Answer as soon as possible

Answer:

ill get back to this question once i get the answer

The radius of the loop is 13 cm

To find the radius of the loop, the values are given as,

Current I = 6A

Magnetic field, B = 2* 10⁻⁴ T

     The magnetic field in a circular loop will have same magnitude and direction. The current carrying loops will be formed due to the magnetic field and there will be n times of loops adds up for every turns.

Formula for magnetic field in the circular loop is,

                   B = µ₀ I 2R Tesla

Here, we have to find the radius of the loop,

                    R = B / µ₀ I × 2

µ₀ = 4π × 10-7 H/m.

Substituting all the values in the equation,

                   R = ( 2 × 10⁻⁴ ) / ( 4π × 10-7 × 6 × 2)

                      = ( 2 × 10⁻⁴ ) / ( 0.0000150796)

    Radius, R  = 13 cm

Thus, the radius of the loop is 13 cm.

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Answer:

10J

Explanation:

In this question we have the following information

The charge of the particle is q = 5 C

The equipotenetial level is V1 = 5.5 v

and also the

equipotenetial level is V2 = 3.5 v

So we calculate the

work done W=q x (v1-v2)

workdone = 5 x (5.5-3.5)

= 5x2

=10 J

Workdone = 10 J

So we conclude that the workdone on a particle with these information is 10j

Answer:

0.25 m.

Explanation:

mass of the block = 7.40 kg, height = 0.83 m, force constant of the spring = 9.50 x [tex]10^{2}[/tex] N/m.

The maximum compression on the spring can be determined by;

Potential energy stored in the spring = [tex]\frac{1}{2}[/tex] K[tex]x^{2}[/tex]

But, potential energy = mgh

So that,

mgh = [tex]\frac{1}{2}[/tex] K[tex]x^{2}[/tex]

7.4 x 9.8 x 0.83 = 9.50 x [tex]10^{2}[/tex] x [tex]x^{2}[/tex]

60.1916 = 9.50 x [tex]10^{2}[/tex] x [tex]x^{2}[/tex]

[tex]x^{2}[/tex]= [tex]\frac{60.1916}{9.50*10^{2} }[/tex]

  = 0.06336

x = 0.2517

x = 0.25 m

The maximum compression of the spring is 0.25 m.

[tex]{\underline{\pink{\textsf{\textbf{ Answer : }}}}}[/tex]

➡ 15.85/5

➡ 3.17 ans.

Answer:

I am pretty sure is either C or D hope this helps

Answer:

A heating up the Earth's surface unevenly

Explanation:

Wind comes from the sun heating up the earth's surface unevenly. This causes air masses to have different temperatures. Differences in temperature causes the density of the air masses on the earth surface to differ.

Answer:

148 V

Explanation:

The electric field can be obtained using the formula;

E= V/d

where;

E is the electric field intensity = 37 volt/m

V is the potential difference (the unknown)

m is the distance of separation = 4m

V = Ed

V = 37 volt/m * 4 m

V= 148 V

Answer:

The magnitude of the bugs displacement is 3.87 m

Explanation:

An illustrative diagram for the scenario is given in the attachment below.

In the diagram, the bug's displacement is given by x. The diagram shows a right angle triangle with x as the hypotenuse. We can determine x from the Pythagorean theorem which states that " the square of the hypotenuse equals sum of squares of the other two sides". That is

x² = 2.25² + 3.15²

x² = 5.0625 + 9.9225

x² = 14.985

x = √14.985

x = 3.87 m

Hence, the magnitude of the bugs displacement is 3.87 m.

Answer:

A

Explanation:

just did it

As the mass of an object increases its momentum increases, and it takes more force to change its motion. So, option A.

Mass in motion is quantified by momentum, which is the measure of the amount of mass in motion.

Here,

Momentum of an object, which is under motion can be defined as the product of the mass and velocity of the object.

Momentum, P = mv

According to Newton's second law, the force is defined as the rate of change of momentum, or the momentum per unit time.

F = dP/dt

So, force is proportional to the amount of momentum imparted on the object.

Therefore, if the mass or velocity of the object increases, it will eventually cause the momentum to be increased and as a result, the force required to exert on the object will increase.

Hence,

As the mass of an object increases its momentum increases, and it takes more force to change its motion. So, option A.

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Answer:

The total kinetic energy is 2.8m J. (NOTE: m is mass of the sphere)

Explanation:

The total kinetic energy of a sphere is given by the sum of the rotational kinetic energy and the translational kinetic energy. That is,

[tex]K_{Total} = K_{R} + K_{T}[/tex]

The rotational kinetic energy [tex]K_{R}[/tex] is given by

[tex]K_{R} = \frac{1}{2}I\omega^{2}[/tex]

Where [tex]I[/tex] is the moment of inertia

and [tex]\omega[/tex] is the angular velocity

The translational kinetic energy [tex]K_{T}[/tex] is given by

[tex]K_{T} = \frac{1}{2}mv^{2}[/tex]

Where [tex]m[/tex] is the mass

and [tex]v[/tex] is the translational speed (velocity)

