An object of mass of 2.0 kg rotates at constant speed in a horizontal circle of radius 5.0 m. The time
for one complete revolution is 3.0 s. What is the magnitude of the resultant force acting on the object.

Answer:

the bird has 550J of potential energy

Explanation:

PEtotal=PE+KE

1000J=PE+450J

subtracting the kinetic energy from the total we get:

1000J-450J=PE

550J=PE

Answer:

"work against the force of the air in the tire"

The air in the tire provides a force opposing the force of the air provided by the plunger.

The question is fishing for "balanced force".

But the description in the question is terrible.

Answer:

Od- Wooden

Explanation:

It would not make sense if it was non-wood because that make it no a wood base product, OC is not right because its not a a plant that produces wood as its structural tissue and thus has a hard stem.   An OA justT o take or get a supply of wood. so its Od

Answer:

Explanation:

The potential energy of a body can be found by using the formula

PE = mgh

where

m is the mass

h is the height

g is the acceleration due to gravity which is 9.8 m/s²

From the question we have

PE = 50 × 9.8 × 600 = 294,000

We have the final answer as

Hope this helps you

Answer:

50.176 [m].

Explanation:

1) the required height can be calculated using the formula:

h=V₀*t+1/2* g*t₂, where V₀ - initial velocity of the rock, t - elapsed time, g - 9.8 m/s²;

2) if V₀=0, t=3.2, g=9.8, then

h=0.5*9.8*3.2²=1024*49*10⁻³=50.176 [m].≈50[m].

Answer:

Answer → Distance is 5 × 10⁴ km

Explanation:

Gravitational formular

[tex]{ \tt{F = \frac{GMm}{ {r}^{2} } }} \\ [/tex]

For the first case;

[tex]{ \tt{F _{1} = \frac{GMm}{2.5 \times {10}^{4} } }} \\ [/tex]

For the second case;

[tex]{ \tt{F _{2} = \frac{GMm}{r _{2}} }} \\ [/tex]

but F2 = ½F1

Therefore, F1 = 2F2

Hence:

[tex]{ \tt{ \frac{GMm}{2.5 \times {10}^{4} } =2 \times \frac{GMm}{r _{2} } }} \\ \\ { \tt{ \frac{1}{2.5 \times {10}^{4} } = \frac{2}{r _{2} } }} \\ \\ { \tt{r _{2} = 2 \times 2.5 \times {10}^{4} }} \\ \\ { \underline{ \tt{ \: \: r _{2} = 5 \times {10}^{4} \: km \: \: }}}[/tex]

Answer: Distance is 5 × 10⁴ km

Explanation:

Answer:

3,900m³

Explanation:

Cuando el niño hace girar 0.7 vueltas por segundo una pelota de hule que se encuentra sujeta mediante un cordón de 0.75 m de longitud, tenemos que:

a) El periodo de la pelota es 1.43 segundos.

b) La velocidad lineal de la pelota es 3.3 m/s.

a) El periodo de la pelota está dado por:

[tex] T = \frac{2\pi}{\omega} [/tex]

En donde:

ω: es la velocidad angular

Dado que la pelota da 0.7 vueltas (revoluciones) cada segundo, la velocidad angular es:

[tex] \omega = \frac{0.7 \:rev}{s}*\frac{2\pi rad}{1 \:rev} = 4.40 rad/s [/tex]

Entonces, el periodo es:

[tex]T = \frac{2\pi}{\omega} = \frac{2\pi}{4.40 rad/s} = 1.43 s[/tex]

b) La velocidad lineal de la pelota se puede calcular usando la siguiente ecuación:

[tex] v = \omega r [/tex]

En donde:

r: es el radio de la circunferencia = longitud del cordón = 0.75 m

[tex]v = \omega r =4.40 rad/s*0.75 m = 3.3 m/s[/tex]

Por lo tanto, la velocidad lineal de la pelota es 3.3 m/s.

Puedes encontar mas aquí:

Espero que te sea de utilidad!

Answer:

2300.68

Explanation:

The metal hammer has a mass of 1500 kg and it hits the baseplate

with a speed of 8.0 m/s.

