An air traffic controller is tracking two planes. To start, Plane A was at an altitude of 700 meters, and Plane B was at an altitude of 424 meters. Plane A is gaining altitude at 16 meters per second, and Plane B is gaining altitude at 22 meters per second. Let x be the number of seconds that have passed.

(A) For each plane, write an expression for the altitude of the plane after x seconds.

(B) Write an equation to show when the two planes would be at the same altitude.

Answers

Answer 1

(A) The expression for each plane are as follows;

Plane A; 700 + 16xPlane B; 424 + 22x

B). The equation to show when the two planes would be at the same altitude is; 700 + 16x = 424 + 22x.

Which equation shows when the two planes would be at the same altitude?

It follows from the task content that the initial altitudes of plane A and B are 700 and 424 respectively.

Hence, since plane A gains altitude at 16 meters per second; The expression for the altitude after x seconds is;

700 + 16x

Also, since plane B gains altitude at 22 meters per second; The expression for the altitude after x seconds is;

424 + 22x

Therefore, when the two planes are at the same altitude; the equation which is true is;

700 + 16x = 424 + 22x.

Read more on linear expressions and equations;

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Answers

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