18} }{\frac{2}{3} }[/tex]+[tex]\frac{\frac{1}{144} }{\frac{5}{6} }[/tex] = [tex]\frac{1}{8}[/tex] -[tex]\frac{1}{12}[/tex] + [tex]\frac{1}{120}[/tex] =[tex]\frac{6}{120}[/tex] = [tex]\frac{1}{20}[/tex]

the probability that every even number appears at least once before the first occurrence of an odd number is  [tex]\frac{1}{20}[/tex]

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the group gives 50% of the money they raised to youth programs. this year the team gave $3,100 to youth programs

Answers

Using the percentage of money the group gave out to the youth program, the amount of money the group raised is 6200 dollars.

How to find the amount the group raised?

In mathematics, a percentage is a number or ratio that can be expressed as a fraction of 100.

The group gives 50% of the money they raised to youth programs. This year the team gave $3,100 to youth programs.

Therefore, the amount of money the group raised can be calculated as follows:

let

x = amount of money raised by the group

Hence,

50% of x = 3100

50 / 100 × x = 3100

50x / 100 = 3100

cross multiply

50x = 3100 × 100

50x = 310000

divide both sides by 50

50x / 50 = 310000 / 50

x = 6200

Therefore, the group raised 6200 dollars this year.

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X Use FOIL to solve (x+2)(x+1): Write x squared as x2
x2+3x+2
x+2x+2
Ox-2x-2
0/2
X

Answers

After using FOIL, the final answer will be

x2 + 3x + 2

What is the FOIL method?
The typical way of multiplying two binomials is known as the FOIL method since FOIL is a shorthand for it. The acronym FOIL stands for the following four terms that describe the item: (Each binomial "initial" term is multiplied together.) The FOIL method is a memory aid for the procedures involved in multiplying two binomials. The result of multiplying the first term, outer term, inner term, and last term is the product of two binomials: (a+b)(c+d)=ac+ad+bc+bd.

Solution explained:

A/Q we have

(x+2)(x-1)

= x * x + x + 2x + 2    (After expanding and applying distributive property)

= x2 + x + 2x + 2

= x2 + 3x + 2

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The mean of a normal distribution is 400 kilos. The standard deviation is 10 kilos. What is the probability of a weight between 420 kilos and the mean of 400
kilos?
****
0.1932
O 0.4772
0.4332
O0.5000

Answers

Second option is correct 0.04772.

The probability of a weight between 420 kilos and the mean of 400

kilos = 0.4772

Mean of a normal probability distribution is μ = 400 kilos

And standard deviation σ = 10 kilos

Let x be the variable in kilos.

X is between 400 kilos and 420 kilos

P( 400 < X < 420 ) = P ( 400 -  μ < X -  μ < 420 -  μ)

= P ( (400-μ)/σ < (X-μ)/σ < (420-μ)/σ )

= P ( (400 - 400) /10 < Z < (420 - 400)/10 )

= P ( 0 < Z < 2 )

= 0.4777 from the table appendix B1.

The link for the appendix table B1 :

www.webassign.net%2Faswsbe13%2Fappendix-b.pdf&usg=AOvVaw3QlkaDTdGZ1Z01YZPYCL6h

The probability of a weight between 420 kilos and the mean of 400

kilos = 0.4772

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7x 3,012=7(____+____)

Answers

Answer:

7x 3,012=7(__3000__+__12_) = 21084

The surface area of this cylinder is 6,732.16 square feet. What is the height? Use 3.14 and round your answer to the nearest hundredth 16 ft=radius h feet​

Answers

The height of the cylinder whose surface area and radius are as given in the task content is; 67 ft.

What is the surface area of the cylinder?

It follows from the task content that the height of the cylinder as described by the surface area and radius above be determined.

On this note, recall that the surface area of a cylinder is given by the formula;

Surface area = 2πrh

Therefore;

6732.16 = 2 × 3.14 × 16 × h

h = 6732.16/100.48

h = 67.

Consequently, the height of the cylinder which is as described is; 67 ft.

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Suppose conditional p→ q is true and conditional q→ r is false. Must the conditional p →r also be false? Explain.​

Answers

Answer:

no

Step-by-step explanation:

the conditional p-> r is the basically both of the beginning 2 conditionals combined

what happens to the probability of rejecting the null hypothesis as the obtained statistic decreases

Answers

if n decreases then the value of level of significance of each samples [tex]\alpha[/tex] decreases

1. Critical Value: The value of the statistic for which the test just rejects the null hypothesis at the given significance level.

2. Power of the Test: The probability that the test correctly rejects the null hypothesis when the alternative is true.

3. Significance Level: The prescribed rejection probability of a statistical hypothesis test when the null hypothesis is true.

4. Size of the test: The probability that the test incorrectly rejects the null hypothesis when it is true.

if n decreases then the value of level of significance of each samples [tex]\alpha[/tex] decreases and hence 1- [tex]\alpha[/tex] increases which are called the rejection of test sample increases

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what is
S+2c=47
5s+8c=201
s=?
c=?
step by step answer

Answers

The values of the variables s and c are 13 and 17, respectively.

We are given a system of two equations. The equations are linear in nature. Each equation represents a straight line. We need to find the solution to the system of linear equations. The coordinates of the intersection point of the straight lines are the solution. The equations are given below.

s + 2c = 47

5s + 8c = 201

We will substitute the value of s from the first equation into the second equation.

s = 47 - 2c

5s + 8c = 201

5(47 - 2c) + 8c = 201

235 - 10c + 8c = 201

235 - 2c = 201

2c = 235 - 201

2c = 34

c = 17

We will substitute the value of c into the first equation to find the value of s.

s = 47 -2c

s = 47 - 2(17)

s = 47 - 34

s = 13

Hence, the values of s and c are 13 and 17, respectively.

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Choose the expression that is equivalent to 1/5 x 3

Answers

3/5, they both equal 0.6.

Answer:

0.2

Step-by-step explanation:

1/5 is equvalent with 10/5=0.2

Finding Angle Measures When Parallel Lines Are Cut By a Transversal

Answers

Answer:

Since angle 8 is 95 degrees, we will have to either subtract or use the rules to solve this!

Lets find angle 1 first!

Since opposite angles are the same, angle 1 will be 95 degrees!

Angle 2 will wave subtracting used to find it!

180 - 95 = 85

Angle 2: 85 degrees

Angle 3 is the same as angle 2 so 85 degrees!

Angle 4 is the same as angle 8 and 1 so 95 degrees!

Angle 5 is the same as 8, 4, and 1 so 95 degrees!

Angle 6 is the same as angle 3 and 2 degrees!

Angle 7 will be 85 by subtraction!

Angle 8 is given and it is 95!

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