An overtone is louder than the fundamental tone.
O True
False

Answer:

Water and hydrogen peroxide are different substances because they have different chemical formulas and molecular structures. Water has the chemical formula H2O, meaning that it has two hydrogen atoms and one oxygen atom. Hydrogen peroxide has the chemical formula H2O2, meaning that it has two hydrogen atoms and two oxygen atoms. The difference in their molecular structures leads to different chemical and physical properties, such as boiling points, melting points, and reactivity.

Explanation:

Neither MacBook Air nor the direction that the sound waves travel affects the speed of the sound.

The highlighted phenomenon in the graph is called the Doppler effect, which involves a modification of frequency for sound waves (or any kind of wave) due to the difference in motion between the observed and the source.

An example of this effect present in the medical field is through ultrasound imaging; doctors use it to measure the velocity and route of blood circulating throughout the patient's body by sending out high-frequency sound waves and analyzing the reflected waves.

What appears in the graphed illustration specifically is linear proportionality, meaning that there is a direct correlation between f and fs, the former being the observed frequency and the latter the source frequency.

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a. The decay constant of iodine-131 is 0.0502 day^-1.

b. the half-life of iodine-131 is 13.8 days.

c. 1.29 mg of iodine-131 will be present in the patient's body 50 days after it was administered.

a) To calculate the decay constant of iodine-131, we can use the formula:

N = N0 * e^(-λt)

where

N is the amount of iodine-131 remaining after time t,

N0 is the initial amount of iodine-131, and

λ is the decay constant.

We are given that N0 = 20.0 mg and N = 3.24 mg, and t = 21 days. Substituting these values into the formula and solving for λ, we get:

λ = ln(N0/N) / t

= ln(20.0/3.24) / 21

= 0.0502 day^-1

Therefore, the decay constant of iodine-131 is 0.0502 day^-1.

b) To calculate the half-life of iodine-131, we can use the formula:

t1/2 = ln(2) / λ

Substituting the value of λ we calculated in part (a), we get:

t1/2 = ln(2) / 0.0502

= 13.8 days

Therefore, the half-life of iodine-131 is 13.8 days.

c) To calculate how much iodine-131 will be present in the patient's body 50 days after it was administered, we can again use the formula:

N = N0 * e^(-λt)

We are given that t = 50 days,

N = 20.0 * e^(-0.0502*50)

= 1.29 mg

Therefore, 1.29 mg of iodine-131 will be present in the patient's body 50 days after it was administered.

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Answer:

Moment of the force = (-10i-28j+32k)Nm

Explanation:

Moment of a force is expressed mathematically as force(F) multipled by its distance(d) and its unit is in newton metre (Nm).

F×d

(8i-4j+3k)×[(6i+2j+3k)-(2i+0j+k)]

-10i-28j+32k

The refracted angle of the electromagnetic wave in glass (θ₂) is approximately 59.64° when the incident angle (θ₁) is 25°.

The refracted angle, denoted as θ₂, can be calculated using Snell's Law, which relates the incident angle, refracted angle, and the refractive indices of the two media involved.

Snell's Law states:

n₁ × sin(θ₁) = n₂ × sin(θ₂)

where:

n₁ = refractive index of the first medium (water) = 1.3

θ₁ = incident angle of the wave in the first medium = 25°

n₂ = refractive index of the second medium (glass) = 1.5

θ₂ = refracted angle of the wave in the second medium

Plugging in the given values:

n₁ = 1.3

θ₁ = 25°

n₂ = 1.5

Can rearrange Snell's Law to solve for θ₂:

θ₂ = arcsin((n₁/n₂) × sin(θ₁))

Now we can substitute in the values and calculate θ₂:

θ₂ = arcsin((1.3/1.5) × sin(25°))

θ₂ = arcsin(0.8667)

θ₂ ≈ 59.64°

So the refracted angle of the electromagnetic wave in glass (θ₂) is approximately 59.64° when the incident angle (θ₁) is 25°.

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Answer:

To calculate the flow rate, we need to first find the cross-sectional area of the cylinder.

The area ratio is defined as the ratio of the cross-sectional area of the extended cylinder to the cross-sectional area of the cylinder before it was extended.