∴ [tex]K_{Total} = \frac{1}{2}I\omega^{2} + \frac{1}{2}mv^{2}[/tex]

But, the moment of inertia [tex]I[/tex] of a sphere is given by

[tex]I = \frac{2}{5}mr^{2}[/tex]

Where [tex]m[/tex] is mass

and [tex]r[/tex] is radius

∴ [tex]K_{Total} = \frac{1}{2}\times \frac{2}{5}mr^{2} \omega^{2} + \frac{1}{2}mv^{2}[/tex]

[tex]K_{Total} = \frac{1}{5}mr^{2} \omega^{2} + \frac{1}{2}mv^{2}[/tex]

Also, [tex]\omega = \frac{v}{r}[/tex]

∴ [tex]\omega^{2} = \frac{v^{2} }{r^{2} }[/tex]

Then,

[tex]K_{Total} = \frac{1}{5}mr^{2} \times \frac{v^{2} }{r^{2} } + \frac{1}{2}mv^{2}[/tex]

[tex]K_{Total} = \frac{1}{5}mv^{2} + \frac{1}{2}mv^{2}[/tex]

∴ [tex]K_{Total} = \frac{7}{10}mv^{2}[/tex]

From the question, [tex]v = 2.00 m/s[/tex]

Then,

[tex]K_{Total} = \frac{7}{10}m(2.00)^{2}[/tex]

[tex]K_{Total} = \frac{7}{10}m\times 4.00[/tex]

[tex]K_{Total} = 2.8m J[/tex]

Hence, the total kinetic energy is 2.8m J. (NOTE: m is mass of the sphere)

Answer:

The maximum speed of the car is 35 m/s

The total distance traveled by the car is 658.33 m

Explanation:

Given;

initial velocity of the car, u = 15 m/s

acceleration of the car, a = 2 m/s²

time of car motion, t = 10 s

(i)

Initial distance traveled by the car is given by;

d₁ = ut + ¹/₂at²

d₁ = (15 x 10) + ¹/₂(2)(10)²

d₁ = 150 + 100

d₁ = 250 m

The maximum speed of the car during this is given by;

v² = u² + 2ad₁

v² = (15)² + (2 x 2 x 250)

v² = 1225

v = √1225

v = 35 m/s

(ii)

The final distance cover by the car during the deceleration of 1.5 m/s².

Note: the final or maximum speed of the car becomes the initial velocity during deceleration.

v² = u² + 2ad₂

where;

v is the final speed of the car when it stops = 0

0 = u² + 2ad₂

0 = (35²) + (2 x - 1.5 x d₂)

0 = 1225 - 3d₂

3d₂ = 1225

d₂ = 1225 / 3

d₂ = 408.33 m

The total distance traveled by the car is given by;

d = d₁ + d₂

d = 250 m + 408.33 m

d = 658.33 m

Answer:

The mellon

Explanation:

I just know

Answer:

A. 24.25 m/s

Explanation:

velocity = [tex]\sqrt{2 * g * d}[/tex]

velocity = sqr 2 * 9.8 * 30 = sqr 588 = 24.25 m/s

The velocity of the watermelon as it smashes into the ground will be 24.2 m/s

The third equation of motion is -

v² - u² = 2aS

Given David Wetterman drops a 5 kg watermelon from the top of a 30 m building.

Height of building [S] = 30 m

Mass of watermelon [M] = 5 Kg

Initial velocity [v] = 0 m/s

acceleration [g] = 9.8 m/s²

Using the third equation of motion -

v² - u² = 2aS

v² = 2aS

v² = 2 x 9.8 x 30

v² = 588

v = 24.2 m/s

Therefore, the velocity of the watermelon as it smashes into the ground will be 24.2 m/s.

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Answer:

Work = Mass * Gravity * Height and is measured in Joules. Imagine you find a 2 -Kg book on the floor and lift it 0.75 meters and put it on a table. Remember, that “force” is simply a push or a pull. If you lift 100 kg of mass 1-meter, you will have done 980 Joules of work.

Explanation:

Answer:

The distance moved is 82 m.

The displacement is 18 m to the south.

Explanation:

The distance is a measure of the total length traveled along the path, while the displacement only takes into account the length between the starting position (departure) and final position (arrival). That is, distance refers to how much space an object travels during its movement, being the amount moved, while displacement refers to the distance and direction of the final position with respect to the initial position of an object.

So, the distance being the sum of the distances traveled, you get:

18 m + 22 m + 14 m + 28 m= 82 m

The distance moved is 82 m.

You know that the tennis ball moves 18 meters to the north, then 22 meters to the south, then 14 meters to the north, and finally 28 meters to the south. Then the tennis ball moves:

Calculating the displacement as the difference between the final position and the initial position, you get:

displacement= 50 m - 32 m= 18 m

The displacement is 18 m to the south.

Answer:

penis

Explanation:

Given :

A 50 kg boy stands on rough horizontal ground. The coefficient  of static friction, us, is 0.68.