0 Calculate the kinetic energy of the hammer as it hits the baseplate. there for it will create the kinetic energy of 2300.68 as it hits the baseplate.

Answer:

Speed can be defined in (C) distance / time.

I hope this helped at all.

Answer: beta particles

Explanation:

that's the answer

Answer:

Molar mass of NH3=14+3=17g

[tex]mole = \frac{given \: mass}{molar \: mass} \\ mole = \frac{28}{17} \\ mole = 1.65[/tex]

BRAINLIST

Answer:

65km/h

Explanation:

Here,

Relative velocity of car moving in different directions with different velocities =Va + Vb

=25+40

=65 km/h

Please find attached photograph for your answer.

Hope it helps.

Do comment if you have any query.

Answer:

this is an example of Newton's Second Law, acceleration happens when a force acts on a mass.

the force that makes the bicycle move is your foot pushing against the pedal

Answer:

its atmospheric pressure decreases

When the temperature of an air mass increases, its atmospheric pressure drops

ok done. Thank to me :>

The extension of the spring when the ball is allowed to hang straight down, motionless is 0.0032 m.

The given parameters;

The radius of the circular path when spring is stretched is calculated as;

R = l₁ + x

R = 0.201 + 0.0176

R = 0.2186 m

The spring constant is calculated as follows;

[tex]F = ma\\\\Kx = \frac{mv^2}{R} \\\\K = \frac{mv^2}{Rx} \\\\K = \frac{(3.41)^2 m}{0.2186 \times 0.0176} \\\\K = 3,022.4 m \ N/m[/tex]

The extension of the spring when the ball is allowed to hang straight down, motionless;

[tex]F = mg\\\\Kx=mg\\\\x = \frac{mg}{K} \\\\x = \frac{9.8 m}{3022.4 m} \\\\x = 0.0032 \ m[/tex]

Thus, the extension of the spring when the ball is allowed to hang straight down, motionless is 0.0032 m.

Learn more here:https://brainly.com/question/15589287

Answer:

carbon dioxide

Explanation:

its common sense

Answer:

Explanation:

The gravitational force = G * m1 * m2 / r^2

That means as the distance increases, r get's bigger and m1 and m2 don't change, the force decreases. Read that sentence carefully. In physics, it is very important to know what goes up and goes down means and especially why.

Answer: I think it's larger

Explanation:  man im just trying to help you

the answer is 100 rad/s2

Hi there!

We can begin by doing a summation of forces. Let the acceleration be positive in the direction of the DOWNWARD movement of the hanging block.

(A)

The system will flow in the direction of the hanging block's movement downwards.

(B)

Summation of forces of block on incline:

∑F = -M₁gsinФ + T

Summation of forces of hanging block:

∑F = M₂g - T

Sum both summations:

∑F =  -M₁gsinФ + T + M₂g - T

∑F = M₂g -M₁gsinФ

According to Newton's Second Law:

∑F = ma

Thus:

(M₁ + M₂)a = M₂g -M₁gsinФ

[tex]a = \frac{M_2g -M_1gsin\theta}{M_1 + M_2}[/tex]

Plug in the values:

[tex]a = \frac{(5 * 9.8) -(8 * 9.8 * sin30)}{8 + 5} = \large\boxed{0.754 m/s^2}[/tex]

(C)

Calculate the rope's tension using one of the above equations:

∑F₂ = M₂g - T

Rearrange for T:

T = M₂g - m₂a

Plug in values:

T = 5(9.8) - 5(0.754) = 45.23 N

Answer:

the answer is A

Explanation:

[tex] \huge \bf༆ Answer ༄[/tex]

The given terms in the question are : -

We have been given the task to find out time (t)

The formula that can be used to find time is : -

[tex] \sf \: I = \dfrac{ Q}{t}{} [/tex]

Rearrange the formula,

[tex] \sf \: t = \dfrac { Q}{I }[/tex]

Solve for time (t)

[tex]꧁ \: \large \frak{Eternal \: Being } \: ꧂[/tex]

Answer:

if your saying can it? then yes or if you are asking what type of magnetic force  then its fr its actual self magnetic force

Explanation:

Hi there!