Let's call the cross-sectional area of the cylinder before it was extended A1, and the cross-sectional area of the extended cylinder A2.

We know that the diameter of the cylinder is 15cm, so the radius is 7.5cm.

The cross-sectional area of a cylinder is given by the formula A = πr^2.

So,

A1 = π(7.5)^2 = 176.71 cm^2

To find A2, we can use the area ratio:

Area ratio = A2/A1 = 0.5

A2 = 0.5 * A1 = 0.5 * 176.71 = 88.36 cm^2

Now we can calculate the flow rate using the formula:

Flow rate = velocity * cross-sectional area

Flow rate = 5 cm/s * 88.36 cm^2 = 441.8 cm^3/s

Therefore, the flow rate is 441.8 cm^3/s.

The tea absorbs 2613420 J of heat energy when it is placed in sunlight until it reaches an equilibrium temperature of 32.4°C.

To calculate the heat energy absorbed by the tea, we can use the formula:

Q = mcΔT

where Q is the heat energy absorbed by the tea, m is the mass of the tea, c is the specific heat capacity of water, and ΔT is the temperature change of the tea.

Using the given values, we get:

m = 500 g

c = 4186 J/kg·°C

ΔT = 32.4°C - 20°C = 12.4°C

Substituting these values into the formula, we get:

Q = (500 g)(4186 J/kg·°C)(12.4°C) = 2613420 J

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--The complete Question is, A jar of tea with a mass of 500 g is initially at a temperature of 20°C. If the jar is placed in sunlight until it reaches an equilibrium temperature of 32.4°C, how much heat energy is absorbed by the tea? Assume the specific heat capacity of the tea to be that of pure liquid water, which is 4186 J/kg·°C.--

Answer:The oxygen molecules have lost a total of 0.94 coulombs in charge of their electrons.

Explanation:No

The resistor is dissipating 1.8 W of power. As a result, 0.15 A is the current flowing through the resistor.

Any equation linking power to current, voltage, and resistance may be used to calculate the power wasted by each resistor because all three variables are known. Since each resistor receives its full voltage, let's use P=V2R P = V 2 R.

(a) We may determine the current flowing through the resistor using Ohm's Law as follows:

I = V/R

where R is the resistance and V is the voltage difference across the resistor.

Therefore, the resistor's current is as follows:

I = 12 V / 80 Ω = 0.15 A

Therefore, the current through the resistor is 0.15 A.

(b) The power being dissipated in the resistor can be calculated using the formula:

P = VI = I²R = V²/R

where P is the power, V is the voltage difference across the resistor, I is the current through the resistor, and R is the resistance.

Substituting the given values, we get:

P = VI = (0.15 A)(12 V) = 1.8 W

Alternatively, we can use the third formula to calculate the power:

P = V²/R = (12 V)²/ 80 Ω = 1.8 W

So, the power being dissipated in the resistor is 1.8 W.

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Answer:

False

Explanation:

The modern kinetic-molecular model is better than the caloric model, not because it is true, but because it produces more workable results. credited to be the first to demonstrate a clear connection between mechanical energy and heat.

The question is incomplete. Here is how to get magnitude and direction

To find the magnitude and direction of a vector, follow these steps:

Write the vector in component form:

For a two-dimensional vector, write it as <x, y>, where x and y are the components of the vector along the x-axis and y-axis, respectively. For a three-dimensional vector, write it as <x, y, z>, where x, y, and z are the components of the vector along the x-axis, y-axis, and z-axis, respectively.

Calculate the magnitude of the vector:

The magnitude of a vector is the length of the vector, which can be found using the Pythagorean theorem. For a two-dimensional vector <x, y>, the magnitude is sqrt(x^2 + y^2). For a three-dimensional vector <x, y, z>, the magnitude is sqrt(x^2 + y^2 + z^2).

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Answer:

17.3 m/s

Explanation:

We can use the conservation of energy principle to find the velocity of the log when it hits the water. At the top of the waterfall, the log has gravitational potential energy, and at the bottom, it has kinetic energy. We can assume that there is no energy lost to friction or air resistance.