To Find :

The maximum static friction  between the boy and the ground is _ N.

Solution :

We know maximum static friction is given by :

[tex]F = \mu mg \\\\F= 0.68\times 50\times 9.8\\\\F = 333.2\ N[/tex]

Therefore, maximum static friction is 333.2 N.

Hence, this is the required solution.

Answer:

Exercising, yoga

Explanation:

Answer:

The value is  [tex]y = 0.0458 \ m[/tex]

Explanation:

From the question we are told that

   The initial amplitude is  A =  2.5 \  m

    The time considered is   t = 20 s

Generally the amplitude at time  t is mathematically represented as

      [tex]y = Ae^{- \frac{t}{\tau} }[/tex]

Here [tex]\tau[/tex] is the time constant let assume the value to be [tex]\tau = 5 \ s[/tex]

So

       [tex]y = 2.5 * e^{- \frac{20}{5} }[/tex]

=>  [tex]y = 0.0458 \ m[/tex]

Answer:

The quantity of charge or electron flowing the wire in the given time is 4.5 x 10¹⁹ electrons.

Explanation:

Given;

emf of the battery, V = 12 V

resistance of the resistor, R = 100-Ω

time of current flow, t = 1 min

charge of 1 electron = 1.602 x 10¹⁹ C

The current through this circuit is given by;

I = V / R

I = (12) / (100)

I = 0.12 A

The quantity of charge or electron flowing the wire in the given time is calculated as;

Q =It

where;

I is the current flowing through the wire

t is the time of current flow = 1 x 60s = 60 s

Q = 0.12 x 60

Q = 7.2 C

1.602 x 10⁻¹⁹ C --------------- 1 electron

7.2 C -----------------------------? electron

[tex]= \frac{7.2 }{1.602*10^{-19}} \\\\= 4.5*10^{19} \ electrons[/tex]

Therefore, the quantity of charge or electron flowing the wire in the given time is 4.5 x 10¹⁹ electrons.

Answer:

the awnser is A

Explanation:

Brainliest Please

Answer:

A

Explanation

Within a cloud, water droplets condense onto one another so its causing so its causing the droplets to grow when they have grown to heavy the fall causing rain.

Answer:

I = 44.1[amp]

P = 9.92 [kw-hr]

Explanation:

We know that electrical power can be calculated by means of the following expression.

[tex]P=V*I[/tex]

where:

P = power = 4.41 [kW] = 4410 [w]

V = 100 [V]

I = current [amp]

Now we have:

[tex]I=P/V\\I = 4410/100\\I = 44.1 [amp][/tex]

Now the power absorbed during this time is equal to the product of power by time.

[tex]15[min]*\frac{1hr}{60min} =0.25 [hr][/tex]

t = time = 2.25 [hr]

[tex]P_{ab}=4.41*2.25\\P=9.92[kW-hr][/tex]

Answer:

concave shape of the waverock

Explanation:

The wave rock is formed by the weathering of the surrounding area. This helps in proving the deposition part, as the wave rock was below the ground, occurred due to deposition of rock years over the years. It is made from very tough material from its surroundings. The weathering reduces the surrounding terrain, while the bedrock remains to witness for the history.  Also, volcanic eruptions have been changing earth for a long time. (first of all, the theory that a volcanic eruption helped in making dinos go extinct.) Real world examples include: Ash and sulfur went pretty high into Earth's atmosphere because of the Tambora eruption which in turn dimmed incoming sunlight, and lowered global temperatures by about 3°F. The Mount Pinatubo eruption in the Philippines in 1991 cooled the planet by about 1°F.

Answer: True

Explanation:

Answer: Trail Braking!

Explanation: Trail braking is used to smoothly and gradually reduce brake pedal pressure at the end of a braking maneuver.

Option A. trail braking.

In four-wheel vehicles, trail braking is using the brakes past the corner entrance, as opposed to the normally taught practice of releasing the brakes before starting the turn. It creates weight transfer to the front tires, increasing their traction and reducing understeer.

Trail-braking allows a driver to brake later by extending the braking zone into the corner. It also improves the car's turn-in response by increasing the load on the front tires to maximize grip. Together, these result in higher corner entry speed and reduced time through the corner.

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Answer:

The bus is moving at a constant speed.

Explanation:

We have the following facts from the question;

- The bus crosses a city block every 10 seconds.

- all the city blocks are the same length

Since all the city block are the same length, let's say the distance is d.

Since it crosses the city block every 10 seconds, we know that;

Speed = distance/time

Thus, Speed = d/10

Thus,it is moving at this speed of d/10 all through.

Therefore we can conclude that the bus is moving at a constant speed.

Answer:

SO I TESTED POSITIVE FOR CORONA IS A SIMPTOM DIEURREUH C SINCE I GOT CORNA I HAVE BEEN HAVE big DIEURREE UH

Explanation:

Answer:

Explanation:

m1v1=m2v2

m1=70 kg

m2=10 g=0.01 kg

v2=500 m/s

m1v1=m2v2

v1=m2v2/m1

v1=0.01*500/70

v1=0.07