[tex]\large\boxed{F_{A} = -5000N}}[/tex]

For an object to be moving at constant velocity:

∑F = 0 (The sum of the forces acting on the object MUST be 0 N)

We can do a summation of forces for this helicopter in the HORIZONTAL direction:

∑Fₓ = Ft (Force of Thrust) + Fa (Force of air resistance) = 0

Thus, if we substitute in the given value for Ft:

Ft = -Fa

5000N = -Fa

Fa = -5000N

Answer:

Oh its fine i am not in college but its still fine

Explanation:

Answer:

D is the answer

Explanation:

D is the most highest one so

the answer is D

Answer:

10 kg rock at 15 degrees celcius

Answer:

3

Explanation:

Astronauts in space can grow up to 3 percent taller during the time spent living in microgravity, NASA scientists say. That means that a 6-foot-tall (1.8 meters) person could gain as many as 2 inches (5 centimeters) while in orbit.

Hi there!

A)

The angle that will produce the same range is the compliment of 35°.

Thus, kicking the ball at 55° will result in the same range.

We can prove this by using the derived range equation:

[tex]R = \frac{v^2sin2\theta}{g}[/tex]

An angle of 35° yields:

[tex]R = \frac{v^2sin(2*35)}{g} = .939R[/tex]

An angle of 55° yields:

[tex]R = \frac{v^2sin(2*55)}{g} = .939R[/tex]

Both are the same, thus indicating that 55° produces the same range.

B)

The angle of 55° will produce the higher ball because the VERTICAL component of the ball's velocity is greater compared to kicking the ball at 35° degree.

sin(55) > sin(35)

C)

The angle of 55° will result in the ball being in the air the longest because when a ball is in the air (assuming no air resistance), the ball experiences an acceleration due to gravity of -9.8 m/s², causing the vertical velocity to decrease until it eventually reaches 0 m/s at the top of its path. A greater initial vertical velocity means that it will take longer for the ball to fall.

We can prove this using:

vf = vi + at

0 = vy - 9.8t

vy/9.8 = t

Greater vy (vertical component of velocity) ⇒ greater time taken.

D)

The angle that would result in the furthest range is 45°.

We can prove this using calculus. Recall the above range equation:

[tex]R = \frac{v^2sin2\theta}{g}[/tex]

We can take the derivative and use the first-derivative test to find its critical point:

[tex]\frac{dR}{d\theta} = \frac{v^22cos2\theta}{g} = 0[/tex]

Evaluate:

[tex]v^22cos2\theta = 0 \\\\cos2\theta = 0 \\\\2\theta = 90^o\\\\\boxed{\theta = 45^o}[/tex]

A. The angle that will produce the same range as a 35° kick is 53°.

B. The angle that produces the highest ball is 45°.

C. The angle that produces the ball that is in the air the longest is 45°.

D. There is no single angle that will produce the furthest range for all initial velocities and accelerations due to gravity.

A. The range of a projectile is the horizontal distance it travels before it hits the ground. The range of a projectile is determined by the initial velocity, the angle of projection, and the acceleration due to gravity.

For a given initial velocity, the range of a projectile is maximized when the angle of projection is 45°. However, if the ground is not level, the range of a projectile can be maximized at other angles.

In the case of a soccer ball kicked at an angle of 35°, the range will be maximized at an angle of 53°. This is because the range of a projectile is maximized when the vertical component of the initial velocity is equal to the horizontal component of the initial velocity.

The angle of 53° is the angle that produces a vertical component of the initial velocity that is equal to the horizontal component of the initial velocity when the ball is kicked at an angle of 35°.

Therefore, the angle that will produce the same range as a 35° kick is 53°.

B. The angle that produces the highest ball is 45°.

C. The angle that produces the ball that is in the air the longest is 45°.

D. The angle that produces the furthest range depends on the initial velocity and the acceleration due to gravity. There is no single angle that will produce the furthest range for all initial velocities and accelerations due to gravity.

To know more about angle here

https://brainly.com/question/30147425

#SPJ3