The gravitational potential energy of the log at the top of the waterfall is given by:

U = mgh

where m is the mass of the log, g is the acceleration due to gravity, and h is the height of the waterfall. Substituting the given values, we get:

U = (15.0 kg)(9.81 m/s^2)(30 m) = 4414.5 J

At the bottom of the waterfall, all of the gravitational potential energy has been converted to kinetic energy:

U = (1/2)mv^2

where v is the velocity of the log when it hits the water. Solving for v, we get:

v = sqrt(2U/m)

Substituting the value of U and m, we get:

v = sqrt(2(4414.5 J)/(15.0 kg)) = 17.3 m/s

Therefore, the velocity of the log when it hits the water is approximately 17.3 m/s.

Hope this helps!

Answer:

Both Corks are subject to the same buoyant force

Explanation:

The buoyant force depends on the volume of the displaced liquid and the density of the liquid, but not the density of the floating object. So the buoyant forces will be the same on each cork whether the water it's floating in is normal or salty.

The maximum speed of the cart is 26.07 cm/s, the velocity of the cart when the position is 2 cm is 0.141 m/s, and the kinetic and potential energies of the system are 4.97 ×10⁻³J and 4×10⁻³J.

From the given,

Mass of the cart = 0.5 kg

Force constant = 20 N/m

The amplitude of the motion = 3 cm = 0.03 m

A) maximum speed of the cart=?

ω = √k/m

   = √(20/0.5) = 8.944

v = ω×amplitude = 8.944×3 = 26.07 cm/s.

B) Velocity of the cart when the position is 2 cm

v = √k/m(A²-x²)

  = √(20/0.5)((0.03)²-(0.02)²)

 = 0.141 m/s

C) Kinetic energy = 1/2 (mv²)

                        = 1/2 (0.5×(0.141)²)

                        = 4.97 × 10⁻³J

K.E = 4.97 ×10⁻³J

Potential energy = 1/2 kx²

                            = 1/2 (20×(2×10⁻²)²)

                            = 4 × 10⁻³J

P.E = 4 × 10⁻³J.

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The false statement regarding gender roles is, they stem primarily from biological differences in the sexes. Option b is correct.

Gender roles are based on cultural traditions and societal norms, rather than solely being determined by biological differences between males and females. While biological differences between the sexes may play a role in certain gender-based behaviors or expectations, the vast majority of gender roles are socially constructed and learned through cultural traditions and socialization. Option b is correct.

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If you do 12 J of work to push 0.001 C of charge from point A to point B in an electric field, then the potential difference between points A and B is 12 kV.

The increase in kinetic energy of an electron if it has been accelerated through a potential difference of 20 million volts is 8000 J.

a )When a charge is accelerated through potential difference then the energy gained by the charge is,

E = eV where E is energy e is charge and V is potential difference.

V = E/e = 12/0.001 = 12 kV

b) E = eV, E = 0.001 × 20×10⁶

E = 20000 J

Increase in the kinetic energy will be, 20000 - 12000 = 8000 J

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Answer:

True

the velocity of sound in air decreases with decrease in temperature.

The projectile with the smallest angle of elevation will have the greatest kinetic energy just before impact.

All three projectiles have the same initial kinetic energy, which means that they all start with the same amount of energy. However, the kinetic energy of a projectile is related to its velocity and mass.

When a projectile is launched at an angle of elevation, its initial velocity will have both horizontal and vertical components. The vertical component of velocity will affect the time it takes for the projectile to reach the ground, but it does not affect the kinetic energy of the projectile just before impact.

Therefore, the projectile with the greatest kinetic energy just as it impacts with the ground will be the one with the largest horizontal component of velocity, which means it will travel the furthest horizontally before hitting the ground.

The horizontal component of velocity is determined by the angle of elevation and the initial velocity of the projectile. Therefore, the projectile with the smallest angle of elevation will have the largest horizontal component of velocity and therefore the greatest kinetic energy just before impact.

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6. Water - B. has a positive and negative end, 7. Nucleic acids - A. contains instructions, 8. Proteins - D. Some help break down nutrients, 9. Lipids - E. do not mix with water, and 10. carbohydrates - C. sugar is one.

6. Water - B. has a positive and negative end: Water is a polar molecule, which means it has a partial positive charge on one end and a partial negative charge on the other. This polarity is due to the asymmetric arrangement of the hydrogen and oxygen atoms in the molecule, with the oxygen atom having a stronger attraction for electrons than the hydrogen atoms. The positive and negative ends of the water molecule allow it to form hydrogen bonds with other polar molecules, including other water molecules, which gives water many of its unique properties, such as high surface tension, high boiling and melting points, and its ability to dissolve many substances.

7. Nucleic Acids - A. contain instructions: Nucleic acids are biomolecules that store and transmit genetic information in living organisms. They are composed of long chains of nucleotides, which are made up of a nitrogenous base, a sugar molecule, and a phosphate group. The two main types of nucleic acids are DNA (deoxyribonucleic acid) and RNA (ribonucleic acid). DNA contains the genetic information that is passed down from one generation to the next, while RNA helps to transcribe and translate that information into functional proteins that perform various cellular processes.

8. Proteins - D. Some help break down nutrients: Proteins are complex biomolecules that perform a variety of functions in the cell, including catalyzing chemical reactions, transporting molecules, and providing structural support. Some proteins, known as enzymes, are specialized molecules that help to break down nutrients in the body by catalyzing chemical reactions that convert them into usable forms. Other proteins, such as antibodies and hormones, have other important roles in the immune system and in cellular communication.

9. Lipids - E. do not mix with water: Lipids are a diverse class of biomolecules that are characterized by their insolubility in water. They include fats, oils, phospholipids, and steroids, among others. Lipids are composed of long chains of hydrocarbons and contain a polar head group and a nonpolar tail. The nonpolar tail makes lipids insoluble in water, while the polar head group allows them to interact with other polar molecules. Lipids are important for energy storage, as a component of cell membranes, and as signaling molecules.

10. Carbohydrates - C. sugar is one: Carbohydrates are a class of biomolecules that are composed of carbon, hydrogen, and oxygen atoms. They include sugars, starches, and fibers, among others. Sugars are simple carbohydrates that consist of one or two sugar molecules linked together, while starches and fibers are complex carbohydrates made up of many sugar molecules linked together. Carbohydrates are an important source of energy for the body and play important roles in cellular processes such as cellular respiration and photosynthesis.

Hence, The correct answer is 6. Water - B. has a positive and negative end, 7. Nucleic acids - A. contains instructions, 8. Proteins - D. Some help break down nutrients, 9. Lipids - E. do not mix with water, and 10. carbohydrates - C. sugar is one

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Ergometer is a device that standardizes the work and power output. The work done by the cycle ergometer is 109.5 kJ and the power output for the 5 minutes is 353.133 W.

Work done by the engine is defined as the product of force and distance and the unit of work done is the joule (J).

From the given,

resistance of the ergometer = 4.5kp

revolutions per minute = 80 rpm

time taken = 5 minutes

Work done (W) = F × d

                        = (4.5 × 9.81) × (80 rpm × 6 m/rev × 5)

                       = 105,948

  Work done (W) = 105.94 kJ

Power is the ratio of the work done and time and the unit of power is the watt (W).

Power    =  Work done / time

              = 105.94 × 10³  / 300   (5 minutes = 300 seconds)

            =  353.13 W.

Hence the work done by the cycle ergometer is 105.94 kJ and the output power in 5 minutes (300 seconds) is 353.133 W.

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Mass of the second object located at a distance r from the origin, r^ is the unit vector in the radial direction, and the negative sign indicates that the force

The System can refer to a set of interacting or interdependent components forming an integrated whole. The term can be applied to various fields, including physics, engineering, biology, and social sciences, among others. In physics, a system typically refers to a collection of objects or particles that are studied together, often with the goal of understanding the behavior of the system as a whole. In engineering, a system can refer to a group of components that work together to perform a specific function, such as an electrical power grid or an automobile engine. In biology, a system can refer to an organism or group of organisms that interact with their environment, such as an ecosystem or the human body.

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Explanation:

d = do + vo t + 1/2 at^2

d = 0 +  14.5 (2) + 1/2 (9.80)(2^2) = 48.6 = ~ 49 m

Explanation:

d = do + vo t + 1/2 at^2

d = 0 +  14.5 (2) + 1/2 (9.80)(2^2) = 48.6 = ~ 49 m

Answer:

In a stable star, the force of nuclear fusion is balanced by the force of gravity. The high temperatures and pressures in the core of the star cause atoms to collide and fuse together, releasing energy in the process. This energy is what keeps the star from collapsing under the force of gravity. The outward pressure from the energy released by nuclear fusion pushes outward, while the force of gravity pulls inward. In a stable star, these two forces are balanced, with the inward force of gravity being counteracted by the outward pressure from fusion. This balance allows the star to maintain a stable size and temperature.

Therefore the answer is A. outward, inward.

A scientific research consists of numerous critical phases. Here's a high-level summary of the procedure: Create a research question, then conduct a review of the literature. Create a hypothesis. Create your research, Gather information, Examine data, Interpret findings and communicate them.

Create a research question: Begin by picking a topic of interest and creating a clear and precise question that you wish to answer via your research.

Conduct a literature review : before beginning your study to establish what is already known about your issue and what research questions have not yet been answered.

Create a hypothesis: Based on your research topic and analysis of the literature, create a hypothesis that you can evaluate using your study

Plan your research as follows: Determine your data collecting and analysis approach, including the research design, population/sample, data gathering methods, and statistical analysis.

Gather information: Carry out your research and gather data in accordance with your approach.

Analyse data: Once you've gathered your information, use relevant statistical tools to test your hypothesis.

Results should be interpreted as follows: Interpret your findings and develop conclusions about your research issue based on your analysis.

Disseminate findings: Share your discoveries with others by publishing them in a scientific journal, giving a presentation at a conference, or another method.

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Astronomers can use how long it takes an object's brightness to vary to estimate the physical size of the object through a method known as photometry. This method involves observing an object's brightness over time and analyzing the patterns of variation.

For example, consider a binary star system in which two stars orbit each other. As one star passes in front of the other, the combined brightness of the system will decrease. The duration of this decrease in brightness can be used to estimate the physical size of the stars, as the duration of the decrease is related to the size of the stars and the distance between them.

Similarly, if an asteroid or other small body passes in front of a star, the star's brightness will decrease for a short period of time. The duration of this decrease can be used to estimate the size of the asteroid, as the duration is related to the size of the asteroid and the distance between it and the observer.

In general, the size of an object can be estimated using photometry by comparing the observed variation in brightness to the expected variation based on the physical characteristics of the object. This can provide valuable information about the properties and behavior of celestial objects and can help astronomers to better understand the structure and evolution of the universe.

Answer:

23 ohm

Explanation:

I = I1 = I2 = 0.25A

V = 6 V

V = V1 + V2

6 = I1R1 + I2R2

6 = ( 0.25 × 1 ) + ( 0.25 × R2 )

6 = 0.25 + 0.25 R2

6 - 0.25 = 0.25 R2

5.75 = 0.25 R2

5.75 ÷ 0.25 = R2

R2 = 23 ohm

Answer:

79.3

Explanation:

We can use the formula:

q = m * c * deltaT

where:

q is the heat added to the system, which is 815 J in this case

m is the mass of the sample we want to find

c is the specific heat of copper, which is 0.385 J/g-K

deltaT is the change in temperature, which is (35 - 12) = 23°C

Plugging in the values given, we get:

815 J = m * 0.385 J/g-K * 23°C

Simplifying this expression yields:

m = 815 J / (0.385 J/g-K * 23°C)

Thus, the mass of the copper sample is:

m = 79.3 g

Therefore, there were approximately 79.3 grams of copper in the sample.

Answer:

Explanation:

We can use the equation q = mCΔT, where q is the amount of heat transferred, m is the mass of the sample, C is the specific heat capacity of the material, and ΔT is the change in temperature.

First, we need to calculate the change in temperature, which is:

ΔT = T₂ - T₁ = 35°C - 12.0°C = 23°C

Next, we can rearrange the equation to solve for the mass of the sample:
m = q / (CΔT)

Substituting the values we have:
m = 815 J / (0.385 J/g-K × 23°C) ≈ 90.2 g

Therefore, the sample of solid copper had a mass of approximately 90.2 grams.